I need to copy from input document to output document all attributes but one.
My input is like this:
<mylink id="nextButton" type="next" href="javascript:;" />
And I need output like this:
<a id="nextButton" href="javascript:;" />
If I use the following XSL:
<xsl:template match="mylink">
<a><xsl:copy-of select="attribute::*"/></a>
</xsl:template>
I get all attributes to output like this:
<a id="nextButton" type="next" href="javascript:;" />
But I want to ignore the "type" attribute.
I've tried the following but none of them seems to work the way I need:
<xsl:copy-of select="attribute::!type"/>
<xsl:copy-of select="attribute::!'type'"/>
<xsl:copy-of select="attribute::*[!type]"/>
<xsl:copy-of select="attribute::not(type)"/>
How should I write my stylesheet to get needed output?
Shortest form:
<xsl:template match="mylink">
<a><xsl:copy-of select="#*[name()!='type']"/></a>
</xsl:template>
Longer one (that's the first thing I came up with, I leave it for reference):
<xsl:template match="mylink">
<a>
<xsl:for-each select="#*">
<xsl:if test="name() != 'type'">
<xsl:attribute name="{name()}"><xsl:value-of select="."/></xsl:attribute>
</xsl:if>
</xsl:for-each>
</a>
</xsl:template>
In XSLT 2.0:
<xsl:template match="mylink">
<a><xsl:copy-of select="#* except #type"/></a>
</xsl:template>
Related
Kindly help me to wrap the img.inline element with the following sibling text comma (if comma exists):
text <img id="1" class="inline" src="1.jpg"/> another text.
text <img id="2" class="inline" src="2.jpg"/>, another text.
Should be changed to:
text <img id="1" class="inline" src="1.jpg"/> another text.
text <span class="img-wrap"><img id="2" class="inline" src="2.jpg"/>,</span> another text.
Currently, my XSLT will wrap the img.inline element and add comma inside the span, now I want to remove the following comma.
text <span class="img-wrap"><img id="2" class="inline" src="2.jpg"/>,</span>
, <!--remove this extra comma--> another text.
My XSLT:
<xsl:template match="//img[#class='inline']">
<xsl:copy>
<xsl:choose>
<xsl:when test="starts-with(following-sibling::text(), ',')">
<span class="img-wrap">
<xsl:apply-templates select="node()|#*"/>
<xsl:text>,</xsl:text>
</span>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="node()|#*"/>
</xsl:otherwise>
</xsl:choose>
</xsl:copy>
<!-- checking following-sibling::text() -->
<xsl:apply-templates select="following-sibling::text()" mode="commatext"/>
</xsl:template>
<!-- here I want to match the following text, if comma, then remove it -->
<xsl:template match="the following comma" mode="commatext">
<!-- remove comma -->
</xsl:template>
Is my approach is correct? or is this something should be handled differently? pls suggest?
Currently you are copying the img and the embedding the span within that. Also, you do <xsl:apply-templates select="node()|#*"/> which will select child nodes of img (or which there are none). And for the attributes it will end add them to the span.
You don't actually need the xsl:choose here as you can add the condition to the match attribute.
<xsl:template match="//img[#class='inline'][starts-with(following-sibling::node()[1][self::text()], ',')]">
Note I have changed the condition as following-sibling::text() selects ALL text elements that follow the img node. You only want to get the node immediately after the img node, but only if it is a text node.
Also, trying to select the following text node with xsl:apply-templates is probably not the right approach, assuming you have a template that matches the parent node which selects all child nodes (not just img ones). I am assuming you were using the identity template here.
Anyway, try this XSLT instead
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" indent="no" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="//img[#class='inline'][starts-with(following-sibling::node()[1][self::text()], ',')]">
<span class="img-wrap">
<xsl:copy-of select="." />
<xsl:text>,</xsl:text>
</span>
</xsl:template>
<xsl:template match="text()[starts-with(., ',')][preceding-sibling::node()[1][self::img]/#class='inline']">
<xsl:value-of select="substring(., 2)" />
</xsl:template>
</xsl:stylesheet>
I've got the following template (excerpt):
<xsl:template match="section[#visible='1']">
<dl>
<dt><xsl:call-template name="content"/></dt>
<xsl:apply-templates select="(page|file)[#visible='1']" />
<xsl:apply-templates select="section[#visible=1]" mode="child" />
</dl>
</xsl:template>
<xsl:template match="section[#visible='1']" mode="child">
<dd><xsl:apply-templates select="." /></dd>
</xsl:template>
My problem is with the two apply-template elements at the end. The source XML elements (page, file, section,...) all have a pos attribute containing a number, which defines when they should be added to the output. But the way I have it currently, prevents a section with a lower pos value to be displayed before a page element with a higher position for example.
How can I achieve that? I've tried this:
<xsl:template match="section[#visible='1']">
<dl>
<dt><xsl:call-template name="content"/></dt>
<xsl:call-template name="kids"/>
</dl>
</xsl:template>
<xsl:template name="kids">
<xsl:for-each select="node()">
<xsl:sort select="#pos"/>
<!-- what would go here? -->
</xsl:for-each>
</xsl:template>
But I don't know what to put into the for-each loop. I could just duplicate the existing 2 templates, slap a name on them, and then call them with the current node as parameter, but that wouldn't be DRY. There must be a better way.
Have you tried this?
<xsl:template match="section[#visible='1']">
<dl>
<dt><xsl:call-template name="content"/></dt>
<xsl:apply-templates select="(page|file|section)[#visible='1']" mode="m">
<xsl:sort select="#pos"/>
</xsl:apply-templates>
</dl>
</xsl:template>
<xsl:template match="*" mode="m">
<xsl:apply-templates select="."/>
</xsl:template>
<xsl:template match="section" mode="m">
<xsl:apply-templates select="." mode="child"/>
</xsl:template>
This is my XSLT file:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:template match="/">
<xsl:for-each select="//child_4331">
<xsl:value-of select="*"/>
<xsl:value-of select="#value" />
<xsl:attribute name="onclick">
<xsl:call-template name="GetOnClickJavaScript" />
</xsl:attribute>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
How can I set the click event on child_4331 value?
You didn't say, but I'm assuming you want to copy the child_4331 element and add the onclick attribute.
I would get rid of the template matching '/' and create one to match 'child_4331'. Use xsl:copy to create a copy of the element and add the attribute inside it. If the child_4331 element has attributes or child elements you will want to use xsl:apply-templates to pick them up.
Here is a sample snippet. Your solution may vary depending on your desired output. I can't give you more without knowing what your source XML looks like and what you expect to see in the result.
<xsl:template match="child_4331">
<xsl:copy>
<xsl:attribute name="onclick">
<xsl:call-template name="GetOnClickJavaScript" />
</xsl:attribute>
</xsl:copy>
</xsl:template>
How do you write element attributes in a specific order without writing it explicitly?
Consider:
<xsl:template match="Element/#1|#2|#3|#4">
<xsl:if test="string(.)">
<span>
<xsl:value-of select="."/><br/>
</span>
</xsl:if>
</xsl:template>
The attributes should appear in the order 1, 2, 3, 4. Unfortunately, you can't guarantee the order of attributes in XML, it could be <Element 2="2" 4="4" 3="3" 1="1">
So the template above will produce the following:
<span>2</span>
<span>4</span>
<span>3</span>
<span>1</span>
Ideally I don't want to test each attribute if it has got a value. I was wondering if I can somehow set an order of my display? Or will I need to do it explicitly and repeating the if test as in:
<xsl:template match="Element">
<xsl:if test="string(./#1)>
<span>
<xsl:value-of select="./#1"/><br/>
</span>
</xsl:if>
...
<xsl:if test="string(./#4)>
<span>
<xsl:value-of select="./#4"/><br/>
</span>
</xsl:if>
</xsl:template>
What can be done in this case?
In an earlier question you seemed to use XSLT 2.0 so I hope this time too an XSLT 2.0 solution is possible.
The order is not determined in the match pattern of a template, rather it is determined when you do xsl:apply-templates. So (with XSLT 2.0) you can simply write a sequence of the attributes in the order you want e.g. <xsl:apply-templates select="#att2, #att1, #att3"/> will process the attributes in that order.
XSLT 1.0 doesn't have sequences, only node-sets. To produce the same result, use xsl:apply-templates in the required order, such as:
<xsl:apply-templates select="#att2"/>
<xsl:apply-templates select="#att1"/>
<xsl:apply-templates select="#att3"/>
Do not produce XML that relies on the order of the attributes. This is very brittle and I would consider it bad style, to say the least. XML was not designed in that way; <elem a="1" b="2" /> and <elem a="1" b="2" /> are explicitly equivalent.
If you want ordered output, order your output (instead of relying on ordered input).
Furthermore, match="Element/#1|#2|#3|#4" is not equivalent to match="Element/#1|Element/#2|Element/#3|Element/#4", but I'm sure you mean the latter.
That being said, you can do:
<xsl:template match="Element/#1|Element/#2|Element/#3|Element/#4">
<xsl:if test="string(.)">
<span>
<xsl:value-of select="."/><br/>
</span>
</xsl:if>
</xsl:template>
<xsl:template match="Element">
<xsl:apply-templates select="#1|#2|#3|#4">
<!-- order your output... -->
<xsl:sort select="name()" />
</xsl:apply-templates>
</xsl:template>
EDIT: I'll take it as read that #1 etc are just examples, because names cannot actually start with a number in XML.
I'd use xsl:sort on the local-name of the attribute to get the result you want. I'd also use a different mode so the results don't get called by accident somewhere else.
<xsl:stylesheet version="1.1" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="Element">
<xsl:apply-templates select="#*" mode="sorted">
<xsl:sort select="local-name()" />
</xsl:apply-templates>
</xsl:template>
<xsl:template match="Element/#a|#b|#c|#d" mode="sorted">
<xsl:if test="string(.)">
<span>
<xsl:value-of select="."/><br/>
</span>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
The clue was is the answer by Martin Honnen
To copy attributes and conditionally add a new attribute to the end of the list of attributes.
Add rel="noopener noreferrer" to all external links.
<xsl:template match="a">
<xsl:copy>
<xsl:if test="starts-with(./#href,'http')">
<xsl:apply-templates select="./#*"/>
<!-- Insert rel as last node -->
<xsl:attribute name="rel">noopener noreferrer</xsl:attribute>
</xsl:if>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="a/#href|a/#target|a/#rel">
<!--
Allowed attribute on anchor
-->
<xsl:attribute name="{name()}">
<xsl:value-of select="."></xsl:value-of>
</xsl:attribute>
</xsl:template>
You can also specify the attribute sequence by calling apply templates with each select in the order you want.
<xsl:template match="a">
<xsl:copy>
<xsl:if test="starts-with(./#href,'http')">
<xsl:apply-templates select="./#id"/>
<xsl:apply-templates select="./#href"/>
<xsl:apply-templates select="./#target"/>
<!-- Insert rel as last node -->
<xsl:attribute name="rel">noopener noreferrer</xsl:attribute>
</xsl:if>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
I'm trying to have an XSLT that copies most of the tags but removes empty "<b/>" tags. That is, it should copy as-is "<b> </b>" or "<b>toto</b>" but completely remove "<b/>".
I think the template would look like :
<xsl:template match="b">
<xsl:if test=".hasChildren()">
<xsl:element name="b">
<xsl:apply-templates/>
</xsl:element>
</xsl:if>
</xsl:template>
But of course, the "hasChildren()" part doesn't exist ... Any idea ?
dsteinweg put me on the right track ... I ended up doing :
<xsl:template match="b">
<xsl:if test="./* or ./text()">
<xsl:element name="b">
<xsl:apply-templates/>
</xsl:element>
</xsl:if>
</xsl:template>
This transformation ignores any <b> elements that do not have any node child. A node in this context means an element, text, comment or processing instruction node.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="b[not(node()]"/>
</xsl:stylesheet>
Notice that here we use one of the most fundamental XSLT design patterns -- using the identity transform and overriding it for specific nodes.
The overriding template will be selected only for nodes that are elements named "b" and do not have (any nodes as) children. This template is empty (does not have any contents), so the effect of its application is that the matching node is ignored/discarded and is not reproduced in the output.
This technique is very powerful and is widely used for such tasks and also for renaming, changing the contents or attributes, adding children or siblings to any specific node that can be matched (avery type of node with the exception of a namespace node can be used as a match pattern in the "match" attribute of <xsl:template/>
Hope this helped.
Cheers,
Dimitre Novatchev
I wonder if this will work?
<xsl:template match="b">
<xsl:if test="b/text()">
...
See if this will work.
<xsl:template match="b">
<xsl:if test=".!=''">
<xsl:element name="b">
<xsl:apply-templates/>
</xsl:element>
</xsl:if>
</xsl:template>
An alternative would be to do the following:
<xsl:template match="b[not(text())]" />
<xsl:template match="b">
<b>
<xsl:apply-templates/>
</b>
</xsl:template>
You could put all the logic in the predicate, and set up a template to match only what you want and delete it:
<xsl:template match="b[not(node())] />
This assumes that you have an identity template later on in the transform, which it sounds like you do. That will automatically copy any "b" tags with content, which is what you want:
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
Edit: Now uses node() like Dimitri, below.
If you have access to update the original XML, you could try using use xml:space=preserve on the root element
<html xml:space="preserve">
...
</html>
This way, the space in the empty <b> </b> tag is preserved, and so can be distinguished from <b /> in the XSLT.
<xsl:template match="b">
<xsl:if test="text() != ''">
....
</xsl:if>
</xsl:template>