Regex, writing a toy compiler, parsing, comment remover - regex

I'm currently working my way through this book:
http://www1.idc.ac.il/tecs/
I'm currently on a section where the excersize is to create a compiler for a very simple java like language.
The book always states what is required but not the how the how (which is a good thing). I should also mention that it talks about yacc and lex and specifically says to avoid them for the projects in the book for the sake of learning on your own.
I'm on chaper 10 which and starting to write the tokenizer.
1) Can anyone give me some general advice - are regex the best approach for tokenizing a source file?
2) I want to remove comments from source files before parsing - this isn't hard but most compilers tell you the line an error occurs on, if I just remove comments this will mess up the line count, are there any simple strategies for preserving the line count while still removing junk?
Thanks in advance!

The tokenizer itself is usually written using a large DFA table that describes all possible valid tokens (stuff like, a token can start with a letter followed by other letters/numbers followed by a non-letter, or with a number followed by other numbers and either a non-number/point or a point followed by at least 1 number and then a non-number, etc etc). The way i built mine was to identify all the regular expressions my tokenizer will accept, transform them into DFA's and combine them.
Now to "remove comments", when you're parsing a token you can have a comment token (the regex to parse a comment, too long to describe in words), and when you finish parsing this comment you just parse a new token, thus ignoring it. Alternatively you can pass it to the compiler and let it deal with it (or ignore it as it will). Either aproach will preserve meta-data like line numbers and characters-into-the-line.
edit for DFA theory:
Every regular expression can be converted (and is converted) into a DFA for performance reasons. This removes any backtracking in parsing them. This link gives you an idea of how this is done. You first convert the regular expression into an NFA (a DFA with backtracking), then remove all the backtracking nodes by inflating your finite automata.
Another way you can build your DFA is by hand using some common sense. Take for example a finite automata that can parse either an identifier or a number. This of course isn't enough, since you most likely want to add comments too, but it'll give you an idea of the underlying structures.
A-Z space
->(Start)----->(I1)------->((Identifier))
| | ^
| +-+
| A-Z0-9
|
| space
+---->(N1)---+--->((Number)) <----------+
0-9 | ^ | |
| | | . 0-9 space |
+-+ +--->(N2)----->(N3)--------+
0-9 | ^
+-+
0-9
Some notes on the notation used, the DFA starts at the (Start) node and moves through the arrows as input is read from your file. At any one point it can match only ONE path. Any paths missing are defaulted to an "error" node. ((Number)) and ((Identifier)) are your ending, success nodes. Once in those nodes, you return your token.
So from the start, if your token starts with a letter, it HAS to continue with a bunch of letters or numbers and end with a "space" (spaces, new lines, tabs, etc). There is no backtracking, if this fails the tokenizing process fails and you can report an error. You should read a theory book on error recovery to continue parsing, its a really huge topic.
If however your token starts with a number, it has to be followed by either a bunch of numbers or one decimal point. If there's no decimal point, a "space" has to follow the numbers, otherwise a number has to follow followed by a bunch of numbers followed by a space. I didn't include the scientific notation but it's not hard to add.
Now for parsing speed, this gets transformed into a DFA table, with all nodes on both the vertical and horizontal lines. Something like this:
I1 Identifier N1 N2 N3 Number
start letter nothing number nothing nothing nothing
I1 letter+number space nothing nothing nothing nothing
Identifier nothing SUCCESS nothing nothing nothing nothing
N1 nothing nothing number dot nothing space
N2 nothing nothing nothing nothing number nothing
N3 nothing nothing nothing nothing number space
Number nothing nothing nothing nothing nothing SUCCESS
The way you'd run this is you store your starting state and move through the table as you read your input character by character. For example an input of "1.2" would parse as start->N1->N2->N3->Number->SUCCESS. If at any point you hit a "nothing" node, you have an error.
edit 2: the table should actually be node->character->node, not node->node->character, but it worked fine in this case regardless. It's been a while since i last written a compiler by hand.

1- Yes regex are good to implement the tokenizer. If using a generated tokenizer like lex, then you describe the each token as a regex. see Mark's answer.
2- The lexer is what normally tracks line/column information, as tokens are consumed by the tokenizer, you track the line/column information with the token, or have it as current state. Therefore when a problem is found the tokenizer knows where you are. Therefore when processing comments, as new lines are processed the tokenizer just increments the line_count.
In Lex you can also have parsing states. Multi-line comments are often implemented using these states, thus allowing simpler regex's. Once you find the match to the start of a comment eg '/*' you change into comment state, which you can setup to be exclusive from the normal state. Therefore as you consume text looking for the end comment marker '*/' you do not match normal tokens.
This state based process is also useful for process string literals that allow nested end makers eg "test\"more text".

Related

How to programmatically learn regexes?

My question is a continuation of this one. Basically, I have a table of words like so:
HAT18178_890909.098070313.1
HAT18178_890909.098070313.2
HAT18178_890909.143412462.1
HAT18178_890909.143412462.2
For my purposes, I do not need the terminal .1 or .2 for this set of names. I can manually write the following regex (using Python syntax):
r = re.compile('(.*\.\d+)\.\d+')
However, I cannot guarantee that my next set of names will have a similar structure where the final 2 characters will be discardable - it could be 3 characters (i.e. .12) and the separator could change as well (i.e. . to _).
What is the appropriate way to either explicitly learn a regex or to determine which characters are unnecessary?
It's an interesting problem.
X y
HAT18178_890909.098070313.1 HAT18178_890909.098070313
HAT18178_890909.098070313.2 HAT18178_890909.098070313
HAT18178_890909.143412462.1 HAT18178_890909.143412462
HAT18178_890909.143412462.2 HAT18178_890909.143412462
The problem is that there is not a single solution but many.
Even for a human it is not clear what the regex should be that you want.
Based on this data, I would think the possibilities to learn are:
Just match a fixed width of 25: .{25}
Fixed first part: HAT18178_890909.
Then:
There's only 2 varying numbers on each single spot (as you show 2 cases).
So e.g. [01] (either 0 or 1), [94] the next spot and so on would be a good solution.
The obvious one would be \d+
But it could also be \d{9}
You see, there are multiple correct answers.
These regexes would still work if the second point would be an underscore instead.
My conclusion:
The problem is that it is much more work to prepare the data for machine learning than it is to create a regex. If you want to be sure you cover everything, you need to have complete data, so then a regex is probably less effort.
You could split on non-alphanumeric characters;
[^a-zA-Z0-9']+
That would get you, in this case, few strings like this:
HAT18178
890909
098070313
1
From there on you can simply discard the last one if that's never necessary, and continue on processing the first sequences

Specific Regex Failing on Neko and Native

So I'm working on some cleanup in haxeflixel, and I need to validate a csv map, so I'm using a regex to check if its ok (don't mention the ending commas, I know thats not valid csv but I want to allow it), and I think I have a decent regex for doing that, and it seems to work well on flash, but c++ crashes, and neko gives me this error: An error occured while running pcre_exec....
here is my regex, I'm sorry its long, but I have no idea where the problem is...
^(([ ]*-?[0-9]+[ ]*,?)+\r?\n?)+$
if anyone knows what might be going on I'd appreciate it,
Thanks,
Nico
ps. there are probably errors in my regex for checking csv, but I can figure those out, its kind of enjoyable, I'd rather just know what specifically could be causing this:)
edit: ah, I've just noticed this doesn't happen on all strings, once I narrow it down to what strings, I will post one... as for what I'm checking for, its basically just to make sure theres no weird xml header, or any non integer value in the map file, basically it should validate this:
1,1,1,1
1,1,1,1
1,1,1,1
or this:
1,1,1,1,
1,1,1,1,
1,1,1,1,
but not:
xml blahh blahh>
1,m,1,1
1,1,b,1
1,1,1,1
xml>
(and yes I know thats not valid xml;))
edit: it gets stranger:
so I'm trying to determine what strings crash it, and while this still wouldnt explain a normal map crashing, its definatly weird, and has the same result:
what happens is:
this will fail a .match() test, but not crash:
a
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
1,1,1,1,1,1,1,1,1,1,1,1,1,1,1
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
1,1,1,1,1,1,1,1,1,1,1,1,1,1,1
while this will crash the program:
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
1,1,1,1,1,1,1,1,1,1,1,1,1,1,1
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
1,*a*,1,1,1,1,1,1,1,1,1,1,1,1,1
To be honest, you wrote one of the worst regexps I ever seen. It actually looks like it was written specifically to be as slow as possible. I write it not to offend you, but to express how much you need to learn to write regexps(hint: writing your own regexp engine is a good exercise).
Going to your problem, I guess it just runs out of memory(it is extremely memory intensive). I am not sure why it happens only on pcre targets(both neko and cpp targets use pcre), but I guess it is about memory limits per regexp run in pcre or some heuristics in other targets to correct such miswritten regexps.
I'd suggest something along the lines of
~/^(( *-?[0-9]+ *,)* *-?[0-9]+ *,?\r?\n)*(( *-?[0-9]+ *,)* *-?[0-9]+ *,?\r?\n?)$/
There, "~/" and last "/" are haxe regexp markers.
I wasnt extensively testing it, just a run on your samples, but it should do the job(probably with a bit of tweaking).
Also, just as a hint, I'd suggest you to split file into lines first before running any regexps, it will lower memmory usage(or you will need to hold only a part of your text in memory) and simplify your regexp.
I'd also note that since you will need to parse csv anyhow(for any properly formed input, which are prevailing in your data I guess), it might be much faster to do all the tests while actually parsing.
Edit: the answer to question "why it eats so much memory"
Well, it is not a short topic, and that's why I proposed to you to write your own regexp engine. There are some differences in implementations, but generally imagine regexp engine works like that:
parses your regular expression and builds a graph of all possible states(state is basically a symbol value and a number of links to other symbols which can follow it).
sets up a list of read pointer and state pointer pairs, current state list, consisting of regexp initial state and a pointer to matched string first letter
sets up read pointer to the first symbol of symbol string
sets up state poiter to initial state of regexp
takes up one pair from current state list and stores it as current state and current read pointer
reads symbol under current read pointer
matches it with symbols in states which current state have links to, and makes a list of states that matched.
if there is a final regexp state in this list, goes to 12
for each item in this list adds a pair of next read pointer(which is current+1) and item to the current state list
if the current state list is empty, returns false, as string didn't match the regexp
goes to 6
here it is, in a final state of matched regexp, returns true, string matches regexp.
Of course, there are some differences between regexp engines, and some of them eliminate some problems afaik. And of course they also have pseudosymbols, groupings, they need to store the positions regexp and groups matched, they have lookahead and lookbehind and also grouping references which makes it a bit(quite a humble measure) more complex and forces to use a bit more complex data structures, but the main idea is the same. So, here we are and your problem is clearly seen from algorithm. The less specific you are about what you want to match and the more there chances for engine to match the same substring as different paths in state graph, the more memory and processor time it will consume, exponentionally.
Try to model how regexp engine matches regexp (a+a+)+b on strings aaaaaab, ab, aa, aaaaaaaaaa, aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa (Don't try the last one, it would take hours or days to compute on a modern PC.)
Also, it worth to note that some regexp engines do things in a bit different way so they can handle this situations properly, but there always are ways to make regexp extremely slow.
And another thing to note is that I may hav ebeen wrong about the exact memory problem. This case it may be processor too, and before that it may be engine limits on memory/processor kicking in, not exactly system starving of memory.

Checking if a string contains an English sentence

As of right now, I decided to take a dictionary and iterate through the entire thing. Every time I see a newline, I make a string containing from that newline to the next newline, then I do string.find() to see if that English word is somewhere in there. This takes a VERY long time, each word taking about 1/2-1/4 a second to verify.
It is working perfectly, but I need to check thousands of words a second. I can run several windows, which doesn't affect the speed (Multithreading), but it still only checks like 10 a second. (I need thousands)
I'm currently writing code to pre-compile a large array containing every word in the English language, which should speed it up a lot, but still not get the speed I want. There has to be a better way to do this.
The strings I'm checking will look like this:
"hithisisastringthatmustbechecked"
but most of them contained complete garbage, just random letters.
I can't check for impossible compinations of letters, because that string would be thrown out because of the 'tm', in between 'thatmust'.
You can speed up the search by employing the Knuth–Morris–Pratt (KMP) algorithm.
Go through every dictionary word, and build a search table for it. You need to do it only once. Now your search for individual words will proceed at faster pace, because the "false starts" will be eliminated.
There are a lot of strategies for doing this quickly.
Idea 1
Take the string you are searching and make a copy of each possible substring beginning at some column and continuing through the whole string. Then store each one in an array indexed by the letter it begins with. (If a letter is used twice store the longer substring.
So the array looks like this:
a - substr[0] = "astringthatmustbechecked"
b - substr[1] = "bechecked"
c - substr[2] = "checked"
d - substr[3] = "d"
e - substr[4] = "echecked"
f - substr[5] = null // since there is no 'f' in it
... and so forth
Then, for each word in the dictionary, search in the array element indicated by its first letter. This limits the amount of stuff that has to be searched. Plus you can't ever find a word beginning with, say 'r', anywhere before the first 'r' in the string. And some words won't even do a search if the letter isn't in there at all.
Idea 2
Expand upon that idea by noting the longest word in the dictionary and get rid of letters from those strings in the arrays that are longer than that distance away.
So you have this in the array:
a - substr[0] = "astringthatmustbechecked"
But if the longest word in the list is 5 letters, there is no need to keep any more than:
a - substr[0] = "astri"
If the letter is present several times you have to keep more letters. So this one has to keep the whole string because the "e" keeps showing up less than 5 letters apart.
e - substr[4] = "echecked"
You can expand upon this by using the longest words starting with any particular letter when condensing the strings.
Idea 3
This has nothing to do with 1 and 2. Its an idea that you could use instead.
You can turn the dictionary into a sort of regular expression stored in a linked data structure. It is possible to write the regular expression too and then apply it.
Assume these are the words in the dictionary:
arun
bob
bill
billy
body
jose
Build this sort of linked structure. (Its a binary tree, really, represented in such a way that I can explain how to use it.)
a -> r -> u -> n -> *
|
b -> i -> l -> l -> *
| | |
| o -> b -> * y -> *
| |
| d -> y -> *
|
j -> o -> s -> e -> *
The arrows denote a letter that has to follow another letter. So "r" has to be after an "a" or it can't match.
The lines going down denote an option. You have the "a or b or j" possible letters and then the "i or o" possible letters after the "b".
The regular expression looks sort of like: /(arun)|(b(ill(y+))|(o(b|dy)))|(jose)/ (though I might have slipped a paren). This gives the gist of creating it as a regex.
Once you build this structure, you apply it to your string starting at the first column. Try to run the match by checking for the alternatives and if one matches, more forward tentatively and try the letter after the arrow and its alternatives. If you reach the star/asterisk, it matches. If you run out of alternatives, including backtracking, you move to the next column.
This is a lot of work but can, sometimes, be handy.
Side note I built one of these some time back by writing a program that wrote the code that ran the algorithm directly instead of having code looking at the binary tree data structure.
Think of each set of vertical bar options being a switch statement against a particular character column and each arrow turning into a nesting. If there is only one option, you don't need a full switch statement, just an if.
That was some fast character matching and really handy for some reason that eludes me today.
How about a Bloom Filter?
A Bloom filter, conceived by Burton Howard Bloom in 1970 is a
space-efficient probabilistic data structure that is used to test
whether an element is a member of a set. False positive matches are
possible, but false negatives are not; i.e. a query returns either
"inside set (may be wrong)" or "definitely not in set". Elements can
be added to the set, but not removed (though this can be addressed
with a "counting" filter). The more elements that are added to the
set, the larger the probability of false positives.
The approach could work as follows: you create the set of words that you want to check against (this is done only once), and then you can quickly run the "in/not-in" check for every sub-string. If the outcome is "not-in", you are safe to continue (Bloom filters do not give false negatives). If the outcome is "in", you then run your more sophisticated check to confirm (Bloom filters can give false positives).
It is my understanding that some spell-checkers rely on bloom filters to quickly test whether your latest word belongs to the dictionary of known words.
This code was modified from How to split text without spaces into list of words?:
from math import log
words = open("english125k.txt").read().split()
wordcost = dict((k, log((i+1)*log(len(words)))) for i,k in enumerate(words))
maxword = max(len(x) for x in words)
def infer_spaces(s):
"""Uses dynamic programming to infer the location of spaces in a string
without spaces."""
# Find the best match for the i first characters, assuming cost has
# been built for the i-1 first characters.
# Returns a pair (match_cost, match_length).
def best_match(i):
candidates = enumerate(reversed(cost[max(0, i-maxword):i]))
return min((c + wordcost.get(s[i-k-1:i], 9e999), k+1) for k,c in candidates)
# Build the cost array.
cost = [0]
for i in range(1,len(s)+1):
c,k = best_match(i)
cost.append(c)
# Backtrack to recover the minimal-cost string.
costsum = 0
i = len(s)
while i>0:
c,k = best_match(i)
assert c == cost[i]
costsum += c
i -= k
return costsum
Using the same dictionary of that answer and testing your string outputs
>>> infer_spaces("hithisisastringthatmustbechecked")
294.99768817854056
The trick here is finding out what threshold you can use, keeping in mind that using smaller words makes the cost higher (if the algorithm can't find any usable word, it returns inf, since it would split everything to single-letter words).
In theory, I think you should be able to train a Markov model and use that to decide if a string is probably a sentence or probably garbage. There's another question about doing this to recognize words, not sentences: How do I determine if a random string sounds like English?
The only difference for training on sentences is that your probability tables will be a bit larger. In my experience, though, a modern desktop computer has more than enough RAM to handle Markov matrices unless you are training on the entire Library of Congress (which is unnecessary- even 5 or so books by different authors should be enough for very accurate classification).
Since your sentences are mashed together without clear word boundaries, it's a bit tricky, but the good news is that the Markov model doesn't care about words, just about what follows what. So, you can make it ignore spaces, by first stripping all spaces from your training data. If you were going to use Alice in Wonderland as your training text, the first paragraph would, perhaps, look like so:
alicewasbeginningtogetverytiredofsittingbyhersisteronthebankandofhavingnothingtodoonceortwiceshehadpeepedintothebookhersisterwasreadingbutithadnopicturesorconversationsinitandwhatistheuseofabookthoughtalicewithoutpicturesorconversation
It looks weird, but as far as a Markov model is concerned, it's a trivial difference from the classical implementation.
I see that you are concerned about time: Training may take a few minutes (assuming you have already compiled gold standard "sentences" and "random scrambled strings" texts). You only need to train once, you can easily save the "trained" model to disk and reuse it for subsequent runs by loading from disk, which may take a few seconds. Making a call on a string would take a trivially small number of floating point multiplications to get a probability, so after you finish training it, it should be very fast.

Separating out a list with regex?

I have a CSV file which has been generated by a system. The problem is with one of the fields which used to be a list of items. An example of the original list is below....
The serial number of the desk is 45TYTU
This is the second item in the list
The colour of the apple is green
The ID code is 489RUI
This is the fourth item in the list.
And unfortunately the system spits out the code below.....
The serial number of the desk is 45TYTUThis is the second item in the listThe colour of the apple is greenThe ID code is 489RUIThis is the fourth item in the list.
As you can see, it ignores the line breaks and just bunches everything up. I am unable to modify the system that generates this output so what I am trying to do is come up with some sort of regex find and replace expression that will separate them out.
My original though would be to try and detect when an upper case letter is in the middle of a lower case word, but as in one of the items in the example, when a serial number is used it throws this out.
Anyone any suggestions? Is regex the way to go?
--- EDIT ---
I think i need to simplify things for myself, if I ignore the fact that lines that end in a serial number will break things for now. I need to just create an expression that will insert a line break if it detects that an upper case letter is being used after a lower case one
--- EDIT 2 ---
Using the example given by fardjad everything works for the sample data given, the strong was...
(.(?=[A-Z][a-z]))
Now as I test with more data I can see an issue appearing, certain lines begin with numbers so it is seeing these as serial numbers, you can see an example of this at http://regexr.com?2vfi5
There are only about 10 known numbers it uses at the start of the lines such as 240v, 120v etc...
Is there a way to exclude these?
That won't be a robust solution but this is what you asked. It matches the character before an uppercase letter followed by a lowercase one. You can simply use regex replace and append a new line character:
(.(?=[A-Z][a-z]))
see this demo.
You could search for this
(?<=\p{Ll})(?=\p{Lu})
and replace with a linebreak. The regex matches the empty space between a lowercase letter \p{Ll} and an uppercase letter \p{Lu}.
This assumes you're using a Unicode-aware regex engine (.NET, PCRE, Perl for example). If not, you might also get away with
(?<=[a-z])(?=[A-Z])
but this of course only detects lower-/uppercase changes in ASCII words.

Tokenize the text depending on some specific rules. Algorithm in C++

I am writing a program which will tokenize the input text depending upon some specific rules. I am using C++ for this.
Rules
Letter 'a' should be converted to token 'V-A'
Letter 'p' should be converted to token 'C-PA'
Letter 'pp' should be converted to token 'C-PPA'
Letter 'u' should be converted to token 'V-U'
This is just a sample and in real time I have around 500+ rules like this. If I am providing input as 'appu', it should tokenize like 'V-A + C-PPA + V-U'. I have implemented an algorithm for doing this and wanted to make sure that I am doing the right thing.
Algorithm
All rules will be kept in a XML file with the corresponding mapping to the token. Something like
<rules>
<rule pattern="a" token="V-A" />
<rule pattern="p" token="C-PA" />
<rule pattern="pp" token="C-PPA" />
<rule pattern="u" token="V-U" />
</rules>
1 - When the application starts, read this xml file and keep the values in a 'std::map'. This will be available until the end of the application(singleton pattern implementation).
2 - Iterate the input text characters. For each character, look for a match. If found, become more greedy and look for more matches by taking the next characters from the input text. Do this until we are getting a no match. So for the input text 'appu', first look for a match for 'a'. If found, try to get more match by taking the next character from the input text. So it will try to match 'ap' and found no matches. So it just returns.
3 - Replace the letter 'a' from input text as we got a token for it.
4 - Repeat step 2 and 3 with the remaining characters in the input text.
Here is a more simple explanation of the steps
input-text = 'appu'
tokens-generated=''
// First iteration
character-to-match = 'a'
pattern-found = true
// since pattern found, going recursive and check for more matches
character-to-match = 'ap'
pattern-found = false
tokens-generated = 'V-A'
// since no match found for 'ap', taking the first success and replacing it from input text
input-text = 'ppu'
// second iteration
character-to-match = 'p'
pattern-found = true
// since pattern found, going recursive and check for more matches
character-to-match = 'pp'
pattern-found = true
// since pattern found, going recursive and check for more matches
character-to-match = 'ppu'
pattern-found = false
tokens-generated = 'V-A + C-PPA'
// since no match found for 'ppu', taking the first success and replacing it from input text
input-text = 'u'
// third iteration
character-to-match = 'u'
pattern-found = true
tokens-generated = 'V-A + C-PPA + V-U' // we'r done!
Questions
1 - Is this algorithm looks fine for this problem or is there a better way to address this problem?
2 - If this is the right method, std::map is a good choice here? Or do I need to create my own key/value container?
3 - Is there a library available which can tokenize string like the above?
Any help would be appreciated
:)
So you're going through all of the tokens in your map looking for matches? You might as well use a list or array, there; it's going to be an inefficient search regardless.
A much more efficient way of finding just the tokens suitable for starting or continuing a match would be to store them as a trie. A lookup of a letter there would give you a sub-trie which contains only the tokens which have that letter as the first letter, and then you just continue searching downward as far as you can go.
Edit: let me explain this a little further.
First, I should explain that I'm not familiar with these the C++ std::map, beyond the name, which makes this a perfect example of why one learns the theory of this stuff as well as than details of particular libraries in particular programming languages: unless that library is badly misusing the name "map" (which is rather unlikely), the name itself tells me a lot about the characteristics of the data structure. I know, for example, that there's going to be a function that, given a single key and the map, will very efficiently search for and return the value associated with that key, and that there's also likely a function that will give you a list/array/whatever of all of the keys, which you could search yourself using your own code.
My interpretation of your data structure is that you have a map where the keys are what you call a pattern, those being a list (or array, or something of that nature) of characters, and the values are tokens. Thus, you can, given a full pattern, quickly find the token associated with it.
Unfortunately, while such a map is a good match to converting your XML input format to a internal data structure, it's not a good match to the searches you need to do. Note that you're not looking up entire patterns, but the first character of a pattern, producing a set of possible tokens, followed by a lookup of the second character of a pattern from within the set of patterns produced by that first lookup, and so on.
So what you really need is not a single map, but maps of maps of maps, each keyed by a single character. A lookup of "p" on the top level should give you a new map, with two keys: p, producing the C-PPA token, and "anything else", producing the C-PA token. This is effectively a trie data structure.
Does this make sense?
It may help if you start out by writing the parsing code first, in this manner: imagine someone else will write the functions to do the lookups you need, and he's a really good programmer and can do pretty much any magic that you want. Writing the parsing code, concentrate on making that as simple and clean as possible, creating whatever interface using these arbitrary functions you need (while not getting trivial and replacing the whole thing with one function!). Now you can look at the lookup functions you ended up with, and that tells you how you need to access your data structure, which will lead you to the type of data structure you need. Once you've figured that out, you can then work out how to load it up.
This method will work - I'm not sure that it is efficient, but it should work.
I would use the standard std::map rather than your own system.
There are tools like lex (or flex) that can be used for this. The issue would be whether you can regenerate the lexical analyzer that it would construct when the XML specification changes. If the XML specification does not change often, you may be able to use tools such as lex to do the scanning and mapping more easily. If the XML specification can change at the whim of those using the program, then lex is probably less appropriate.
There are some caveats - notably that both lex and flex generate C code, rather than C++.
I would also consider looking at pattern matching technology - the sort of stuff that egrep in particular uses. This has the merit of being something that can be handled at runtime (because egrep does it all the time). Or you could go for a scripting language - Perl, Python, ... Or you could consider something like PCRE (Perl Compatible Regular Expressions) library.
Better yet, if you're going to use the boost library, there's always the Boost tokenizer library -> http://www.boost.org/doc/libs/1_39_0/libs/tokenizer/index.html
You could use a regex (perhaps the boost::regex library). If all of the patterns are just strings of letters, a regex like "(a|p|pp|u)" would find a greedy match. So:
Run a regex_search using the above pattern to locate the next match
Plug the match-text into your std::map to get the replace-text.
Print the non-matched consumed input and replace-text to your output, then repeat 1 on the remaining input.
And done.
It may seem a bit complicated, but the most efficient way to do that is to use a graph to represent a state-chart. At first, i thought boost.statechart would help, but i figured it wasn't really appropriate. This method can be more efficient that using a simple std::map IF there are many rules, the number of possible characters is limited and the length of the text to read is quite high.
So anyway, using a simple graph :
0) create graph with "start" vertex
1) read xml configuration file and create vertices when needed (transition from one "set of characters" (eg "pp") to an additional one (eg "ppa")). Inside each vertex, store a transition table to the next vertices. If "key text" is complete, mark vertex as final and store the resulting text
2) now read text and interpret it using the graph. Start at the "start" vertex. ( * ) Use table to interpret one character and to jump to new vertex. If no new vertex has been selected, an error can be issued. Otherwise, if new vertex is final, print the resulting text and jump back to start vertex. Go back to (*) until there is no more text to interpret.
You could use boost.graph to represent the graph, but i think it is overly complex for what you need. Make your own custom representation.