Date/time conversion: string representation to time_t [closed] - c++

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How do I convert a date string, formatted as "MM-DD-YY HH:MM:SS", to a time_t value in either C or C++?

Answer 1

Use strptime() to parse the time into a struct tm, then use mktime() to convert to a time_t.

Answer 2

In the absence of strptime you could use sscanf to parse the data into a struct tm and then call mktime. Not the most elegant solution but it would work.

Answer 3

Boost's date time library should help; in particular you might want to look at http://www.boost.org/doc/libs/1_37_0/doc/html/date_time/date_time_io.html

Answer 4

Note that strptime mentioned in accepted answer is not portable. Here's handy C++11 code I use to convert string to std::time_t :
static std::time_t to_time_t(const std::string& str, bool is_dst = false, const std::string& format = "%Y-%b-%d %H:%M:%S")
{
std::tm t = {0};
t.tm_isdst = is_dst ? 1 : 0;
std::istringstream ss(str);
ss >> std::get_time(&t, format.c_str());
return mktime(&t);
}
You can call it like this:
std::time_t t = to_time_t("2018-February-12 23:12:34");
You can find string format parameters here.

Answer 5

I'm afraid there isn't any in Standard C / C++ . There is the POSIX function strptime which can convert to struct tm, which can then be converted to time_t using mktime.
If you are aiming for cross platform compatibility, better use boost::date_time, which has sophisticated functions for this.

Answer 6

best way to convert a date string, formatted as "MM-DD-YY HH:MM:SS", to a time_t
Restricting code to standard C library functions is looking for the inverse of strftime(). To expand #Rob general idea, uses sscanf().
Use "%n" to detect completed scan
time_t date_string_to_time(const char *date) {
struct tm tm = { 0 }; // Important, initialize all members
int n = 0;
sscanf(date, "%d-%d-%d %d:%d:%d %n", &tm.tm_mon, &tm.tm_mday, &tm.tm_year,
&tm.tm_hour, &tm.tm_min, &tm.tm_sec, &n);
// If scan did not completely succeed or extra junk
if (n == 0 || date[n]) {
return (time_t) -1;
}
tm.tm_isdst = -1; // Assume local daylight setting per date/time
tm.tm_mon--; // Months since January
// Assume 2 digit year if in the range 2000-2099, else assume year as given
if (tm.tm_year >= 0 && tm.tm_year < 100) {
tm.tm_year += 2000;
}
tm.tm_year -= 1900; // Years since 1900
time_t t = mktime(&tm);
return t;
}
Additional code could be used to insure only 2 digit timestamp parts, positive values, spacing, etc.
Note: this assume the "MM-DD-YY HH:MM:SS" is a local time.

Answer 7

static time_t MKTimestamp(int year, int month, int day, int hour, int min, int sec)
{
time_t rawtime;
struct tm * timeinfo;
time ( &rawtime );
timeinfo = gmtime ( &rawtime );
timeinfo->tm_year = year-1900 ;
timeinfo->tm_mon = month-1;
timeinfo->tm_mday = day;
timeinfo->tm_hour = hour;
timeinfo->tm_min = min;
timeinfo->tm_sec = sec;
timeinfo->tm_isdst = 0; // disable daylight saving time
time_t ret = mktime ( timeinfo );
return ret;
}
static time_t GetDateTime(const std::string pstr)
{
try
{
// yyyy-mm-dd
int m, d, y, h, min;
std::istringstream istr (pstr);
istr >> y;
istr.ignore();
istr >> m;
istr.ignore();
istr >> d;
istr.ignore();
istr >> h;
istr.ignore();
istr >> min;
time_t t;
t=MKTimestamp(y,m,d,h-1,min,0);
return t;
}
catch(...)
{
}
}