Although this seems like a trivial question, I am quite sure it is not :)
I need to validate names and surnames of people from all over the world. Imagine a huge list of miilions of names and surnames where I need to remove as well as possible any cruft I identify. How can I do that with a regular expression? If it were only English ones I think that this would cut it:
^[a-z -']+$
However, I need to support also these cases:
other punctuation symbols as they might be used in different countries (no idea which, but maybe you do!)
different Unicode letter sets (accented letter, greek, japanese, chinese, and so on)
no numbers or symbols or unnecessary punctuation or runes, etc..
titles, middle initials, suffixes are not part of this data
names are already separated by surnames.
we are prepared to force ultra rare names to be simplified (there's a person named '#' in existence, but it doesn't make sense to allow that character everywhere. Use pragmatism and good sense.)
note that many countries have laws about names so there are standards to follow
Is there a standard way of validating these fields I can implement to make sure that our website users have a great experience and can actually use their name when registering in the list?
I would be looking for something similar to the many "email address" regexes that you can find on google.
I sympathize with the need to constrain input in this situation, but I don't believe it is possible - Unicode is vast, expanding, and so is the subset used in names throughout the world.
Unlike email, there's no universally agreed-upon standard for the names people may use, or even which representations they may register as official with their respective governments. I suspect that any regex will eventually fail to pass a name considered valid by someone, somewhere in the world.
Of course, you do need to sanitize or escape input, to avoid the Little Bobby Tables problem. And there may be other constraints on which input you allow as well, such as the underlying systems used to store, render or manipulate names. As such, I recommend that you determine first the restrictions necessitated by the system your validation belongs to, and create a validation expression based on those alone. This may still cause inconvenience in some scenarios, but they should be rare.
I'll try to give a proper answer myself:
The only punctuations that should be allowed in a name are full stop, apostrophe and hyphen. I haven't seen any other case in the list of corner cases.
Regarding numbers, there's only one case with an 8. I think I can safely disallow that.
Regarding letters, any letter is valid.
I also want to include space.
This would sum up to this regex:
^[\p{L} \.'\-]+$
This presents one problem, i.e. the apostrophe can be used as an attack vector. It should be encoded.
So the validation code should be something like this (untested):
var name = nameParam.Trim();
if (!Regex.IsMatch(name, "^[\p{L} \.\-]+$"))
throw new ArgumentException("nameParam");
name = name.Replace("'", "'"); //' does not work in IE
Can anyone think of a reason why a name should not pass this test or a XSS or SQL Injection that could pass?
complete tested solution
using System;
using System.Text.RegularExpressions;
namespace test
{
class MainClass
{
public static void Main(string[] args)
{
var names = new string[]{"Hello World",
"John",
"João",
"タロウ",
"やまだ",
"山田",
"先生",
"мыхаыл",
"Θεοκλεια",
"आकाङ्क्षा",
"علاء الدين",
"אַבְרָהָם",
"മലയാളം",
"상",
"D'Addario",
"John-Doe",
"P.A.M.",
"' --",
"<xss>",
"\""
};
foreach (var nameParam in names)
{
Console.Write(nameParam+" ");
var name = nameParam.Trim();
if (!Regex.IsMatch(name, #"^[\p{L}\p{M}' \.\-]+$"))
{
Console.WriteLine("fail");
continue;
}
name = name.Replace("'", "'");
Console.WriteLine(name);
}
}
}
}
I would just allow everything (except an empty string) and assume the user knows what his name is.
There are 2 common cases:
You care that the name is accurate and are validating against a real paper passport or other identity document, or against a credit card.
You don't care that much and the user will be able to register as "Fred Smith" (or "Jane Doe") anyway.
In case (1), you can allow all characters because you're checking against a paper document.
In case (2), you may as well allow all characters because "123 456" is really no worse a pseudonym than "Abc Def".
I would think you would be better off excluding the characters you don't want with a regex. Trying to get every umlaut, accented e, hyphen, etc. will be pretty insane. Just exclude digits (but then what about a guy named "George Forman the 4th") and symbols you know you don't want like ##$%^ or what have you. But even then, using a regex will only guarantee that the input matches the regex, it will not tell you that it is a valid name.
EDIT after clarifying that this is trying to prevent XSS: A regex on a name field is obviously not going to stop XSS on its own. However, this article has a section on filtering that is a starting point if you want to go that route:
s/[\<\>\"\'\%\;\(\)\&\+]//g;
"Secure Programming for Linux and Unix HOWTO" by David A. Wheeler, v3.010 Edition (2003)
v3.72, 2015-09-19 is a more recent version.
BTW, do you plan to only permit the Latin alphabet, or do you also plan to try to validate Chinese, Arabic, Hindi, etc.?
As others have said, don't even try to do this. Step back and ask yourself what you are actually trying to accomplish. Then try to accomplish it without making any assumptions about what people's names are, or what they mean.
I don’t think that’s a good idea. Even if you find an appropriate regular expression (maybe using Unicode character properties), this wouldn’t prevent users from entering pseudo-names like John Doe, Max Mustermann (there even is a person with that name), Abcde Fghijk or Ababa Bebebe.
You could use the following regex code to validate 2 names separeted by a space with the following regex code:
^[A-Za-zÀ-ú]+ [A-Za-zÀ-ú]+$
or just use:
[[:lower:]] = [a-zà-ú]
[[:upper:]] =[A-ZÀ-Ú]
[[:alpha:]] = [A-Za-zÀ-ú]
[[:alnum:]] = [A-Za-zÀ-ú0-9]
It's a very difficult problem to validate something like a name due to all the corner cases possible.
Corner Cases
Anything anything here
Sanitize the inputs and let them enter whatever they want for a name, because deciding what is a valid name and what is not is probably way outside the scope of whatever you're doing; given the range of potential strange - and legal names is nearly infinite.
If they want to call themselves Tricyclopltz^2-Glockenschpiel, that's their problem, not yours.
A very contentious subject that I seem to have stumbled along here. However sometimes it's nice to head dear little-bobby tables off at the pass and send little Robert to the headmasters office along with his semi-colons and SQL comment lines --.
This REGEX in VB.NET includes regular alphabetic characters and various circumflexed european characters. However poor old James Mc'Tristan-Smythe the 3rd will have to input his pedigree in as the Jim the Third.
<asp:RegularExpressionValidator ID="RegExValid1" Runat="server"
ErrorMessage="ERROR: Please enter a valid surname<br/>" SetFocusOnError="true" Display="Dynamic"
ControlToValidate="txtSurname" ValidationGroup="MandatoryContent"
ValidationExpression="^[A-Za-z'\-\p{L}\p{Zs}\p{Lu}\p{Ll}\']+$">
This one worked perfectly for me in JavaScript:
^[a-zA-Z]+[\s|-]?[a-zA-Z]+[\s|-]?[a-zA-Z]+$
Here is the method:
function isValidName(name) {
var found = name.search(/^[a-zA-Z]+[\s|-]?[a-zA-Z]+[\s|-]?[a-zA-Z]+$/);
return found > -1;
}
Steps:
first remove all accents
apply the regular expression
To strip the accents:
private static string RemoveAccents(string s)
{
s = s.Normalize(NormalizationForm.FormD);
StringBuilder sb = new StringBuilder();
for (int i = 0; i < s.Length; i++)
{
if (CharUnicodeInfo.GetUnicodeCategory(s[i]) != UnicodeCategory.NonSpacingMark) sb.Append(s[i]);
}
return sb.ToString();
}
This somewhat helps:
^[a-zA-Z]'?([a-zA-Z]|\.| |-)+$
This one should work
^([A-Z]{1}+[a-z\-\.\']*+[\s]?)*
Add some special characters if you need them.
Related
I have a plain text and need to extract company names. It's a huge document including company names, financial reports and lots of text.Here are examples of company names:
Big laundry, a.s.
AVERA, s.r.o.
Airoflot Airlines, a.s.
Is it even possible to make regex like this? I'm complete beginner to regex and have no idea how to create this one. Thanks for any help.
Example of text:
`There are many competitors of AVERA, s.r.o. the main one is Airflot Airlines, a.s. and Big laundry, s.r.o. These organisations hold main share of market.
Another companies:
a. Big Company, a.s.
b. Smaller company, s.r.o.
c. Huge company, a.s.`
As the question currently stands, no it is not possible to create a regex for company names.
It would be possible if you are able to create a PATTERN.
Means e.g. A company name always:
starts with an uppercase letter
has a comma
after the comma there is always one of "a.s." or "s.r.o."
So, the difficulties that I see here are:
How many words before the comma belong to the name?
Is there always a comma with following abbreviation?
Names are always difficult to match because a name can be nearly everything, especially company names.
The examples you give follow this pattern : ([A-Z][A-Za-z]+ ?)+, (\w\.)+
The matching operation will be dependent of the tool you use.
For example in JavaScript :
var line = "some name is Airoflot Airlines, a.s. in this line";
var m = line.match(/([A-Z][A-Za-z]+ ?)+, (\w\.)+/);
if (m.length) console.log(m[0]);
This logs
"Airoflot Airlines, a.s."
But this isn't a very reliable solutions : many real company names wouldn't fit and, more importantly perhaps, this would match sentences that aren't company names. So this can only be used as an help in a solution which also incorporates some kind of validation (human or dictionary based).
I use this
(?:\s*[a-zA-Z0-9,_\.\077\0100\*\+\&\#\'\~\;\-\!\#\;]{2,}\s*)*
it matches all a-z, A-Z,0-9 and some special characters which Quickbook supports.
https://community.intuit.com/articles/1146006-acceptable-characters-in-the-company-name-in-quickbooks-online
with your given examples, this regexp would match
Big laundry, a\.s\.|AVERA, s\.r\.o\.|Airoflot Airlines, a\.s\.
The trick is to use the alternation operator | on a set of strings
You may wish to consider missing punctuation and white space in the company names too
I recently started working with ontologies and I am using Protege to build an ontology which I'd also like to use for automatically classifying strings. The following illustrates a very basic class hierarchy:
String
|_ AlphabeticString
|_ CountryName
|_ CityName
|_ AlphaNumericString
|_ PrefixedNumericString
|_ NumericString
Eventually strings like Spain should be classified as CountryName or UE4564 would be a PrefixedNumericString.
However I am not sure how to model this knowledge. Would I have to first define if a character is alphabetic, numeric, etc. and then construct a word from the existing characters or is there a way to use Regexes? So far I only managed to classify strings based on an exact phrase like String and hasString value "UE4565".
Or would it be better to safe a regex for each class in the ontology and then classify the string in Java using those regexes?
An approach that might be appropriate here, especially if the ontology is large/complicated or might change in the future, and assuming that some errors are acceptable, is machine learning.
An outline of a process utilizing this approach might be:
Define a feature set you can extract from each string, relating to your ontology (some examples below).
Collect a "train set" of strings and their true matching categories.
Extract features from each string, and train some machine-learning algorithm on this data.
Use the trained model to classify new strings.
Retrain or update your model as needed (e.g. when new categories are added).
To illustrate more concretely, here are some suggestions based on your ontology example.
Some boolean features that might be applicable: does the string matches a regexp (e.g the ones Qtax suggests); does the string exist in a prebuilt known city-names list; does it exist in a known country-names list; existence of uppercase letters; string length (not boolean), etc.
So if, for instance, you have a total of 8 features: match to the 4 regular expressions mentioned above; and the additional 4 suggested here, then "Spain" would be represented as (1,1,0,0,1,0,1,5) (matching the first 2 regular expressions but not the last two, is a city name but not a country name, has an uppercase letter and length is 5).
This set of feature will represent any given string.
to train and test a machine learning algorithm, you can use WEKA. I would start from rule or tree based algorithms, e.g. PART, RIDOR, JRIP or J48.
Then the trained models can be used via Weka either from within Java or as an external command line.
Obviously, the features I suggest have almost 1:1 match with your Ontology, but assuming your taxonomy is larger and more complex, this approach would probably be one of the best in terms of cost-effectiveness.
I don't know anything about Protege, but you can use regex to match most of those cases. The only problem would be differentiating between country and city name, I don't see how you could do that without a complete list of either one.
Here are some expressions that you could use:
AlphabeticString:
^[A-Za-z]+\z (ASCII) or ^\p{Alpha}+\z (Unicode)
AlphaNumericString:
^[A-Za-z0-9]+\z (ASCII) or ^\p{Alnum}+\z (Unicode)
PrefixedNumericString:
^[A-Za-z]+[0-9]+\z (ASCII) or ^\p{Alpha}+\p{N}+\z (Unicode)
NumericString:
^[0-9]+\z (ASCII) or ^\p{N}+\z (Unicode)
A particular string is an instance, so you'll need some code to make the basic assertions about the particular instance. That code itself might contain the use of regular expressions. Once you've got those assertions, you'll be able to use your ontology to reason about them.
The hard part is that you've got to decide what level you're going to model at. For example, are you going to talk about individual characters? You can, but it's not necessarily sensible. You've also got the challenge that arises from the fact that negative information is awkward (as the basic model of such models is intuitionistic, IIRC) which means (for example) that you'll know that a string contains a numeric character but not that it is purely numeric. Yes, you'd know that you don't have an assertion that the instance contains an alphabetic character, but you wouldn't know whether that's because the string doesn't have one or just because nobody's said so yet. This stuff is hard!
It's far easier to write an ontology if you know exactly what problems you intend to solve with it, as that allows you to at least have a go at working out what facts and relations you need to establish in the first place. After all, there's a whole world of possible things that could be said which are true but irrelevant (“if the sun has got his hat on, he'll be coming out to play”).
Responding directly to your question, you start by checking whether a given token is numeric, alphanumeric or alphabetic (you can use regex here) and then you classify it as such. In general, the approach you're looking for is called generalization hierarchy of tokens or hierarchical feature selection (Google it). The basic idea is that you could treat each token as a separate element, but that's not the best approach since you can't cover them all [*]. Instead, you use common features among tokens (for example, 2000 and 1981 are distinct tokens but they share a common feature of being 4 digit numbers and possibly years). Then you have a class for four digit numbers, another for alphanumeric, and so on. This process of generalization helps you to simplify your classification approach.
Frequently, if you start with a string of tokens, you need to preprocess them (for example, remove punctuation or special symbols, remove words that are not relevant, stemming, etc). But maybe you can use some symbols (say, punctuation between cities and countries - e.g. Melbourne, Australia), so you assign that set of useful punctuation symbols to other symbol (#) and use that as a context (so the next time you find an unknown word next to a comma next to a known country, you can use that knowledge to assume that the unknown word is a city.
Anyway, that's the general idea behind classification using an ontology (based on a taxonomy of terms). You may also want to read about part-of-speech tagging.
By the way, if you only want to have 3 categories (numeric, alphanumeric, alphabetic), a viable option would be to use edit distance (what is more likely, that UA4E30 belongs to the alphanumeric or numeric category, considering that it doesn't correspond to the traditional format of prefixed numeric strings?). So, you assume a cost for each operation (insertion, deletion, subtitution) that transforms your unknown token into a known one.
Finally, although you said you're using Protege (which I haven't used) to build your ontology, you may want to look at WordNet.
[*] There are probabilistic approaches that help you to determine a probability for an unknown token, so the probability of such event is not zero. Usually, this is done in the context of Hidden Markov Models. Actually, this could be useful to improve the suggestion given by etov.
It seems hard to detect a sentence boundary in a text. Quotation marks like .!? may be used to delimite sentences but not so accurate as there may be ambiguous words and quotations such as U.S.A or Prof. or Dr. I am studying Tperlregex library and Regular Expression Cookbook by Jan Goyvaerts but I do not know how to write the expression that detects sentence?
What may be comparatively accurate expression using Tperlregex in delphi?
Thanks
First, you probably need to arrive at your own definition of what a "sentence" is, then implement that definition. For example, how about:
He said: "It's OK!"
Is it one sentence or two? A general answer is irrelevant. Decide whether you want it to interpret it as one or two sentences, and proceed accordingly.
Second, I don't think I'd be using regular expressions for this. Instead, I would scan each character and try to detect sequences. A period by itself may not be enough to delimit a sentence, but a period followed by whitespace or carriage return (or end of string) probably does. This immediately lets you weed out U.S.A (periods not followed by whitespace).
For common abbreviations like Prof. an Dr. it may be a good idea to create a dictionary - perhaps editable by your users, since each language will have its own set of common abbreviations.
Each language will have its own set of punctuation rules too, which may affect how you interpret punctuation characters. For example, English tends to put a period inside the parentheses (like this.) while Polish does the opposite (like this). The same difference will apply to double quotes, single quotes (some languages don't use them at all, sometimes they are indistinguishable from apostrophes etc.). Your rules may well have to be language-specific, at least in part.
In the end, you may approximate the human way of delimiting sentences, but there will always be cases that can throw the analysis off. For example, assuming that you have a dictionary that recognizes "Prof." as an abbreviation, what are you going to do about
Most people called him Professor Jones, but to me he was simply The Prof.
Even if you have another sentence that follows and starts with a capital letter, that still won't help you know where the sentence ends, because it might as well be
Most people called him Professor Jones, but to me he was simply Prof. Bill.
Check my tutorial here http://code.google.com/p/graph-expression/wiki/SentenceSplitting. This concrete example can be easily rewritten to regular expressions and some imperative code.
It will be wise to use a NLP processor with a pre-trained model. EnglishSD.nbin is one such model that is available for OpenNLP and it can be used in Visual Studio with SharpNLP.
The advantage of using this method is numerous. For example consider the input
Prof. Jessica is a wonderful woman. She is a native of U.S.A. She is married to Mr. Jacob Jr.
If you are using a regex split, for example
string[] sentences = Regex.Split(text, #"(?<=['""A-Za-z0-9][\.\!\?])\s+(?=[A-Z])");
Then the above input will be split as
Prof.
Jessica is a wonderful woman.
She is a native of U.
S.
A.
She is married to Mr.
Jacob Jr.
However the desired output is
Prof. Jessica is a wonderful woman.
She is a native of U.S.A. She is married to Mr. Jacob Jr.
This kind of logical sentence split can be achieved only using trained models from OpenNLP project. The method is as simple as this.
private string mModelPath = #"C:\Users\ATS\Documents\Visual Studio 2012\Projects\Google_page_speed_json\Google_page_speed_json\bin\Release\";
private OpenNLP.Tools.SentenceDetect.MaximumEntropySentenceDetector mSentenceDetector;
private string[] SplitSentences(string paragraph)
{
if (mSentenceDetector == null)
{
mSentenceDetector = new OpenNLP.Tools.SentenceDetect.EnglishMaximumEntropySentenceDetector(mModelPath + "EnglishSD.nbin");
}
return mSentenceDetector.SentenceDetect(paragraph);
}
where mModelPath is the path of the directory containing the nbin file.
The mSentenceDetector is derived from the OpenNLP dll.
You can get the desired output by
string[] sentences = SplitSentences(text);
Kindly read through this article I have written for integrating SharpNLP with your Application in Visual Studio to make use of the NLP tools
This might be a hard one (if not impossible), but can anyone think of a regular expression that will find a person's name, in say, a resume? I know this won't be 100% accurate, but I can't come up with something.
Let's assume the name only shows up once in the document.
No, you can't use regular expressions for this. The only chance you have is if the document is always in the same format and you can find the name based on the context surrounding it. But this probably isn't the case for you.
If you are asking your applicants to submit their résumé online you could provide a separate field for them to enter their name and any other information you need instead of trying to automatically parse résumés.
Forget it - seriously.
Or expect to get a lot of applications from a Mr C Vitae
In my experience, having written something very similar (but a very long time ago), about 95% of resumes have the person's name as the very first line. You could probably have a pretty loose regex checking for alpha, hyphens, periods, and assume that's the name.
Obviously there's no way to do this 100% accurately, as you said, but this would be close.
Unless you wanted to build an expression that contained every possible name, or-ed together, the expression you are referring to is not "Regular," with a capital R. A good guess might be to go looking for the largest-font words in the document. If they follow a pattern that looks like firstname-lastname, name-initial-name, etc., you could call it a good guess...
That's a really hairy problem to tackle. The regex has to match two words that could be someone's name. The problem with that is that some people, of Hispanic origin, for example, might have a name that's more than 2 words. Also, how would you define two words to match for a name? Would you use a database of common first and last name fields? That might work unless someone has an uncommon name.
I'm reminded of a story of a COBOL teacher in college told me about an individual of Asian origin who's name would break every rule the programmers defined for a bank's internal system. His first name was "O." just the letter O.
The only remotely dependable way to nail down the regex would be if you had something to set off your search with; maybe if a line of text in the resume began with "Name: " then you'd know where to start looking.
tl;dr: People's names and individual resumes are too heavily varied for a regular expression to pick apart.
You could do something like Amazon does for book overviews: SIPs. This would require some after-the-fact double checking by humans but you might find the person's name(s) in there.
I have a website form that requires a US phone number input for follow up purposes, and this is very necessary in this case. I want try to eliminate users entering junk data 330-000-0000. I have seen some options of third parties that validate phone numbers for you, however idk if that is the best option for this situation. However if you have every used one of these third parties and can make a recommendation that would also be greatly appreciated here.
However I am considering checking the number against a set of rules to just try to narrow down the junk phone numbers received.
not a 555 number
does not contain 7 identical digits
valid area code (this is readily available)
not a 123-1234 or 123-4567
I guess I could also count out 867-5309 (heh*)
Would this result in any situations that you can think of that would not allow a user to enter their phone number? Could you think of any other rules that a phone number should not contain? Any other thoughts?
It seems to me that you're putting more effort into this than it warrants. Consider:
If your purpose is to guard against mis-entered phone numbers, then you can probably catch well over 90% of them with just a very simple check.
If your purpose is to try to force users to provide a valid number whether they want to give that information out or not, then you've taken on a hopeless task - even if you were able to access 100% accurate, up-to-the-second telco databases to verify that the exact number entered is currently live, you still don't gain any assurance that the number they gave you is their own. Once again, a simple check will foil the majority of people entering bogus numbers, but those who are willing to try more than two or three times will find a way to defeat your attempts to gain their numbers.
Either way, a simple test is going to get you good results and going into more complex rule sets will take up increasingly more time while providing increasingly little benefit to you (while also potentially adding false positives, as already shown with the "seven of the same digit" and 867-5309 cases).
You can do phone number validation internally in your app using regular expressions. Depending on your language you can call a function that will return true if a supplied phone number matches the expression.
In PHP:
function phone_number_is_valid($phone) {
return (eregi('^(?:\([2-9]\d{2}\)\ ?|[2-9]\d{2}(?:\-?|\ ?))[2-9]\d{2}[- ]?\d{4}$', $phone));
}
You can look up different regular expressions online. I found the one above one at http://regexlib.com/DisplayPatterns.aspx?categoryId=7&cattabindex=2
Edit: Some language specific sites for regular expressions:
PHP at php.net: http://php.net/regex
C# at MSDN
Java: http://java.sun.com/developer/technicalArticles/releases/1.4regex/
867-5309 is a valid phone number that is assigned to people in different area codes.
If you can verify the area code then unless you really, really need to know their phone number you're probably doing as much as is reasonable.
In Django there is a nice little contrib package called localflavor wich has a lot of country specific validation code, for example postal codes or phone numbers. You can look in the source too see how django handles these for the country you would like to use; For example: US Form validation. This can be a great recourse for information about countries you know little of as well.
Your customers can still do what I do, which is give out the local moviefone number.
Also, 123-1234 or 123-4567 are only invalid numbers because the prefix begins with a 1, but 234-5678 or 234-1234 would actually be valid (though it looks fake).
Maybe take a look at the answers to this question.
If you're sticking with just US- and Canada-format numbers, I think the following regex might work:
[2-9][0-9][0-9]-[2-9][0-9][0-9]-[0-9][0-9][0-9][0-9] & ![2-9][0-9][0-9]-555-[0-9][0-9][0-9][0-9]
You also need to take into account ten-digit dialing, which is used in some areas now: this is different from long-distance dialing (ie, 303-555-1234, as opposed to 1-303-555-1234). In some places, a valid phone number is ten digits long; in others, it is seven.
This is a quick function that I use (below). I do have access to a zipcode database that contains areacode and prefix data which is updated monthly. I have often thought about doing a data dip to confirm that the prefix exists for the area code.
public static bool isPhone(string phoneNum)
{
Regex rxPhone1, rxPhone2;
rxPhone1 = new Regex(#"^\d{10,}$");
rxPhone2 = new Regex(#"(\d)\1\1\1\1\1\1\1\1\1");
if(phoneNum.Trim() == string.Empty)
return false;
if(phoneNum.Length != 10)
return false;
//Check to make sure the phone number has at least 10 digits
if (!rxPhone1.IsMatch(phoneNum))
return false;
//Check for repeating characters (ex. 9999999999)
if (rxPhone2.IsMatch(phoneNum))
return false;
//Make sure first digit is not 1 or zero
if(phoneNum.Substring(0,1) == "1" || phoneNum.Substring(0,1) == "0")
return false;
return true;
}
I don't nkow if this is the right place, it's a formatting function rather than a validation function, I thought let's share it with the community, maybe one day it will be helpful..
Private Sub OnNumberChanged()
Dim sep = "-"
Dim num As String = Number.ToCharArray.Where(Function(c) Char.IsDigit(c)) _
.ToArray
Dim ext As String = Nothing
If num.Length > 10 Then ext = num.Substring(10)
ext = If(IsNullOrEmpty(ext), "", " x" & ext)
_Number = Left(num, 3) & sep & Mid(num, 4, 3) & sep & Mid(num, 7, 4) & ext
End Sub
My validation function is like so:
Public Shared Function ValidatePhoneNumber(ByVal number As String)
Return number IsNot Nothing AndAlso number.ToCharArray. _
Where(Function(c) Char.IsNumber(c)).Count >= 10
End Function
I call this last function # the OnNumberChanging(number As String) method of the entity.
For US and International Phone validation I found this code the most suitable:
((\+[1-9]{1,4}[ \-]*)|(\([0-9]{2,3}\)[ \-]*)|([0-9]{2,4})[ \-]*)*?[0-9]{3,4}?[ \-]*[0-9]{3,4}?$
You can find an (albeit somewhat dated) discussion here.
Those parameters look pretty good to me, I might also avoid numbers starting with 911 just to be safe.