Is there a cross-platform way to get the current date and time in C++?
Since C++ 11 you can use std::chrono::system_clock::now()
Example (copied from en.cppreference.com):
#include <iostream>
#include <chrono>
#include <ctime>
int main()
{
auto start = std::chrono::system_clock::now();
// Some computation here
auto end = std::chrono::system_clock::now();
std::chrono::duration<double> elapsed_seconds = end-start;
std::time_t end_time = std::chrono::system_clock::to_time_t(end);
std::cout << "finished computation at " << std::ctime(&end_time)
<< "elapsed time: " << elapsed_seconds.count() << "s"
<< std::endl;
}
This should print something like this:
finished computation at Mon Oct 2 00:59:08 2017
elapsed time: 1.88232s
C++ shares its date/time functions with C. The tm structure is probably the easiest for a C++ programmer to work with - the following prints today's date:
#include <ctime>
#include <iostream>
int main() {
std::time_t t = std::time(0); // get time now
std::tm* now = std::localtime(&t);
std::cout << (now->tm_year + 1900) << '-'
<< (now->tm_mon + 1) << '-'
<< now->tm_mday
<< "\n";
}
You can try the following cross-platform code to get current date/time:
#include <iostream>
#include <string>
#include <stdio.h>
#include <time.h>
// Get current date/time, format is YYYY-MM-DD.HH:mm:ss
const std::string currentDateTime() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
// Visit http://en.cppreference.com/w/cpp/chrono/c/strftime
// for more information about date/time format
strftime(buf, sizeof(buf), "%Y-%m-%d.%X", &tstruct);
return buf;
}
int main() {
std::cout << "currentDateTime()=" << currentDateTime() << std::endl;
getchar(); // wait for keyboard input
}
Output:
currentDateTime()=2012-05-06.21:47:59
Please visit here for more information about date/time format
std C libraries provide time().
This is seconds from the epoch and can be converted to date and H:M:S using standard C functions. Boost also has a time/date library that you can check.
time_t timev;
time(&timev);
New answer for an old question:
The question does not specify in what timezone. There are two reasonable possibilities:
In UTC.
In the computer's local timezone.
For 1, you can use this date library and the following program:
#include "date.h"
#include <iostream>
int
main()
{
using namespace date;
using namespace std::chrono;
std::cout << system_clock::now() << '\n';
}
Which just output for me:
2015-08-18 22:08:18.944211
The date library essentially just adds a streaming operator for std::chrono::system_clock::time_point. It also adds a lot of other nice functionality, but that is not used in this simple program.
If you prefer 2 (the local time), there is a timezone library that builds on top of the date library. Both of these libraries are open source and cross platform, assuming the compiler supports C++11 or C++14.
#include "tz.h"
#include <iostream>
int
main()
{
using namespace date;
using namespace std::chrono;
auto local = make_zoned(current_zone(), system_clock::now());
std::cout << local << '\n';
}
Which for me just output:
2015-08-18 18:08:18.944211 EDT
The result type from make_zoned is a date::zoned_time which is a pairing of a date::time_zone and a std::chrono::system_clock::time_point. This pair represents a local time, but can also represent UTC, depending on how you query it.
With the above output, you can see that my computer is currently in a timezone with a UTC offset of -4h, and an abbreviation of EDT.
If some other timezone is desired, that can also be accomplished. For example to find the current time in Sydney , Australia just change the construction of the variable local to:
auto local = make_zoned("Australia/Sydney", system_clock::now());
And the output changes to:
2015-08-19 08:08:18.944211 AEST
Update for C++20
This library is now largely adopted for C++20. The namespace date is gone and everything is in namespace std::chrono now. And use zoned_time in place of make_time. Drop the headers "date.h" and "tz.h" and just use <chrono>.
#include <chrono>
#include <iostream>
int
main()
{
using namespace std::chrono;
auto local = zoned_time{current_zone(), system_clock::now()};
std::cout << local << '\n'; // 2021-05-03 15:02:44.130182 EDT
}
As I write this, partial implementations are just beginning to emerge on some platforms.
the C++ standard library does not provide a proper date type. C++ inherits the structs and functions for date and time manipulation from C, along with a couple of date/time input and output functions that take into account localization.
// Current date/time based on current system
time_t now = time(0);
// Convert now to tm struct for local timezone
tm* localtm = localtime(&now);
cout << "The local date and time is: " << asctime(localtm) << endl;
// Convert now to tm struct for UTC
tm* gmtm = gmtime(&now);
if (gmtm != NULL) {
cout << "The UTC date and time is: " << asctime(gmtm) << endl;
}
else {
cerr << "Failed to get the UTC date and time" << endl;
return EXIT_FAILURE;
}
auto time = std::time(nullptr);
std::cout << std::put_time(std::localtime(&time), "%F %T%z"); // ISO 8601 format.
Get the current time either using std::time() or std::chrono::system_clock::now() (or another clock type).
std::put_time() (C++11) and strftime() (C) offer a lot of formatters to output those times.
#include <iomanip>
#include <iostream>
int main() {
auto time = std::time(nullptr);
std::cout
// ISO 8601: %Y-%m-%d %H:%M:%S, e.g. 2017-07-31 00:42:00+0200.
<< std::put_time(std::gmtime(&time), "%F %T%z") << '\n'
// %m/%d/%y, e.g. 07/31/17
<< std::put_time(std::gmtime(&time), "%D");
}
The sequence of the formatters matters:
std::cout << std::put_time(std::gmtime(&time), "%c %A %Z") << std::endl;
// Mon Jul 31 00:00:42 2017 Monday GMT
std::cout << std::put_time(std::gmtime(&time), "%Z %c %A") << std::endl;
// GMT Mon Jul 31 00:00:42 2017 Monday
The formatters of strftime() are similar:
char output[100];
if (std::strftime(output, sizeof(output), "%F", std::gmtime(&time))) {
std::cout << output << '\n'; // %Y-%m-%d, e.g. 2017-07-31
}
Often, the capital formatter means "full version" and lowercase means abbreviation (e.g. Y: 2017, y: 17).
Locale settings alter the output:
#include <iomanip>
#include <iostream>
int main() {
auto time = std::time(nullptr);
std::cout << "undef: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("en_US.utf8"));
std::cout << "en_US: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("en_GB.utf8"));
std::cout << "en_GB: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("de_DE.utf8"));
std::cout << "de_DE: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("ja_JP.utf8"));
std::cout << "ja_JP: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("ru_RU.utf8"));
std::cout << "ru_RU: " << std::put_time(std::gmtime(&time), "%c");
}
Possible output (Coliru, Compiler Explorer):
undef: Tue Aug 1 08:29:30 2017
en_US: Tue 01 Aug 2017 08:29:30 AM GMT
en_GB: Tue 01 Aug 2017 08:29:30 GMT
de_DE: Di 01 Aug 2017 08:29:30 GMT
ja_JP: 2017年08月01日 08時29分30秒
ru_RU: Вт 01 авг 2017 08:29:30
I've used std::gmtime() for conversion to UTC. std::localtime() is provided to convert to local time.
Heed that asctime()/ctime() which were mentioned in other answers are marked as deprecated now and strftime() should be preferred.
(For fellow googlers)
There is also Boost::date_time :
#include <boost/date_time/posix_time/posix_time.hpp>
boost::posix_time::ptime date_time = boost::posix_time::microsec_clock::universal_time();
#include <stdio.h>
#include <time.h>
int main ()
{
time_t rawtime;
struct tm * timeinfo;
time ( &rawtime );
timeinfo = localtime ( &rawtime );
printf ( "Current local time and date: %s", asctime (timeinfo) );
return 0;
}
Yes and you can do so with formatting rules specified by the currently-imbued locale:
#include <iostream>
#include <iterator>
#include <string>
class timefmt
{
public:
timefmt(std::string fmt)
: format(fmt) { }
friend std::ostream& operator <<(std::ostream &, timefmt const &);
private:
std::string format;
};
std::ostream& operator <<(std::ostream& os, timefmt const& mt)
{
std::ostream::sentry s(os);
if (s)
{
std::time_t t = std::time(0);
std::tm const* tm = std::localtime(&t);
std::ostreambuf_iterator<char> out(os);
std::use_facet<std::time_put<char>>(os.getloc())
.put(out, os, os.fill(),
tm, &mt.format[0], &mt.format[0] + mt.format.size());
}
os.width(0);
return os;
}
int main()
{
std::cout << timefmt("%c");
}
Output: Fri Sep 6 20:33:31 2013
you could use C++ 11 time class:
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
time_t now = chrono::system_clock::to_time_t(chrono::system_clock::now());
cout << put_time(localtime(&now), "%F %T") << endl;
return 0;
}
out put:
2017-08-25 12:30:08
There's always the __TIMESTAMP__ preprocessor macro.
#include <iostream>
using namespace std
void printBuildDateTime () {
cout << __TIMESTAMP__ << endl;
}
int main() {
printBuildDateTime();
}
example: Sun Apr 13 11:28:08 2014
std::ctime
Why was ctime only mentioned in the comments so far?
#include <ctime>
#include <iostream>
int main()
{
std::time_t result = std::time(nullptr);
std::cout << std::ctime(&result);
}
Output
Tue Dec 27 17:21:29 2011
You can use the following code to get the current system date and time in C++ :
#include <iostream>
#include <time.h> //It may be #include <ctime> or any other header file depending upon
// compiler or IDE you're using
using namespace std;
int main() {
// current date/time based on current system
time_t now = time(0);
// convert now to string form
string dt = ctime(&now);
cout << "The local date and time is: " << dt << endl;
return 0;
}
PS: Visit this site for more information.
You can also directly use ctime():
#include <stdio.h>
#include <time.h>
int main ()
{
time_t rawtime;
struct tm * timeinfo;
time ( &rawtime );
printf ( "Current local time and date: %s", ctime (&rawtime) );
return 0;
}
I found this link pretty useful for my implementation:
C++ Date and Time
Here's the code I use in my implementation, to get a clear "YYYYMMDD HHMMSS" output format. The param in is for switching between UTC and local time. You can easily modify my code to suite your need.
#include <iostream>
#include <ctime>
using namespace std;
/**
* This function gets the current date time
* #param useLocalTime true if want to use local time, default to false (UTC)
* #return current datetime in the format of "YYYYMMDD HHMMSS"
*/
string getCurrentDateTime(bool useLocalTime) {
stringstream currentDateTime;
// current date/time based on current system
time_t ttNow = time(0);
tm * ptmNow;
if (useLocalTime)
ptmNow = localtime(&ttNow);
else
ptmNow = gmtime(&ttNow);
currentDateTime << 1900 + ptmNow->tm_year;
//month
if (ptmNow->tm_mon < 9)
//Fill in the leading 0 if less than 10
currentDateTime << "0" << 1 + ptmNow->tm_mon;
else
currentDateTime << (1 + ptmNow->tm_mon);
//day
if (ptmNow->tm_mday < 10)
currentDateTime << "0" << ptmNow->tm_mday << " ";
else
currentDateTime << ptmNow->tm_mday << " ";
//hour
if (ptmNow->tm_hour < 10)
currentDateTime << "0" << ptmNow->tm_hour;
else
currentDateTime << ptmNow->tm_hour;
//min
if (ptmNow->tm_min < 10)
currentDateTime << "0" << ptmNow->tm_min;
else
currentDateTime << ptmNow->tm_min;
//sec
if (ptmNow->tm_sec < 10)
currentDateTime << "0" << ptmNow->tm_sec;
else
currentDateTime << ptmNow->tm_sec;
return currentDateTime.str();
}
Output (UTC, EST):
20161123 000454
20161122 190454
This works with G++ I'm not sure if this helps you.
Program output:
The current time is 11:43:41 am
The current date is 6-18-2015 June Wednesday
Day of month is 17 and the Month of year is 6,
also the day of year is 167 & our Weekday is 3.
The current year is 2015.
Code :
#include <ctime>
#include <iostream>
#include <string>
#include <stdio.h>
#include <time.h>
using namespace std;
const std::string currentTime() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%H:%M:%S %P", &tstruct);
return buf;
}
const std::string currentDate() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%B %A ", &tstruct);
return buf;
}
int main() {
cout << "\033[2J\033[1;1H";
std:cout << "The current time is " << currentTime() << std::endl;
time_t t = time(0); // get time now
struct tm * now = localtime( & t );
cout << "The current date is " << now->tm_mon + 1 << '-'
<< (now->tm_mday + 1) << '-'
<< (now->tm_year + 1900)
<< " " << currentDate() << endl;
cout << "Day of month is " << (now->tm_mday)
<< " and the Month of year is " << (now->tm_mon)+1 << "," << endl;
cout << "also the day of year is " << (now->tm_yday)
<< " & our Weekday is " << (now->tm_wday) << "." << endl;
cout << "The current year is " << (now->tm_year)+1900 << "."
<< endl;
return 0;
}
This compiled for me on Linux (RHEL) and Windows (x64) targeting g++ and OpenMP:
#include <ctime>
#include <iostream>
#include <string>
#include <locale>
////////////////////////////////////////////////////////////////////////////////
//
// Reports a time-stamped update to the console; format is:
// Name: Update: Year-Month-Day_of_Month Hour:Minute:Second
//
////////////////////////////////////////////////////////////////////////////////
//
// [string] strName : name of the update object
// [string] strUpdate: update descripton
//
////////////////////////////////////////////////////////////////////////////////
void ReportTimeStamp(string strName, string strUpdate)
{
try
{
#ifdef _WIN64
// Current time
const time_t tStart = time(0);
// Current time structure
struct tm tmStart;
localtime_s(&tmStart, &tStart);
// Report
cout << strName << ": " << strUpdate << ": " << (1900 + tmStart.tm_year) << "-" << tmStart.tm_mon << "-" << tmStart.tm_mday << " " << tmStart.tm_hour << ":" << tmStart.tm_min << ":" << tmStart.tm_sec << "\n\n";
#else
// Current time
const time_t tStart = time(0);
// Current time structure
struct tm* tmStart;
tmStart = localtime(&tStart);
// Report
cout << strName << ": " << strUpdate << ": " << (1900 + tmStart->tm_year) << "-" << tmStart->tm_mon << "-" << tmStart->tm_mday << " " << tmStart->tm_hour << ":" << tmStart->tm_min << ":" << tmStart->tm_sec << "\n\n";
#endif
}
catch (exception ex)
{
cout << "ERROR [ReportTimeStamp] Exception Code: " << ex.what() << "\n";
}
return;
}
The ffead-cpp provides multiple utility classes for various tasks, one such class is the Date class which provides a lot of features right from Date operations to date arithmetic, there's also a Timer class provided for timing operations. You can have a look at the same.
http://www.cplusplus.com/reference/ctime/strftime/
This built-in seems to offer a reasonable set of options.
localtime_s() version:
#include <stdio.h>
#include <time.h>
int main ()
{
time_t current_time;
struct tm local_time;
time ( ¤t_time );
localtime_s(&local_time, ¤t_time);
int Year = local_time.tm_year + 1900;
int Month = local_time.tm_mon + 1;
int Day = local_time.tm_mday;
int Hour = local_time.tm_hour;
int Min = local_time.tm_min;
int Sec = local_time.tm_sec;
return 0;
}
#include <iostream>
#include <chrono>
#include <string>
#pragma warning(disable: 4996)
// Ver: C++ 17
// IDE: Visual Studio
int main() {
using namespace std;
using namespace chrono;
time_point tp = system_clock::now();
time_t tt = system_clock::to_time_t(tp);
cout << "Current time: " << ctime(&tt) << endl;
return 0;
}
Here is the non-deprecated modern C++ solution for getting a timestamp as a std::string for use with e.g. filenames:
std::string get_file_timestamp()
{
const auto now = std::chrono::system_clock::now();
const auto in_time_t = std::chrono::system_clock::to_time_t(now);
std::stringstream output_stream;
struct tm time_info;
const auto errno_value = localtime_s(&time_info, &in_time_t);
if(errno_value != 0)
{
throw std::runtime_error("localtime_s() failed: " + std::to_string(errno_value));
}
output_stream << std::put_time(&time_info, "%Y-%m-%d.%H_%M_%S");
return output_stream.str();
}
You could use boost and chrono library:
#include <iostream>
#include <chrono>
#include <boost/date_time/posix_time/posix_time.hpp>
using boost::posix_time::to_iso_extended_string;
using boost::posix_time::from_time_t;
using std::chrono::system_clock;
int main()
{
auto now = system_clock::now();
std::cout << to_iso_extended_string(from_time_t(system_clock::to_time_t(now)));
}
#include <Windows.h>
void main()
{
//Following is a structure to store date / time
SYSTEMTIME SystemTime, LocalTime;
//To get the local time
int loctime = GetLocalTime(&LocalTime);
//To get the system time
int systime = GetSystemTime(&SystemTime)
}
I needed a way to insert current date-time at every update of a list.
This seems to work well, simply.
#include<bits/stdc++.h>
#include<unistd.h>
using namespace std;
int main()
{ //initialize variables
time_t now;
//blah..blah
/*each time I want the updated stamp*/
now=time(0);cout<<ctime(&now)<<"blah_blah";
}
Related
I am new to C++ programming in Windows environment.
I want to get the current system date and time in the below format:
DD-MM-YYYY HH:MM:SS.Milliseconds using Windows C++ API.I need to capture is up to microseconds. Could you please share a sample code on how to achieve this in Windows.
Using the draft C++20 spec:
#include <chrono>
#include <iostream>
int
main()
{
using namespace std;
using namespace std::chrono;
cout << format("%d-%m-%Y %T", floor<microseconds>(system_clock::now())) << '\n';
}
Currently VS does not implement this, but you can get a preview by using Howard Hinnant's date/time library. Just include it and add a using directive:
#include "date/date.h"
#include <chrono>
#include <iostream>
int
main()
{
using namespace date;
using namespace std;
using namespace std::chrono;
cout << format("%d-%m-%Y %T", floor<microseconds>(system_clock::now())) << '\n';
}
As you asked for "system time", this delivers a UTC time stamp, as that is what your system time measures. If you instead want local time, that is also available, but requires some installation.
Sample output:
29-11-2018 14:45:03.679098
I recommend to use std::chrono library. Look at this example:
#include <chrono>
#include <ctime>
#include <sstream>
#include <iomanip>
#include <string>
std::string current_datetime()
{
using namespace std::chrono;
// get current time
auto now = high_resolution_clock::now();
// get duration in milliseconds
auto msec = duration_cast<milliseconds>(now.time_since_epoch()).count();
msec %= 1000;
// get printable result:
auto now_time_t = high_resolution_clock::to_time_t(now);
std::stringstream ss;
ss << std::put_time(std::gmtime(&now_time_t), "%d-%m-%Y %X:") << msec;
return ss.str();
}
int main()
{
for(auto i = 0U;i < 1000;i++)
std::cout << current_datetime() << std::endl;
}
Also it's possible to get microseconds:
auto mksec = duration_cast<microseconds>(now.time_since_epoch()).count();
mksec %= 1000;
If you need WinAPI-specific version that's it:
std::string current_datetime2()
{
FILETIME ft;
GetSystemTimeAsFileTime(&ft);
unsigned long long mks = static_cast<unsigned long long>(ft.dwHighDateTime) << 32 | ft.dwLowDateTime;
mks /= 10; // interval in microsecond
mks %= 1000;
SYSTEMTIME st;
FileTimeToSystemTime(&ft, &st);
std::stringstream ss;
ss << st.wDay << "-" << st.wMonth << "-" << st.wYear << " " <<
st.wHour << ":" << st.wMinute << ":" << st.wSecond << ":" << st.wMilliseconds << ":" << mks << std::endl;
return ss.str();
}
or another very simple WinAPI-version, but without microseconds:
std::string current_datetime3()
{
SYSTEMTIME st;
GetSystemTime(&st);
std::stringstream ss;
ss << st.wDay << "-" << st.wMonth << "-" << st.wYear << " " <<
st.wHour << ":" << st.wMinute << ":" << st.wSecond << ":" << st.wMilliseconds;
return ss.str();
}
on windows platform:
SYSTEMTIME st;
GetLocalTime(&st);
TCHAR buf[128];
_stprintf_s(buf, _ARRAYSIZE(buf),
_T("%04u-%02u%-%02u %02u:%02u:%02u.%03u"),
st.wYear, st.wMonth, st.wDay,
st.wHour, st.wMinute, st.wSecond, st.wMilliseconds);
will fulfill most cases. If you want to get more accurate timespan, use
QueryPerformanceFrequency,
QueryPerformanceCounter;
I'm trying to turn arbitrary integer values representing the seconds since Jan 1, 1970 into human readable dates.
This is as close as I've gotten, but I keep getting the current date. How can I get a struct tm of a date that is not the current date?
#include <iostream>
#include <string>
#include <time.h>
using namespace std;
int main() {
struct tm * timeStruct;
time_t myTime = 946684800; //s from 1970 to 2000
int timeStamp = time(&myTime); //I thought this would set the date to the values of myTime, it just sets it to now
timeStruct = localtime(&myTime);
cout << timeStamp;
cout << "\n";
cout << asctime(timeStruct); //This should read Jan 1, 2000, instead it keeps giving me the current time
cout << "\n";
system("pause");
return 0;
}
time(&myTime) was setting the value of myTime to the current time (this is apparently to be expected).
Solution:
#include <iostream>
#include <string>
#include <time.h>
using namespace std;
int main() {
struct tm * timeStruct;
time_t myTime = 946684800; //s from 1970 to 2000
int timeStamp = myTime;
timeStruct = localtime(&myTime);
cout << timeStamp;
cout << "\n";
cout << asctime(timeStruct);
cout << "\n";
system("pause");
return 0;
}
Suppose I receive from a web server a string to parse. This string contains a date in the format YYYY-MM-DD.
What I want is to convert it to the timestamp that represents the begin of that day, hence I don't want seconds, minutes and hours.
As a dummy example, I'm trying to extract the timestamp of the current day, once converted to the YYYY-MM-DD format. Here's the code:
#include <chrono>
#include <iomanip>
#include <iostream>
#include <sstream>
int main()
{
// Current time at GMT
std::time_t now = std::time(0);
std::tm *now_tm = std::gmtime(&now);
std::ostringstream oss;
// Extract yyyy-mm-dd = %F
oss << std::put_time(now_tm, "%F");
// Use oss to get a date without seconds from
// current time at gmt
std::tm tm;
std::istringstream ss(oss.str());
ss >> std::get_time(&tm, "%F");
std::time_t current_date = std::mktime(&tm);
std::cout << oss.str() << std::endl;
std::cout << "cd: " << current_date << std::endl;
return 0;
}
The output is:
2017-10-19
cd: 1908337984324104
The extracted timestamp is clearly wrong. Where's the problem in the parsing the 2017-10-19 string using the %F format?
You can do this without leaving the safety of the chrono type system by using Howard Hinnant's, free, open-source, header-only chrono-extension library.
#include "date/date.h"
#include <iostream>
int
main()
{
std::istringstream ss{"2017-10-19"};
date::sys_seconds tp;
ss >> date::parse("%F", tp);
std::cout << date::format("%F\n", tp);
using date::operator<<;
std::cout << "cd: " << tp.time_since_epoch() << '\n';
}
date::sys_seconds is a std::chrono::time_point that counts chrono::seconds in Unix Time. You can parse directly into it using %F. You can also format it, using the same format string (%F), and also inspect the underlying count of chrono::seconds. This program outputs:
2017-10-19
cd: 1508371200s
The documentation of std::get_time lists no conversion specifier %F. When checking the stream flag (which you always should do!), it will also tell that the conversion failed, at least with my compiler.
So by replacing it with %Y-%m-%d, the conversion succeeds. Finally, you default-constructed the tm variable without zeroing it (e.g. by value-initialization). When fixing this as well, the code works as expected:
#include <chrono>
#include <iomanip>
#include <iostream>
#include <sstream>
int main()
{
// Current time at GMT
std::time_t now = std::time(0);
std::tm *now_tm = std::gmtime(&now);
std::ostringstream oss;
// Extract yyyy-mm-dd = %F
oss << std::put_time(now_tm, "%Y-%m-%d");
// Use oss to get a date without seconds from
// current time at gmt
std::tm tm{ }; // value-initialize!
std::istringstream ss(oss.str());
ss >> std::get_time(&tm, "%Y-%m-%d");
if(!ss) std::cout << "conversion error\n";
else {
std::time_t current_date = std::mktime(&tm);
std::cout << current_date << '\n';
std::cout << "cd: " << current_date << '\n';
}
return 0;
}
http://coliru.stacked-crooked.com/a/d86aa1e1d890a14d
I wrote this code snippet to generate random dates:
std::time_t curr_time = time(0);
std::time_t ten_years = 365 * 12 * 30 * 24 * 60;
std::time_t rand_date = curr_time - std::rand() % ten_years;
tm *ltm = std::localtime(&rand_date);
std::cout << ltm->tm_year + 1900 << " " << ltm->tm_mon + 1 << " " << ltm->tm_mday << std::endl;
However it always gives me the current date. What am i doing wrong?
std::rand() may return rather small values, 0..32767 is the minimum range, and does so on some popular 32-bit platforms (MSVC among them). With time_t in seconds this only gives you about eight hours of random noise.
Try combining the results from a pair of std::rand calls instead. E.g.
(std::time_t) std::rand() * RAND_MAX + std::rand() or switch to a better random number generator.
I would suggest you don't modify a time_t directly, as the implementation is not specified by the standard. Better to convert it a la this question: How to add one day to a time obtained from time()
I would suggest to do it differently, based on the CPP Reference:
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#include <iostream>
using namespace std;
int main() {
time_t timer;
struct tm x_years;
struct tm* current;
int how_many_years = 10;
srand (time(NULL));
int randomYear = (rand()%how_many_years)+1;
int randomMonth = (rand()%12)+1;
int randomDays = (rand()%30)+1;
time(&timer); /* get current time; same as: timer = time(NULL) */
current = localtime(&timer);
x_years.tm_hour = 0;
x_years.tm_min = 0;
x_years.tm_sec = 0;
x_years.tm_year = current->tm_year - randomYear;
x_years.tm_mon = (current->tm_mon - randomMonth) <= 0 ? current->tm_mon + (12-randomMonth) : current->tm_mon - randomMonth;
x_years.tm_mday = (current->tm_mday - randomDays) <= 0 ? current->tm_mday + (30-randomDays) : current->tm_mday - randomDays;
//returns seconds ever since the random generated date until now
cout << "Years rolled back: " << randomYear << endl;
cout << "Months rolled back: " << randomMonth << endl;
cout << "Days rolled back: " << randomDays << endl;
cout << endl;
cout << "Current Year: " << current->tm_year+1900 << endl;
cout << "Current Month: " << current->tm_mon << endl;
cout << "Current Day: " << current->tm_mday << endl;
cout << endl;
cout << "Year: " << x_years.tm_year+1900 << endl;
cout << "Month: " << x_years.tm_mon << endl;
cout << "Day: " << x_years.tm_mday << endl;
}
EDIT
I have edited the code, and with it, you can even select how many years you want to go back. Basically, you go back X years in the time, and you can get the date rollbacked in the x_years struct.
Hope this helped!
The following solution uses C++11 with an internal uniform_int_distribution:
// uniform_time_dist.h
#include <chrono>
#include <random>
template <class TimePoint>
class uniform_time_distribution{
public:
uniform_time_distribution(TimePoint start, TimePoint end)
: m_start(start), m_end(end),
m_seconds(std::chrono::duration_cast<std::chrono::seconds>(end - start))
{}
template <class Generator>
TimePoint operator()(Generator && g){
std::uniform_int_distribution<std::chrono::seconds::rep> d(0, m_seconds.count());
return m_start + std::chrono::seconds(d(g));
}
private:
TimePoint m_start;
TimePoint m_end;
std::chrono::seconds m_seconds;
};
You can use it like any other distribution function with a generator:
// uniform_time_dist.h -- continuation
template <class TimePoint>
TimePoint randomTime(TimePoint start, TimePoint end){
static std::random_device rd;
static std::mt19937 gen(rd());
uniform_time_distribution<TimePoint> t(start, end);
return t(gen);
}
You can combine this method with your time_t functions by using clock::to_time_t:
#include <iostream>
#include "uniform_time_dist.h" // see above
using namespace std::chrono;
int main(){
auto k = system_clock::to_time_t(randomTime(
system_clock::now(),
system_clock::now() + hours(24 * 365 * 10)));
std::cout << std::ctime(&k);
}
Note that the class above is just a small sketch, you should be able to improve it vastly in order to match the other distribution functions.
I managed to create a solution based on Phil's answer:
time_t currTime = time(0);
tm *ltm = std::localtime(&currTime);
ltm->tm_mday = std::rand() % 3650 * -1;
time_t next = mktime(ltm);
ltm = std::localtime(&next);
std::cout << ltm->tm_year + 1900 << " " << ltm->tm_mon + 1 << " " << ltm->tm_mday << std::endl;
If you are using boost libs you can use this class that I wrote to get random dates:
#include <iostream>
#include <ctime>
#include <boost/random/mersenne_twister.hpp>
#include <boost/random/uniform_int_distribution.hpp>
#include <boost/random/variate_generator.hpp>
#include "boost/date_time/posix_time/posix_time.hpp"
#include "boost/date_time/gregorian/gregorian.hpp"
using namespace std;
using namespace boost;
using namespace boost::posix_time;
using namespace boost::gregorian;
class Randomizer {
private:
static const bool debug_mode = false;
random::mt19937 rng_;
// The private constructor so that the user can not directly instantiate
Randomizer() {
if(debug_mode==true){
this->rng_ = random::mt19937();
}else{
this->rng_ = random::mt19937(current_time_nanoseconds());
}
};
int current_time_nanoseconds(){
struct timespec tm;
clock_gettime(CLOCK_REALTIME, &tm);
return tm.tv_nsec;
}
// C++ 03
// ========
// Dont forget to declare these two. You want to make sure they
// are unacceptable otherwise you may accidentally get copies of
// your singleton appearing.
Randomizer(Randomizer const&); // Don't Implement
void operator=(Randomizer const&); // Don't implement
public:
static Randomizer& get_instance(){
// The only instance of the class is created at the first call get_instance ()
// and will be destroyed only when the program exits
static Randomizer instance;
return instance;
}
bool method() { return true; };
int rand(unsigned int floor, unsigned int ceil){
random::uniform_int_distribution<> rand_ = random::uniform_int_distribution<> (floor,ceil);
return (rand_(rng_));
}
// Is not considering the millisecons
time_duration rand_time_duration(){
boost::posix_time::time_duration floor(0, 0, 0, 0);
boost::posix_time::time_duration ceil(23, 59, 59, 0);
unsigned int rand_seconds = rand(floor.total_seconds(), ceil.total_seconds());
return seconds(rand_seconds);
}
date rand_date_from_epoch_to_now(){
date now = second_clock::local_time().date();
return rand_date_from_epoch_to_ceil(now);
}
date rand_date_from_epoch_to_ceil(date ceil_date){
date epoch = ptime(date(1970,1,1)).date();
return rand_date_in_interval(epoch, ceil_date);
}
date rand_date_in_interval(date floor_date, date ceil_date){
return rand_ptime_in_interval(ptime(floor_date), ptime(ceil_date)).date();
}
ptime rand_ptime_from_epoch_to_now(){
ptime now = second_clock::local_time();
return rand_ptime_from_epoch_to_ceil(now);
}
ptime rand_ptime_from_epoch_to_ceil(ptime ceil_date){
ptime epoch = ptime(date(1970,1,1));
return rand_ptime_in_interval(epoch, ceil_date);
}
ptime rand_ptime_in_interval(ptime floor_date, ptime ceil_date){
time_duration const diff = ceil_date - floor_date;
long long gap_seconds = diff.total_seconds();
long long step_seconds = Randomizer::get_instance().rand(0, gap_seconds);
return floor_date + seconds(step_seconds);
}
};
How to convert std::chrono::time_point to calendar datetime string with fractional seconds?
For example:
"10-10-2012 12:38:40.123456"
If system_clock, this class have time_t conversion.
#include <iostream>
#include <chrono>
#include <ctime>
using namespace std::chrono;
int main()
{
system_clock::time_point p = system_clock::now();
std::time_t t = system_clock::to_time_t(p);
std::cout << std::ctime(&t) << std::endl; // for example : Tue Sep 27 14:21:13 2011
}
example result:
Thu Oct 11 19:10:24 2012
EDIT:
But, time_t does not contain fractional seconds.
Alternative way is to use time_point::time_since_epoch() function. This function returns duration from epoch.
Follow example is milli second resolution's fractional.
#include <iostream>
#include <chrono>
#include <ctime>
using namespace std::chrono;
int main()
{
high_resolution_clock::time_point p = high_resolution_clock::now();
milliseconds ms = duration_cast<milliseconds>(p.time_since_epoch());
seconds s = duration_cast<seconds>(ms);
std::time_t t = s.count();
std::size_t fractional_seconds = ms.count() % 1000;
std::cout << std::ctime(&t) << std::endl;
std::cout << fractional_seconds << std::endl;
}
example result:
Thu Oct 11 19:10:24 2012
925
Self-explanatory code follows which first creates a std::tm corresponding to 10-10-2012 12:38:40, converts that to a std::chrono::system_clock::time_point, adds 0.123456 seconds, and then prints that out by converting back to a std::tm. How to handle the fractional seconds is in the very last step.
#include <iostream>
#include <chrono>
#include <ctime>
int main()
{
// Create 10-10-2012 12:38:40 UTC as a std::tm
std::tm tm = {0};
tm.tm_sec = 40;
tm.tm_min = 38;
tm.tm_hour = 12;
tm.tm_mday = 10;
tm.tm_mon = 9;
tm.tm_year = 112;
tm.tm_isdst = -1;
// Convert std::tm to std::time_t (popular extension)
std::time_t tt = timegm(&tm);
// Convert std::time_t to std::chrono::system_clock::time_point
std::chrono::system_clock::time_point tp =
std::chrono::system_clock::from_time_t(tt);
// Add 0.123456 seconds
// This will not compile if std::chrono::system_clock::time_point has
// courser resolution than microseconds
tp += std::chrono::microseconds(123456);
// Now output tp
// Convert std::chrono::system_clock::time_point to std::time_t
tt = std::chrono::system_clock::to_time_t(tp);
// Convert std::time_t to std::tm (popular extension)
tm = std::tm{0};
gmtime_r(&tt, &tm);
// Output month
std::cout << tm.tm_mon + 1 << '-';
// Output day
std::cout << tm.tm_mday << '-';
// Output year
std::cout << tm.tm_year+1900 << ' ';
// Output hour
if (tm.tm_hour <= 9)
std::cout << '0';
std::cout << tm.tm_hour << ':';
// Output minute
if (tm.tm_min <= 9)
std::cout << '0';
std::cout << tm.tm_min << ':';
// Output seconds with fraction
// This is the heart of the question/answer.
// First create a double-based second
std::chrono::duration<double> sec = tp -
std::chrono::system_clock::from_time_t(tt) +
std::chrono::seconds(tm.tm_sec);
// Then print out that double using whatever format you prefer.
if (sec.count() < 10)
std::cout << '0';
std::cout << std::fixed << sec.count() << '\n';
}
For me this outputs:
10-10-2012 12:38:40.123456
Your std::chrono::system_clock::time_point may or may not be precise enough to hold microseconds.
Update
An easier way is to just use this date library. The code simplifies down to (using C++14 duration literals):
#include "date.h"
#include <iostream>
#include <type_traits>
int
main()
{
using namespace date;
using namespace std::chrono;
auto t = sys_days{10_d/10/2012} + 12h + 38min + 40s + 123456us;
static_assert(std::is_same<decltype(t),
time_point<system_clock, microseconds>>{}, "");
std::cout << t << '\n';
}
which outputs:
2012-10-10 12:38:40.123456
You can skip the static_assert if you don't need to prove that the type of t is a std::chrono::time_point.
If the output isn't to your liking, for example you would really like dd-mm-yyyy ordering, you could:
#include "date.h"
#include <iomanip>
#include <iostream>
int
main()
{
using namespace date;
using namespace std::chrono;
using namespace std;
auto t = sys_days{10_d/10/2012} + 12h + 38min + 40s + 123456us;
auto dp = floor<days>(t);
auto time = make_time(t-dp);
auto ymd = year_month_day{dp};
cout.fill('0');
cout << ymd.day() << '-' << setw(2) << static_cast<unsigned>(ymd.month())
<< '-' << ymd.year() << ' ' << time << '\n';
}
which gives exactly the requested output:
10-10-2012 12:38:40.123456
Update
Here is how to neatly format the current time UTC with milliseconds precision:
#include "date.h"
#include <iostream>
int
main()
{
using namespace std::chrono;
std::cout << date::format("%F %T\n", time_point_cast<milliseconds>(system_clock::now()));
}
which just output for me:
2016-10-17 16:36:02.975
C++17 will allow you to replace time_point_cast<milliseconds> with floor<milliseconds>. Until then date::floor is available in "date.h".
std::cout << date::format("%F %T\n", date::floor<milliseconds>(system_clock::now()));
Update C++20
In C++20 this is now simply:
#include <chrono>
#include <iostream>
int
main()
{
using namespace std::chrono;
auto t = sys_days{10d/10/2012} + 12h + 38min + 40s + 123456us;
std::cout << t << '\n';
}
Or just:
std::cout << std::chrono::system_clock::now() << '\n';
std::format will be available to customize the output.
In general, you can't do this in any straightforward fashion. time_point is essentially just a duration from a clock-specific epoch.
If you have a std::chrono::system_clock::time_point, then you can use std::chrono::system_clock::to_time_t to convert the time_point to a time_t, and then use the normal C functions such as ctime or strftime to format it.
Example code:
std::chrono::system_clock::time_point tp = std::chrono::system_clock::now();
std::time_t time = std::chrono::system_clock::to_time_t(tp);
std::tm timetm = *std::localtime(&time);
std::cout << "output : " << std::put_time(&timetm, "%c %Z") << "+"
<< std::chrono::duration_cast<std::chrono::milliseconds>(tp.time_since_epoch()).count() % 1000 << std::endl;
This worked for me for a format like YYYY.MM.DD-HH.MM.SS.fff. Attempting to make this code capable of accepting any string format will be like reinventing the wheel (i.e. there are functions for all this in Boost.
std::chrono::system_clock::time_point string_to_time_point(const std::string &str)
{
using namespace std;
using namespace std::chrono;
int yyyy, mm, dd, HH, MM, SS, fff;
char scanf_format[] = "%4d.%2d.%2d-%2d.%2d.%2d.%3d";
sscanf(str.c_str(), scanf_format, &yyyy, &mm, &dd, &HH, &MM, &SS, &fff);
tm ttm = tm();
ttm.tm_year = yyyy - 1900; // Year since 1900
ttm.tm_mon = mm - 1; // Month since January
ttm.tm_mday = dd; // Day of the month [1-31]
ttm.tm_hour = HH; // Hour of the day [00-23]
ttm.tm_min = MM;
ttm.tm_sec = SS;
time_t ttime_t = mktime(&ttm);
system_clock::time_point time_point_result = std::chrono::system_clock::from_time_t(ttime_t);
time_point_result += std::chrono::milliseconds(fff);
return time_point_result;
}
std::string time_point_to_string(std::chrono::system_clock::time_point &tp)
{
using namespace std;
using namespace std::chrono;
auto ttime_t = system_clock::to_time_t(tp);
auto tp_sec = system_clock::from_time_t(ttime_t);
milliseconds ms = duration_cast<milliseconds>(tp - tp_sec);
std::tm * ttm = localtime(&ttime_t);
char date_time_format[] = "%Y.%m.%d-%H.%M.%S";
char time_str[] = "yyyy.mm.dd.HH-MM.SS.fff";
strftime(time_str, strlen(time_str), date_time_format, ttm);
string result(time_str);
result.append(".");
result.append(to_string(ms.count()));
return result;
}
I would have put this in a comment on the accepted answer, since that's where it belongs, but I can't. So, just in case anyone gets unreliable results, this could be why.
Be careful of the accepted answer, it fails if the time_point is before the epoch.
This line of code:
std::size_t fractional_seconds = ms.count() % 1000;
will yield unexpected values if ms.count() is negative (since size_t is not meant to hold negative values).
In my case I use chrono and c function localtime_r which is thread-safe (in opposition to std::localtime).
#include <iostream>
#include <chrono>
#include <ctime>
#include <time.h>
#include <iomanip>
int main() {
std::chrono::system_clock::time_point now = std::chrono::system_clock::now();
std::time_t currentTime = std::chrono::system_clock::to_time_t(now);
std::chrono::milliseconds now2 = std::chrono::duration_cast<std::chrono::milliseconds>(now.time_since_epoch());
struct tm currentLocalTime;
localtime_r(¤tTime, ¤tLocalTime);
char timeBuffer[80];
std::size_t charCount { std::strftime( timeBuffer, 80,
"%b %d %T",
¤tLocalTime)
};
if (charCount == 0) return -1;
std::cout << timeBuffer << "." << std::setfill('0') << std::setw(3) << now2.count() % 1000 << std::endl;
return 0;
}
If you are to format a system_clock::time_point in the format of numpy datetime64, you could use:
std::string format_time_point(system_clock::time_point point)
{
static_assert(system_clock::time_point::period::den == 1000000000 && system_clock::time_point::period::num == 1);
std::string out(29, '0');
char* buf = &out[0];
std::time_t now_c = system_clock::to_time_t(point);
std::strftime(buf, 21, "%Y-%m-%dT%H:%M:%S.", std::localtime(&now_c));
sprintf(buf+20, "%09ld", point.time_since_epoch().count() % 1000000000);
return out;
}
sample output: 2019-11-19T17:59:58.425802666