Django models: you need to display the menu and submenus - django

Question

Can you please help. That's the question. I have a menu, the name of the menu is 'catr' and there is a submenu 'subcat' , I want to make the entire menu list output, and if the menu id matches the menu, then a subcategory is output, but I don't understand how to implement it.Help please.Sorry if I didn't explain it clearly, I hope you will understand, thank you in advance
Here's what I tried to do
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Answer 1

From what I can understand you can do this using functions in your models like this...
class Category(models.Model):
name = models.CharField(max_length=100 db_index=True)
slug= models.SlugField(max_length=255, unique=True, db_index=True, verbose_name = 'URL')
def ___str__(self):
return self.name
def get_absolute_url(self):
return reverse('category' kwargs={'cat_slug':self.slug})
def get_sub_category(self):
return Subcategory.objects.filter(parent_category=self)
class Meta:
verbose_name = 'Kатегоpии'
verbose_name_plural = 'Kaтегоpии'
ordering = ['id']
and in your templates do this...
{% for item in catr %}
<li>
{{item.name}}
{% if item.get_sub_category %}
<ul>
{% for child in item.get_sub_category %}
<li>{{ child.sub }}</li>
{% endfor %}
</ul>
{% endif %}
</li>
{% endfor %}