Container with two indexes (or a compound index) - c++

I have a class like this
class MyClass
{
int Identifier;
int Context;
int Data;
}
and I plan to store it in a STL container like
vector<MyClass> myVector;
but I will need to access it either by the extenal Index (using myVector[index]); and the combination of Identifier and Context which in this case I would perform a search with something like
vector<MyClass>::iterator myIt;
for( myIt = myVector.begin(); myIt != myVector.end(); myIt++ )
{
if( ( myIt->Idenfifier == target_id ) &&
( myIt->Context == target_context ) )
return *myIt; //or do something else...
}
Is there a better way to store or index the data?

Boost::Multi-Index has this exact functionality if you can afford the boost dependency (header only). You would use a random_access index for the array-like index, and either hashed_unique, hashed_non_unique, ordered_unique, or ordered_non_unique (depending on your desired traits) with a functor that compares Identifier and Context together.

We need to know your usage. Why do you need to be able to get them by index, and how often do you need to search the container for a specific element.
If you store it in an std::set, your search time with be O(ln n), but you cannot reference them by index.
If you use an std::vector, you can index them, but you have to use std::find to get a specific element, which will be O(n).
But if you need an index to pass it around to other things, you could use a pointer. That is, use a set for faster look-up, and pass pointers (not index's) to specific elements.

Yes, but if you want speed, you'll need to sacrifice space. Store it in a collection (like an STL set) with the identifier/context as key, and simultaneously store it in a vector. Of course, you don't want two copies of the data itself, so store it in the set using a smart pointer (auto_ptr or variant) and store it in the vector using a dumb pointer.

Related

Iterating over Unorderd_map using indexed for loop

I am trying to access values stored in an unorderd_map using a for loop, but I am stuck trying to access values using the current index of my loop. Any suggestion, or link to look-on? thanks. [Hint: I don't want to use an iterator].
my sample code:
#include <iostream>
#include <string>
#include <unordered_map>
#include <vector>
using namespace std;
int main()
{
unordered_map<int,string>hash_table;
//filling my hash table
hash_table.insert(make_pair(1,"one"));
hash_table.insert(make_pair(2,"two"));
hash_table.insert(make_pair(3,"three"));
hash_table.insert(make_pair(4,"four"));
//now, i want to access values of my hash_table with for loop, `i` as index.
//
for (int i=0;i<hash_table.size();i++ )
{
cout<<"Value at index "<<i<<" is "<<hash_table[i].second;//I want to do something like this. I don't want to use iterator!
}
return 0;
}
There are two ways to access an element from an std::unordered_map.
An iterator.
Subscript operator, using the key.
I am stuck trying to access values using the current index of my loop
As you can see, accessing an element using the index is not listed in the possible ways to access an element.
I'm sure you realize that since the map is unordered the phrase element at index i is quite meaningless in terms of ordering. It is possible to access the ith element using the begin iterator and std::advance but...
Hint: I don't want to use an iterator].
Hint: You just ran out of options. What you want to do is not possible. Solution: Start wanting to use tools that are appropriate to achieving your objective.
If you want to iterate a std::unordered_map, then you use iterators because that's what they're for. If you don't want to use iterators, then you cannot iterate an std::unordered_map. You can hide the use of iterators with a range based for loop, but they're still used behind the scenes.
If you want to iterate something using a position - index, then what you need is an array such as a std::vector.
First, why would you want to use an index versus an iterator?
Suppose you have a list of widgets you want your UI to draw. Each widget can have its own list of child widgets, stored in a map. Your options are:
Make each widget draw itself. Not ideal since widgets are now coupled to the UI kit you are using.
Return the map and use an iterator in the drawing code. Not ideal because now the drawing code knows your storage mechanism.
An API that can avoid both of these might look like this.
const Widget* Widget::EnumerateChildren(size_t* io_index) const;
You can make this work with maps but it isn't efficient. You also can't guarantee the stability of the map between calls. So this isn't recommended but it is possible.
const Widget* Widget::EnumerateChildren(size_t* io_index) const
{
auto& it = m_children.begin();
std::advance(it, *io_index);
*io_index += 1;
return it->second;
}
You don't have to use std::advance and could use a for loop to advance the iterator yourself. Not efficient or very safe.
A better solution to the scenario I described would be to copy out the values into a vector.
void Widget::GetChildren(std::vector<Widget*>* o_children) const;
You can't do it without an iterator. An unordered map could store the contents in any order and move them around as it likes. The concept of "3rd element" for example means nothing.
If you had a list of the keys from the map then you could index into that list of keys and get what you want. However unless you already have it you would need to iterate over the map to generate the list of keys so you still need an iterator.
An old question.
OK, I'm taking the risk: here may be a workaround (not perfect though: it is just a workaround).
This post is a bit long because I explain why this may be needed. In fact one might want to use the very same code to load and save data from and to a file. This is very useful to synchronize the loading and saving of data, to keep the same data, the same order, and the same types.
For example, if op is load_op or save_op:
load_save_data( var1, op );
load_save_data( var2, op );
load_save_data( var3, op );
...
load_save_data hides the things performed inside. Maintenance is thus much more easy.
The problem is when it comes to containers. For example (back to the question) it may do this for sets (source A) to save data:
int thesize = theset.size();
load_save(thesize, load); // template (member) function with 1st arg being a typename
for( elem: theset) {
load_save_data( thesize, save_op );
}
However, to read (source B):
int thesize;
load_save_data( thesize, save);
for( int i=0; i<thesize, i++) {
Elem elem;
load_save_data( elem, load_op);
theset.insert(elem);
}
So, the whole source code would be something like this, with too loops:
if(op == load_op) { A } else { B }
The problem is there are two different kinds of loop, and it would be nice to merge them as one only. Ideally, it would be nice to be able to do:
int thesize;
load_save_data( thesize, save);
for( int i=0; i<thesize, i++) {
Elem elem;
if( op == save_op ) {
elem=theset[i]; // not possible
}
load_save_data( elem, op);
if( op == load_op ) {
theset.insert(elem);
}
}
(as this code is used in different contexts, care may be taken to provide enough information to the compiler to allow it the strip the unnecessary code (the right "if"), not obvious but possible)
This way, each call to load_save_data is in the same order, the same type. You forget a field for both or none, but everything is kept synchronized between save and load. You may add a variable, change a type, change the order etc in one place only. The code maintenance is thus easier.
A solution to the impossible "theset[i]" is indeed to use a vector or a map instead of a set but you're losing the properties of a set (avoid two identical items).
So a workaround (but it has a heavy price: efficiency and simplicity) is something like:
void ...::load_save( op )
{
...
int thesize;
set<...> tmp;
load_save_data( thesize, save);
for( int i=0; i<thesize, i++) {
Elem elem;
if( op == save_op ) {
elem=*(theset.begin()); \
theset.erase(elem); > <-----
tmp.insert(elem); /
}
load_save_data( elem, op);
if( op == load_op ) {
theset.insert(elem);
}
}
if(op == save_op) {
theset.insert(tmp.begin(), tmp.end()); <-----
}
...
}
Not very beautiful but it does the trick, and (IMHO) itis the closest answer to the question.

Memory Allocation in C++, Using a Map of Linked Lists

The underlying data structure I am using is:
map<int, Cell> struct Cell{ char c; Cell*next; };
In effect the data structure maps an int to a linked list. The map(in this case implemented as a hashmap) ensures that finding a value in the list runs in constant time. The Linked List ensures that insertion and deletion also run in constant time. At each processing iteration I am doing something like:
Cell *cellPointer1 = new Cell;
//Process cells, build linked list
Once the list is built I put the elements Cell in map. The structure was working just fine and after my program I deallocate memory. For each Cell in the list.
delete cellPointer1
But at the end of my program I have a memory leak!!
To test memory leak I use:
#include <stdlib.h>
#include <crtdbg.h>
#define _CRTDBG_MAP_ALLOC
_CrtDumpMemoryLeaks();
I'm thinking that somewhere along the way the fact that I am putting the Cells in the map does not allow me to deallocate the memory correctly. Does anyone have any ideas on how to solve this problem?
We'll need to see your code for insertion and deletion to be sure about it.
What I'd see as a memleak-free insert / remove code would be:
( NOTE: I'm assuming you don't store the Cells that you allocate in the map )
//
// insert
//
std::map<int, Cell> _map;
Cell a; // no new here!
Cell *iter = &a;
while( condition )
{
Cell *b = new Cell();
iter->next = b;
iter = b;
}
_map[id] = a; // will 'copy' a into the container slot of the map
//
// cleanup:
//
std::map<int,Cell>::iterator i = _map.begin();
while( i != _map.end() )
{
Cell &a = i->second;
Cell *iter = a.next; // list of cells associated to 'a'.
while( iter != NULL )
{
Cell *to_delete = iter;
iter = iter->next;
delete to_delete;
}
_map.erase(i); // will remove the Cell from the map. No need to 'delete'
i++;
}
Edit: there was a comment indicating that I might not have understood the problem completely. If you insert ALL the cells you allocate in the map, then the faulty thing is that your map contains Cell, not Cell*.
If you define your map as: std::map<int, Cell *>, your problem would be solved at 2 conditions:
you insert all the Cells that you allocate in the map
the integer (the key) associated to each cell is unique (important!!)
Now the deletion is simply a matter of:
std::map<int, Cell*>::iterator i = _map.begin();
while( i != _map.end() )
{
Cell *c = i->second;
if ( c != NULL ) delete c;
}
_map.clear();
I've built almost the exact same hybrid data structure you are after (list/map with the same algorithmic complexity if I were to use unordered_map instead) and have been using it from time to time for almost a decade though it's a kind of bulky structure (something I'd use with convenience in mind more than efficiency).
It's worth noting that this is quite different from just using std::unordered_map directly. For a start, it preserves the original order in which one inserts elements. Insertion, removal, and searches are guaranteed to happen in logarithmic time (or constant time depending on whether key searching is involved and whether you use a hash table or BST), iterators do not get invalidated on insertion/removal (the main requirement I needed which made me favor std::map over std::unordered_map), etc.
The way I did it was like this:
// I use this as the iterator for my container with
// the list being the main 'focal point' while I
// treat the map as a secondary structure to accelerate
// key searches.
typedef typename std::list<Value>::iterator iterator;
// Values are stored in the list.
std::list<Value> data;
// Keys and iterators into the list are stored in a map.
std::map<Key, iterator> accelerator;
If you do it like this, it becomes quite easy. push_back is a matter of pushing back to the list and adding the last iterator to the map, iterator removal is a matter of removing the key pointed to by the iterator from the map before removing the element from the list as the list iterator, finding a key is a matter of searching the map and returning the associated value in the map which happens to be the list iterator, key removal is just finding a key and then doing iterator removal, etc.
If you want to improve all methods to constant time, then you can use std::unordered_map instead of std::map as I did here (though that comes with some caveats).
Taking an approach like this should simplify things considerably over an intrusive list-based solution where you're manually having to free memory.
Is there a reason why you are not using built-in containers like, say, STL?
Anyhow, you don't show the code where the allocation takes place, nor the map definition (is this coming from a library?).
Are you sure you deallocate all of the previously allocated Cells, starting from the last one and going backwards up to the first?
You could do this using the STL (remove next from Cell):
std::unordered_map<int,std::list<Cell>>
Or if cell only contains a char
std::unordered_map<int,std::string>
If your compiler doesn't support std::unordered_map then try boost::unordered_map.
If you really want to use intrusive data structures, have a look at Boost Intrusive.
As others have pointed out, it may be hard to see what you're doing wrong without seeing your code.
Someone should mention, however, that you're not helping yourself by overlaying two container types here.
If you're using a hash_map, you already have constant insertion and deletion time, see the related Hash : How does it work internally? post. The only exception to the O(c) lookup time is if your implementation decides to resize the container, in which case you have added overhead regardless of your linked list addition. Having two addressing schemes is only going to make things slower (not to mention buggier).
Sorry if this doesn't point you to the memory leak, but I'm sure a lot of memory leaks / bugs come from not using stl / boost containers to their full potential. Look into that first.
You need to be very careful with what you are doing, because values in a C++ map need to be copyable and with your structure that has raw pointers, you must handle your copy semantics properly.
You would be far better off using std::list where you won't need to worry about your copy semantics.
If you can't change that then at least std::map<int, Cell*> will be a bit more manageable, although you would have to manage the pointers in your map because std::map will not manage them for you.
You could of course use std::map<int, shared_ptr<Cell> >, probably easiest for you for now.
If you also use shared_ptr within your Cell object itself, you will need to beware of circular references, and as Cell will know it's being shared_ptr'd you could derive it from enable_shared_from_this
My final point will be that list is very rarely the correct collection type to use. It is the correct one to use sometimes, especially when you have an LRU cache situation and you want to move accessed elements to the end of the list fast. However that is the minority case and it probably doesn't apply here. Think of an alternative collection you really want. map< int, set<char> > perhaps? or map< int, vector< char > > ?
Your list has a lot of overheads to store a few chars

Accessing map value by index

If I have a structure like
std::map<string, int> myMap;
myMap["banana"] = 1;
myMap["apple"] = 1;
myMap["orange"] = 1;
How can I access myMap[0]?
I know that the map sorts internally and I'm fine with this, I want to get a value in the map by index. I've tried myMap[0] but I get the error:
Error 1 error C2679: binary '[' : no operator found which takes a right-hand operand of type 'int' (or there is no acceptable conversion)
I realise I could do something like this:
string getKeyAtIndex (int index){
map<string, int>::const_iterator end = myMap.end();
int counter = 0;
for (map<string, int>::const_iterator it = myMap.begin(); it != end; ++it) {
counter++;
if (counter == index)
return it->first;
}
}
But surely this is hugely inefficient? Is there a better way?
Your map is not supposed to be accessed that way, it's indexed by keys not by positions. A map iterator is bidirectional, just like a list, so the function you are using is no more inefficient than accessing a list by position. If you want random access by position then use a vector or a deque.
Your function could be written with help from std::advance(iter, index) starting from begin():
auto it = myMap.begin();
std::advance(it, index);
return it->first;
There may be an implementation specific (non-portable) method to achieve your goal, but not one that is portable.
In general, the std::map is implemented as a type of binary tree, usually sorted by key. The definition of the first element differs depending on the ordering. Also, in your definition, is element[0] the node at the top of the tree or the left-most leaf node?
Many binary trees are implemented as linked lists. Most linked lists cannot be directly accessed like an array, because to find element 5, you have to follow the links. This is by definition.
You can resolve your issue by using both a std::vector and a std::map:
Allocate the object from dynamic memory.
Store the pointer, along with the key, into the std::map.
Store the pointer in the std::vector at the position you want it
at.
The std::map will allow an efficient method to access the object by key.
The std::vector will allow an efficient method to access the object by index.
Storing pointers allows for only one instance of the object instead of having to maintain multiple copies.
Well, actually you can't. The way you found is very unefficient, it have a computational complexity of O(n) (n operations worst case, where n is the number of elements in a map).
Accessing an item in a vector or in an array have complexity O(1) by comparison (constant computational complexity, a single operation).
Consider that map is internally implemented as a red black tree (or avl tree, it depends on the implementation) and every insert, delete and lookup operation are O(log n) worst case (it requires logarithm in base 2 operations to find an element in the tree), that is quite good.
A way you can deal with is to use a custom class that have inside both a vector and a map.
Insertion at the end of the class will be averaged O(1), lookup by name will be O(log n), lookup by index will be O(1) but in this case, removal operation will be O(n).
Previous answer (see comment): How about just myMap.begin();
You could implement a random-access map by using a vector backing-store, which is essentially a vector of pairs. You of course lose all the benefits of the standard library map at that point.
you can use some other map like containers .
keep a size fields can make binary search tree easy to random access .
here is my implementation ...
std style , random access iterator ...
size balanced tree ...
https://github.com/mm304321141/zzz_lib/blob/master/sbtree.h
and B+tree ...
https://github.com/mm304321141/zzz_lib/blob/master/bpptree.h
std::map is an ordered container, but it's iterators don't support random access, but rather bidirectional access. Therefore, you can only access the nth element by navigating all its prior elements. A shorter alternative to your example is using the standard iterator library:
std::pair<const std::string, int> &nth_element = *std::next(myMap.begin(), N);
This has linear complexity, which is not ideal if you plan to frequently access this way in large maps.
An alternative is to use an ordered container that supports random access. For example, boost::container::flat_map provides a member function nth which allows you exactly what you are looking for.
std::map<string,int>::iterator it = mymap.begin() + index;

How do I remove duplicates from a C++ array?

I have an array of structs; the array is of size N.
I want to remove duplicates from the array; that is, do an in-place change, converting the array to have a single appearance of each struct. Additionally, I want to know the new size M (highest index in the reduced array).
The structs include primitives so it's trivial to compare them.
How can I do that efficiently in C++?
I have implemented the following operators:
bool operator==(const A &rhs1, const A &rhs2)
{
return ( ( rhs1.x== rhs2.x ) &&
( rhs1.y == rhs2.y ) );
}
bool operator<(const A &rhs1, const A &rhs2)
{
if ( rhs1.x == rhs2.x )
return ( rhs1.y < rhs2.y );
return ( rhs1.x < rhs2.x );
}
However, I get an error when running:
std::sort(array, array+ numTotalAvailable);
* array will have all elements here valid.
std::unique_copy(
array,
array+ numTotalAvailable,
back_inserter(uniqueElements));
* uniqueElements will have non-valid elements.
What is wrong here?
You could use a combination of the std::sort and std::unique algorithms to accomplish this:
std::sort(elems.begin(), elems.end()); // Now in sorted order.
iterator itr = std::unique(elems.begin(), elems.end()); // Duplicates overwritten
elems.erase(itr, elems.end()); // Space reclaimed
If you are working with a raw array (not, say, a std::vector), then you can't actually reclaim the space without copying the elements over to a new range. However, if you're okay starting off with a raw array and ending up with something like a std::vector or std::deque, you can use unique_copy and an iterator adapter to copy over just the unique elements:
std::sort(array, array + size); // Now in sorted order
std::vector<T> uniqueElements;
std::unique_copy(array, array + size,
back_inserter(uniqueElements)); // Append unique elements
At this point, uniqueElements now holds all the unique elements.
Finally, to more directly address your initial question: if you want to do this in-place, you can get the answer by using the return value from unique to determine how many elements remain:
std::sort(elems, elems + N); // Now in sorted order.
T* endpoint = std::unique(elems, elems + N);// Duplicates overwritten
ptrdiff_t M = endpoint - elems; // Find number of elements left
Hope this helps!
std::set<T> uniqueItems(v.begin(), v.end());
Now uniqueItems contains only the unique items. Do whatever you want to do with it. Maybe, you would like v to contain all the unique items. If so, then do this:
//assuming v is std::vector<T>
std::vector<T>(uniqueItems.begin(), uniqueItems.end()).swap(v);
Now v contains all the unique items. It also shrinks v to a minimum size. It makes use of Shrink-to-fit idiom.
You could use the flyweight pattern. Easiest way to do so, would be using the Boost Flyweight library.
Edit: I'm not sure if there is some way to find out how many objects are stored by the Boost flyweight implementation, if there is, I can't seem to find it in the documentation.
An alternative approach to applying algorithms to your array would be to insert its elements in a std::set. Whether it is reasonable to do it this way depends on how you plan to use your items.

Order a container by member with STL

Suppose I have some data stored in a container of unique_ptrs:
struct MyData {
int id; // a unique id for this particular instance
data some_data; // arbitrary additional data
};
// ...
std::vector<std::unique_ptr<MyData>> my_data_vec;
The ordering of my_data_vec is important. Suppose now I have another vector of IDs of MyDatas:
std::vector<int> my_data_ids;
I now want to rearrange my_data_vec such that the elements are in the sequence specified by my_data_ids. (Don't forget moving a unique_ptr requires move-semantics with std::move().)
What's the most algorithmically efficient way to achieve this, and do any of the STL algorithms lend themselves well to achieving this? I can't see that std::sort would be any help.
Edit: I can use O(n) memory space (not too worried about memory), but the IDs are arbitrary (in my specific case they are actually randomly generated).
Create a map that maps ids to their index in my_data_ids.
Create a function object that compares std::unique_ptr<MyData> based on their ID's index in that map.
Use std::sort to sort the my_data_vec using that function object.
Here's a sketch of this:
// Beware, brain-compiled code ahead!
typedef std::vector<int> my_data_ids_type;
typedef std::map<int,my_data_ids_type::size_type> my_data_ids_map_type;
class my_id_comparator : public std::binary_function< bool
, std::unique_ptr<MyData>
, std::unique_ptr<MyData> > {
public:
my_id_comparator(const my_data_ids_map_type& my_data_ids_map)
: my_data_ids_map_(my_data_ids_map) {}
bool operator()( const std::unique_ptr<MyData>& lhs
, const std::unique_ptr<MyData>& rhs ) const
{
my_data_ids_map_type::const_iterator it_lhs = my_data_ids_map_.find(lhs.id);
my_data_ids_map_type::const_iterator it_rhs = my_data_ids_map_.find(rhs.id);
if( it_lhs == my_data_ids_map_.end() || it_rhs == my_data_ids_map_.end() )
throw "dammit!"; // whatever
return it_lhs->second < it_rhs->second;
}
private
my_data_ids_map_type& my_data_ids_map_;
};
//...
my_data_ids_map_type my_data_ids_map;
// ...
// populate my_data_ids_map with the IDs and their indexes from my_data_ids
// ...
std::sort( my_data_vec.begin(), my_data_vec.end(), my_id_comparator(my_data_ids_map) );
If memory is scarce, but time doesn't matter, you could do away with the map and search the IDs in the my_data_ids vector for each comparison. However, you would have to be really desperate for memory to do that, since two linearly complex operations per comparison are going to be quite expensive.
Why don't you try moving the data into a STL Set ? you need only to implement the comparison function, and you will end up with a perfectly ordered set of data very fast.
Why don't you just use a map<int, unique_ptr<MyData>> (or multimap)?