C++20 stopping a detached std::jthread using an std::stop_token - c++

In C++20 std::jthread was introduced as a safer version of std::thread; where std::jthread, as far as I understand, cleans up after itself when the thread exits.
Also, the concept of cooperative cancellation is introduced such that an std::jthread manages an std::stop_source that handles the state of the underlying thread, this std::stop_source exposes an std::stop_token that outsiders can use to read the state of the thread sanely.
What I have is something like this.
class foo {
std::stop_token stok;
std::stop_source ssource;
public:
void start_foo() {
// ...
auto calculation = [this](std::stop_token inner_tok) {
// ... (*this is used here)
while(!inner_tok.stop_requested()) {
// stuff
}
}
auto thread = std::jthread(calculation);
ctok = thread.get_stop_token();
ssource = thread.get_stop_source();
thread.detach(); // ??
}
void stop_foo() {
if (ssource.stop_possible()) {
ssource.request_stop();
}
}
~foo() {
stop_foo();
}
}
Note foo is managed by a std::shared_ptr, and there is no public constructor.
Somewhere along the line, another thread can call foo::stop_foo() on a possibly detached thread.
Is what I am doing safe?
Also, when detaching a thread, the C++ handle is no longer associated with the running thread, and the OS manages it, but does the thread keep receiving stop notifications from the std::stop_source?
Is there a better way to achieve what I need? In MVSC, this doesn't seem to raise any exceptions or halt program execution, and I've done a lot of testing to verify this.
So, is this solution portable?

What you wrote is potentially unsafe if the thread accesses this after the foo has been destroyed. It's also a bit convoluted. A simpler approach would just be to stick the jthread in the structure...
class foo {
std::jthread thr;
public:
void start_foo() {
// ...
jthr = std::jthread([this](std::stop_token inner_tok) {
// ... (*this is used here)
while(!inner_tok.stop_requested()) {
// stuff
}
});
}
void stop_foo() {
jthr.request_stop();
}
~foo() {
stop_foo();
// jthr.detatch(); // this is a bad idea
}
}
To match the semantics of your code, you would uncomment the jthr.detach() in the destructor, but this is actually a bad idea since then you could end up destroying foo while the thread is still accessing it. The code I wrote above is safe, but obviously whichever thread drops the last reference to the foo will have to wait for the jthread to exit. If that's really intolerable, then maybe you want to change the API to stick a shared_ptr in the thread itself, so that the thread can destroy foo if it is still running after the last external reference is dropped.

Related

How to initiate a thread in a class in C++ 14?

class ThreadOne {
public:
ThreadOne();
void RealThread();
void EnqueueJob(s_info job);
std::queue<s_info> q_jobs;
private:
H5::H5File* targetFile = new H5::H5File("file.h5", H5F_ACC_TRUNC);
std::condition_variable cv_condition;
std::mutex m_job_q_;
};
ThreadOne::ThreadOne() {
}
void ThreadOne::RealThread() {
while (true) {
std::unique_lock<std::mutex> lock(m_job_q_);
cv_condition.wait(lock, [this]() { return !this->q_jobs.empty(); });
s_info info = std::move(q_jobs.front());
q_jobs.pop();
lock.unlock();
//* DO THE JOB *//
}
}
void ThreadOne::EnqueueJob(s_info job) {
{
std::lock_guard<std::mutex> lock(m_job_q_);
q_jobs.push(std::move(job));
}
cv_condition.notify_one();
}
ThreadOne *tWrite = new ThreadOne();
I want to make a thread and send it a pointer of an array and its name as a struct(s_info), and then make the thread write it into a file. I think that it's better than creating a thread whenever writing is needed.
I could make a thread pool and allocate jobs to it, but it's not allowed to write the same file concurrently in my situation, I think that just making a thread will be enough and the program will still do CPU-bound jobs when writing job is in process.
To sum up, this class (hopefully) gets array pointers and their dataset names, puts them in q_jobs and RealThread writes the arrays into a file.
I referred to a C++ thread pool program and the program initiates threads like this:
std::vector<std::thread> vec_worker_threads;
vector_worker_threads.reserve(num_threads_);
vector_worker_threads.emplace_back([this]() { this->RealThread(); });
I'm new to C++ and I understand what the code above does, but I don't know how to initiate RealThread in my class without a vector. How can I make an instance of the class that has a thread(RealThread) that's already ready inside it?
From what I can gather, and as already discussed in the comments, you simply want a std::thread member for ThreadOne:
class ThreadOne {
std::thread thread;
public:
~ThreadOne();
//...
};
//...
ThreadOne::ThreadOne() {
thread = std::thread{RealThread, this};
}
ThreadOne::~ThreadOne() {
// (potentially) notify thread to finish first
if(thread.joinable())
thread.join();
}
//...
ThreadOne tWrite;
Note that I did not start the thread in the member-initializer-list of the constructor in order to avoid the thread accessing other members that have not been initialized yet. (The default constructor of std::thread does not start any thread.)
I also wrote a destructor which will wait for the thread to finish and join it. You must always join threads before destroying the std::thread object attached to it, otherwise your program will call std::terminate and abort.
Finally, I replaced tWrite from being a pointer to being a class type directly. There is probably no reason for you to use dynamic allocation there and even if you have a need for it, you should be using
auto tWrite = std::make_unique<ThreadOne>();
or equivalent, instead, so that you are not going to rely on manually deleteing the pointer at the correct place.
Also note that your current RealThread function seems to never finish. It must return at some point, probably after receiving a notification from the main thread, otherwise thread.join() will wait forever.

How to start an empty thread using c++ [duplicate]

I'm getting into C++11 threads and have run into a problem.
I want to declare a thread variable as global and start it later.
However all the examples I've seen seem to start the thread immediately for example
thread t(doSomething);
What I want is
thread t;
and start the thread later.
What I've tried is
if(!isThreadRunning)
{
thread t(readTable);
}
but now t is block scope. So I want to declare t and then start the thread later so that t is accessible to other functions.
Thanks for any help.
std::thread's default constructor instantiates a std::thread without starting or representing any actual thread.
std::thread t;
The assignment operator moves the state of a thread object, and sets the assigned-from thread object to its default-initialized state:
t = std::thread(/* new thread code goes here */);
This first constructs a temporary thread object representing a new thread, transfers the new thread representation into the existing thread object that has a default state, and sets the temporary thread object's state to the default state that does not represent any running thread. Then the temporary thread object is destroyed, doing nothing.
Here's an example:
#include <iostream>
#include <thread>
void thread_func(const int i) {
std::cout << "hello from thread: " << i << std::endl;
}
int main() {
std::thread t;
std::cout << "t exists" << std::endl;
t = std::thread{ thread_func, 7 };
t.join();
std::cout << "done!" << std::endl;
}
As antred says in his answer, you can use a condition variable to make the thread to wait in the beginning of its routine.
Scott Meyers in his book “Effective Modern C++” (in the “Item 39: Consider void futures for one-shot event communication”) proposes to use void-future instead of lower level entities (boolean flag, conditional variable and mutex). So the problem can be solved like this:
auto thread_starter = std::promise<void>;
auto thread = std::thread([starter_future = thread_starter.get_future()]() mutable {
starter_future.wait(); //wait before starting actual work
…; //do actual work
});
…; //you can do something, thread is like “paused” here
thread_starter.set_value(); //“start” the thread (break its initial waiting)
Scott Meyers also warns about exceptions in the second … (marked by the you can do something, thread is like “paused” here comment). If thread_starter.set_value() is never called for some reasons (for example, due to exception throws in the second …), the thread will wait forever, and any attempt to join it would result in deadlock.
As both ways (condvar-based and future-based) contain hidden unsafety, and the first way (condvar-based) needs some boilerplate code, I propose to write a wrapper class around std::thread. Its interface should be similar to the one of std::thread (except that its instances should be assignable from other instances of the same class, not from std::thread), but contain additional void start() method.
Future-based thread-wrapper
class initially_suspended_thread {
std::promise<bool> starter;
std::thread impl;
public:
template<class F, class ...Args>
explicit initially_suspended_thread(F &&f, Args &&...args):
starter(),
impl([
starter_future = starter.get_future(),
routine = std::bind(std::forward<F>(f), std::forward<Args>(args)...)
]() mutable {if (starter_future.get()) routine();})
{}
void start() {starter.set_value(true);}
~initially_suspended_thread() {
try {starter.set_value(false);}
catch (const std::future_error &exc) {
if (exc.code() != std::future_errc::promise_already_satisfied) throw;
return; //already “started”, no need to do anything
}
impl.join(); //auto-join not-yet-“started” threads
}
…; //other methods, trivial
};
Condvar-based thread-wrapper
class initially_suspended_thread {
std::mutex state_mutex;
enum {INITIAL, STARTED, ABORTED} state;
std::condition_variable state_condvar;
std::thread impl;
public:
template<class F, class ...Args>
explicit initially_suspended_thread(F &&f, Args &&...args):
state_mutex(), state(INITIAL), state_condvar(),
impl([
&state_mutex = state_mutex, &state = state, &state_condvar = state_condvar,
routine = std::bind(std::forward<F>(f), std::forward<Args>(args)...)
]() {
{
std::unique_lock state_mutex_lock(state_mutex);
state_condvar.wait(
state_mutex_lock,
[&state]() {return state != INITIAL;}
);
}
if (state == STARTED) routine();
})
{}
void start() {
{
std::lock_guard state_mutex_lock(state_mutex);
state = STARTED;
}
state_condvar.notify_one();
}
~initially_suspended_thread() {
{
std::lock_guard state_mutex_lock(state_mutex);
if (state == STARTED) return; //already “started”, no need to do anything
state = ABORTED;
}
impl.join(); //auto-join not-yet-“started” threads
}
…; //other methods, trivial
};
There is no "standard" of creating a thread "suspended" which I assume is what you wanted to do with the C++ thread library. Because it is not supported on every platform that has threads, it is not there in the C++ API.
You might want to create a class with all the data it is required but not actually run your thread function. This is not the same as creating the thread but may be what you want. If so, create that, then later bind the object and its operator() or start() function or whatever to the thread.
You might want the thread id for your thread. That means you do actually need to start the thread function. However it can start by waiting on a condition variable. You then signal or broadcast to that condition variable later when you want it to continue running. Of course you can have the function check a condition after it resumes in case you might have decided to close it and not run it after all (in which case it will just return instantly).
You might want a std::thread object with no function. You can do that and attach it to a function later to run that function in a new thread.
I would give the thread a condition variable and a boolean called startRunning (initially set to false). Effectively you would start the thread immediately upon creation, but the first thing it would do is suspend itself (using the condition_variable) and then only begin processing its actual task when the condition_variable is signaled from outside (and the startRunning flag set to true).
EDIT: PSEUDO CODE:
// in your worker thread
{
lock_guard l( theMutex );
while ( ! startRunning )
{
cond_var.wait( l );
}
}
// now start processing task
// in your main thread (after creating the worker thread)
{
lock_guard l( theMutex );
startRunning = true;
cond_var.signal_one();
}
EDIT #2: In the above code, the variables theMutex, startRunning and cond_var must be accessible by both threads. Whether you achieve that by making them globals or by encapsulating them in a struct / class instance is up to you.
first declared in class m_grabber runs nothing. We assign member class object with new one with lambda function in launch_grabber method and thread with lambda runs within source class context.
class source {
...
std::thread m_grabber;
bool m_active;
...
}
bool source::launch_grabber() {
// start grabber
m_grabber = std::thread{
[&] () {
m_active = true;
while (true)
{
if(!m_active)
break;
// TODO: something in new thread
}
}
};
m_grabber.detach();
return true;
}
You could use singleton pattern. Or I would rather say antipattern.
Inside a singleton you would have std::thread object encapsulated. Upon first access to singleton your thread will be created and started.

Delayed start of a thread in C++ 11

I'm getting into C++11 threads and have run into a problem.
I want to declare a thread variable as global and start it later.
However all the examples I've seen seem to start the thread immediately for example
thread t(doSomething);
What I want is
thread t;
and start the thread later.
What I've tried is
if(!isThreadRunning)
{
thread t(readTable);
}
but now t is block scope. So I want to declare t and then start the thread later so that t is accessible to other functions.
Thanks for any help.
std::thread's default constructor instantiates a std::thread without starting or representing any actual thread.
std::thread t;
The assignment operator moves the state of a thread object, and sets the assigned-from thread object to its default-initialized state:
t = std::thread(/* new thread code goes here */);
This first constructs a temporary thread object representing a new thread, transfers the new thread representation into the existing thread object that has a default state, and sets the temporary thread object's state to the default state that does not represent any running thread. Then the temporary thread object is destroyed, doing nothing.
Here's an example:
#include <iostream>
#include <thread>
void thread_func(const int i) {
std::cout << "hello from thread: " << i << std::endl;
}
int main() {
std::thread t;
std::cout << "t exists" << std::endl;
t = std::thread{ thread_func, 7 };
t.join();
std::cout << "done!" << std::endl;
}
As antred says in his answer, you can use a condition variable to make the thread to wait in the beginning of its routine.
Scott Meyers in his book “Effective Modern C++” (in the “Item 39: Consider void futures for one-shot event communication”) proposes to use void-future instead of lower level entities (boolean flag, conditional variable and mutex). So the problem can be solved like this:
auto thread_starter = std::promise<void>;
auto thread = std::thread([starter_future = thread_starter.get_future()]() mutable {
starter_future.wait(); //wait before starting actual work
…; //do actual work
});
…; //you can do something, thread is like “paused” here
thread_starter.set_value(); //“start” the thread (break its initial waiting)
Scott Meyers also warns about exceptions in the second … (marked by the you can do something, thread is like “paused” here comment). If thread_starter.set_value() is never called for some reasons (for example, due to exception throws in the second …), the thread will wait forever, and any attempt to join it would result in deadlock.
As both ways (condvar-based and future-based) contain hidden unsafety, and the first way (condvar-based) needs some boilerplate code, I propose to write a wrapper class around std::thread. Its interface should be similar to the one of std::thread (except that its instances should be assignable from other instances of the same class, not from std::thread), but contain additional void start() method.
Future-based thread-wrapper
class initially_suspended_thread {
std::promise<bool> starter;
std::thread impl;
public:
template<class F, class ...Args>
explicit initially_suspended_thread(F &&f, Args &&...args):
starter(),
impl([
starter_future = starter.get_future(),
routine = std::bind(std::forward<F>(f), std::forward<Args>(args)...)
]() mutable {if (starter_future.get()) routine();})
{}
void start() {starter.set_value(true);}
~initially_suspended_thread() {
try {starter.set_value(false);}
catch (const std::future_error &exc) {
if (exc.code() != std::future_errc::promise_already_satisfied) throw;
return; //already “started”, no need to do anything
}
impl.join(); //auto-join not-yet-“started” threads
}
…; //other methods, trivial
};
Condvar-based thread-wrapper
class initially_suspended_thread {
std::mutex state_mutex;
enum {INITIAL, STARTED, ABORTED} state;
std::condition_variable state_condvar;
std::thread impl;
public:
template<class F, class ...Args>
explicit initially_suspended_thread(F &&f, Args &&...args):
state_mutex(), state(INITIAL), state_condvar(),
impl([
&state_mutex = state_mutex, &state = state, &state_condvar = state_condvar,
routine = std::bind(std::forward<F>(f), std::forward<Args>(args)...)
]() {
{
std::unique_lock state_mutex_lock(state_mutex);
state_condvar.wait(
state_mutex_lock,
[&state]() {return state != INITIAL;}
);
}
if (state == STARTED) routine();
})
{}
void start() {
{
std::lock_guard state_mutex_lock(state_mutex);
state = STARTED;
}
state_condvar.notify_one();
}
~initially_suspended_thread() {
{
std::lock_guard state_mutex_lock(state_mutex);
if (state == STARTED) return; //already “started”, no need to do anything
state = ABORTED;
}
impl.join(); //auto-join not-yet-“started” threads
}
…; //other methods, trivial
};
There is no "standard" of creating a thread "suspended" which I assume is what you wanted to do with the C++ thread library. Because it is not supported on every platform that has threads, it is not there in the C++ API.
You might want to create a class with all the data it is required but not actually run your thread function. This is not the same as creating the thread but may be what you want. If so, create that, then later bind the object and its operator() or start() function or whatever to the thread.
You might want the thread id for your thread. That means you do actually need to start the thread function. However it can start by waiting on a condition variable. You then signal or broadcast to that condition variable later when you want it to continue running. Of course you can have the function check a condition after it resumes in case you might have decided to close it and not run it after all (in which case it will just return instantly).
You might want a std::thread object with no function. You can do that and attach it to a function later to run that function in a new thread.
I would give the thread a condition variable and a boolean called startRunning (initially set to false). Effectively you would start the thread immediately upon creation, but the first thing it would do is suspend itself (using the condition_variable) and then only begin processing its actual task when the condition_variable is signaled from outside (and the startRunning flag set to true).
EDIT: PSEUDO CODE:
// in your worker thread
{
lock_guard l( theMutex );
while ( ! startRunning )
{
cond_var.wait( l );
}
}
// now start processing task
// in your main thread (after creating the worker thread)
{
lock_guard l( theMutex );
startRunning = true;
cond_var.signal_one();
}
EDIT #2: In the above code, the variables theMutex, startRunning and cond_var must be accessible by both threads. Whether you achieve that by making them globals or by encapsulating them in a struct / class instance is up to you.
first declared in class m_grabber runs nothing. We assign member class object with new one with lambda function in launch_grabber method and thread with lambda runs within source class context.
class source {
...
std::thread m_grabber;
bool m_active;
...
}
bool source::launch_grabber() {
// start grabber
m_grabber = std::thread{
[&] () {
m_active = true;
while (true)
{
if(!m_active)
break;
// TODO: something in new thread
}
}
};
m_grabber.detach();
return true;
}
You could use singleton pattern. Or I would rather say antipattern.
Inside a singleton you would have std::thread object encapsulated. Upon first access to singleton your thread will be created and started.

Using a boost thread: Signal and wait for termination

i'm currently writing a c/c++ dll for later use mostly in Delphi and i'm more familiar with threads in Delphi than c/c++ and especially boost. So i wonder how i can achieve the following scenario?
class CMyClass
{
private:
boost::thread* doStuffThread;
protected:
void doStuffExecute(void)
{
while(!isTerminationSignal()) // loop until termination signal
{
// do stuff
}
setTerminated(); // thread is finished
};
public:
CMyClass(void)
{
// create thread
this->doStuffThread = new boost::thread(boost::bind(&CMyClass::doStuffExecute, this));
};
~CMyClass(void)
{
// finish the thread
signalThreadTermination();
waitForThreadFinish();
delete this->doStuffThread;
// do other cleanup
};
}
I have red countless articles about boost threading, signals and mutexes but i don't get it, maybe because it's friday ;) or is it not doable how i think to do it?
Regards
Daniel
Just use an atomic boolean to tell the thread to stop:
class CMyClass
{
private:
boost::thread doStuffThread;
boost::atomic<bool> stop;
protected:
void doStuffExecute()
{
while(!stop) // loop until termination signal
{
// do stuff
}
// thread is finished
};
public:
CMyClass() : stop(false)
{
// create thread
doStuffThread = boost::thread(&CMyClass::doStuffExecute, this);
};
~CMyClass()
{
// finish the thread
stop = true;
doStuffThread.join();
// do other cleanup
};
}
To wait for the thread to finish you just join it, that will block until it is finished and can be joined. You need to join the thread anyway before you can destroy it, or it will terminate your program.
There is no need to use a pointer and create the thread with new, just use a boost::thread object directly. Creating everything on the heap is wasteful, unsafe and poor style.
There is no need to use boost::bind to pass arguments to the thread constructor. For many many years boost::thread has supported passing multiple arguments to its constructor directly and it does the binding internally.
It's important that stop has been initialized to false before the new thread is created, otherwise if the new thread is spawned very quickly it could check the value of stop before it is initialized, and might happen to read a true value from the uninitialized memory, and then it would never enter the loop.
On the subject of style, writing foo(void) is considered by many C++ programmers to be a disgusting abomination. If you want to say your function takes no arguments then just write foo().

Best way to handle multi-thread cleanup

I have a server-type application, and I have an issue with making sure thread's aren't deleted before they complete. The code below pretty much represents my server; the cleanup is required to prevent a build up of dead threads in the list.
using namespace std;
class A {
public:
void doSomethingThreaded(function<void()> cleanupFunction, function<bool()> getStopFlag) {
somethingThread = thread([cleanupFunction, getStopFlag, this]() {
doSomething(getStopFlag);
cleanupFunction();
});
}
private:
void doSomething(function<bool()> getStopFlag);
thread somethingThread;
...
}
class B {
public:
void runServer();
void stop() {
stopFlag = true;
waitForListToBeEmpty();
}
private:
void waitForListToBeEmpty() { ... };
void handleAccept(...) {
shared_ptr<A> newClient(new A());
{
unique_lock<mutex> lock(listMutex);
clientData.push_back(newClient);
}
newClient.doSomethingThreaded(bind(&B::cleanup, this, newClient), [this]() {
return stopFlag;
});
}
void cleanup(shared_ptr<A> data) {
unique_lock<mutex> lock(listMutex);
clientData.remove(data);
}
list<shared_ptr<A>> clientData;
mutex listMutex;
atomc<bool> stopFlag;
}
The issue seems to be that the destructors run in the wrong order - i.e. the shared_ptr is destructed at when the thread's function completes, meaning the 'A' object is deleted before thread completion, causing havok when the thread's destructor is called.
i.e.
Call cleanup function
All references to this (i.e. an A object) removed, so call destructor (including this thread's destructor)
Call this thread's destructor again -- OH NOES!
I've looked at alternatives, such as maintaining a 'to be removed' list which is periodically used to clean the primary list by another thread, or using a time-delayed deletor function for the shared pointers, but both of these seem abit chunky and could have race conditions.
Anyone know of a good way to do this? I can't see an easy way of refactoring it to work ok.
Are the threads joinable or detached? I don't see any detach,
which means that destructing the thread object without having
joined it is a fatal error. You might try simply detaching it,
although this can make a clean shutdown somewhat complex. (Of
course, for a lot of servers, there should never be a shutdown
anyway.) Otherwise: what I've done in the past is to create
a reaper thread; a thread which does nothing but join any
outstanding threads, to clean up after them.
I might add that this is a good example of a case where
shared_ptr is not appropriate. You want full control over
when the delete occurs; if you detach, you can do it in the
clean up function (but quite frankly, just using delete this;
at the end of the lambda in A::doSomethingThreaded seems more
readable); otherwise, you do it after you've joined, in the
reaper thread.
EDIT:
For the reaper thread, something like the following should work:
class ReaperQueue
{
std::deque<A*> myQueue;
std::mutex myMutex;
std::conditional_variable myCond;
A* getOne()
{
std::lock<std::mutex> lock( myMutex );
myCond.wait( lock, [&]( !myQueue.empty() ) );
A* results = myQueue.front();
myQueue.pop_front();
return results;
}
public:
void readyToReap( A* finished_thread )
{
std::unique_lock<std::mutex> lock( myMutex );
myQueue.push_back( finished_thread );
myCond.notify_all();
}
void reaperThread()
{
for ( ; ; )
{
A* mine = getOne();
mine->somethingThread.join();
delete mine;
}
}
};
(Warning: I've not tested this, and I've tried to use the C++11
functionality. I've only actually implemented it, in the past,
using pthreads, so there could be some errors. The basic
principles should hold, however.)
To use, create an instance, then start a thread calling
reaperThread on it. In the cleanup of each thread, call
readyToReap.
To support a clean shutdown, you may want to use two queues: you
insert each thread into the first, as it is created, and then
move it from the first to the second (which would correspond to
myQueue, above) in readyToReap. To shut down, you then wait
until both queues are empty (not starting any new threads in
this interval, of course).
The issue is that, since you manage A via shared pointers, the this pointer captured by the thread lambda really needs to be a shared pointer rather than a raw pointer to prevent it from becoming dangling. The problem is that there's no easy way to create a shared_ptr from a raw pointer when you don't have an actual shared_ptr as well.
One way to get around this is to use shared_from_this:
class A : public enable_shared_from_this<A> {
public:
void doSomethingThreaded(function<void()> cleanupFunction, function<bool()> getStopFlag) {
somethingThread = thread([cleanupFunction, getStopFlag, this]() {
shared_ptr<A> temp = shared_from_this();
doSomething(getStopFlag);
cleanupFunction();
});
this creates an extra shared_ptr to the A object that keeps it alive until the thread finishes.
Note that you still have the problem with join/detach that James Kanze identified -- Every thread must have either join or detach called on it exactly once before it is destroyed. You can fulfill that requirement by adding a detach call to the thread lambda if you never care about the thread exit value.
You also have potential for problems if doSomethingThreaded is called multiple times on a single A object...
For those who are interested, I took abit of both answers given (i.e. James' detach suggestion, and Chris' suggestion about shared_ptr's).
My resultant code looks like this and seems neater and doesn't cause a crash on shutdown or client disconnect:
using namespace std;
class A {
public:
void doSomething(function<bool()> getStopFlag) {
...
}
private:
...
}
class B {
public:
void runServer();
void stop() {
stopFlag = true;
waitForListToBeEmpty();
}
private:
void waitForListToBeEmpty() { ... };
void handleAccept(...) {
shared_ptr<A> newClient(new A());
{
unique_lock<mutex> lock(listMutex);
clientData.push_back(newClient);
}
thread clientThread([this, newClient]() {
// Capture the shared_ptr until thread over and done with.
newClient->doSomething([this]() {
return stopFlag;
});
cleanup(newClient);
});
// Detach to remove the need to store these threads until their completion.
clientThread.detach();
}
void cleanup(shared_ptr<A> data) {
unique_lock<mutex> lock(listMutex);
clientData.remove(data);
}
list<shared_ptr<A>> clientData; // Can remove this if you don't
// need to connect with your clients.
// However, you'd need to make sure this
// didn't get deallocated before all clients
// finished as they reference the boolean stopFlag
// OR make it a shared_ptr to an atomic boolean
mutex listMutex;
atomc<bool> stopFlag;
}