I'm trying to write a regular expression that validates a date. The regex needs to match the following
M/D/YYYY
MM/DD/YYYY
Single digit months can start with a leading zero (eg: 03/12/2008)
Single digit days can start with a leading zero (eg: 3/02/2008)
CANNOT include February 30 or February 31 (eg: 2/31/2008)
So far I have
^(([1-9]|1[012])[-/.]([1-9]|[12][0-9]|3[01])[-/.](19|20)\d\d)|((1[012]|0[1-9])(3[01]|2\d|1\d|0[1-9])(19|20)\d\d)|((1[012]|0[1-9])[-/.](3[01]|2\d|1\d|0[1-9])[-/.](19|20)\d\d)$
This matches properly EXCEPT it still includes 2/30/2008 & 2/31/2008.
Does anyone have a better suggestion?
Edit: I found the answer on RegExLib
^((((0[13578])|([13578])|(1[02]))[\/](([1-9])|([0-2][0-9])|(3[01])))|(((0[469])|([469])|(11))[\/](([1-9])|([0-2][0-9])|(30)))|((2|02)[\/](([1-9])|([0-2][0-9]))))[\/]\d{4}$|^\d{4}$
It matches all valid months that follow the MM/DD/YYYY format.
Thanks everyone for the help.
This is not an appropriate use of regular expressions. You'd be better off using
[0-9]{2}/[0-9]{2}/[0-9]{4}
and then checking ranges in a higher-level language.
Here is the Reg ex that matches all valid dates including leap years. Formats accepted mm/dd/yyyy or mm-dd-yyyy or mm.dd.yyyy format
^(?:(?:(?:0?[13578]|1[02])(\/|-|\.)31)\1|(?:(?:0?[1,3-9]|1[0-2])(\/|-|\.)(?:29|30)\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:0?2(\/|-|\.)29\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$
courtesy Asiq Ahamed
I landed here because the title of this question is broad and I was looking for a regex that I could use to match on a specific date format (like the OP). But I then discovered, as many of the answers and comments have comprehensively highlighted, there are many pitfalls that make constructing an effective pattern very tricky when extracting dates that are mixed-in with poor quality or non-structured source data.
In my exploration of the issues, I have come up with a system that enables you to build a regular expression by arranging together four simpler sub-expressions that match on the delimiter, and valid ranges for the year, month and day fields in the order you require.
These are :-
Delimeters
[^\w\d\r\n:]
This will match anything that is not a word character, digit character, carriage return, new line or colon. The colon has to be there to prevent matching on times that look like dates (see my test Data)
You can optimise this part of the pattern to speed up matching, but this is a good foundation that detects most valid delimiters.
Note however; It will match a string with mixed delimiters like this 2/12-73 that may not actually be a valid date.
Year Values
(\d{4}|\d{2})
This matches a group of two or 4 digits, in most cases this is acceptable, but if you're dealing with data from the years 0-999 or beyond 9999 you need to decide how to handle that because in most cases a 1, 3 or >4 digit year is garbage.
Month Values
(0?[1-9]|1[0-2])
Matches any number between 1 and 12 with or without a leading zero - note: 0 and 00 is not matched.
Date Values
(0?[1-9]|[12]\d|30|31)
Matches any number between 1 and 31 with or without a leading zero - note: 0 and 00 is not matched.
This expression matches Date, Month, Year formatted dates
(0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](0?[1-9]|1[0-2])[^\w\d\r\n:](\d{4}|\d{2})
But it will also match some of the Year, Month Date ones. It should also be bookended with the boundary operators to ensure the whole date string is selected and prevent valid sub-dates being extracted from data that is not well-formed i.e. without boundary tags 20/12/194 matches as 20/12/19 and 101/12/1974 matches as 01/12/1974
Compare the results of the next expression to the one above with the test data in the nonsense section (below)
\b(0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](0?[1-9]|1[0-2])[^\w\d\r\n:](\d{4}|\d{2})\b
There's no validation in this regex so a well-formed but invalid date such as 31/02/2001 would be matched. That is a data quality issue, and as others have said, your regex shouldn't need to validate the data.
Because you (as a developer) can't guarantee the quality of the source data you do need to perform and handle additional validation in your code, if you try to match and validate the data in the RegEx it gets very messy and becomes difficult to support without very concise documentation.
Garbage in, garbage out.
Having said that, if you do have mixed formats where the date values vary, and you have to extract as much as you can; You can combine a couple of expressions together like so;
This (disastrous) expression matches DMY and YMD dates
(\b(0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](0?[1-9]|1[0-2])[^\w\d\r\n:](\d{4}|\d{2})\b)|(\b(0?[1-9]|1[0-2])[^\w\d\r\n:](0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](\d{4}|\d{2})\b)
BUT you won't be able to tell if dates like 6/9/1973 are the 6th of September or the 9th of June. I'm struggling to think of a scenario where that is not going to cause a problem somewhere down the line, it's bad practice and you shouldn't have to deal with it like that - find the data owner and hit them with the governance hammer.
Finally, if you want to match a YYYYMMDD string with no delimiters you can take some of the uncertainty out and the expression looks like this
\b(\d{4})(0[1-9]|1[0-2])(0[1-9]|[12]\d|30|31)\b
But note again, it will match on well-formed but invalid values like 20010231 (31th Feb!) :)
Test data
In experimenting with the solutions in this thread I ended up with a test data set that includes a variety of valid and non-valid dates and some tricky situations where you may or may not want to match i.e. Times that could match as dates and dates on multiple lines.
I hope this is useful to someone.
Valid Dates in various formats
Day, month, year
2/11/73
02/11/1973
2/1/73
02/01/73
31/1/1973
02/1/1973
31.1.2011
31-1-2001
29/2/1973
29/02/1976
03/06/2010
12/6/90
month, day, year
02/24/1975
06/19/66
03.31.1991
2.29.2003
02-29-55
03-13-55
03-13-1955
12\24\1974
12\30\1974
1\31\1974
03/31/2001
01/21/2001
12/13/2001
Match both DMY and MDY
12/12/1978
6/6/78
06/6/1978
6/06/1978
using whitespace as a delimiter
13 11 2001
11 13 2001
11 13 01
13 11 01
1 1 01
1 1 2001
Year Month Day order
76/02/02
1976/02/29
1976/2/13
76/09/31
YYYYMMDD sortable format
19741213
19750101
Valid dates before Epoch
12/1/10
12/01/660
12/01/00
12/01/0000
Valid date after 2038
01/01/2039
01/01/39
Valid date beyond the year 9999
01/01/10000
Dates with leading or trailing characters
12/31/21/
31/12/1921AD
31/12/1921.10:55
12/10/2016 8:26:00.39
wfuwdf12/11/74iuhwf
fwefew13/11/1974
01/12/1974vdwdfwe
01/01/99werwer
12321301/01/99
Times that look like dates
12:13:56
13:12:01
1:12:01PM
1:12:01 AM
Dates that runs across two lines
1/12/19
74
01/12/19
74/13/1946
31/12/20
08:13
Invalid, corrupted or nonsense dates
0/1/2001
1/0/2001
00/01/2100
01/0/2001
0101/2001
01/131/2001
31/31/2001
101/12/1974
56/56/56
00/00/0000
0/0/1999
12/01/0
12/10/-100
74/2/29
12/32/45
20/12/194
2/12-73
Maintainable Perl 5.10 version
/
(?:
(?<month> (?&mon_29)) [\/] (?<day>(?&day_29))
| (?<month> (?&mon_30)) [\/] (?<day>(?&day_30))
| (?<month> (?&mon_31)) [\/] (?<day>(?&day_31))
)
[\/]
(?<year> [0-9]{4})
(?(DEFINE)
(?<mon_29> 0?2 )
(?<mon_30> 0?[469] | (11) )
(?<mon_31> 0?[13578] | 1[02] )
(?<day_29> 0?[1-9] | [1-2]?[0-9] )
(?<day_30> 0?[1-9] | [1-2]?[0-9] | 30 )
(?<day_31> 0?[1-9] | [1-2]?[0-9] | 3[01] )
)
/x
You can retrieve the elements by name in this version.
say "Month=$+{month} Day=$+{day} Year=$+{year}";
( No attempt has been made to restrict the values for the year. )
To control a date validity under the following format :
YYYY/MM/DD or YYYY-MM-DD
I would recommand you tu use the following regular expression :
(((19|20)([2468][048]|[13579][26]|0[48])|2000)[/-]02[/-]29|((19|20)[0-9]{2}[/-](0[4678]|1[02])[/-](0[1-9]|[12][0-9]|30)|(19|20)[0-9]{2}[/-](0[1359]|11)[/-](0[1-9]|[12][0-9]|3[01])|(19|20)[0-9]{2}[/-]02[/-](0[1-9]|1[0-9]|2[0-8])))
Matches
2016-02-29 | 2012-04-30 | 2019/09/31
Non-Matches
2016-02-30 | 2012-04-31 | 2019/09/35
You can customise it if you wants to allow only '/' or '-' separators.
This RegEx strictly controls the validity of the date and verify 28,30 and 31 days months, even leap years with 29/02 month.
Try it, it works very well and prevent your code from lot of bugs !
FYI : I made a variant for the SQL datetime. You'll find it there (look for my name) : Regular Expression to validate a timestamp
Feedback are welcomed :)
Sounds like you're overextending regex for this purpose. What I would do is use a regex to match a few date formats and then use a separate function to validate the values of the date fields so extracted.
Perl expanded version
Note use of /x modifier.
/^(
(
( # 31 day months
(0[13578])
| ([13578])
| (1[02])
)
[\/]
(
([1-9])
| ([0-2][0-9])
| (3[01])
)
)
| (
( # 30 day months
(0[469])
| ([469])
| (11)
)
[\/]
(
([1-9])
| ([0-2][0-9])
| (30)
)
)
| ( # 29 day month (Feb)
(2|02)
[\/]
(
([1-9])
| ([0-2][0-9])
)
)
)
[\/]
# year
\d{4}$
| ^\d{4}$ # year only
/x
Original
^((((0[13578])|([13578])|(1[02]))[\/](([1-9])|([0-2][0-9])|(3[01])))|(((0[469])|([469])|(11))[\/](([1-9])|([0-2][0-9])|(30)))|((2|02)[\/](([1-9])|([0-2][0-9]))))[\/]\d{4}$|^\d{4}$
if you didn't get those above suggestions working, I use this, as it gets any date I ran this expression through 50 links, and it got all the dates on each page.
^20\d\d-(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)-(0[1-9]|[1-2][0-9]|3[01])$
This regex validates dates between 01-01-2000 and 12-31-2099 with matching separators.
^(0[1-9]|1[012])([- /.])(0[1-9]|[12][0-9]|3[01])\2(19|20)\d\d$
var dtRegex = new RegExp(/[1-9\-]{4}[0-9\-]{2}[0-9\-]{2}/);
if(dtRegex.test(date) == true){
var evalDate = date.split('-');
if(evalDate[0] != '0000' && evalDate[1] != '00' && evalDate[2] != '00'){
return true;
}
}
Regex was not meant to validate number ranges(this number must be from 1 to 5 when the number preceding it happens to be a 2 and the number preceding that happens to be below 6).
Just look for the pattern of placement of numbers in regex. If you need to validate is qualities of a date, put it in a date object js/c#/vb, and interogate the numbers there.
I know this does not answer your question, but why don't you use a date handling routine to check if it's a valid date? Even if you modify the regexp with a negative lookahead assertion like (?!31/0?2) (ie, do not match 31/2 or 31/02) you'll still have the problem of accepting 29 02 on non leap years and about a single separator date format.
The problem is not easy if you want to really validate a date, check this forum thread.
For an example or a better way, in C#, check this link
If you are using another platform/language, let us know
Perl 6 version
rx{
^
$<month> = (\d ** 1..2)
{ $<month> <= 12 or fail }
'/'
$<day> = (\d ** 1..2)
{
given( +$<month> ){
when 1|3|5|7|8|10|12 {
$<day> <= 31 or fail
}
when 4|6|9|11 {
$<day> <= 30 or fail
}
when 2 {
$<day> <= 29 or fail
}
default { fail }
}
}
'/'
$<year> = (\d ** 4)
$
}
After you use this to check the input the values are available in $/ or individually as $<month>, $<day>, $<year>. ( those are just syntax for accessing values in $/ )
No attempt has been made to check the year, or that it doesn't match the 29th of Feburary on non leap years.
If you're going to insist on doing this with a regular expression, I'd recommend something like:
( (0?1|0?3| <...> |10|11|12) / (0?1| <...> |30|31) |
0?2 / (0?1| <...> |28|29) )
/ (19|20)[0-9]{2}
This might make it possible to read and understand.
/(([1-9]{1}|0[1-9]|1[0-2])\/(0[1-9]|[1-9]{1}|[12]\d|3[01])\/[12]\d{3})/
This would validate for following -
Single and 2 digit day with range from 1 to 31. Eg, 1, 01, 11, 31.
Single and 2 digit month with range from 1 to 12. Eg. 1, 01, 12.
4 digit year. Eg. 2021, 1980.
A slightly different approach that may or may not be useful for you.
I'm in php.
The project this relates to will never have a date prior to the 1st of January 2008. So, I take the 'date' inputed and use strtotime(). If the answer is >= 1199167200 then I have a date that is useful to me. If something that doesn't look like a date is entered -1 is returned. If null is entered it does return today's date number so you do need a check for a non-null entry first.
Works for my situation, perhaps yours too?
Related
Is there someone to help me with the following:
I'm trying to find specific date and time strings in a text (to be used within VBA Word).
Currently working with the following RegEx string:
(?:([0-9]{1,2})[ |-])?(?:(jan(?:uari)?|feb(?:ruari)?|m(?:aa)?rt|apr(?:il)?|mei|jun(?:i)?|jul(?:i)?|aug(?:ustus)?|sep(?:tember|t)?|okt(?:ober)?|nov(?:ember)?|dec(?:ember)?))?(?: |-)?(?(3)(?: around | at | ))?(?:([0-9]{1,2}:[0-9]{1,2})?(?: uur| u|u)?)?
Tested output on following text:
date with around time: 26 sep 2016 around 09:00u
date with at time: 1 sep 2016 at 09:00 uur
date and time u: 1 sep 2018 09:00 u
time without date: 08:30 uur
date with time u: 1 sep 2016 at 09:00u
only time: 09:00
only month: jan
month and year: feb 2019
only day: 02
only day with '-': 2-
day and month: 2 jan
month year: jan 2018
date with '-': 2-feb-2018 09:00
other month: 01 sept 2016
full month: 1 september 2018
shortened year: jul '18
Rules:
a date followed by time is valid
a date followed by text 'around' or 'at', followed by time is valid
a date without day number is valid
a date without year is valid
a date, month only is not valid
a day, without month or year not valid
a date may contain dashes '-'
a year may be shortenend with ', like jun '18
month name can be short or long
full match includes ' uur' or 'u' (to highlight the text in ms-Word)
submatches text from capture are without prepending or trailing spaces
example at: [https://regex101.com/r/6CFgBP/1/]
Expected output (when using in VBA Word):
An regex Matches collection object in which each Match.SubMatches contains the individual items d, m, y, hh:mm from the capture groups in the regex search string.
So for example 1: the Submatches (or capture groups) contains values: '26' ','sep','2016','09:00'
The RegEx works fine, but some false-positives need to be excluded:
In case there is a day without month/year, should be excluded from Regex (example 9 and 10)
In case there is a month without day, should be excluded (example 7)
(I was trying with som lookahead and reference \1 and ?(1), but was not able to get it running properly...)
Any advice highly appreciated!
As I understood, you require that each date/time part (day, month, year, hour
and minute) must be present.
So you should remove ? after relevant groups (they are not optional).
It is also a good practice to have each group captured as a relevant capturing group.
There is no need to write something like jun(?:i)?. It is enough
(and easier to read) when you write just juni? (the ? refers just
to preceding i).
Another hint: As the regex language contains \d char class, use just
it instead of [0-9] (the regex is shorter and easier to read.
Optional parts (at / around) should be an optional and non-capturing group.
Anything after the minute part is not needed in the regex.
So I propose a regex like below (for readability, I divided it into rows):
(\d{1,2})[ -](jan(?:uari)?|feb(?:ruari)?|m(?:aa)?rt|apr(?:il)?|mei|juni?
|juli?|aug(?:ustus)?|sep(?:tember|t)?|okt(?:ober)?|nov(?:ember)?|dec(?:ember)?)
[ -](\d{4}) (?:around |at )?(\d{1,2}:\d{1,2})
Details:
(\d{1,2}) - Day.
[ -] - A separator after the day (either a space or a minus).
(jan(?:uari)?|...dec(?:ember)?) - Month.
[ -] - A separator after the month.
(\d{4}) - year.
(?:around |at )? - Actually, 3 variants of a separator between year
and hour (space / around / at), note the space before (...)?.
(\d{1,2}:\d{1,2}) - Hour and minute.
It matches variants 1, 2, 3, 5 and 13.
All remaining fail to contain each required part, so they are not matched.
If you allow e.g. that the hour/minute part is optional, change the respective fragment
into:
( (?:around |at )?(\d{1,2}:\d{1,2}))?
i.e. surround the space/around/at / hour / minute part with ( and )?,
making this part an optional group. Then, variants 14 and 15 will also
be matched.
One more extension: If you also allow the hour/minute part alone,
add |(\d{1,2}:\d{1,2}) to the regex (all before is the first variant and
the added part is the second variant for just hour/minute.
Then, your variants No 4 and 6 will also be matched.
For a working example see https://regex101.com/r/33t1ps/1
Edit
Following your list of rules, I propose the following regex:
(\d{1,2}[ -])? - Day + separator, optional.
(jan(?:uari)?|...|dec(?:ember)?) - Month.
(?:[ -](\d{4}|'\d{2}))? - Separator + year (either 4 or 2 digits with "'").
( (?:around |at )?(\d{1,2}:\d{1,2}))? - Separator + hour/minute -
optional end of variant 1.
|(\d{1,2}:\d{1,2}) - Variant 2 - only hour and minute.
It does not match only your variants No 9 and 10.
For full regex, including also "uur" see https://regex101.com/r/33t1ps/3
Finally I found something that helps me using the month properly :-)
\b(?:([1-3]|[0-3]\d)[ |-](?'month'(?:[1-9]|\d[12])|(?:jan(?:uari)?|feb(?:ruari)?|m(?:aa)?rt|apr(?:il)?|mei|jun(?:i)?|jul(?:i)?|aug(?:ustus)?|sep(?:tember|t)?|okt(?:ober)?|nov(?:ember)?|dec(?:ember)?))?)?(?:(\g'month')[ |-]((?:19|20|\')(?:\d{2})))?\b(?: omstreeks | om | )?(?:(\d{1,2}[:]\d{2}(?: uur|u)?|[0-2]\d{3}(?: uur|u)))?\b
It uses a named constructor/subroutine. Found here:
https://www.regular-expressions.info/subroutine.html
I am trying to use Regex to parse a series of strings to extract one or more text dates that may be in multiple formats. The strings will look something like the following:
24 Aug 2016: nno-emvirt010a/b; 16 Aug 2016 nnt-emvirt010a/b nnd-emvirt010a/b COSI-1.6.5
24.16 nno-emvirt010a/b nnt-emvirt010a/b nnd-emvirt010a/b EI.01.02.03\
9/23/16: COSI-1.6.5 Logs updated at /vobs/COTS/1.6.5/files/Status_2016-07-27.log, Status_2016-07-28.log, Status_2016-08-05.log, Status_2016-08-08.log
I am not concerned about validating the individual date fields; just extracting the date string. The part I am unable to figure out is how to not match on number sequences that match the pattern but aren’t dates (‘1.6.5’ in ex. (1) and 01.02.03 in ex. (2)) and dates that are part of a file name (2016-07-27 in ex. (3)). In each of these exception cases in my input data, the initial numbers are preceded by either a period(.), underscore (_) or dash (-), but I cannot determine how to use this to edit the pattern syntax to not match these strings.
The pattern I have that partially works is below. It will only ignore the non date matches if it starts with 1 digit as in example 1.
/[^_\.\(\/]\d{1,4}[/\-\.\s*]([1-9]|0[1-9]|[12][0-9]|3[01]|[a-z]{3})[/\-\.\s*]\d{1,4}/ig`
I am not sure about vba check if this works . seems they have given so much options : https://www.safaribooksonline.com/library/view/regular-expressions-cookbook/9781449327453/ch04s04.html
^(?:(1[0-2]|0?[1-9])/(3[01]|[12][0-9]|0?[1-9])|↵
(3[01]|[12][0-9]|0?[1-9])/(1[0-2]|0?[1-9]))/(?:[0-9]{2})?[0-9]{2}$
^(?:
# m/d or mm/dd
(1[0-2]|0?[1-9])/(3[01]|[12][0-9]|0?[1-9])
|
# d/m or dd/mm
(3[01]|[12][0-9]|0?[1-9])/(1[0-2]|0?[1-9])
)
# /yy or /yyyy
/(?:[0-9]{2})?[0-9]{2}$
According to the test strings you've presented, you can use the following regex
See this regex in use here
(?<=[^a-zA-Z\d.]|^)((?:\d{1,2}\s*[A-Z][a-z]{2}\s*\d+)|(?:(?:\d{1,2}\/){2}\d+)|(?:\d+(?:-\d{2}){2})|\d{2}\.\d{2})(?=[^a-zA-Z\d.])
This regex ensures that specific date formats are met and are preceded by nothing (beginning of the string) or by a non-word character (specifically a-z, A-Z, 0-9) or dot .. The date formats that will be matched are:
24 Aug 2016
24.16
9/23/16
The regex could be further manipulated to ensure numbers are in the proper range according to days/month, etc., however, I don't feel that is really necessary.
Edits
Edit 1
Since VBA doesn't support lookbehinds, you can use the following. The date is in capture group 1.
(?:[^a-zA-Z\d.]|^)((?:\d{1,2}\s*[A-Z][a-z]{2}\s*\d+)|(?:(?:\d{1,2}\/){2}\d+)|(?:\d+(?:-\d{2}){2})|\d{2}\.\d{2})(?=[^a-zA-Z\d.])
Edit 2
As per bulbus's comment below
(?:[^\w.]|^)((?:\d{1,2}\s*[A-Z][a-z]{2}\s*\d{2,4})|(?:(?:\d{1,2}\/){2}\d{2,4})|(?:\d{2,4}(?:-\d{2}){2})|\d{2}\.\d{2})
Took liberty to edit that a bit.
replaced [^a-zA-Z\d.] with [^\w.], comes with added advantage of excluding dates with _2016-07-28.log
Due to 1 removed trailing condition (?=[^a-zA-Z\d.]).
Forced year digits from \d+ to \d{2,4}
Edit 3
Due to added conditions of the regex, I've made the following edits (to improve upon both previous edits). As per the OP:
The edited pattern above works in all but 2 cases:
it does not find dates with the year first (ex. 2016/07/11)
if the date is contained within parenthesis in the string, it returns the left parenthesis as part of the date (ex. match = (8/20/2016)
Can you provide the edit to fix these?
In the below regexes, I've changed years to \d+ in order for it to work on any year greater than or equal to 0.
See the code in use here
(?:[^\w.]|^)((?:\d{1,2}\s+[A-Z][a-z]{2}\s+\d+)|(?:(?:\d{1,2}\/){2}\d+)|(?:\d+(?:\/\d{1,2}){2})|(?:\d+(?:-\d{2}){2})|\d{2}\.\d+)
This regex adds the possibility of dates in the XXXX/XX/XX format where the date may appear first.
The reason you are getting ( as a match before the regex is the nature of the Full Match. You need to, instead, grab the value of the first capture group and not the whole regex result. See this answer on how to grab submatches from a regex pattern in VBA.
Also, note that any additional date formats you need to catch need to be explicitly set in the regex. Currently, the regex supports the following date formats:
\d{1,2}\s+[A-Z][a-z]{2}\s+\d+
12 Apr 17
12 Apr 2017
(?:\d{1,2}\/){2}\d+
1/4/17
01/04/17
1/4/2017
01/04/2017
\d+(?:\/\d{1,2}){2}
17/04/01
2017/4/1
2017/04/01
17/4/1
\d+(?:-\d{2}){2}
17-04-01
2017-04-01
\d{2}\.\d+ - Although I'm not sure what this date format is even used for and how it could be considered efficient if it's missing month
24.16
I need to validate a date string for the format dd/mm/yyyy with a regular expresssion.
This regex validates dd/mm/yyyy, but not the invalid dates like 31/02/4500:
^(0?[1-9]|[12][0-9]|3[01])[\/\-](0?[1-9]|1[012])[\/\-]\d{4}$
What is a valid regex to validate dd/mm/yyyy format with leap year support?
The regex you pasted does not validate leap years correctly, but there is one that does in the same post.
I modified it to take dd/mm/yyyy, dd-mm-yyyy or dd.mm.yyyy.
^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]))\1|(?:(?:29|30)(\/|-|\.)(?:0?[13-9]|1[0-2])\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)0?2\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$
I tested it a bit in the link Arun provided in his answer and also here and it seems to work.
Edit February 14th 2019: I've removed a comma that was in the regex which allowed dates like 29-0,-11
I have extended the regex given by #Ofir Luzon for the formats dd-mmm-YYYY, dd/mmm/YYYY, dd.mmm.YYYY as per my requirement. Anyone else with same requirement can refer this
^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec)))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)(?:0?2|(?:Feb))\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$
and tested for some test cases here https://regexr.com/39tr1.
For better understanding for this Regular expression refer this image:
Edit
Extending it for yyyy/mm/dd, yyyy-mm-dd or yyyy.mm.dd
some test cases https://regex101.com/r/3TZfyU/1
^(?:(?:1[6-9]|[2-9]\d)?\d{2})(?:(?:(\/|-|\.)(?:0?[13578]|1[02])\1(?:31))|(?:(\/|-|\.)(?:0?[13-9]|1[0-2])\2(?:29|30)))$|
^(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00)))(\/|-|\.)0?2\3(?:29)$|
^(?:(?:1[6-9]|[2-9]\d)?\d{2})(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:0?[1-9]|1\d|2[0-8])$
Notice:
Your regexp does not work for years that "are multiples of 4 and 100, but not of 400". Years that pass that test are not leap years. For example: 1900, 2100, 2200, 2300, 2500, etc. In other words, it puts all years with the format \d\d00 in the same class of leap years, which is incorrect. – MuchToLearn
So it works properly only for [1901 - 2099] (Whew) 😊
dd/MM/yyyy:
Checks if leap year.
Years from 1900 to 9999 are valid. Only dd/MM/yyyy
(^(((0[1-9]|1[0-9]|2[0-8])[\/](0[1-9]|1[012]))|((29|30|31)[\/](0[13578]|1[02]))|((29|30)[\/](0[4,6,9]|11)))[\/](19|[2-9][0-9])\d\d$)|(^29[\/]02[\/](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)
try this.
^(0[1-9]|[12][0-9]|3[01])[- /.](0[1-9]|1[012])[- /.](19|20)\d\d$
you can test regular expression at http://www.regular-expressions.info/javascriptexample.html easily.
For those who look at these and get completely confused, here is an excerpt from my script. Unfortunately, all it does is match valid numbers in a date time input, and 31st Feb will be marked as valid, but as so many have said, regex really isn't the best tool to do this test.
To match a date in the format 'yyyy-MM-dd hh:mm' (Or indeed in whatever order you please)
var dateerrors = false;
var yearReg = '(201[4-9]|202[0-9])'; ///< Allows a number between 2014 and 2029
var monthReg = '(0[1-9]|1[0-2])'; ///< Allows a number between 00 and 12
var dayReg = '(0[1-9]|1[0-9]|2[0-9]|3[0-1])'; ///< Allows a number between 00 and 31
var hourReg = '([0-1][0-9]|2[0-3])'; ///< Allows a number between 00 and 24
var minReg = '([0-5][0-9])'; ///< Allows a number between 00 and 59
var reg = new RegExp('^' + yearReg + '-' + monthReg + '-' + dayReg + ' ' + hourReg + ':' + minReg + '$', 'g');
$('input').filter(function () {return this.id.match(/myhtml_element_with_id_\d+_datetime/);}).each(function (e) {
if (e > 0) {
// Don't test the first input. This will use the default
var val = $(this).val();
if (val && !val.trim().match(reg)) {
dateerrors = true;
return false;
}
}
});
if (dateerrors) {
alert('You must enter a validate date in the format "yyyy-mm-dd HH:MM", e.g. 2019-12-31 19:30');
return false;
}
The above script starts off by building a regex object. It then finds all of the inputs whose id's match a certain pattern and then loops through these. I don't test the first input I find (if (e > 0)).
A bit of explanation:
var reg = new RegExp('^' + yearReg + '-' + monthReg + '-' + dayReg + ' ' + hourReg + ':' + minReg + '$', 'g');
^ means start of match, whereas $ means end of match.
return this.id.match(/myhtml_element_with_id_\d+_datetime/);
\d+ means match a single or a contiguous sequence of integers, so myhtml_element_with_id_56_datetime and myhtml_element_with_id_2_datetime will match, but myhtml_element_with_id_5a_datetime will not
I suspect that the following is as accurate as can be expected without knowing when the user's locale switched over from the Julian to the Gregorian calendars.
It accepts either '-', '/', or nothing as separators between year, month, and day, no matter the order.
MMddyyyy:
^(((0[13-9]|1[012])[-/]?(0[1-9]|[12][0-9]|30)|(0[13578]|1[02])[-/]?31|02[-/]?(0[1-9]|1[0-9]|2[0-8]))[-/]?[0-9]{4}|02[-/]?29[-/]?([0-9]{2}(([2468][048]|[02468][48])|[13579][26])|([13579][26]|[02468][048]|0[0-9]|1[0-6])00))$
ddMMyyyy:
^(((0[1-9]|[12][0-9]|30)[-/]?(0[13-9]|1[012])|31[-/]?(0[13578]|1[02])|(0[1-9]|1[0-9]|2[0-8])[-/]?02)[-/]?[0-9]{4}|29[-/]?02[-/]?([0-9]{2}(([2468][048]|[02468][48])|[13579][26])|([13579][26]|[02468][048]|0[0-9]|1[0-6])00))$
yyyyMMdd:
^([0-9]{4}[-/]?((0[13-9]|1[012])[-/]?(0[1-9]|[12][0-9]|30)|(0[13578]|1[02])[-/]?31|02[-/]?(0[1-9]|1[0-9]|2[0-8]))|([0-9]{2}(([2468][048]|[02468][48])|[13579][26])|([13579][26]|[02468][048]|0[0-9]|1[0-6])00)[-/]?02[-/]?29)$
Other than order, these all are accurate to the Julian Calendar (leap year every four years) until 1700, when the Gregorian Calendar diverges from the Julian. It has two issues:
It accepts the year 0000, which doesn't exist in many, but not all, standards. Note that ISO 8601 does accept year 0000 (equivalent to 1 BCE).
It doesn't skip the 10-13 days which were lost when the Gregorian Calendar came into use. This varies by locality though. For example, the Roman Catholic Church skipped 10 days, October 5th through October 14th, 1582, but Greece (the last to switch) skipped February 16th through the 28th of 1923, 13 days, having to take into account the leap years of 1700, 1800, and 1900.
This has been tested against Java's calendar implementation from the year 0001 until the year 9999 with the only discrepancy being the abovementioned 10 days in 1582.
Here is another version of regex to match any of the following date formats and allow leading zeros to be omitted:
Regex: ^[0-3]?[0-9].[0-3]?[0-9].(?:[0-9]{2})?[0-9]{2}$
Matches:
1/1/11 or 1.1.11 or 1-1-11 : true
01/01/11 or 01.01.11 or 01-01-11 : true
01/01/2011 or 01.01.2011 or 01-01-2011 : true
01/1/2011 or 01.1.2011 or 01-1-2011 : true
1/11/2011 or 1.11.2011 or 1-11-2011 : true
1/11/11 or 1.11.11 or 1-11-11 : true
11/1/11 or 11.1.11 or 11-1-11 : true
Debuggex Demo
year = ((20[012]\d|19\d\d)|(1\d|2[0123]))
month = ((0[0-9])|(1[012]))
day = ((0[1-9])|([12][0-9])|(3[01]))
year-month-day = (((20[012]\d|19\d\d)|(1\d|2[0123]))-((0[0-9])|(1[012]))-((0[1-9])|([12][0-9])|(3[01])))
day-month-year = (((0[1-9])|([12][0-9])|(3[01]))-((0[0-9])|(1[012]))-((20[012]\d|19\d\d)|(1\d|2[0123])))
year/month/day = (((20[012]\d|19\d\d)|(1\d|2[0123]))\/((0[0-9])|(1[012]))\/((0[1-9])|([12][0-9])|(3[01])))
month/day/year = (((0[0-9])|(1[012]))\/((0[1-9])|([12][0-9])|(3[01]))\/((20[012]\d|19\d\d)|(1\d|2[0123])))
day/month/year = (((0[1-9])|([12][0-9])|(3[01]))\/((0[0-9])|(1[012]))\/((20[012]\d|19\d\d)|(1\d|2[0123])))
day.month.year = (((0[1-9])|([12][0-9])|(3[01]))\.((0[0-9])|(1[012]))\.((20[012]\d|19\d\d)|(1\d|2[0123])))
year.month.day = (((20[012]\d|19\d\d)|(1\d|2[0123]))\.((0[0-9])|(1[012]))\.((0[1-9])|([12][0-9])|(3[01])))
all = (((20[012]\d|19\d\d)|(1\d|2[0123]))-((0[0-9])|(1[012]))-((0[1-9])|([12][0-9])|(3[01])))|(((0[1-9])|([12][0-9])|(3[01]))-((0[0-9])|(1[012]))-((20[012]\d|19\d\d)|(1\d|2[0123])))|(((20[012]\d|19\d\d)|(1\d|2[0123]))\/((0[0-9])|(1[012]))\/((0[1-9])|([12][0-9])|(3[01])))|(((0[0-9])|(1[012]))\/((0[1-9])|([12][0-9])|(3[01]))\/((20[012]\d|19\d\d)|(1\d|2[0123])))|(((0[1-9])|([12][0-9])|(3[01]))\/((0[0-9])|(1[012]))\/((20[012]\d|19\d\d)|(1\d|2[0123])))|(((0[1-9])|([12][0-9])|(3[01]))\.((0[0-9])|(1[012]))\.((20[012]\d|19\d\d)|(1\d|2[0123])))|(((20[012]\d|19\d\d)|(1\d|2[0123]))\.((0[0-9])|(1[012]))\.((0[1-9])|([12][0-9])|(3[01])))
its work for
yyyy-mm-dd
dd-mm-yyyy
yyyy/mm/dd
mm/dd/yyyy
dd/mm/yyyy
dd.mm.yyyy
yyyy.mm.dd
yy-mm-dd
dd-mm-yy
yyyy/mm/dd
mm/dd/yy
dd/mm/yy
dd.mm.yy
yy.mm.dd
but not work for where day = d or month = m, example d.m.yyyy
all example - enter link description here
Here I wrote one for dd/mm/yyyy where separator can be one of -.,/ year range 0000-9999.
It deals with leap years and is designed for regex flavors, that support lookaheads, capturing groups and backreferences. NOT valid for such as d/m/yyyy. If needed add further separators to [-.,/]
^(?=\d{2}([-.,\/])\d{2}\1\d{4}$)(?:0[1-9]|1\d|[2][0-8]|29(?!.02.(?!(?!(?:[02468][1-35-79]|[13579][0-13-57-9])00)\d{2}(?:[02468][048]|[13579][26])))|30(?!.02)|31(?=.(?:0[13578]|10|12))).(?:0[1-9]|1[012]).\d{4}$
Test at regex101; as a Java string:
"^(?=\\d{2}([-.,\\/])\\d{2}\\1\\d{4}$)(?:0[1-9]|1\\d|[2][0-8]|29(?!.02.(?!(?!(?:[02468][1-35-79]|[13579][0-13-57-9])00)\\d{2}(?:[02468][048]|[13579][26])))|30(?!.02)|31(?=.(?:0[13578]|10|12))).(?:0[1-9]|1[012]).\\d{4}$"
explained:
(?x) # modifier x: free spacing mode (for comments)
# verify date dd/mm/yyyy; possible separators: -.,/
# valid year range: 0000-9999
^ # start anchor
# precheck xx-xx-xxxx,... add new separators here
(?=\d{2}([-.,\/])\d{2}\1\d{4}$)
(?: # day-check: non caturing group
# days 01-28
0[1-9]|1\d|[2][0-8]|
# february 29d check for leap year: all 4y / 00 years: only each 400
# 0400,0800,1200,1600,2000,...
29
(?!.02. # not if feb: if not ...
(?!
# 00 years: exclude !0 %400 years
(?!(?:[02468][1-35-79]|[13579][0-13-57-9])00)
# 00,04,08,12,...
\d{2}(?:[02468][048]|[13579][26])
)
)|
# d30 negative lookahead: february cannot have 30 days
30(?!.02)|
# d31 positive lookahead: month up to 31 days
31(?=.(?:0[13578]|10|12))
) # eof day-check
# month 01-12
.(?:0[1-9]|1[012])
# year 0000-9999
.\d{4}
$ # end anchor
Also see SO Regex FAQ; Please let me know, if it fails.
Found this reg ex here
^(((0[1-9]|[12]\d|3[01])\/(0[13578]|1[02])\/((19|[2-9]\d)\d{2}))|((0[1-9]|[12]\d|30)\/(0[13456789]|1[012])\/((19|[2-9]\d)\d{2}))|((0[1-9]|1\d|2[0-8])\/02\/((19|[2-9]\d)\d{2}))|(29\/02\/((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))$
This validates the format mm/dd/yyyy and valid dates correctly (but not m/d/yyyy).
Some tests
"^(0[1-9]|[12][0-9]|3[01])[- /.](0[1-9]|1[012])[- /.]((19|20)\\d\\d)$"
will validate any date between 1900-2099
The following expression is nice and easy to manipulate:
((((0[13578]|1[02])(\/|-|.)(0[1-9]|1[0-9]|2[0-9]|3[01]))|((0[469]|11)(\/|-|.)(0[1-9]|1[0-9]|2[0-9]|3[0]))|((02)((\/|-|.)(0[1-9]|1[0-9]|2[0-8]))))(\/|-|.)(19([6-9][0-9])|20(0[0-9]|1[0-4])))|((02)(\/|-|.)(29)(\/|-|.)(19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26])))
It validates according to the MM/dd/YYYY format and allows for leap year support from 1960 to 2016. If you need the leap year support extended you need only manipulate this part of the expression:
(19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]))
Hope this helped you a lot
Another answer which validates day (dd) depending upon the month (mm) and the year (yyyy) (i.e., also validates 29th Feb in leap years) and allows years ranging from 0001 to 9999 (0000 in a invalid year according to the Gregorian calendar)
^(?:(?:(?:0[1-9]|[12]\d|3[01])/(?:0[13578]|1[02])|(?:0[1-9]|[12]\d|30)/(?:0[469]|11)|(?:0[1-9]|1\d|2[0-8])/02)/(?!0000)\d{4}|(?:(?:0[1-9]|[12]\d)/02/(?:(?!0000)(?:[02468][048]|[13579][26])00|(?!..00)\d{2}(?:[02468][048]|[13579][26]))))$
The best way according to me is to use the Moment.js isValid() method by specifying the format and use strict parsing.
As moment.js documentation says
As of version 2.3.0, you may specify a boolean for the last argument
to make Moment use strict parsing. Strict parsing requires that the
format and input match exactly, including delimiters.
value = '2020-05-25';
format = 'YYYY-MM-DD';
moment(value, format, true).isValid() // true
Further extended the regex given by #AlokChaudhary to support:
1. dd mmm YYYY (in addition to dd-mmm-YYYY, dd/mmm/YYYY, dd.mmm.YYYY).
2. mmm in all CAPITAL LETTERS format (in addition to Title format)
dd mmm YYYY e.g. 30 Apr 2026 or 24 DEC 2028 are popular.
Extended regex:
(^(?:(?:(?:31(?:(?:([-.\/])(?:0?[13578]|1[02])\1)|(?:([-.\/ ])(?:Jan|JAN|Mar|MAR|May|MAY|Jul|JUL|Aug|AUG|Oct|OCT|Dec|DEC)\2)))|(?:(?:29|30)(?:(?:([-.\/])(?:0?[13-9]|1[0-2])\3)|(?:([-.\/ ])(?:Jan|JAN|Mar|MAR|Apr|APR|May|MAY|Jun|JUN|Jul|JUL|Aug|AUG|Sep|SEP|Oct|OCT|Nov|NOV|Dec|DEC)\4))))(?:(?:1[6-9]|[2-9]\d)?\d{2}))$|^(?:29(?:(?:([-.\/])(?:0?2)\5)|(?:([-.\/ ])(?:Feb|FEB)\6))(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00)))$|^(?:(?:0?[1-9]|1\d|2[0-8])(?:(?:([-.\/])(?:(?:0?[1-9]|(?:1[0-2])))\7)|(?:([-.\/ ])(?:Jan|JAN|Feb|FEB|Mar|MAR|May|MAY|Jul|JUL|Aug|AUG|Oct|OCT|Dec|DEC)\8))(?:(?:1[6-9]|[2-9]\d)?\d{2}))$)
Test cases included in the Regex Demo
Features (retained):
Leap year checking (Feb 29 validation) includes the logics: (divisible by 4 but not divisible by 100) or (divisible by 400)
Supports years 1600 ~ 9999
Supports dd/mm/YYYY, dd-mm-YYYY, dd.mm.YYYY (but not dd mm YYYY)
Supports dd mmm YYYY, dd-mmm-YYYY, dd/mmm/YYYY, dd.mmm.YYYY (dd mmm YYYY newly added. mmm can be in CAPITAL e.g. DEC or Title format e.g. Dec)
Some additional minor touch-up as follows:
Included the fix by Ofir Luzon on February 14th 2019 to remove a comma that was in the regex which allowed dates like 29-0,-11 [error replicated to Alok Chaudhary's regex]
Replaced (\/|-|\.) by ([-.\/]) to minimize the use of backslash. \/ is still used in order to support some regex flavor e.g. PCRE(PHP) although some other regex flavor e.g. Python can simply use / inside the character class [ ]
Added a pair of parenthesis () surrounding the whole regex to make it a capturing group for the whole matching string. This is useful for people using findAll type of functions to get a matching item list (e.g. re.findall in Python). This enable us to capture all the matching strings within a mult-line string with the following codes:
re.findall sample codes:
match_list = re.findall(regex, source_string)
for item in match_list:
print(item[0])
Extended regex image:
Credits should go to Ofir Luzon and Alok Chaudhary who created such excellent regexes for us all!
I'm working with an API that only accepts MM/DD/YYYY format. I couldn't find any other post that did leap years quite as well as Ofir's answer, so I tweaked it and am re-posting it here for anyone that might need it.
/^(?:(?:(?:0[13578]|1[02])(\/)31)\1|(?:(?:0[1,3-9]|1[0-2])(\/)(?:29|30)\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:02(\/)29\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/)(?:0[1-9]|1\d|2[0-8])\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$/
In case you are looking for specific format, This works fine for "dd/MM/yyyy" & "dd/MMM/yyyy" date format only based on Alok answer.
function isValidDateFormatDDMMYYYY(inputDate) {
var date_regex = /^(?:(?:31(\/)(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec)))\1|(?:(?:29|30)(\/)(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/)(?:0?2|(?:Feb))\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/)(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$/;
return date_regex.test(inputDate);
}
Few examples working thru this code -
isValidDateFormatDDMMYYYY("15/01/1999") // returns True
isValidDateFormatDDMMYYYY("15/Jan/1999") // returns True
isValidDateFormatDDMMYYYY("15/1/1999") // returns True
isValidDateFormatDDMMYYYY("1/15/1999") // returns False
Thanks
import re
expression = "Nov 05 20:10:09 2020"
reg_ex = r'((Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) ([0-2][0-9]|(3)[0-1]) (([0-1][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])) (\d{4}))'
assert re.fullmatch(reg_ex, expression), True
Expaination with respect to given Example
Nov = A group of possible months i.e. (Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)
05 = A group of valid days i.e. ([0-2][0-9]|(3)[0-1])
20:10:09 = A group for getting valid Hours : ([0-1][0-9]|2[0-3]), Minutes : ([0-5][0-9]) and Seconds : ([0-5][0-9])
2020 = A group for getting year i.e (\d{4}))
Please Following Expression
Regex regex = new Regex(#"(((0|1)[0-9]|2[0-9]|3[0-1])\/(0[1-9]|1[0-2])\/((19|20)\d\d))$");
((((0[13578]|1[02])\/(0[1-9]|1[0-9]|2[0-9]|3[01]))|((0[469]|11)\/(0[1-9]|1[0-9]|2[0-9]|3[0]))|((02)(\/(0[1-9]|1[0-9]|2[0-8]))))\/(19([6-9][0-9])|20([0-9][0-9])))|((02)\/(29)\/(19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]|2[048])))
will validate MM/DD/YYYY format with 1960 to 2028
if you need to extend leap year support then add
19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]|2[048]|3[26]|4[048])))
this is also work
^((((0[13578]|1[02])[/](0[1-9]|1[0-9]|2[0-9]|3[01]))|((0[469]|11)[/](0[1-9]|1[0-9]|2[0-9]|3[0]))|((02)([/](0[1-9]|1[0-9]|2[0-8]))))[/](19([6-9][0-9])|20([0-9][0-9])))|((02)[/](29)[/](19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]|2[048])))
if you can change format mm-dd-yyyy than replace [/] to [-]
also check online http://regexr.com/
For date MM/DD/YYYY you can use
^((((0[13578])|([13578])|(1[02]))[\/](([1-9])|([0-2][0-9])|(3[01])))|(((0[469])|([469])|(11))[\/](([1-9])|([0-2][0-9])|(30)))|((2|02)[\/](([1-9])|([0-2][0-9]))))[\/]\d{4}$|^\d{4}$
It verify proper days and moths.
Remeber that you can check your regular expression at
regex101
which i recommend :)
Have fun!
^(((([13578]|0[13578]|1[02])[-](0[1-9]|[1-9]|1[0-9]|2[0-9]|3[01]))|(([469]|0[469]|11)[-]([1-9]|1[0-9]|2[0-9]|3[0]))|((2|02)([-](0[1-9]|1[0-9]|2[0-8]))))[-](19([6-9][0-9])|20([0-9][0-9])))|((02)[-](29)[-](19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]|2[048])))
this regex will validate dates in format:
12-30-2016 (mm-dd-yyyy) or 12-3-2016 (mm-d-yyyy) or
1-3-2016 (m-d-yyyy) or 1-30-2016 (m-dd-yyyy)
I know it is a tangential answer to the question, but if the intention of the question is 'how do I validate a date?', then why not try letting the programming language do all the hard work (if you are using a language that can)?
e.g. in php
$this_date_object = date_create($this_date);
if ($this_date_object == false )
{
// process the error
}
For use only for the day:
<input placeholder="day" maxlength="2" minlength="1" formControlName="birthDay"
name="birthDay"pattern="(0[1-9]|1[0-9]|2[0-9]|3[0-1])" >/
For use only for the month:
<input placeholder="month" maxlength="2" minlength="1"
formControlName="month" name="month" formControlName="month" name="month" pattern="(0[1-
9]|1[0-2])">/
I know it's been a long time since this was answered, but maybe this could help someone else. The thing is that i wanted to, also, check the year, and let some past years match too. This regex match dates formated as "DD-MM-YYYY". So this function will return a regex:
const check_year = "01-01-2021"
console.log(get_regex())
console.log(check_year.match(get_regex()))
function get_regex(){
let actual_year = `${new Date().getFullYear()}`
let regex = new RegExp()
let split_year = actual_year.split("")
let year_regex = `${split_year[0]}[0-${split_year[1]}][0-${split_year[2]}][0-${split_year[3]}]$`
let day_month_regex = "^([1-2][0-9]|3[0-1]|0?[1-9])[-]([1][0-2]|0?[1-9])[-]"
regex.compile(day_month_regex+year_regex, "g")
return regex
}
simple function for python
def is_valid_date(date_text):
pattern = re.compile('\d{4}-\d{2}-\d{2}$')
return pattern.match(date_text)
This is a regex to match strings of the date format, YYYY-MM-DD, with different kind of separators. It matches a string even in sentences, and with dates ending with st, nd and others.
As an example, it matches the date in these sentences:
"Her birthday is 2022 February 23rd; I will present here a gift."
"Her birthday is 2022 Feb 23rd; I will present here a gift."
"Her birthday is 2022 02 23; I will present here a gift."
This is the date regex:
"\b
(?<YYYY>[0-9]{4})
(?<!0000)(?<sep>[ /.,-])
(?|
(?:(?<MM>0[13578]|1[02]|Jan(?:uary)?|Mar(?:ch)?|May|Jul(?:y)?|Aug(?:ust)?|Oct(?:ober)?|Dec(?:ember)?)\g{sep}(?<DD>0[1-9]|[12][0-9]|3[01]))|
(?:(?<MM>0[469]|11|Apr(?:il)?|Jun(?:e)?|Sep(?:tember)?|Nov(?:ember)?)\g{sep}(?<DD>0[1-9]|[12][0-9]|30))|
(?:(?<MM>02|Feb(?:ruary)?)\g{sep}(?<DD>0[1-9]|[12][0-9]))
)
(?:
(?<=[023][1])st|
(?<=[02][2])nd|
(?<=[02][3])rd|
(?<=(?:0[4-9])|(?:1[0-9])|20|(?:2[4-9])|30)th
)?
[,;.]?
\b"x
IMHO, it makes no sense for a regex to check for a leap year, when a simple, clear and understandable one-liner can be written for it:
is_leap_year(y) = ((y%4 == 0) && (y%100 != 0)) || (y%400 == 0)
Regexes are for matching strings and not for carrying out calculation. The best way is to match the string and then pass the captured MM group to the is_leap_year function if its 02, Feb or February, to validate the string.
I need to validate a date string for the format dd/mm/yyyy with a regular expresssion.
This regex validates dd/mm/yyyy, but not the invalid dates like 31/02/4500:
^(0?[1-9]|[12][0-9]|3[01])[\/\-](0?[1-9]|1[012])[\/\-]\d{4}$
What is a valid regex to validate dd/mm/yyyy format with leap year support?
The regex you pasted does not validate leap years correctly, but there is one that does in the same post.
I modified it to take dd/mm/yyyy, dd-mm-yyyy or dd.mm.yyyy.
^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]))\1|(?:(?:29|30)(\/|-|\.)(?:0?[13-9]|1[0-2])\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)0?2\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$
I tested it a bit in the link Arun provided in his answer and also here and it seems to work.
Edit February 14th 2019: I've removed a comma that was in the regex which allowed dates like 29-0,-11
I have extended the regex given by #Ofir Luzon for the formats dd-mmm-YYYY, dd/mmm/YYYY, dd.mmm.YYYY as per my requirement. Anyone else with same requirement can refer this
^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec)))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)(?:0?2|(?:Feb))\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$
and tested for some test cases here https://regexr.com/39tr1.
For better understanding for this Regular expression refer this image:
Edit
Extending it for yyyy/mm/dd, yyyy-mm-dd or yyyy.mm.dd
some test cases https://regex101.com/r/3TZfyU/1
^(?:(?:1[6-9]|[2-9]\d)?\d{2})(?:(?:(\/|-|\.)(?:0?[13578]|1[02])\1(?:31))|(?:(\/|-|\.)(?:0?[13-9]|1[0-2])\2(?:29|30)))$|
^(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00)))(\/|-|\.)0?2\3(?:29)$|
^(?:(?:1[6-9]|[2-9]\d)?\d{2})(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:0?[1-9]|1\d|2[0-8])$
Notice:
Your regexp does not work for years that "are multiples of 4 and 100, but not of 400". Years that pass that test are not leap years. For example: 1900, 2100, 2200, 2300, 2500, etc. In other words, it puts all years with the format \d\d00 in the same class of leap years, which is incorrect. – MuchToLearn
So it works properly only for [1901 - 2099] (Whew) 😊
dd/MM/yyyy:
Checks if leap year.
Years from 1900 to 9999 are valid. Only dd/MM/yyyy
(^(((0[1-9]|1[0-9]|2[0-8])[\/](0[1-9]|1[012]))|((29|30|31)[\/](0[13578]|1[02]))|((29|30)[\/](0[4,6,9]|11)))[\/](19|[2-9][0-9])\d\d$)|(^29[\/]02[\/](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)
try this.
^(0[1-9]|[12][0-9]|3[01])[- /.](0[1-9]|1[012])[- /.](19|20)\d\d$
you can test regular expression at http://www.regular-expressions.info/javascriptexample.html easily.
For those who look at these and get completely confused, here is an excerpt from my script. Unfortunately, all it does is match valid numbers in a date time input, and 31st Feb will be marked as valid, but as so many have said, regex really isn't the best tool to do this test.
To match a date in the format 'yyyy-MM-dd hh:mm' (Or indeed in whatever order you please)
var dateerrors = false;
var yearReg = '(201[4-9]|202[0-9])'; ///< Allows a number between 2014 and 2029
var monthReg = '(0[1-9]|1[0-2])'; ///< Allows a number between 00 and 12
var dayReg = '(0[1-9]|1[0-9]|2[0-9]|3[0-1])'; ///< Allows a number between 00 and 31
var hourReg = '([0-1][0-9]|2[0-3])'; ///< Allows a number between 00 and 24
var minReg = '([0-5][0-9])'; ///< Allows a number between 00 and 59
var reg = new RegExp('^' + yearReg + '-' + monthReg + '-' + dayReg + ' ' + hourReg + ':' + minReg + '$', 'g');
$('input').filter(function () {return this.id.match(/myhtml_element_with_id_\d+_datetime/);}).each(function (e) {
if (e > 0) {
// Don't test the first input. This will use the default
var val = $(this).val();
if (val && !val.trim().match(reg)) {
dateerrors = true;
return false;
}
}
});
if (dateerrors) {
alert('You must enter a validate date in the format "yyyy-mm-dd HH:MM", e.g. 2019-12-31 19:30');
return false;
}
The above script starts off by building a regex object. It then finds all of the inputs whose id's match a certain pattern and then loops through these. I don't test the first input I find (if (e > 0)).
A bit of explanation:
var reg = new RegExp('^' + yearReg + '-' + monthReg + '-' + dayReg + ' ' + hourReg + ':' + minReg + '$', 'g');
^ means start of match, whereas $ means end of match.
return this.id.match(/myhtml_element_with_id_\d+_datetime/);
\d+ means match a single or a contiguous sequence of integers, so myhtml_element_with_id_56_datetime and myhtml_element_with_id_2_datetime will match, but myhtml_element_with_id_5a_datetime will not
I suspect that the following is as accurate as can be expected without knowing when the user's locale switched over from the Julian to the Gregorian calendars.
It accepts either '-', '/', or nothing as separators between year, month, and day, no matter the order.
MMddyyyy:
^(((0[13-9]|1[012])[-/]?(0[1-9]|[12][0-9]|30)|(0[13578]|1[02])[-/]?31|02[-/]?(0[1-9]|1[0-9]|2[0-8]))[-/]?[0-9]{4}|02[-/]?29[-/]?([0-9]{2}(([2468][048]|[02468][48])|[13579][26])|([13579][26]|[02468][048]|0[0-9]|1[0-6])00))$
ddMMyyyy:
^(((0[1-9]|[12][0-9]|30)[-/]?(0[13-9]|1[012])|31[-/]?(0[13578]|1[02])|(0[1-9]|1[0-9]|2[0-8])[-/]?02)[-/]?[0-9]{4}|29[-/]?02[-/]?([0-9]{2}(([2468][048]|[02468][48])|[13579][26])|([13579][26]|[02468][048]|0[0-9]|1[0-6])00))$
yyyyMMdd:
^([0-9]{4}[-/]?((0[13-9]|1[012])[-/]?(0[1-9]|[12][0-9]|30)|(0[13578]|1[02])[-/]?31|02[-/]?(0[1-9]|1[0-9]|2[0-8]))|([0-9]{2}(([2468][048]|[02468][48])|[13579][26])|([13579][26]|[02468][048]|0[0-9]|1[0-6])00)[-/]?02[-/]?29)$
Other than order, these all are accurate to the Julian Calendar (leap year every four years) until 1700, when the Gregorian Calendar diverges from the Julian. It has two issues:
It accepts the year 0000, which doesn't exist in many, but not all, standards. Note that ISO 8601 does accept year 0000 (equivalent to 1 BCE).
It doesn't skip the 10-13 days which were lost when the Gregorian Calendar came into use. This varies by locality though. For example, the Roman Catholic Church skipped 10 days, October 5th through October 14th, 1582, but Greece (the last to switch) skipped February 16th through the 28th of 1923, 13 days, having to take into account the leap years of 1700, 1800, and 1900.
This has been tested against Java's calendar implementation from the year 0001 until the year 9999 with the only discrepancy being the abovementioned 10 days in 1582.
Here is another version of regex to match any of the following date formats and allow leading zeros to be omitted:
Regex: ^[0-3]?[0-9].[0-3]?[0-9].(?:[0-9]{2})?[0-9]{2}$
Matches:
1/1/11 or 1.1.11 or 1-1-11 : true
01/01/11 or 01.01.11 or 01-01-11 : true
01/01/2011 or 01.01.2011 or 01-01-2011 : true
01/1/2011 or 01.1.2011 or 01-1-2011 : true
1/11/2011 or 1.11.2011 or 1-11-2011 : true
1/11/11 or 1.11.11 or 1-11-11 : true
11/1/11 or 11.1.11 or 11-1-11 : true
Debuggex Demo
year = ((20[012]\d|19\d\d)|(1\d|2[0123]))
month = ((0[0-9])|(1[012]))
day = ((0[1-9])|([12][0-9])|(3[01]))
year-month-day = (((20[012]\d|19\d\d)|(1\d|2[0123]))-((0[0-9])|(1[012]))-((0[1-9])|([12][0-9])|(3[01])))
day-month-year = (((0[1-9])|([12][0-9])|(3[01]))-((0[0-9])|(1[012]))-((20[012]\d|19\d\d)|(1\d|2[0123])))
year/month/day = (((20[012]\d|19\d\d)|(1\d|2[0123]))\/((0[0-9])|(1[012]))\/((0[1-9])|([12][0-9])|(3[01])))
month/day/year = (((0[0-9])|(1[012]))\/((0[1-9])|([12][0-9])|(3[01]))\/((20[012]\d|19\d\d)|(1\d|2[0123])))
day/month/year = (((0[1-9])|([12][0-9])|(3[01]))\/((0[0-9])|(1[012]))\/((20[012]\d|19\d\d)|(1\d|2[0123])))
day.month.year = (((0[1-9])|([12][0-9])|(3[01]))\.((0[0-9])|(1[012]))\.((20[012]\d|19\d\d)|(1\d|2[0123])))
year.month.day = (((20[012]\d|19\d\d)|(1\d|2[0123]))\.((0[0-9])|(1[012]))\.((0[1-9])|([12][0-9])|(3[01])))
all = (((20[012]\d|19\d\d)|(1\d|2[0123]))-((0[0-9])|(1[012]))-((0[1-9])|([12][0-9])|(3[01])))|(((0[1-9])|([12][0-9])|(3[01]))-((0[0-9])|(1[012]))-((20[012]\d|19\d\d)|(1\d|2[0123])))|(((20[012]\d|19\d\d)|(1\d|2[0123]))\/((0[0-9])|(1[012]))\/((0[1-9])|([12][0-9])|(3[01])))|(((0[0-9])|(1[012]))\/((0[1-9])|([12][0-9])|(3[01]))\/((20[012]\d|19\d\d)|(1\d|2[0123])))|(((0[1-9])|([12][0-9])|(3[01]))\/((0[0-9])|(1[012]))\/((20[012]\d|19\d\d)|(1\d|2[0123])))|(((0[1-9])|([12][0-9])|(3[01]))\.((0[0-9])|(1[012]))\.((20[012]\d|19\d\d)|(1\d|2[0123])))|(((20[012]\d|19\d\d)|(1\d|2[0123]))\.((0[0-9])|(1[012]))\.((0[1-9])|([12][0-9])|(3[01])))
its work for
yyyy-mm-dd
dd-mm-yyyy
yyyy/mm/dd
mm/dd/yyyy
dd/mm/yyyy
dd.mm.yyyy
yyyy.mm.dd
yy-mm-dd
dd-mm-yy
yyyy/mm/dd
mm/dd/yy
dd/mm/yy
dd.mm.yy
yy.mm.dd
but not work for where day = d or month = m, example d.m.yyyy
all example - enter link description here
Here I wrote one for dd/mm/yyyy where separator can be one of -.,/ year range 0000-9999.
It deals with leap years and is designed for regex flavors, that support lookaheads, capturing groups and backreferences. NOT valid for such as d/m/yyyy. If needed add further separators to [-.,/]
^(?=\d{2}([-.,\/])\d{2}\1\d{4}$)(?:0[1-9]|1\d|[2][0-8]|29(?!.02.(?!(?!(?:[02468][1-35-79]|[13579][0-13-57-9])00)\d{2}(?:[02468][048]|[13579][26])))|30(?!.02)|31(?=.(?:0[13578]|10|12))).(?:0[1-9]|1[012]).\d{4}$
Test at regex101; as a Java string:
"^(?=\\d{2}([-.,\\/])\\d{2}\\1\\d{4}$)(?:0[1-9]|1\\d|[2][0-8]|29(?!.02.(?!(?!(?:[02468][1-35-79]|[13579][0-13-57-9])00)\\d{2}(?:[02468][048]|[13579][26])))|30(?!.02)|31(?=.(?:0[13578]|10|12))).(?:0[1-9]|1[012]).\\d{4}$"
explained:
(?x) # modifier x: free spacing mode (for comments)
# verify date dd/mm/yyyy; possible separators: -.,/
# valid year range: 0000-9999
^ # start anchor
# precheck xx-xx-xxxx,... add new separators here
(?=\d{2}([-.,\/])\d{2}\1\d{4}$)
(?: # day-check: non caturing group
# days 01-28
0[1-9]|1\d|[2][0-8]|
# february 29d check for leap year: all 4y / 00 years: only each 400
# 0400,0800,1200,1600,2000,...
29
(?!.02. # not if feb: if not ...
(?!
# 00 years: exclude !0 %400 years
(?!(?:[02468][1-35-79]|[13579][0-13-57-9])00)
# 00,04,08,12,...
\d{2}(?:[02468][048]|[13579][26])
)
)|
# d30 negative lookahead: february cannot have 30 days
30(?!.02)|
# d31 positive lookahead: month up to 31 days
31(?=.(?:0[13578]|10|12))
) # eof day-check
# month 01-12
.(?:0[1-9]|1[012])
# year 0000-9999
.\d{4}
$ # end anchor
Also see SO Regex FAQ; Please let me know, if it fails.
Found this reg ex here
^(((0[1-9]|[12]\d|3[01])\/(0[13578]|1[02])\/((19|[2-9]\d)\d{2}))|((0[1-9]|[12]\d|30)\/(0[13456789]|1[012])\/((19|[2-9]\d)\d{2}))|((0[1-9]|1\d|2[0-8])\/02\/((19|[2-9]\d)\d{2}))|(29\/02\/((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))$
This validates the format mm/dd/yyyy and valid dates correctly (but not m/d/yyyy).
Some tests
"^(0[1-9]|[12][0-9]|3[01])[- /.](0[1-9]|1[012])[- /.]((19|20)\\d\\d)$"
will validate any date between 1900-2099
The following expression is nice and easy to manipulate:
((((0[13578]|1[02])(\/|-|.)(0[1-9]|1[0-9]|2[0-9]|3[01]))|((0[469]|11)(\/|-|.)(0[1-9]|1[0-9]|2[0-9]|3[0]))|((02)((\/|-|.)(0[1-9]|1[0-9]|2[0-8]))))(\/|-|.)(19([6-9][0-9])|20(0[0-9]|1[0-4])))|((02)(\/|-|.)(29)(\/|-|.)(19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26])))
It validates according to the MM/dd/YYYY format and allows for leap year support from 1960 to 2016. If you need the leap year support extended you need only manipulate this part of the expression:
(19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]))
Hope this helped you a lot
Another answer which validates day (dd) depending upon the month (mm) and the year (yyyy) (i.e., also validates 29th Feb in leap years) and allows years ranging from 0001 to 9999 (0000 in a invalid year according to the Gregorian calendar)
^(?:(?:(?:0[1-9]|[12]\d|3[01])/(?:0[13578]|1[02])|(?:0[1-9]|[12]\d|30)/(?:0[469]|11)|(?:0[1-9]|1\d|2[0-8])/02)/(?!0000)\d{4}|(?:(?:0[1-9]|[12]\d)/02/(?:(?!0000)(?:[02468][048]|[13579][26])00|(?!..00)\d{2}(?:[02468][048]|[13579][26]))))$
The best way according to me is to use the Moment.js isValid() method by specifying the format and use strict parsing.
As moment.js documentation says
As of version 2.3.0, you may specify a boolean for the last argument
to make Moment use strict parsing. Strict parsing requires that the
format and input match exactly, including delimiters.
value = '2020-05-25';
format = 'YYYY-MM-DD';
moment(value, format, true).isValid() // true
Further extended the regex given by #AlokChaudhary to support:
1. dd mmm YYYY (in addition to dd-mmm-YYYY, dd/mmm/YYYY, dd.mmm.YYYY).
2. mmm in all CAPITAL LETTERS format (in addition to Title format)
dd mmm YYYY e.g. 30 Apr 2026 or 24 DEC 2028 are popular.
Extended regex:
(^(?:(?:(?:31(?:(?:([-.\/])(?:0?[13578]|1[02])\1)|(?:([-.\/ ])(?:Jan|JAN|Mar|MAR|May|MAY|Jul|JUL|Aug|AUG|Oct|OCT|Dec|DEC)\2)))|(?:(?:29|30)(?:(?:([-.\/])(?:0?[13-9]|1[0-2])\3)|(?:([-.\/ ])(?:Jan|JAN|Mar|MAR|Apr|APR|May|MAY|Jun|JUN|Jul|JUL|Aug|AUG|Sep|SEP|Oct|OCT|Nov|NOV|Dec|DEC)\4))))(?:(?:1[6-9]|[2-9]\d)?\d{2}))$|^(?:29(?:(?:([-.\/])(?:0?2)\5)|(?:([-.\/ ])(?:Feb|FEB)\6))(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00)))$|^(?:(?:0?[1-9]|1\d|2[0-8])(?:(?:([-.\/])(?:(?:0?[1-9]|(?:1[0-2])))\7)|(?:([-.\/ ])(?:Jan|JAN|Feb|FEB|Mar|MAR|May|MAY|Jul|JUL|Aug|AUG|Oct|OCT|Dec|DEC)\8))(?:(?:1[6-9]|[2-9]\d)?\d{2}))$)
Test cases included in the Regex Demo
Features (retained):
Leap year checking (Feb 29 validation) includes the logics: (divisible by 4 but not divisible by 100) or (divisible by 400)
Supports years 1600 ~ 9999
Supports dd/mm/YYYY, dd-mm-YYYY, dd.mm.YYYY (but not dd mm YYYY)
Supports dd mmm YYYY, dd-mmm-YYYY, dd/mmm/YYYY, dd.mmm.YYYY (dd mmm YYYY newly added. mmm can be in CAPITAL e.g. DEC or Title format e.g. Dec)
Some additional minor touch-up as follows:
Included the fix by Ofir Luzon on February 14th 2019 to remove a comma that was in the regex which allowed dates like 29-0,-11 [error replicated to Alok Chaudhary's regex]
Replaced (\/|-|\.) by ([-.\/]) to minimize the use of backslash. \/ is still used in order to support some regex flavor e.g. PCRE(PHP) although some other regex flavor e.g. Python can simply use / inside the character class [ ]
Added a pair of parenthesis () surrounding the whole regex to make it a capturing group for the whole matching string. This is useful for people using findAll type of functions to get a matching item list (e.g. re.findall in Python). This enable us to capture all the matching strings within a mult-line string with the following codes:
re.findall sample codes:
match_list = re.findall(regex, source_string)
for item in match_list:
print(item[0])
Extended regex image:
Credits should go to Ofir Luzon and Alok Chaudhary who created such excellent regexes for us all!
I'm working with an API that only accepts MM/DD/YYYY format. I couldn't find any other post that did leap years quite as well as Ofir's answer, so I tweaked it and am re-posting it here for anyone that might need it.
/^(?:(?:(?:0[13578]|1[02])(\/)31)\1|(?:(?:0[1,3-9]|1[0-2])(\/)(?:29|30)\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:02(\/)29\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/)(?:0[1-9]|1\d|2[0-8])\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$/
In case you are looking for specific format, This works fine for "dd/MM/yyyy" & "dd/MMM/yyyy" date format only based on Alok answer.
function isValidDateFormatDDMMYYYY(inputDate) {
var date_regex = /^(?:(?:31(\/)(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec)))\1|(?:(?:29|30)(\/)(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/)(?:0?2|(?:Feb))\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/)(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$/;
return date_regex.test(inputDate);
}
Few examples working thru this code -
isValidDateFormatDDMMYYYY("15/01/1999") // returns True
isValidDateFormatDDMMYYYY("15/Jan/1999") // returns True
isValidDateFormatDDMMYYYY("15/1/1999") // returns True
isValidDateFormatDDMMYYYY("1/15/1999") // returns False
Thanks
import re
expression = "Nov 05 20:10:09 2020"
reg_ex = r'((Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) ([0-2][0-9]|(3)[0-1]) (([0-1][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])) (\d{4}))'
assert re.fullmatch(reg_ex, expression), True
Expaination with respect to given Example
Nov = A group of possible months i.e. (Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)
05 = A group of valid days i.e. ([0-2][0-9]|(3)[0-1])
20:10:09 = A group for getting valid Hours : ([0-1][0-9]|2[0-3]), Minutes : ([0-5][0-9]) and Seconds : ([0-5][0-9])
2020 = A group for getting year i.e (\d{4}))
Please Following Expression
Regex regex = new Regex(#"(((0|1)[0-9]|2[0-9]|3[0-1])\/(0[1-9]|1[0-2])\/((19|20)\d\d))$");
((((0[13578]|1[02])\/(0[1-9]|1[0-9]|2[0-9]|3[01]))|((0[469]|11)\/(0[1-9]|1[0-9]|2[0-9]|3[0]))|((02)(\/(0[1-9]|1[0-9]|2[0-8]))))\/(19([6-9][0-9])|20([0-9][0-9])))|((02)\/(29)\/(19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]|2[048])))
will validate MM/DD/YYYY format with 1960 to 2028
if you need to extend leap year support then add
19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]|2[048]|3[26]|4[048])))
this is also work
^((((0[13578]|1[02])[/](0[1-9]|1[0-9]|2[0-9]|3[01]))|((0[469]|11)[/](0[1-9]|1[0-9]|2[0-9]|3[0]))|((02)([/](0[1-9]|1[0-9]|2[0-8]))))[/](19([6-9][0-9])|20([0-9][0-9])))|((02)[/](29)[/](19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]|2[048])))
if you can change format mm-dd-yyyy than replace [/] to [-]
also check online http://regexr.com/
For date MM/DD/YYYY you can use
^((((0[13578])|([13578])|(1[02]))[\/](([1-9])|([0-2][0-9])|(3[01])))|(((0[469])|([469])|(11))[\/](([1-9])|([0-2][0-9])|(30)))|((2|02)[\/](([1-9])|([0-2][0-9]))))[\/]\d{4}$|^\d{4}$
It verify proper days and moths.
Remeber that you can check your regular expression at
regex101
which i recommend :)
Have fun!
^(((([13578]|0[13578]|1[02])[-](0[1-9]|[1-9]|1[0-9]|2[0-9]|3[01]))|(([469]|0[469]|11)[-]([1-9]|1[0-9]|2[0-9]|3[0]))|((2|02)([-](0[1-9]|1[0-9]|2[0-8]))))[-](19([6-9][0-9])|20([0-9][0-9])))|((02)[-](29)[-](19(6[048]|7[26]|8[048]|9[26])|20(0[048]|1[26]|2[048])))
this regex will validate dates in format:
12-30-2016 (mm-dd-yyyy) or 12-3-2016 (mm-d-yyyy) or
1-3-2016 (m-d-yyyy) or 1-30-2016 (m-dd-yyyy)
I know it is a tangential answer to the question, but if the intention of the question is 'how do I validate a date?', then why not try letting the programming language do all the hard work (if you are using a language that can)?
e.g. in php
$this_date_object = date_create($this_date);
if ($this_date_object == false )
{
// process the error
}
For use only for the day:
<input placeholder="day" maxlength="2" minlength="1" formControlName="birthDay"
name="birthDay"pattern="(0[1-9]|1[0-9]|2[0-9]|3[0-1])" >/
For use only for the month:
<input placeholder="month" maxlength="2" minlength="1"
formControlName="month" name="month" formControlName="month" name="month" pattern="(0[1-
9]|1[0-2])">/
I know it's been a long time since this was answered, but maybe this could help someone else. The thing is that i wanted to, also, check the year, and let some past years match too. This regex match dates formated as "DD-MM-YYYY". So this function will return a regex:
const check_year = "01-01-2021"
console.log(get_regex())
console.log(check_year.match(get_regex()))
function get_regex(){
let actual_year = `${new Date().getFullYear()}`
let regex = new RegExp()
let split_year = actual_year.split("")
let year_regex = `${split_year[0]}[0-${split_year[1]}][0-${split_year[2]}][0-${split_year[3]}]$`
let day_month_regex = "^([1-2][0-9]|3[0-1]|0?[1-9])[-]([1][0-2]|0?[1-9])[-]"
regex.compile(day_month_regex+year_regex, "g")
return regex
}
simple function for python
def is_valid_date(date_text):
pattern = re.compile('\d{4}-\d{2}-\d{2}$')
return pattern.match(date_text)
This is a regex to match strings of the date format, YYYY-MM-DD, with different kind of separators. It matches a string even in sentences, and with dates ending with st, nd and others.
As an example, it matches the date in these sentences:
"Her birthday is 2022 February 23rd; I will present here a gift."
"Her birthday is 2022 Feb 23rd; I will present here a gift."
"Her birthday is 2022 02 23; I will present here a gift."
This is the date regex:
"\b
(?<YYYY>[0-9]{4})
(?<!0000)(?<sep>[ /.,-])
(?|
(?:(?<MM>0[13578]|1[02]|Jan(?:uary)?|Mar(?:ch)?|May|Jul(?:y)?|Aug(?:ust)?|Oct(?:ober)?|Dec(?:ember)?)\g{sep}(?<DD>0[1-9]|[12][0-9]|3[01]))|
(?:(?<MM>0[469]|11|Apr(?:il)?|Jun(?:e)?|Sep(?:tember)?|Nov(?:ember)?)\g{sep}(?<DD>0[1-9]|[12][0-9]|30))|
(?:(?<MM>02|Feb(?:ruary)?)\g{sep}(?<DD>0[1-9]|[12][0-9]))
)
(?:
(?<=[023][1])st|
(?<=[02][2])nd|
(?<=[02][3])rd|
(?<=(?:0[4-9])|(?:1[0-9])|20|(?:2[4-9])|30)th
)?
[,;.]?
\b"x
IMHO, it makes no sense for a regex to check for a leap year, when a simple, clear and understandable one-liner can be written for it:
is_leap_year(y) = ((y%4 == 0) && (y%100 != 0)) || (y%400 == 0)
Regexes are for matching strings and not for carrying out calculation. The best way is to match the string and then pass the captured MM group to the is_leap_year function if its 02, Feb or February, to validate the string.
Given a value I want to validate it to check if it is a valid year. My criteria is simple where the value should be an integer with 4 characters. I know this is not the best solution as it will not allow years before 1000 and will allow years such as 5000. This criteria is adequate for my current scenario.
What I came up with is
\d{4}$
While this works it also allows negative values.
How do I ensure that only positive integers are allowed?
Years from 1000 to 2999
^[12][0-9]{3}$
For 1900-2099
^(19|20)\d{2}$
You need to add a start anchor ^ as:
^\d{4}$
Your regex \d{4}$ will match strings that end with 4 digits. So input like -1234 will be accepted.
By adding the start anchor you match only those strings that begin and end with 4 digits, which effectively means they must contain only 4 digits.
The "accepted" answer to this question is both incorrect and myopic.
It is incorrect in that it will match strings like 0001, which is not a valid year.
It is myopic in that it will not match any values above 9999. Have we already forgotten the lessons of Y2K? Instead, use the regular expression:
^[1-9]\d{3,}$
If you need to match years in the past, in addition to years in the future, you could use this regular expression to match any positive integer:
^[1-9]\d*$
Even if you don't expect dates from the past, you may want to use this regular expression anyway, just in case someone invents a time machine and wants to take your software back with them.
Note: This regular expression will match all years, including those before the year 1, since they are typically represented with a BC designation instead of a negative integer. Of course, this convention could change over the next few millennia, so your best option is to match any integer—positive or negative—with the following regular expression:
^-?[1-9]\d*$
This works for 1900 to 2099:
/(?:(?:19|20)[0-9]{2})/
Building on #r92 answer, for years 1970-2019:
(19[789]\d|20[01]\d)
To test a year in a string which contains other words along with the year you can use the following regex: \b\d{4}\b
In theory the 4 digit option is right. But in practice it might be better to have 1900-2099 range.
Additionally it need to be non-capturing group. Many comments and answers propose capturing grouping which is not proper IMHO. Because for matching it might work, but for extracting matches using regex it will extract 4 digit numbers and two digit (19 and 20) numbers also because of paranthesis.
This will work for exact matching using non-capturing groups:
(?:19|20)\d{2}
Use;
^(19|[2-9][0-9])\d{2}$
for years 1900 - 9999.
No need to worry for 9999 and onwards - A.I. will be doing all programming by then !!! Hehehehe
You can test your regex at https://regex101.com/
Also more info about non-capturing groups ( mentioned in one the comments above ) here http://www.manifold.net/doc/radian/why_do_non-capture_groups_exist_.htm
you can go with sth like [^-]\d{4}$: you prevent the minus sign - to be before your 4 digits.
you can also use ^\d{4}$ with ^ to catch the beginning of the string. It depends on your scenario actually...
/^\d{4}$/
This will check if a string consists of only 4 numbers. In this scenario, to input a year 989, you can give 0989 instead.
You could convert your integer into a string. As the minus sign will not match the digits, you will have no negative years.
I use this regex in Java ^(0[1-9]|1[012])[/](0[1-9]|[12][0-9]|3[01])[/](19|[2-9][0-9])[0-9]{2}$
Works from 1900 to 9999
If you need to match YYYY or YYYYMMDD you can use:
^((?:(?:(?:(?:(?:[1-9]\d)(?:0[48]|[2468][048]|[13579][26])|(?:(?:[2468][048]|[13579][26])00))(?:0?2(?:29)))|(?:(?:[1-9]\d{3})(?:(?:(?:0?[13578]|1[02])(?:31))|(?:(?:0?[13-9]|1[0-2])(?:29|30))|(?:(?:0?[1-9])|(?:1[0-2]))(?:0?[1-9]|1\d|2[0-8])))))|(?:19|20)\d{2})$
You can also use this one.
([0-2][0-9]|3[0-1])\/([0-1][0-2])\/(19[789]\d|20[01]\d)
In my case I wanted to match a string which ends with a year (4 digits) like this for example:
Oct 2020
Nov 2020
Dec 2020
Jan 2021
It'll return true with this one:
var sheetName = 'Jan 2021';
var yearRegex = new RegExp("\b\d{4}$");
var isMonthSheet = yearRegex.test(sheetName);
Logger.log('isMonthSheet = ' + isMonthSheet);
The code above is used in Apps Script.
Here's the link to test the Regex above: https://regex101.com/r/SzYQLN/1
You can try the following to capture valid year from a string:
.*(19\d{2}|20\d{2}).*
Works from 1950 to 2099 and value is an integer with 4 characters
^(?=.*?(19[56789]|20\d{2}).*)\d{4}$