Problem:
^.+ matches only the first line of the source code in dreamweaver. I need it to match each line so that I can wrap each full line in P tags. I have 500 files to do this in.
I know ^ should match the beginning of a line and I also know that multi-line mode must be enabled for it to work on each line and not just at the beginning of the file. I also know dreamweaver uses javascript source code.
Is lack of multi-line mode the problem? Is there any way to turn it on in dreamweaver? I tried using /m at the beginning search to enable multi-line mode, but that didn't work either.
I'm open to any solution for my current problem, even if it involves a different program. However, a fix for dreamweaver is ideal, 2nd place is a way to do this in notepad++, 3rd place is a way do to this in python or something (I only know javascript, you'll have to spell it out exactly in another language).
Thank you,
robert
p.s.
I found I can "select all > right click > selection > indent" to add two spaces to the beginning of each line in dreamweaver. This allows me to find the beginning of each line with / {2,}/. I really don't want to select all > indent on all 500 files, but i'm about to start since I've already spent a few hours bludgeoning dreamweaver.
Don't use Dreamweaver for this - use Notepad++ (since you are familiar with it) at its regular expression support is superior.
If you are comfortable with a more robust scripting language (Python, Ruby, Perl, etc.) then that would be an ever better way to do it.
The way that I might do this in DW would not involve using the find-replace tool's "Regular Expression" option, but instead using just plain old matching on a CrLf.
In the Find portion, since you can't directly enter a CrLf, you'll have to copy one to your clipboard beforehand and paste it in where needed.
In the Replace portion, replace with:
</p>[CrLf]
<p>
Again, be sure to paste in a proper "[CrLf]". This will work on all but the very first and very last lines of your document, so I know this isn't a 100% solution. There are probably better solutions using other tools that someone else can recommend!
Good luck!
-Mike
I had a flash of insight right after posting. (isn't that the way of it?)
Dreamweaver can find the end of each line with \r\n so instead of trying to work forward, i should have just worked backwards.
search: (.+)(\r\n)
replace: <p>$1</p>$2
[\w\W]* matches anything, including a newline. Its greedy, so it fact it matches everything.
Related
I need a help with mass search and replace using regex.
I have a longer strings where I need to look for any number and particular string - e.g. 321BS and I need to replace just the text string that I was looking for. So I need to look for BS in "gf test test2 321BS test" (the pattern is always the same just the position differs) and change just BS.
Can you please help me to find particular regex for this?
Update: I need t keep the number and change just the text string. I will be doing this notepad++. However I need a general funcion for this if possible. I am a rookie in regex. Moreover, is it possible to do it in Trados SDL Studio? Or how am i able to do it in excel file in bulk?
Thank you very much!
Your question is a bit vague, however, as I understand it you want to match any digits followed by BS, ie 123BS. You want to keep 123 but replace BS?
Regex: (\d+)BS matches 123BS
In notepad++ you can:
match (\d+)BS
replace \1NEWTEXT
This will replace 123BS with 123NEWTXT.
\1 will substitue the capture group (\d+). (which matches 1 or more digits.
You could do this in Trados Studio using an app. The SDLXLIFF Toolkit may be the most appropriate for you. The advantage over Notepad++ is that it's controlled and will only affect the translatable text and not anything that might break the integrity of the file if you make a mistake. You can also handle multiple files, or even multiple Trados Studio projects in one go.
The syntax would be very similar to the suggestion above... you would:
match (\d+)BS
replace $1NEWTEXT
I'm using TextWrangler, the free version of BBEdit on the Mac, which I understand uses the PCRE engine.
What I want to do is match a specific number of lines and replace as well.
After a lot of searching I came up with this:
(^(.*\r)){25}
This lets me match up to 25 lines. It works great, but the problem comes when I want to actually replace something. I can't figure out how to do it.
For example, I would like to replace all of the returns "\r" with tabs "\t".
Hopefully this is actually possible. I'd appreciate any help. Thanks!
Regexp domain is searching. You cannot replace using regexp; a programming language or editor can use regexp as the search part of its search-and-replace function. Thus, the way to do 25 replacements is purely in the domain of said programming language or editor. If it does not provide such capability, either directly in search-and-replace or as a macro/loop/other, then you cannot do it automatically.
I'm working with load files and trying to write a regex that will check for any rows in the file that do not have the correct number of delimiters. Let's pretend the delimiter is % (I'm not sure this text field supports the delimiters that are in the load file). The regex I wrote that finds all rows that are correct is:
^%([^%]*%){20}$
Sometimes it's more beneficial to find any rows that do not have the correct number of delimiters, so to accomplish that, I wrote this:
(^%([^%]*%){0,19}$)|(^%([^%]*%){21,}$)
I'm concerned about the efficiency of this (and any regex I write in general), so I'm wondering if there's a better way to write it, or if the way I wrote it is fine. I thought maybe there would be some way to use alternation with the repetition tokens, such as:
{0,19}|{21,}
but that doesn't seem to work.
If it's helpful to know, I'm just searching through the files in Sublime Text, which I believe uses PCRE. I'm also open to suggestions for making the first regex better in general, although I've found it to work pretty well even in exceptionally large load files.
If your regex engine supports negative lookaheads, you can slightly modify your original regex.
^(?!%([^%]*%){20}$)
The regex above is useful for test only. If you want to capture, then you need to add .* part.
^(?!%([^%]*%){20}$).*$
I've been searching a lot in the web and in here but I can't find a solution to this.
I have to make two replacements in all registry paths saved in a text file as follows:
replace all asterisc with: [#42]
replace all single backslashes with two.
I already have two expressions that do this right:
1st case:
Find: (\*) - Replace: \[#42\]
2nd case:
Find: ([^\\])(\\)([^\\]) - Replace: $1$2\\$3
Now, all I want is to join them together into just one expression so that I can do run this in one time only.
I'm using Notepad++ 6.5.1 in Windows 7 (64 bits).
Example line in which I want this to work (I include backslashes but i don't know if they will appear right in the html):
HKLM\SOFTWARE\Classes\*\shellex\ContextMenuHandlers\
I already tried separating it with a pipe, like I do in Jscript (WSH), but it doesn't work here. I also tried a lot of other things but none worked.
Any help?
Thanks!
Edit: I have put all the backslashes right, but the page html seem to be "eating" some of them!
Edit2: Someone reedited my text to include an accent that doesn't remove the backslashes, so the expressions went wrong again. But I got it and fixed it. ;-)
Sorry, but this was my first post here. :)
As everyone else already mentioned this is not possible.
But, you can achieve what you want in Notepad++ by using a Macro.
Go to "Macro" > "Start Recording" menu, apply those two search and replace regular expressions, press "Stop Recording", then "Save Current Recorded Macro", there give it a name, assign a shortcut, and you are done. You now can reuse the same replacements whenever you want with one shortcut.
Since your replacement strings are totally different and use data that come not from any capture (i.e. [#42]), you can't.
Keep in mind that replacement strings are only masks, and can not contain any conditional content.
Sometimes I want to search and replace in Vim using the s/search_for/replace_with/options format, but the search_for part becomes a complicated regex that I can't get right the first time.
I have set incsearch hlsearch in my .vimrc so Vim will start highlighting as I type when I am searching using the /search_for format. This is useful to first "test"/"preview" my regex. Then once I get the regex I want, I apply to the s/ to search and replace.
But there is two big limitation to this approach:
It's a hassle to copy and paste the regex I created in / mode to s/ mode.
I can't preview with matched groups in regex (ie ( and )) or use the magic mode \v while in /.
So how do you guys on SO try to do complicated regex search and replace in Vim?
Test your regex in search mode with /, then use s//new_value/. When you pass nothing to the search portion of s, it takes the most recent search.
As #Sam Brink also says, you can use <C-r>/ to paste the contents of the search register, so s/<C-r>//new_value/ works too. This may be more convenient when you have a complicated search expression.
As already noted, you can practice the search part with /your-regex-here/. When that is working correctly, you can use s//replacement/ to use the latest search.
Once you've done that once, you can use & to repeat the last s/// command, even if you've done different searches since then. You can also use :&g to do the substitute globally on the current line. And you could use :.,$&g to do the search on all matches between here (.) and the end of the file ($), amongst a legion of other possibilities.
You also, of course, have undo if the operation didn't work as you expected.
As the others have noted I typically use s//replacement/ to do my replacements but you can also use <C-r>/ to paste what is in the search register. So you can use s/<C-r>//replacement/ where the <C-r>/ will paste your search and you can do any last minute changes you want.
<C-r> inserts the contents of a register where the cursor is
The / register holds the most recent search term
:registers will display the contents of every register so you can see whats available.
Since Neovim 0.1.7 there is the Incremental (“live”) :substitute function. (so this only works in Neovim!)
To enable it set the incommand option:
:set inccommand=split
It was announced here: https://neovim.io/news/2016/11/