What is the best way to create a list like this in R Markdown. Instead of just saying "1" or "2" it says "1st" and "2nd" and the "the" in each row is aligned with the one below?
1st. the first item
2nd. the second item
3rd. the third item
Related
I have searched as much as I can, and I have found solutions for similar problems, but I haven't been able to find a solution to my exact problem.
Issue: I would like to highlight the row when one cell in column A of that row is an exact match for another cell in that column, AND part of another cell in column B of that row is a match for part of another cell in that column, in Google Sheets. I would like to use conditional formatting, and only highlight the second occurence and on.
For example, is this "sheet":
A B C
1|John Smith|john#test.com|Test Co.
2|Jane Doe |jane#x.com |X Company
3|John Smith|j.s#test.com |Test Inc.
4|John Smith|jsm#test.com |Test Incorporated
I would like row 3 and row 4 to highlight, because column A3 is a duplicate of A1, and everything in B3 after # matches everything in B1 after #, and the same is true of row 4. Also, only rows 3 and 4 should highlight; not row 1, since it is the first instance. I understand regexes, and I've found how to highlight a row if one cell in column A and one cell in column B is an exact match with other cells is their respective columns, but I haven't figured out how to combine the two where I can search for one cell that is an exact match with another cell in that column AND for one cell that is a partial match with another cell in that particular column. Here is a link to a test sheet that contains the sample info from above. https://docs.google.com/spreadsheets/d/1neZd213C1ssY7bPeBfu2xI3WPCmt-oKkfbdrXrid9I8/edit?usp=sharing
use:
=INDEX(COUNTIFS($A:$A®EXEXTRACT($B:$B, "#.+"), $A1®EXEXTRACT($B1, "#.+"),
ROW($A:$A), "<="&ROW($A1))>1)*(A:A<>"")
Try the following custom formula applied to A1:C:
=index((countif($A$1:$A1,$A1)>1)*
(countif(regexextract($B$1:$B1,"#(.*)"),
regexextract($B1,"#(.*)"))>1))
Using OpenOffice CALC v4.1.3.
The dataset contains 400,000 rows and I am looking for the rows that are not in sequence order in column B. Column B contains integers from 1,2,3, etc. to the last row of data.
I am trying to set the cells in column-A with the formula as follow:
=IF(B3 = (B2+1);[empty];"BAD SEQUENCE")
I do not want to have the TRUE part to be "" (empty-string).
I want it to be [empty] or [blank] or [null] or [no-value] or [nothing] (using other language words here)
because I want to be able to use the [shift]+[down-arrow] key combination to find the next BAD-SEQUENCE row(s).
When the set of cells is actually [empty] then the [shift]+[down-arrow] navigates to the next "cell-with-value" (if not [empty]).
In this question, I have presented the code to show [empty] but I need the proper OO-CALC representation of [empty] to have empty cells when the if-statement is TRUE.
Your comments and solutions are welcome...thanks John
From https://superuser.com/questions/346873/openoffice-calc-how-to-insert-blank-in-a-formula:
No value will make isblank return true, because C1 will always contain a formula, and isblank literally tests for blanks. Not empty strings, but actual empty cells.
Like ISBLANK, Ctrl+Down considers any formula to be non-empty, regardless of its result.
Instead, do the following workaround:
Use "" as the [empty] value.
Copy column A.
Select an unused column such as column C.
Paste Special, with the Formulas box unchecked.
Alternatively, instead of using formulas, fill column A with values using a macro.
I have a list of products in calc (excel), each with an associated IP address. Many of the names have multiple IP addresses, however they are organized one column at a time. I am trying to remove all of the multiples and pull all of the IP addresses under a single name. I have tried nslookup and index match, they do not deal well with multiple outputs though. Right now it looks like this
a| 1
a| 2
a| 3
b| 1
b| 2
b| 3
etc...
I would like it to look like this
a 1,2,3
b 1,2,3
Is there any way to do this without wasting a ton of time, I have a few ways that work but they will take me forever to setup.
I recommend setting up your formulas in multiple "helper" cells before getting to the final "result cell". This breaks down the problem into smaller steps that are more easily formulated and, if needed in the future, updated. Once the setup is complete you can hide the helper columns by right-clicking on the column letter and choosing "Hide".
The first column to set up is the list of distinct product names. For the formula below to work, the product/IP list will need to be sorted in ascending order. If the list is not already sorted, to sort it first highlight the entire list, including headers. Then choose Data→Sort; select sort by "Product", make sure the radio button "Ascending" is selected, and press OK.
For purposes of this example, I'll assume product names are in column A, starting on row 2 and IPs are in column B starting on row 2 (with row 1 being the header labels). In the column where you want to list the distinct product names (I used column D), enter in the top cell =A2. In the cell below enter
=INDEX($A$2:$A$13;MATCH(D2;$A$2:$A$13;1)+1)
The match formula has a 1 as the third variable, meaning the range is sorted ascending and MATCH will return the position of the last matching cell. We add 1 to the position of the last matching cell, and this will be the position of the first cell with a new product name. That position is fed into the INDEX function to show the next product name.
Copy and paste that cell down as far as you need to show all the product names.
Now we'll set up a series of cells to display each IP address. I used columns F to I to show up to 4 addresses:
=IF(MATCH(D2;$A$2:$A$13;0)<=MATCH($D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH($D2;$A$2:$A$13;0));"")
=IF(MATCH(D2;$A$2:$A$13;0)+1<=MATCH(D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH(D2;$A$2:$A$13;0)+1);"")
=IF(MATCH(D2;$A$2:$A$13;0)+2<=MATCH(D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH(D2;$A$2:$A$13;0)+2);"")
=IF(MATCH(D2;$A$2:$A$13;0)+3<=MATCH(D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH(D2;$A$2:$A$13;0)+3);"")
MATCH with the third variable of 1 returns the position of the last matching cell; MATCH with the third variable of 0 returns the position of the first matching cell.
The IF statement checks if the position of the first matching cell (in the first lookup column) or the cell below that (in the second lookup column) or the cell two below the first match (in the third lookup column), etc. is less than or equal to the position of the last matching cell. If yes, then it looks up the relevant IP address. If no, it displays a blank.
In the formulas above you would need to manually enter the formula in the top row of each column. If you have some products with a large number of IP addresses, you may want to set up the formula so you can copy and paste between columns as well as down the rows. This would work if you were starting in column F:
=IF(MATCH($D2;$A$2:$A$13;0)+COLUMN()-6<=MATCH($D2;$A$2:$A$13;1);INDEX($B$2:$B$13;MATCH($D2;$A$2:$A$13;0)+COLUMN()-6);"")
Once you have your top row set up as you want, copy and paste down however many rows you need.
If you want to combine all the IPs into a single cell separated by commas, you can use a formula like this:
=CONCATENATE(F2;IF(G2<>"";","&G2;"");IF(H2<>"";","&H2;"");IF(I2<>"";","&I2;""))
Each IF statement will add a comma separator followed by the cell contents if the checked cell is not empty, otherwise it returns a blank string. You will need to manually adjust to add additional IF statements for however many maximum columns you want to concatenate. Again, once you have the top row set up, copy and paste down however far you need.
Assuming you have two columns (A and B), that these are labelled and sorted as shown, then enter in C2:
=IF(A1<>A2;B2;C1&","&B2)
and in D1:
=A1<>A2
Copy both down to suit, select ColumnC and Copy, Paste Special... with each Selection ticked other than Paste all and Formulas, click OK.
Select ColumnsA:D, Data > Filter > AutoFilter, click Yes and select 1 for ColumnD and all visible range.
Copy and paste into a new sheet, move B1 to C1 and delete Columns B and D.
I have two columns of numbers, and I want to make a 3rd column as the answer to the first two. I want to do this: in the third column call the row number of the first column using the second columns value.
Any help is greatly appreciated.
You can use the INDIRECT() function combined with CONCATENATE() to do this:
=INDIRECT(CONCATENATE("I";E1))
Here, i assume the resulting value is in column I, while column E has the row number.
The formula takes the string "I" and concatenates it with the content of E1. If E1 has the value "1", the resulting string is "I1". INDIRECT() uses that string as cell reference and returns the value of cell "I1"
I have a table with 3 columns and 2 rows.
In the 1st row: That first column drops down to the entire page, and the 2nd and 3rd columns only drop an inch.
In the 2nd Row: There are only two columns that use the middle and right columns. This currently gets added to the 2nd page.
Right now that 2nd row is appended below where the 1st column in the 1st row end. Is it possible in xsl 1.1 to have that 2nd row append below where the 2nd and 3rd columns are in the 1st column [aka added in the white space on the first page]?
Quickly refreshing my memory on xsl-fo, i quite quickly found this:
<fo:table-cell number-rows-spanned="2">
When applied to your first cel in your first ro in your first column, it should then span two rows, meaning that the data on your second row appear next to it.