This question already has answers here:
Is floating point math broken?
(31 answers)
Are all integer values perfectly represented as doubles? [duplicate]
(5 answers)
Closed 2 years ago.
I have the following snippet
cout.precision(30);
long double d = 85952643841691072928.0;
cout << d << endl;
The print statement outputs 85952643841691074560. Why are the last 4 digits before the decimal incorrect? A long double should be capable of handling a number of this size?
Related
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How to work with Base 8 (Octal) numbers?
(3 answers)
Octal number literals: When? Why? Ever? [closed]
(13 answers)
Closed 3 months ago.
uint32_t number = 00000000000000000000000000001011;
std::cout << number;
Why is the number's value 521 here?
Number literals starting with a zero are interpreted as octal numbers (base 8).
1011 in base 8 is 521.
This question already has answers here:
Is floating point math broken?
(31 answers)
Why are floating point numbers inaccurate?
(5 answers)
Floating point comparison `a != 0.7` [duplicate]
(3 answers)
Closed 1 year ago.
This is a simple code which should have printed "No" , but its printing "Yes". It works fine if I use double instead of float Or compare digits upto 1 decimal place. I am using online C++14(gcc+14) compiler here. Why is this happening?
#include <iostream>
using namespace std;
int main() {
float s= 10.11;
cout<<(( s < 10.11) ? "Yes": "No")<<endl;
return 0;
}
This question already has answers here:
Why does division result in zero instead of a decimal?
(5 answers)
Closed 3 years ago.
I want to write 4/3 as a fraction in C++. I know that 4/3 is equal to 1.33333. But when I write 4/3 in the code it outputs it's quotient which is 1. Can anyobody tell me how to write this number as fraction?
The code:
double vol_sphere(double radiusS){
return (4/3) * pi * pow(radiusS, 3);
}
Because 4 and 3 are both integers, when you perform division of two integers, the result will be also integer, so 1.333333333 will be only 1.
This question already has answers here:
How do I print a double value with full precision using cout?
(17 answers)
Printing the correct number of decimal points with cout
(13 answers)
c++ cout << [double] not printing decimal places
(2 answers)
Closed 3 years ago.
setlocale(LC_ALL, "Portuguese");
double var = 1.0;
cout << var << endl;
system("pause");
return 0;
output:
1
Press any key to continue . . .
float and double only represent the values of numbers. “1” and “1.0” are both numerals for the same number, so 1 is the correct value of the var you set to 1.0. float and double do not represent the original numerals used to set their values, nor do they represent how much accuracy (relative to some ideal mathematical value) is present. The “1” you see as output is a result of default formatting. Other formatting options are available, but you must specify them yourself.
This question already has answers here:
Floating point inaccuracy examples
(7 answers)
exact representation of floating points in c
(9 answers)
Closed 8 years ago.
As the title states, I'd like to start from 1 and decrement with by 0.01 all the way down to zero.
Problem is, I'm using floats and I keep getting values such as 0.5000000001.
Simply use an int, Start at 100 decrement down to 0 and divide the value by 100.0
for (int i=100; i>=0; --i)
{
float f = i/100.0f;
...
}