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I would like to format many chains of a text in italic. They are of the type 'Arbre 10523' I can capture them with
(Arbre)\b [0-9]{3,5}
but I do not know how to transform all these words in italic, if I replace the chain is just erased.
Thanks
Are you talking about LibreOffice Writer? If so, you can use the Find & Replace function from the ribbon (or Ctrl+H). Make sure to select 'Match Case' for case-sensitive matching, 'Regular Expresions' and select 'Italic' under Format:
I used the pattern:
\b(Arbre \d{3,5}(?!\d))
\b - Word-boundary to assert position is not preceded with other word-characters;
( - Open a capture group for backreference in the replace field;
Arbre \d{3,5} - Match 'Arbre ' followed by 3-5 digits;
(?!\d) - Negative lookahead to assert position is not followed by more digits;
) - Close capture group.
Now refer to $1 in your replace field. Then click replace all:
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I have set of numbers format like 1.8789 and would like the output to become 1878.9
These number is inside specific column and have million lines to be update.
I didn't find any similar to solve this.
Below is the highlight screenshot.
data set
For the exact style/precision of number you gave, you may try the following find and replace, in regex mode:
Find: (\d+)\.(\d{3})(\d+)
Replace: $1$2.$3
Demo
Try this code ...
Find: (?<=1)\.(\d{3})
Replace with: $1.
As far as I understand, you want to change only the last column. Here is a way to go:
Ctrl+H
Find what: \.(\d{3})(?=\d*$)
Replace with: $1.
CHECK Wrap around
CHECK Regular expression
Replace all
Explanation:
\. # a dot
(\d{3}) # group 1, 3 digits
(?= # positive lookahead, make sure we have after:
\d* # 0 or more digits
$ # end of line
) # end lookahead
Replacement:
$1 # content of group 1, 3 digits
. # a dot
Screenshot (before):
Screenshot (after):
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I'm working on a regex to take #users
In italian, sometime there is something like l'#Orazio.
I can't find the right way to take this.
I'm using this line /(?<=^|\s)(#(\S+))/
this is my online tester
https://regex101.com/r/s5BTm0/12
as you can see I have an issue with the case 4
Any tips?
You may use
(?<!\S)(?:\w+['’])?#(\S+)
(?<!\w)(?:\w+['’])?#(\S+)
See the regex demo
Details
(?<!\S) - whitespace or start of string must appear immediately to the left of the current location
(?<!\w) - a location the is not immediately preceded with a word char
(?:\w+['’])? - an optinal sequence of 1+ word chars and then ' or ’
# - a # char
(\S+) - Capturing group 1: one or more non-whitespace chars.
Use an optional group:
(?<=^|\s)(?:\w?'?)(#(\S+))
https://regex101.com/r/s5BTm0/5
For more than 1 letter in front, use:
(?<=^|\s)(?:(\w*')?)(#(\S+))
https://regex101.com/r/s5BTm0/8
And to match all your updated cases:
https://regex101.com/r/s5BTm0/10
For different types of apostrophes:
(?<=^|\s)(?:(\w*['´])?)(#(\S+))
https://regex101.com/r/s5BTm0/13
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I want to match a string where there are 5 characters where first four characters are A-Z and 5th is a digit. Also the first and the fourth character should be same.
I have a regex: [A-Z]{4}\d
However this wont check if 1st and 4th character are same. Please help
Regex: ^([A-Z])[A-Z]{2}\1\d$
1. ^ start of string.
2. ([A-Z]) capture first character.
3. [A-Z]{2} match next two character which can be in A-Z
4. \1 using captured group which contains first character of string.
5. \d a digit which can be 0-9
6. $ for end of string.
Regex demo
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I have in Notepad++ plenty of datetime texts like:
'20160310 17:59:00'
And I want to add '-' character to separate numbers in the date like
'2016-03-10 17:59:00'
How I would be a RegEx expression to do that?
The following regex expression:
('\d{4})(\d{2})(\d{2} \d{2}:\d{2}:\d{2}')
Combined with the following replace expression:
$1-$2-$3
will achieve what you want.
Explanation:
('\d{4}) capture group 1: an apostrophe followed by 4 digits
(\d{2}) capture group 2: 2 digits
(\d{2} \d{2}:\d{2}:\d{2}') capture group 3: 2 digits, a space, 2 digits, a colon, 2 digits, a colon and 2 digits, followed by an apostrophe
$1-$2-$3 - capture group 1, followed by a -, followed by capture group 2, followed by a -, followed by capture group 3
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I have these inputs:
DFDBDFDFDF21R123
DFDBDFDFDF34R123
I want to match these inputs, except positions 9 and 10, like below:
DFDBDFDFxxR123
DFDBDFDFxxR123
So, to be clear: match 1-8, exclude 9-10, match 11-16.
To expand upon the answer from https://stackoverflow.com/users/557597/sln of
(.{8})..(.+)
The 'thing' you are missing from your understanding of Regex is 'grouping'
(SOME MATCHING SUB-STRING A)(SOME MATCHING SUB-STRING B)
If you use regex like this, you can do lots of nice things including 'pull out' parts of a line and then re-arrange them. But it also helps you group 'parts' that you want to search for.
so his
.{8}
matches '.' which is 'any single character' and then {8} means 'match any single character 8 times.
(.{8})
means 'group the first 8 characters' for use.
..
means 'match any two characters'
.+
means 'match 1 or more of 'any character'
(.+)
means "group that 1 or more of 'any character' for later use"
Therefore...
When you put them all together you get
(.{8})..(.+)
Which means 'match the first 8 characters (any 8 characters) as group 1' then 'any two characters' then '1 or more characters as group 2'
This would allow you to (depending on your regex client/etc.) is use $1 and $2 to print out, use or ...whatever... the values of group 1 and/or group 2.
Hope this helps.