I have tis jdcb call results
[{string_agg=1268#jm_eo_2283,1343#jm_eo_2333}]
so i use this regex code to remove brackets (?<=[=]).*\d
In theory i should get only
jm_eo_2283,1343#jm_eo_2333
i have 2022-08-30 13:35:49,291 ERROR o.a.j.e.RegexExtractor: Error in pattern: '(?<=[=]).*\d'
Any idea what is going on?? Is a way to get the result without brackets??
According to the JDBC Request sampler documentation:
If the Variable Names list is provided, then for each row returned by a Select statement, the variables are set up with the value of the corresponding column (if a variable name is provided), and the count of rows is also set up. For example, if the Select statement returns 2 rows of 3 columns, and the variable list is A,,C, then the following variables will be set up:
A_#=2 (number of rows)
A_1=column 1, row 1
A_2=column 1, row 2
C_#=2 (number of rows)
C_1=column 3, row 1
C_2=column 3, row 2
So you should be able to access:
first row as ${eo_id_1}
second row as ${eo_id_2}
etc.
More information: Using JDBC Sampler in JMeter
You can use
=[0-9]*#(.*[0-9])
See the regex demo. Keep the template field set to $1$, it will extract the value captured with the first parenthesized pattern part.
Details:
= - a = sign
[0-9]* - zero or more digits
# - a # char
(.*[0-9]) - Group 1 ($1$): any zero or more chars other than line break chars as many as possible, and then a digit.
Related
I am new to regex and having difficulty obtaining values that are caught in between spaces.
I am trying to get the values "field 1" "abc/def try" from the sameple data below just using regex
Currently im using (^.{18}\s+) to skip the first 18 characters, but am at at loss of how to do grab values with spaces between.
A1234567890 field 1 abc/def try
02021051812 12 test test 12 pass
3333G132021 no test test cancel
any help/pointers will be appreciated.
If this text has fixed-width columns, you can match and trim the column values knowing the amount of chars between start of string and the column text.
For example, this regex will work for the text you posted:
^(.*?)\s*(?<=.{19})(.*?)\s*(?<=^.{34})(.*?)\s*(?<=^.{46})
See the regex demo.
So, Column 2 starts at Position 19, Column 3 starts at Position 34 and Column 4 (end of string here) is at Position 46.
However, this regex is not that efficient, and it would be really great if the data format is fixed on the provider's side.
Given the not knowing if the data is always the same length I created the following, which will provide you with a group per column you might want to use:
^((\s{0,1}\S{1,})*)(\s{2,})((\s{0,1}\S{1,})*)(\s{2,})((\s{0,1}\S{1,})*)
Regex demo
I have a scenario which I am not able to do in 10.7 version. Basically, I have a data column in which I need to find the Reg Exp pattern inside the data which is in the form of notes/comments/description.
For example, Data in the column : The SSN number is 760-56-6289
In the above data 760-56-6289 is the actual SSN number which I need to find across all schemas/tables/columns for the defined reg exp pattern. And, we can have a pre or post text for actual SSN value.
Could you please let me know how to achieve this PostgreSQL 10.7?
Please let me know if you need more information for the same.
demo:db<>fiddle
SELECT
(regexp_matches(mycolumn, '^.*([\d]{3}-[\d]{2}-[\d]{4}).*$'))[1]
FROM mytable
The RegEx means:
Start of text: ^
arbitrary number of characters: .*
group of your number: (...)
3 digit characters: [\d]{3}
- character
2 digits: [\d]{2}
- character
4 digits: [\d]{4}
arbitrary number of characters: .*
end of text: $
regexp_matches() gives out all found groups as an array. So, there is only one group, the array contains only one value. This is your number which can be get with the index [1]
I have the below string:
rollover#7500,another1#3000,another2#4000, another1#7000
I need to extract the number that comes directly after rollover#
So far, I have this, but it's matching rollover#7500
(?:rollover#[0-9]*)
I'm not sure how to extract only the numbers?
I will be running this in a Hive query
You may use
regexp_extract(your_col,'rollover#([0-9]+)', 1)
The rollover#([0-9]+) pattern will find rollover# and then will capture 1 or more digits into Group 1, the third 1 argument will make regexp_extract return just the Group 1 value.
I'm having difficulties extracting irregular data using Regex. I attempted to use Lookheads however when the value doesn't exist the entire match returns false. The data set is consistent all the way until I reach the characters starting with RXX. The RXX are unique identifiers (groups) and the numeric values in between each set of Rxx's is what I would like to capture and assigned them to group names.
The Rxx values are random from R01 to R15 and 1 to all 15 could exist in the string.
The string values could vary from
12*000000000**S304JB01811*8*0*8*4*4*34R0332R152~~~
12*000000000**S304JB01811*9*0*4*3*4*224R023R032R10234R1325~~~
I'm able to extract the values and assign a group name until I reach the Rxx
My attempt are extracting the values are as follow
S304JB0...(?<Total1>[\d]+).(?<Total2>[\d]+).(?<Total3>[\d]+).(?<Total4>[\d]+).(?<Total5>[\d]+).(?<Total6>[\d]+).(?<Total7>[\d]+)
Which gives me what I want below
Total1 `1`
Total2 `8`
Total3 `0`
Total4 `8`
Total5 `4`
Total6 `4`
Total7 `34`
Capturing the R03 value and assigning it to Row is achieved below but if the value R03 doesn't exist in the string then the entire match returns false
(?<Row3>(R03)[\d]+)
Looking how I can make these regex statements optional allowing me to return the following
Total1 `1`
Total2 `8`
Total3 `0`
Total4 `8`
Total5 `4`
Total6 `4`
Total7 `34`
Row1 `32`
Row15 `2`
S304JB0...(?<Total1>[\d]+).(?<Total2>[\d]+).(?<Total3>[\d]+).(?<Total4>[\d]+).(?<Total5>[\d]+).(?<Total6>[\d]+).(?<Total7>[\d]+)(?<Row3>(R03)[\d]+)(?<Row4>(R04)[\d]+) ------> (?<Row15>(R15)[\d]+)
Thanks for your help
-Edited
Thanks for the quick reply Jorge
The input data will be
12*000000000**S304JB01811*8*0*8*4*4*34R0332R152~~~
The output will be 9 captured groups results
Group | Result
Total1 = 1
Total2 = 8
Total3 = 0
Total4 = 8
Total5 = 4
Total6 = 4
Total7 = 34
Row1 = 32
Row15 = 2
My example is shared below with input and
https://regex101.com/r/wG3aM3/68
Hopefully this helped to clarify things
D.
I'm certain this would be easier parsing char by char and storing each value.
As for the regex question, basically what you want to do is create all the groups, just like you've already tried, but you also want to make them optional, because not all groups might be there.
You can make the group optional with a construct like:
(?:R01(?<Row1>\d+))?
So you should add one of each to get the values in different capture groups. Notice I used the construct (?:non-capturing) which is exactly the same as a group, but it doesn't create a backreference. You can read about it here.
Edit: One more thing. You're using a . to allow any delimiter. However, performance-wise it would be better to use something like \D (anything except digits). In case of failure, it saves the regex engine quite a few backtracking steps.
This would be the whole expression, assuming the Rxx groups are always ordered.
S304JB0...(?<Total1>\d+)\D(?<Total2>\d+)\D(?<Total3>\d+)\D(?<Total4>\d+)\D(?<Total5>\d+)\D(?<Total6>\d+)\D(?<Total7>\d+)(?:R01(?<Row1>\d+))?(?:R02(?<Row2>\d+))?(?:R03(?<Row3>\d+))?(?:R04(?<Row4>\d+))?(?:R05(?<Row5>\d+))?(?:R06(?<Row6>\d+))?(?:R07(?<Row7>\d+))?(?:R08(?<Row8>\d+))?(?:R09(?<Row9>\d+))?(?:R10(?<Row10>\d+))?(?:R11(?<Row11>\d+))?(?:R12(?<Row12>\d+))?(?:R13(?<Row13>\d+))?(?:R14(?<Row14>\d+))?(?:R15(?<Row15>\d+))?
DEMO
I have a list of dates (YYYY-M or YYYY-MM) and want to prefix 0 before the first 9 months for consistency. Data format : Date in YYYY-M or YYYY-MM followed by a comma and a number.
Eg:
2012-1,789
2012-11,563
2012-1,789 should be changed to 2012-01,789. The entry `2012-11,563' should remain unchanged.
Correct output should be:
2012-01,789
2012-11,563
I tried following regular expression in Vim.
:%s/-\(\d\),/-0\0,/g
However, I get the following output:
2012-0-1,789
2012-11,563
Why am I getting an additional dash - between two digits?
Capturing group number starts from 1, not from 0.
So the command should be:
:%s/-\(\d\),/-0\1,/g