Working with enum-like data in C++ - c++

Question

I am updating an old piece of C++ code and am stuck on a design issue and need advice on the best course of action. The code handles geometric data. Currently, the code defines many global constants to handle element types:
#define TETRAHEDRON 0
#define HEXAHEDRON 1
Each constant has information associated with it that remains constant and which is currently handled by a class, in our case Topology.
int Topology::nodesPerElement(int topType)
{
switch(topType) {
case TETRAHEDRON:
return 4;
break;
case HEXAHEDRON:
return 8;
break;
}
}
The Topology class has many of these functions that simply switch on the global constant to figure out associated information. There are a lot of element types and many bugs are introduced by switch statements that don't consider all element types. If an element type is added all of these methods need to be fixed. I need a better way of doing this that keeps the associated information with the type.
Enumerations are an improvement over this design, but it doesn't solve the problem of associating data with the enumeration.
For simplicity, I would like to avoid needing to instantiate classes for each type, as each will contain only static data that doesn't change.
What I really need is a "static class" that holds this information and performs like the pseudocode below:
class Tetrahedron : public TopType {
static const int nodesPerElement = 4;
static const std::string name = "Tet";
etc...
}
Each method in Topology becomes trivial:
int Topology::nodesPerElement(TopType topType)
{
return topType.nodesPerElement;
}
Is there a way to do this in C++? I've thought about just getting rid of the enumerations and having separate child Topology classes for each TopologyType, but the feedback I get from others is that it's too complicated of a solution. I hope that my question is clear enough.

Answer 1

Create a base class that contains all of the properties that your objects should support, and a private constructor to set those properties. You don't need derived classes, then: you can use static public objects to create the objects that you want with the desired properties.
class TopologyObject
{
private:
int numberVertices;
int numberFaces;
// etc.
public:
int getVertices() { return numberVertices; };
int getFaces() { return numberFaces; };
protected:
TopologyObject(int vertices, int faces) :
numberVertices(vertices),
numberFaces(faces)
{};
public:
static TopologyObject Tetrahedron = new TopologyObject(4, 4);
// etc.
}
You can access the Tetrahedron with all of its properties via TopologyObject::Tetrahedron.
If you decide that you need more complex variable behavior based on the type of object, then you really do need derived classes and virtual methods for the overrideable behavior.

Answer 2

Unless your Topology types have different runtime behaviors (like drawing themselves), then I agree with your peers that sub-classing is overkill. Reporting static properties like nodesPerElement and name is hardly a runtime behavior.
Unless you are not telling us the whole story about Topology, it seems that what you need is a simple property map. Use std::map to associate a topology type code with a structure of topology properties. This refactoring resembles Replace Subclass with Fields.
Here's some code that may serve as inspiration:
#include <cassert>
#include <iostream>
#include <map>
#include <string>
struct Topology
{
enum Code {tetrahedron, hexahedron};
int nodesPerElement;
std::string name;
};
namespace // Anonymous namespace
{
// Lookup table associating topology code with properties
const struct {Topology::Code code; Topology topo;} topoTable_[] =
{
{Topology::tetrahedron, {4, "Tetrahedron"}},
{Topology::hexahedron, {6, "Hexahedron"}}
};
};
class TopologyMap // Singleton
{
public:
static TopologyMap lookup(Topology::Code code)
{
return Topology(instance().doLookup(code));
}
private:
typedef std::map<Topology::Code, Topology> Map;
Map map_;
TopologyMap()
{
// Initialize map with constant property table
size_t tableSize = sizeof(topoTable_) / sizeof(topoTable_[0]);
for (size_t row=0; row<tableSize; ++row)
{
map_[topoTable_[row].code] = topoTable_[row].topo;
}
}
static TopologyMap& instance()
{
static TopologyMap instance;
return instance;
}
const Topology& doLookup(Topology::Code code) const
{
Map::const_iterator match = map_.find(code);
assert(match != map_.end());
return match->second;
}
};
class Shape
{
public:
Shape(Topology::Code topoCode)
: topo_(TopologyMap::lookup(topoCode)) {}
const Topology& topology() const {return topo_;}
// etc...
private:
Topology topo_;
};
int main()
{
Shape shape1(Topology::tetrahedron);
Shape shape2(Topology::hexahedron);
std::cout << "shape1 is a " << shape1.topology().name << " with " <<
shape1.topology().nodesPerElement << " nodes per element.\n";
std::cout << "shape2 is a " << shape2.topology().name << " with " <<
shape2.topology().nodesPerElement << " nodes per element.\n";
};
Output:
shape1 is a Tetrahedron with 4 nodes per element.
shape2 is a Hexahedron with 6 nodes per element.
If the topology code is zero-based and continuous, then you may use simple array indexing instead of a map. However, array indexing will be more error-prone if someone messes around with the topology code enum. Here is the same example that uses array indexing:
#include <cassert>
#include <iostream>
#include <map>
#include <string>
struct Topology
{
enum Code {tetrahedron, hexahedron, CODE_COUNT};
int nodesPerElement;
std::string name;
};
namespace // Anonymous namespace
{
// Lookup table associating topology code with properties
const Topology topoTable_[] =
{
{4, "Tetrahedron"},
{6, "Hexahedron"}
};
};
class TopologyMap // Singleton
{
public:
static Topology lookup(Topology::Code code)
{
assert(code < Topology::CODE_COUNT);
return topoTable_[code];
}
private:
TopologyMap() {} // Non-instantiable
};
class Shape
{
public:
Shape(Topology::Code topoCode)
: topo_(TopologyMap::lookup(topoCode)) {}
const Topology& topology() const {return topo_;}
// etc...
private:
Topology topo_;
};
int main()
{
Shape shape1(Topology::tetrahedron);
Shape shape2(Topology::hexahedron);
std::cout << "shape1 is a " << shape1.topology().name << " with " <<
shape1.topology().nodesPerElement << " nodes per element.\n";
std::cout << "shape2 is a " << shape2.topology().name << " with " <<
shape2.topology().nodesPerElement << " nodes per element.\n";
};
Note that because the details of storing and retrieving Topology was encapsulated in TopologyMap, I didn't have to rewrite any code in Shape and main.

Answer 3

You can have classes with nothing but static member variables. And that's a nice way to encapsulate attribute data.
If you'd rather not do that, traits might get you what you want.

Answer 4

I'm not sure who advised you to avoid derived classes for each Toplogy type. To my eye, this problem is screaming for derived classes.
Unless you would need a very large number of such classes.

Answer 5

Personally I think the best way to store this information would be to create a general Shape class. Then, instead of coding all those static variables put them in a file/database and load your shape information from the data store when you start your program.

Answer 6

Couldn't you use a record to do this if your goal is to avoid class instantiation?
Really though, you should class the poop out of this.

Answer 7

If topType is contiguous and starting a 0, you could just maintain an array of structs and index into that, instead of trying to have classes and subclasses. This way the only code change you would need is to
add the struct: Easy
add an array of structs: Easy
change each method to index into array and return proper field of struct: Tedious, but you have to do this anyway.
It your TopologyType can just be modelled as an instance of a struct (i.e no methods on it etc), Classes + Derived classes is overkill, IMO.

Answer 8

Since (apparently) all the relevant data is available at compile time, one possibility would be to use an enumeration along with templates and specialization to do the job:
enum { tetrahedron, hexahedron };
template <int type>
struct nodes_per_element { int operator()() const {
throw std::invalid_argument("Attempt to use unknown shape");
};
template <>
struct nodes_per_element<tetrahedron> { int operator()() const { return 4; } };
template <>
struct nodes_per_element<hexahedron> { int operator()() const { return 8; } };
You'd use this like: int x = nodes_per_element<hexahedron>()(); If you try to use it for a value for which there's no specialization, that will invoke the un-specialized template, which will throw an exception, halting the program and (normally) displaying a message saying you attempted to use an unknown shape. Of course, you can customize how that's displayed (if at all).
This should quickly show where you have problems due to values that haven't been defined.
The other obvious possibility would be to just define a struct for each shape you're going to use, and create an array of those structs, using the name of the shape as an index into the data, and the name of the specific data you want will be the member of the struct. For just the nodes per element you've given, that would look like:
struct shape_data {
int nodes_per_element;
std::string name;
};
shape_data data[] = {
{4, "Tetrahedron"},
{8, "Hexahedron" }
};
Retrieving data would be something like:
shape_data &s = data[hexahedron];
std::cout << "A " << s.name << " has " << s.nodes_per_element << "nodes per element.\n";

Answer 9

Having look at the previous answers, I've decided to add my own.
To me there are 2 things that I would require of such a design:
the ability to define a new item without recompiling the whole program
the ability to look up an item based on a property (like the number of faces)
This can be quite easy to do, so here is my little bit of code:
class Solid
{
typedef std::vector<Solid> solids_type;
public:
Solid(std::string name, size_t faces, size_t nodes):
mName(name), mFaces(faces), mNodes(nodes)
{
}
///
/// Properties
///
const std::string& getName() const { return mName; }
size_t getFaces() const { return mFaces; }
size_t getNodes() const { return mNodes; }
///
/// Collection Handling
///
static bool Add(Solid solid); // only add if it's not already there.
///
/// struct Predicate: std::unary_function<Solid,bool>
///
template <class Predicate>
static const Solid* Get(Predicate pred)
{
solids_type::const_iterator it =
std::find_if(Solids().begin(), Solids().end(), pred);
return it == Solids().end()) ? 0 : &(*it);
} // Get
///
/// Some Predicates
///
class ByName: std::unary_function<Solid,bool>
{
public:
ByName(std::string name): mName(name) {}
bool operator()(const Solid& s) const { return s.getName() == mName; }
private:
std::string mName;
};
class ByFaces; /// ...
class ByNodes; /// ...
private:
/// Properties
std::string mName;
size_t mFaces;
size_t mNodes;
/// Collection
static solids_type& Solids()
{
static solids_type MSolids;
return MSolids;
}
}; // class Solid
And thus, now we can have:
// in tetrahedron.cpp
namespace
{
bool gTetrahedron = Solid::Add(Solid("Tetrahedron", 4, 4));
}
// in main.cpp
int main(int argc, char* argv[])
{
const Solid* myTetra = Solid::Get(Solid::ByFaces(4));
assert(myTetra->getName() == "Tetrahedron");
assert(myTetra->getFaces() == 4);
assert(myTetra->getNodes() == 4);
return 0;
} // main
And now we have met our goals:
Adding one new solid does not cause any recompilation
We can lookup solid based on their properties
We could also imagine:
being able to iterate through all the registered solids
having them sorted by number of faces, or whatever
defining a little macro for the registration

Answer 10

This is precisely what virtual functions are for. The classical way to do it would be:
class Topology
{
public:
virtual int nodesPerElement() const = 0;
// etc
};
class Tetrahedrom : public Topology
{
public:
virtual nodesPerElement() const { return 4; }
// etc
}
// etc
But if you really have an aversion to re-implementing the accessor methods (as opposed to just defining variables) you could do the following with templates (although it's really no less verbose):
class Topology
{
public:
virtual int nodesPerElement() const = 0;
// etc
};
template<typename T>
class ConcreteTopology : public Topology
{
public:
virtual int nodesPerElement() const { return T::nodesPerElement; }
// etc
};
struct Tetrahedron_Data {
int nodesPerElement = 4;
// etc
};
typedef ConcreteTypology<Tetraheadron_Data> Tetrahedron;
// etc