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How to work with Base 8 (Octal) numbers?
(3 answers)
Octal number literals: When? Why? Ever? [closed]
(13 answers)
Closed 3 months ago.
uint32_t number = 00000000000000000000000000001011;
std::cout << number;
Why is the number's value 521 here?
Number literals starting with a zero are interpreted as octal numbers (base 8).
1011 in base 8 is 521.
Related
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Is floating point math broken?
(31 answers)
Are all integer values perfectly represented as doubles? [duplicate]
(5 answers)
Closed 2 years ago.
I have the following snippet
cout.precision(30);
long double d = 85952643841691072928.0;
cout << d << endl;
The print statement outputs 85952643841691074560. Why are the last 4 digits before the decimal incorrect? A long double should be capable of handling a number of this size?
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Why is initializing an integer in C++ to 010 different from initializing it to 10?
(4 answers)
Closed 4 years ago.
What happened here?
long long value;
value = 001111011112;
in Visualstudio debugging, the value shows with value 153358922.
If the number doesn't start with 0, all is correct...
Any recommendations how to keep using my initialization style?
In C++, a number beginning by 0 is an octal (base 8) literal.
If you want to print this value with leading zeros, you can do:
long long value;
value = 1111011112;
cout << setw(12) << setfill('0') << value;
This question already has answers here:
How does C Handle Integer Literals with Leading Zeros, and What About atoi?
(8 answers)
Closed 8 years ago.
Why does:
int test() {
return 00101 % 10;
}
return 5, while:
int test() {
return 101 % 10;
}
returns 1? I can't think of an explanation.
Integer literals beginning with 0 like
00101
is actually an octal constant.
00101 is octal value which is 65 in decimal so it returns 5.
00101 is in octal which is equal to 65 in decimal, so that is why the modulus operator will always give us 5.
You can do octal to decimal converstion on this link http://www.rapidtables.com/convert/number/octal-to-decimal.htm
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Floating point inaccuracy examples
(7 answers)
exact representation of floating points in c
(9 answers)
Closed 8 years ago.
As the title states, I'd like to start from 1 and decrement with by 0.01 all the way down to zero.
Problem is, I'm using floats and I keep getting values such as 0.5000000001.
Simply use an int, Start at 100 decrement down to 0 and divide the value by 100.0
for (int i=100; i>=0; --i)
{
float f = i/100.0f;
...
}
This question already has answers here:
What does it mean when a numeric constant in C/C++ is prefixed with a 0?
(7 answers)
Closed 7 years ago.
This code, when I run it on C++ Borland compiler 5.02
#include<iostream.h>
void main()
{
int x;
cin>>x;
cout << x;
}
When enter 0010 to x, the output is 8? And these for some entries that have zeroes on its left, but not all?
In C++:
Octal numbers have a leading 0.
Hexadecimal numbers have a leading 0x.
Otherwise, you have a decimal number.
Therefore:
0x10 is a hexadecimal number representing 16.
010 is an octal number representing 8.
10 is a decimal number representing 10.