Hyperlinks within XSLT Templates - xslt

I am trying to create hyperlinks using XML information and XSLT templates. Here is the XML source.
<smartText>
Among individual stocks, the top percentage gainers in the S. and P. 500 are
<smartTextLink smartTextRic="http://investing.domain.com/research/stocks/snapshot
/snapshot.asp?ric=HBAN.O">Huntington Bancshares Inc</smartTextLink>
and
<smartTextLink smartTextRic="http://investing.domain.com/research/stocks/snapshot
/snapshot.asp?ric=EK">Eastman Kodak Co</smartTextLink>
.
</smartText>
I want the output to look like this, with the company names being hyperlinks based on the "smartTextLink" tags in the Xml.
Among individual stocks, the top percentage gainers in the S.&P. 500 are Eastman Kodak Co and Huntington Bancshares Inc.
Here are the templates that I am using right now. I can get the text to display, but not the hyperlinks.
<xsl:template match="smartText">
<p class="smartText">
<xsl:apply-templates select="child::node()" />
</p>
</xsl:template>
<xsl:template match="smartTextLink">
<a>
<xsl:apply-templates select="child::node()" />
<xsl:attribute name="href">
<xsl:value-of select="#smartTextRic"/>
</xsl:attribute>
</a>
</xsl:template>
I have tried multiple variations to try to get the hyperlinks to work correctly. I am thinking that the template match="smartTextLink" is not being instantiated for some reason. Does anyone have any ideas on how I can make this work?
EDIT: After reviewing some of the answers, it is still not working in my overall application.
I am calling the smartText template from within my main template
using the following statement...
<xsl:value-of select="marketSummaryModuleData/smartText"/>
Could this also be a part of the problem?
Thank you
Shane

Either move the xsl:attribute before any children, or use an attribute value template.
<xsl:template match="smartTextLink">
<a href="{#smartTextRic}">
<xsl:apply-templates/>
</a>
</xsl:template>
From the creating attributes section of the XSLT 1 spec:
The following are all errors:
Adding an attribute to an element after children have been added to it; implementations may either signal the error or ignore the attribute.

Try this - worked for me:
<xsl:template match="smartText">
<p class="smartText">
<xsl:apply-templates/>
</p>
</xsl:template>
<xsl:template match="smartTextLink">
<a>
<xsl:attribute name="href">
<xsl:value-of select="#smartTextRic"/>
</xsl:attribute>
<xsl:value-of select="text()"/>
</a>
</xsl:template>
Trick is - <xsl:attribute> first, before you do any other processing.
Marc

Related

Attempts to use following-sibling to convert

I try to convert my old html by xslt-script to my new xml stucture.
I have a Problem to converting the folowing source to my needed xml structure.
Source
<p>
<a class="DropDown">Example Text</a>
</p>
<div class="collapsed">
<table>..</table>
<p>..</p>
</div>
xml structure
<lq>
<p>Example Text</p>
<table>..</table>
<p>..</p>
</lp>
I tried the following xls, but the div class="collapsed" is not adopted into the lp tag.
<xsl:template match="p/a[#class='DropDown']">
<lp>
<p><xsl:apply-templates select="text()"/></p>
<xsl:if test="/p/a/following-sibling::*[1][self::div]">
<xsl:apply-templates select="*|text()"/>
</xsl:if>
</lp>
</xsl:template>
Can anyone tell me what I did wrong ore where the mistake is?
Thanks much
IMHO, you want to do:
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="p[a/#class='DropDown']">
<lp>
<p>
<xsl:value-of select="a"/>
</p>
<xsl:copy-of select="following-sibling::*[1][self::div]/node()"/>
</lp>
</xsl:template>
<xsl:template match="div[preceding-sibling::*[1][self::p/a/#class='DropDown']]"/>
As for your mistake:
You are testing the existence of some p that is the root element
and contains an a whose following sibling is div. None of these are true in the given example;
xsl:if does not change the context: your <xsl:apply-templates
select="*|text()"/> applies templates to the child nodes of the
current a;
Presumably you don't want the div to appear again in the original place -
so if you have another template to suppress it, you cannot use
<xsl:apply-templates> to insert it at the place you do want it -
at least not without using another mode.

How to make XSLT xsl:if work

I am trying to make this (xml 1.0) code work . I am new to this and already exhausted myself in
trying different ways. Does someone know my mistake?
<xsl:for-each select="News/Sport">
<xsl:if test="local-name()='Basketball'">
<p>
<xsl:text>Basketball Sport</xsl:text>
</p>
<xsl:value-of select="News/Sport/Basketball/Phrases/Phrase"/>
</xsl:if>
</xsl:for-each>
When I transform it into an HTML file the content doesn't show up. When I remove the xsl:for each and the xsl:if statements the content is successfully presented. I only wish that the content is first checked (if it is available in the XML file) and if yes, that it is taken from the XML content.
Thank you in advance for your help!
EDIT:
This is my XML code
<News>
<Sport>
<Basketball>
<Phrases>
<Phrase>Zach Randolph recovered the opening tipoff in Game 1 of the Western Conference Finals, and he didn’t touch the ball again until the possession following the Grizzlies’ first timeout.
</Phrase>
<Phrases>
</Basketball>
</Sport>
</News>
EDIT2:
Could you tell me why I cannot apply a template inside this below function? Only the text works now:(
<xsl:for-each select="News/Sport[Basketball]">
<xsl:apply-templates select="News/Sport/*" />
</xsl:for-each>
<xsl:template match="Basketball">
<p>
<xsl:text>Basketball Sport</xsl:text>
</p>
<xsl:apply-templates select="Phrases/Phrase"/>
</xsl:template>
<xsl:for-each select="News/Sport">
<xsl:if test="local-name()='Basketball'">
In this if test, the context node is a Sport element, so local-name() will always be Sport and will never equal Basketball.
I only wish that the content is first checked (if it is available in the XML file) and if yes, that it is taken from the XML content.
The usual way to handle this sort of thing in XSLT is to define templates matching the various nodes that might be present and then applying templates to all the nodes that are actually found. If there are no nodes of a particular type then the corresponding template will not fire
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" />
<xsl:template match="/">
<html>
<body>
<!-- apply templates that match all elements inside Sport, which may
be Basketball, Football, etc. -->
<xsl:apply-templates select="News/Sport/*" />
</body>
</html>
</xsl:template>
<!-- when we find a Basketball element ... -->
<xsl:template match="Basketball">
<p>
<xsl:text>Basketball Sport</xsl:text>
</p>
<xsl:apply-templates select="Phrases/Phrase"/>
</xsl:template>
<!-- when we find a Football element ... -->
<xsl:template match="Football">
<p>
<xsl:text>Football Sport</xsl:text>
</p>
<!-- whatever you need to do for Football elements -->
</xsl:template>
<xsl:template match="Phrase">
<p><xsl:value-of select="." /></p>
</xsl:template>
</xsl:stylesheet>
That way you don't need any explicit for-each or if, the template matching logic handles it all for you.
You are missing the idea of a context node. Within a xsl:for-each, everything you refer to is about or relative to the selected nodes. So, for instance, within <xsl:for-each select="News/Sport">, the context node is the Sport elements, and a test like <xsl:if test="local-name()='Basketball'"> is always going to be false because the local name is always Sport.
It looks like you want just <xsl:if test="Basketball"> which tests whether there are any Basketball child nodes of the current Sport node.
The same thing applies to <xsl:value-of select="News/Sport/Basketball/Phrases/Phrase"/>. Because everything is relative to the Sport node, XSLT is looking for News/Sport/Basketball/Phrases/Phrase within the Sport element, which never exists.
In addition, you can just put text in literally: there is no need for an xsl:text element here, so your code should look like
<xsl:for-each select="News/Sport">
<xsl:if test="Basketball">
<p>Basketball Sport</p>
<xsl:value-of select="Basketball/Phrases/Phrase"/>
</xsl:if>
</xsl:for-each>
You can refine this further by adding a predicate to the for-each selection, so that it matches only Sport elements with a Basketball child. Like this
<xsl:for-each select="News/Sport[Basketball]">
<p>Basketball Sport</p>
<xsl:value-of select="Basketball/Phrases/Phrase"/>
</xsl:for-each>

xslt matching and stripping

I have a XML structure like this, just some valid XML structure mixed with HTML tags. I am trying to match <p>MyHeader</p> in the section and set it to empty.
That is after running the XSLT on this structure, i don't want to print the <p>MyHeader</p> tag.
<abstract>
<section>
<p>MyHeader</p>
<p> other content in section </p>
<h1> other content in section </h1>
</section>
</abstract>
Here's what I am trying in the XSL
<xsl:template match="abstract/section/p">
<xsl:choose>
<xsl:when test="text() ='MyHeader'"></xsl:when>
<xsl:otherwise><xsl:apply-templates /></xsl:otherwise>
</xsl:choose>
</xsl:template>
any ideas on what's wrong with my code above? I dont see <p>MyHeader</p> tag being stripped out.
<xsl:template match="abstract/section/p">
<xsl:choose>
<xsl:when test="text() ='MyHeader'"></xsl:when>
<xsl:otherwise><xsl:apply-templates /></xsl:otherwise>
</xsl:choose>
</xsl:template>
what's wrong with my code
Nothing wrong with the code shown -- the problem is in the code you haven't shown to us.
Guessing:
The template isn't selected for execution.
There is an explicit <xsl:copy-of> selecting this p element.
Recommendation: just use:
<xsl:template match="abstract/section/p[.='MyHeader']"/>

Using a link in XSL Files

I am completely new to XML so hopefully my explanations will make sense..
I am using an XSL file with 2 sections of HTML text, reading from 2 templates set up within the file.
The first text and associated template is a table, and I have set up a link within that. I want the link to then point to a picture that is part of the 2nd HTML text/template.
The link in the table is setup in that it appears as a link, underlined, etc. However it doesnt go anywhere when clicked.
The second section works fine on it's own, eg, pictures and text appears.
But what I cant figure out is how to actually get the link to work. I've tried numerous things but nothing has worked so far. And I-m not sure whether I am very close and just perhaps need to alter a line of code. Or whether I need to be doing something very different. Also, there are no error messages, and everything displays well, it's just the link itself that doesnt work.
<xsl:template match="portion">
<tr>
<td valign="top"><xsl:value-of select="food-description"/></td>
<td valign="top"><xsl:value-of select="food-number"/></td>
<!--the following is the link text-->
<td valign="top"><a><xsl:attribute name="href">#<xsl:value-of select="portion- photo/#file"/></xsl:attribute>
<xsl:value-of select="portion-photo/#file"/></a><br/>
</td>
</tr>
</xsl:template>
<xsl:template match="portion-photo">
<!--I know that this is the code that is not correct, however, believe it should be something similar-->
<a><xsl:attribute name="portion-photo"><xsl:value-of select="./#file"/></xsl:attribute></a>
<p><xsl:value-of select="../food-description"/>
<xsl:value-of select="./#file"/></p>
<img>
<xsl:attribute name="src"><xsl:value-of select="./#file"/></xsl:attribute>
<xsl:attribute name="width"><xsl:value-of select="ceiling(./#w div v2)"/></xsl:attribute>
<xsl:attribute name="height"><xsl:value-of select="ceiling(./#h div 2)"/></xsl:attribute>
</img>
</xsl:template>
Something like the following should work. Just add the missing name attribute to the anchor element:
<xsl:template match="portion">
...
<a href="#{portion-photo/#file}">
<xsl:value-of select="portion-photo/#file"/>
</a>
...
</xsl:template>
<xsl:template match="portion-photo">
<a name="{#file}">
<xsl:value-of select="#file"/>
</a>
</xsl:template>
However, you have to ensure that #file evaluates to a valid anchor name. If the values of all file attributes are unique, you could also create save IDs with generate-id():
<xsl:template match="portion">
...
<a href="#{generate-id(portion-photo)}">
<xsl:value-of select="portion-photo/#file"/>
</a>
...
</xsl:template>
<xsl:template match="portion-photo">
<a name="{generate-id()}">
<xsl:value-of select="#file"/>
</a>
</xsl:template>

avoid mismatched tags outputting HTML with XSLT

I'm new to XSLT, and there's one specific thing I don't know how to do, despite hours of searching for the answer.
I'm outputting blocks of HTML (result sets), and sometimes the result is a hyperlink, sometimes it is not.
The simple flow looks like this:
<a...> if #url
some HTML code
</a> if #url
But if I do:
when #url
<a...>
/when
some HTML code
when #url
</a>
/when
... I'm told that I have mismatched tags.
I was using CDATA text for the anchor set, but a lot of messages say that this is a "hack" approach.
I'm trying to avoid having to repeat the entire HTML code block only to include the anchors on only one of them.
How do I do this?
-------edit / additional info-----------
Does this make more sense?
<xsl:template match="Row">
<xsl:choose>
<xsl:when test="#url!=''">
<a><xsl:attribute name="href"><xsl:value-of select="#url" /></xsl:attribute>
</xsl:when>
</xsl:choose>
<img />
<xsl:choose>
<xsl:when test="#url!=''">
</a>
</xsl:when>
</xsl:choose>
</xsl:template>
In XSLT, your output is a tree of nodes. Writing an element node is a single atomic operation; it can't be split into separate operations of writing a start tag and writing an end tag. You can't create half a node.
If you do try to treat <a> and </a> as separate and separable operations, you will get this error, because the stylesheet must be well-formed XML.
So, stand back and explain what you are trying to achieve, and then we can tell you how to achieve it properly in XSLT.
One way to refactor the XSLT to conditionally apply the hyperlink and not repeat the logic to produce the <img/> (or whatever more complex logic you are trying to avoid repeating) is to extract that logic out into a different template(s) as either a named template or a template with a #mode.
For instance:
<xsl:template match="Row">
<xsl:choose>
<xsl:when test="#url!=''">
<a>
<xsl:attribute name="href">
<xsl:value-of select="#url"/>
</xsl:attribute>
<xsl:apply-templates select="." mode="image"/>
</a>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="." mode="image"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<!--The "common" logic to produce an image element, whether or not it will be surrounded by an anchor linking to the #url -->
<xsl:template match="Row" mode="image">
<img/>
</xsl:template>
An alternative way of accomplishing the same thing, but using templates instead of <xsl:choose>:
<xsl:template match="Row[#url]">
<a href="#url">
<xsl:apply-templates select="." mode="image"/>
</a>
</xsl:template>
<xsl:template match="Row">
<xsl:apply-templates select="." mode="image"/>
</xsl:template>
<xsl:template match="Row" mode="image">
<img/>
</xsl:template>