Reorder users in django auth - django

I have a model that has a ForeignKey to the built-in user model in django.contrib.auth and I'm frustrated by the fact the select box in the admin always sorts by the user's primary key.
I'd much rather have it sort by username alphabetically, and while it's my instinct not to want to fiddle with the innards of Django, I can't seem to find a simpler way to reorder the users.
The most straightforward way I can think of would be to dip into my Django install and add
ordering = ('username',)
to the Meta class of the User model.
Is there some kind of monkeypatching that I could do or any other less invasive way to modify the ordering of the User model?
Alternatively, can anyone thing of anything that could break by making this change?

There is a way using ModelAdmin objects to specify your own form. By specifying your own form, you have complete control over the form's composition and validation.
Say that the model which has an FK to User is Foo.
Your myapp/models.py might look like this:
from django.db import models
from django.contrib.auth.models import User
class Foo(models.Model):
user = models.ForeignKey(User)
some_val = models.IntegerField()
You would then create a myapp/admin.py file containing something like this:
from django.contrib.auth.models import User
from django import forms
from django.contrib import admin
class FooAdminForm(forms.ModelForm):
user = forms.ModelChoiceField(queryset=User.objects.order_by('username'))
class Meta:
model = Foo
class FooAdmin(admin.ModelAdmin):
form = FooAdminForm
admin.site.register(Foo, FooAdmin)
Once you've done this, the <select> dropdown will order the user objects according to username. No need to worry about to other fields on Foo... you only need to specify the overrides in your FooAdminForm class. Unfortunately, you'll need to provide this custom form definition for every model having an FK to User that you wish to present in the admin site.

Jarret's answer above should actually read:
from django.contrib.auth.models import User
from django.contrib import admin
from django import forms
from yourapp.models import Foo
class FooAdminForm(forms.ModelForm):
class Meta:
model = Foo
def __init__(self, *args, **kwds):
super(FooAdminForm, self).__init__(*args, **kwds)
self.fields['user'].queryset = User.objects.order_by(...)
class FooAdmin(admin.ModelAdmin):
# other stuff here
form = FooAdminForm
admin.site.register(Foo, FooAdmin)
so the queryset gets re-evaluated each time you create the form, as opposed to once, when the module containing the form is imported.

Related

Difference between get_user_model() and importing User from auth

When I need to use the current user in a model.
lets say I have a model with a current_user field, something like:
class MyModel(models.Model):
user = models.ForeignKey(User,on_delete=models.CASCADE,default=None)
my understanding is User can be fetched either:
1)by importing the current user:
from django.contrib.auth.models import User
or
2) setting User to:
from django.contrib.auth import get_user_model
User = get_user_model()
I understand both will work if I am not wrong!!
So What is the main difference between those two methods if there is any?
Thanks
If you are using the default User model, both approaches will work.
However if you are using a custom user model (or are writing a reusable app), then you should use get_user_model() to ensure you get the correct model.
Note that the docs suggest you use settings.AUTH_USER_MODEL in foreign keys.
class MyModel(models.Model):
user = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE,default=None)

Extending User profile in Django 1.7

I know, this question has been already asked many times in SO, but most of the answers I read were either outdated (advising the now deprecated AUTH__PROFILE_MODULE method), or were lacking of a concrete example.
So, I read the Django documentation [1,2], but I lack a real example on how to use it properly.
In fact, my problem comes when a new user is created (or updated) through a form. The user is obviously created but, the fields from the extension are all unset. I know that the Django documentation is stating that:
These profile models are not special in any way - they are just Django models that happen to have a one-to-one link with a User model. As such, they do not get auto created when a user is created, but a django.db.models.signals.post_save could be used to create or update related models as appropriate.
But, I don't know how to do it in practice (should I add a a receiver and if 'yes', which one).
For now, I have the following (taken from the documentation for the sake of brevity):
File models.py
from django.contrib.auth.models import User
class Employee(models.Model):
user = models.OneToOneField(User)
department = models.CharField(max_length=100)
File admin.py
from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User
from my_user_profile_app.models import Employee
# Define an inline admin descriptor for Employee model
class EmployeeInline(admin.StackedInline):
model = Employee
can_delete = False
verbose_name_plural = 'employee'
# Define a new User admin
class UserAdmin(UserAdmin):
inlines = (EmployeeInline, )
# Re-register UserAdmin
admin.site.unregister(User)
admin.site.register(User, UserAdmin)
File forms.py
class SignupForm(account.forms.SignupForm):
department = forms.CharField(label="Department", max_length=100)
class SettingsForm(account.forms.SignupForm):
department = forms.CharField(label="Department", max_length=100)
Then, in my code, I use it like this:
u = User.objects.get(username='fsmith')
freds_department = u.employee.department
But, Signup and Settings forms do not operates as expected and new values for the departement is not recorded.
Any hint is welcome !
I have looked at all the answers but none does really hold the solution for my problem (though some of you gave me quite good hints for looking in the right direction). I will summarize here the solution I have found to solve my problem.
First of all, I have to admit I didn't tell everything about my problem. I wanted to insert extra fields in the User model and use other apps such as the default authentication scheme of Django. So, extending the default User by inheritance and setting AUTH_USER_MODEL was a problem because the other Django applications were stopping to work properly (I believe they didn't use user = models.OneToOneField(settings.AUTH_USER_MODEL) but user = models.OneToOneField(User)).
As, it would have been too long to rewrite properly the other applications I am using, I decided to add this extra field through a One-to-One field. But, the documentation miss several points that I would like to fill in the following.
So, here is a complete example of adding an extra field to the User model with other applications using the same model.
First, write the description of the model gathering the extra fields that you want to add to your models.py file:
from django.contrib.auth.models import User
class UserProfile(models.Model):
user = models.OneToOneField(User)
extra_field = models.CharField(max_length=100)
Then, we need to trigger the addition of an object UserProfile each time a User is created. This is done through attaching this code to the proper signal in the receiver.py file:
from django.contrib.auth.models import User
from django.db.models.signals import post_save
from django.dispatch import receiver
from my_user_profile_app.models import UserProfile
#receiver(post_save, sender=User)
def handle_user_save(sender, instance, created, **kwargs):
if created:
UserProfile.objects.create(user=instance)
Now, if you want to be able to modify it through the administration interface, just stack it with the usual UserAdmin form in the admin.py file.
from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User
from my_user_profile_app.models import UserProfile
# Define an inline admin descriptor for UserProfile model
class UserProfileInline(admin.StackedInline):
model = UserProfile
can_delete = False
# Define a new User admin
class UserAdmin(UserAdmin):
inlines = (UserProfileInline, )
# Re-register UserAdmin
admin.site.unregister(User)
admin.site.register(User, UserAdmin)
Then, it is time now to try to mix this extra field with the default Django authentication application. For this, we need to add an extra field to fill in the SignupForm and the SettingsForm through inheritance in the forms.py file:
import account.forms
from django import forms
class SignupForm(account.forms.SignupForm):
extra_field = forms.CharField(label="Extra Field", max_length=100)
class SettingsForm(account.forms.SignupForm):
extra_field = forms.CharField(label="Extra Field", max_length=100)
And, we also need to add some code to display and get properly the data that you have been added to the original User model. This is done through inheritance onto the SignupView and the SettingsView views in the views.py file:
import account.views
from my_user_profile_app.forms import Settings, SignupForm
from my_user_profile_app.models import UserProfile
class SettingsView(account.views.SettingsView):
form_class = SettingsForm
def get_initial(self):
initial = super(SettingsView, self).get_initial()
initial["extra_field"] = self.request.user.extra_field
return initial
def update_settings(self, form):
super(SettingsView, self).update_settings(form)
profile = self.request.user.userprofile
profile.extra_field = form_cleaned_data['extra_field']
profile.save()
class SignupView(account.views.SignupView):
form_class = SignupForm
def after_signup(self, form):
profile = self.created_user.userprofile
profile.extra_field = form_cleaned_data['extra_field']
profile.save()
super(SignupView, self).after_signup(form)
Once everything is in place, it should work nicely (hopefully).
I struggled with this topic for about a year off and on until I finally found a solution I was happy with, and I know exactly what you mean by "there is a lot out there, but it doesn't work". I had tried extending the User model in different ways, I had tried the UserProfile method, and some other 1-off solutions as well.
I finally figured out how to simply extend the AbstractUser class to create my custom user model which has been a great solution for many of my projects.
So, let me clarify one of your comments above, you really shouldn't be creating a link between 2 models, the generally accepted "best" solution is to have one model which is inherited from AbstractUser or AbstractBaseUser depending on your needs.
One tricky thing that got me was that "Extending the User Model" did not get me where I wanted and I needed to Substitute the User Model, which I'm sure you've seen/read multiple times, but possibly not absorbed it (at least I know I didn't).
Once you get the hang of it, there's really not that much code and it's not too complicated either.
# models.py
from django.contrib.auth.models import AbstractUser
from django.db import models
class User(AbstractUser):
'''
Here is your User class which is fully customizable and
based off of the AbstractUser from auth.models
'''
my_custom_field = models.CharField(max_length=20)
def my_custom_model_method(self):
# do stuff
return True
There are a couple things to look out for after this, some of which came up in django 1.7.
First of all, if you want the admin page to look like it did before, you have to use the UserAdmin
# admin.py
from django.contrib import admin
from django.contrib.auth import get_user_model
from django.contrib.auth.admin import UserAdmin
# Register your models here.
admin.site.register(get_user_model(), UserAdmin)
The other thing is that if you're wanting to import the User class in a models file, you have to import it from the settings and not with get_user_model(). If you run into this, it's easy to fix, so I just wanted to give you a heads up.
You can check out my seed project I use to start projects to get a full but simple project that uses a Custom User Model. The User stuff is in the main app.
From there all the Registration and Login stuff works the same way as with a normal Django User, so I won't go into detail on that topic. I hope this helps you as much as it has helped me!
I try to avoid to extend the user model as explained in the django docs.
I use this:
class UserExtension(models.Model):
user=models.OneToOneField(User, primary_key=True)
... your extra model fields come here
Docs of OneToOneField: https://docs.djangoproject.com/en/1.7/topics/db/examples/one_to_one/
I see these benefits:
the same pattern works for other models (e.g. Group)
If you have N apps, every app can extend the model on his own.
Creating the UserExtension should be possible without giving parameters. All fields must have sane defaults.
Then you can create a signal handler which creates UserExtension instances if a user gets created.
I prefer extend the User model. For example:
class UserProfile(User):
def __unicode__(self):
return self.last_name + self.first_name
department = models.CharField(max_length=100)
class SignupForm(forms.Form):
username = forms.CharField(max_length=30)
first_name = forms.CharField(max_length=30)
last_name = forms.CharField(max_length=30)
department = forms.CharField(label="Department", max_length=100)
To save the data
form = UserRegistrationForm(request.POST)
if form.is_valid():
client = UserProfile()
client.username = username
client.set_password(password)
client.first_name = first_name
client.department = department
client.save()
check how are you saving the data after validate the form

Showing more than '__str__' for a Django foreign key field

I've two simple Django model classes,
models.py
from django.db import models
class ParentModel(models.Model):
small_text = models.CharField(max_length=20)
big_text = models.CharField(max_length=500)
def __str__(self):
return self.small_text
class ChildModel(models.Model):
parent = models.ForeignKey(ParentModel)
def __str__(self):
return '%s is my parent' % self.parent
admin.py
from django.contrib import admin
import models
admin.site.register(models.ChildModel)
admin.site.register(models.ParentModel)
So the default view is you see the 'small_text' in a select element in the admin section. What I'd love to be able to do is extend that so that there's another TextArea, or something else I can , underneath the select which changes as you choose a different Daddy.
I've looked into a few different ways to do this, but they all seem hella complicated for what with Django, I'd have thought should be an easy task. Any ideas?
If you're looking to be able to change ChildModel's properties while viewing the ParentModel in the admin, you should look into using an inline in the admin
If you're looking to have additional fields appear when viewing the index page in the admin for a model, then you'll want to add additional properties to the list_display property on the model's admin class.

Dynamical choices in model's field

I want my models to have order field, which will contain order of an item among all items of its kind.
And I want to use choices within that IntegerField, which would contain all the numbers of currently existing items in that table.
So it would need to be dynamic choices.
How do I load all existing "order" values of all existing items in a table, and use this list for choices?
It sounds like you want to build a manager for your model:
models.py
from django.db import models
class OrderManager(models.Manager):
def order_choices(self):
return [(i, i) for i in OrderModel.objects.values_list('order', flat=True)]
class OrderModel(models.Model):
objects = OrderManager()
order = models.IntegerField()
class Meta:
ordering = ['order']
def __unicode__(self):
return '%i' % self.order
forms.py
from django import forms
from yourapp.models import OrderModel
class OrderModelForm(forms.ModelForm):
order = forms.ChoiceField(choices=OrderModel.objects.order_choices())
class Meta:
model = OrderModel
admin.py
from django.contrib import admin
from yourapp.forms import OrderModelForm
from yourapp.models import OrderModel
class OrderModelAdmin(admin.ModelAdmin):
form = OrderModelForm
admin.site.register(OrderModel, OrderModelAdmin)
Edit
Managers are use to make general model queries without having an instance of a model object. If you don't understand the concept of managers, you can still refactor the code out of the manager class, stick it somewhere else and import that function across your code. Managers allow you to abstract custom general queryset that you can reuse. See more details https://docs.djangoproject.com/en/dev/topics/db/managers/
The code without the manager will look like
views.py or some other file
from app.models import OrderModel
def order_choices():
return [(i, i) for i in OrderModel.objects.values_list('order', flat=True)]
From anywhere in your code, if you want to reuse the above multiple times:
from app.views import oder_choices
order_choices()
as opposed to:
from app.models import OderModel
OrderModel.objects.order_choices()
If you only want to use the above once, you can leave it in the forms.py as shown in the other answer. It's really up to you on how you want to refactor your code.
Dont add the choices directly to the model, add them to a form represnting the model later, by overriding the field with a set of choices.
than, do something like:
class MyForm(..):
myfield_order_field = IntegerField(choices = [(i,i) for range(MyModel.objects.count)])
class Meta():
model = MyModel
if you want to use it in the admin, add to your Admin Class:
class MyModelAdmin(admin.ModelAdmin):
...
form = MyForm
it will override this field in the admin too.

django - Joining LogEntry to actual models

so i'm using the admin LogEntry object/table to log events in my app. I have a view where i'd like to display each LogEntry.
It would be really great if i could join the LogEntry with the actual objects they represent (so i can display attributes of the object inline with the log entry)
In theory this should be easy as we have the model type and id from the LogEntry but i can't figure out how to join them using a queryset.
i thought i could just grab all the ids of the different objects and make another dictionary for each object type and then join them somehow (maybe zip the lists together?) but that seems dumb and not very djano-ish/pythonic.
does anybody have better suggestions?
** edit **
just want to clarify am not looking to use admin, but roll a custom view and template.
As I know Django uses contenttypes framework to perform logging in admin. So you should create generic relation inside your model and then to show inlines in admin use GenericTabularInline and GenericStackedInline. Please consult with the article.
from django.contrib import admin
from django.contrib.admin.models import LogEntry
from django.contrib.contenttypes.generic import GenericTabularInline
from django import forms
from some_app import models
from some_app.models import Item
class LogForm(forms.ModelForm):
class Meta:
model = LogEntry
class LogInline(GenericTabularInline):
ct_field = 'content_type'
ct_fk_field = 'object_id'
model = LogEntry
extra = 0
class ItemForm(forms.ModelForm):
class Meta:
model = Item
class ItemAdmin(admin.ModelAdmin):
form = ItemForm
inlines = [LogInline,]
admin.site.register(models.Item, ItemAdmin)
and you add to Item:
class Item(models.Model):
name = models.CharField(max_length=100)
logs = generic.GenericRelation(LogEntry)
this change won't create anything in your database, so there is no need to sync
Recent Django versions require to create a proxy for LogEntry:
from django.contrib import admin
from django.contrib.admin.models import LogEntry
from django.contrib.contenttypes.generic import GenericTabularInline
class LogEntryProxy(LogEntry):
content_object = GenericForeignKey('content_type', 'object_id')
class Meta:
proxy = True
class LogInline(GenericTabularInline):
model = LogEntry
extra = 0
class ItemAdmin(admin.ModelAdmin):
inlines = [LogInline,]
admin.site.register(models.Item, ItemAdmin)