Extract all substrings bounded by the same characters - regex

Question

Given a name_loc column of text like the following:
{"Charlie – White Plains, NY","Wrigley – Minneapolis, MN","Ana – Decatur, GA"}
I'm trying to extract the names, ideally separated by commas:
Charlie, Wrigley, Ana
I've gotten this far:
SELECT SUBSTRING(CAST(name_loc AS VARCHAR) from '"([^ –]+)')
FROM table;
which returns
Charlie
How can I extend this query to extract all names?

Answer 1

You can do this with a combination of regexp_matches (to extract the names), array_agg (to regroup all matches in a row) and array_to_string (to format the array as you'd like, e.g. with a comma separator):
WITH input(name_loc) AS (
VALUES ('{"Charlie – White Plains, NY","Wrigley – Minneapolis, MN","Ana – Decatur, GA"}')
, ('{"Other - somewhere}') -- added this to show multiple rows do not get merged
)
SELECT array_to_string(names, ', ')
FROM input
CROSS JOIN LATERAL (
SELECT array_agg(name)
FROM regexp_matches(name_loc, '"(\w+)', 'g') AS f(name)
) AS f(names);
array_to_string
Charlie, Wrigley, Ana
Other
View on DB Fiddle

Answer 2

My two cents, though I'm rather new to postgreSQL and I had to copy the 1st piece from #Marth's his answer:
WITH input(name_loc) AS (
VALUES ('{"Charlie – White Plains, NY","Wrigley – Minneapolis, MN","Ana – Decatur, GA"}')
, ('{"Other - somewhere"}')
)
SELECT REGEXP_REPLACE(name_loc, '{?(,)?"(\w+)[^"]+"}?','\1\2', 'g') FROM input;
regexp_replace
Charlie,Wrigley,Ana
Other

Answer 3

Your string literal happens to be a valid array literal.
(Maybe not by coincidence? And the column should be type text[] to begin with?)
If that's the reliable format, there is a safe and simple solution:
SELECT t.id, x.names
FROM tbl t
CROSS JOIN LATERAL (
SELECT string_agg(split_part(elem, ' – ', 1), ', ') AS names
FROM unnest(t.name_loc::text[]) elem
) x;
Or:
SELECT id, string_agg(split_part(elem, ' – ', 1), ', ') AS names
FROM (SELECT id, unnest(name_loc::text[]) AS elem FROM tbl) t
GROUP BY id;
db<>fiddle here
Steps
Unnest the array with unnest() in a LATERAL CROSS JOIN, or directly in the SELECT list.
What is the difference between LATERAL JOIN and a subquery in PostgreSQL?
Take the first part with split_part(). I chose ' – ' as delimiter, not just ' ', to allow for names with nested space like "Anne Nicole". See:
Split comma separated column data into additional columns
Aggregate results with string_agg(). I added no particular order as you didn't specify one.
Concatenate multiple result rows of one column into one, group by another column