I'm not a Django expert but I need to make customizations of this software which is written in Django using the rest framework.
I need to render a custom html template let's say a.html, however when I go to http://localhost:8080/custom/custom/a I get redirected back to different page - not a.html.
This is what I've done so far. I created a new folder in apps called custom:
cvat
apps
custom
templates
custom
_init.py
a.html, b.html, ...
urls.py
apps.py
from django.apps import AppConfig
class CustomConfig(AppConfig):
name = 'cvat.apps.custom'
urls.py
from django.urls import path
from . import views
urlpatterns = [
path('custom/<str:name>', views.CustomView),
]
views.py
from django.shortcuts import render
def CustomView(request, name):
return render(request, 'custom/'+name+'.html')
In addition, I have modified these existing files to add the custom folder that was created in apps:
in urls.py added my url patterns:
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('cvat.apps.engine.urls')),
path('django-rq/', include('django_rq.urls')),
path('custom/', include('cvat.apps.custom.urls')),
]
in base.py added this:
INSTALLED_APPS = [
...
'cvat.apps.custom'
]
Any advice on what I'm doing wrong?
You can try something like this
url can be like this
urlpatterns = [
path('custom/<name>/', views.CustomView),
]
and your view should be like this.
def CustomView(request, name):
return render(request, f'custom/{name}.html')
Hope this will help you.
Related
I currently have a website where the home page at www.mysite.com is the wagtail blog index page
I wish to move the blogindex page to another url
I can easily have a different homepage by amending my urls.py file:
#original
path("", include(wagtail_urls))
#new
path(
"",
TemplateView.as_view(template_name="pages/newhomepage.html"),
name="newhomepage",
),
However I would like the blogindex page available at e.g. myste.com/blog but I am not sure how to go about this. Adding the following to urls.py does not do it
path("blog/", include(wagtail_urls))
There are a couple of changes in project required to achieve this.
Firstly, create a urls.py file inside your specific app, this will be different from the one that you should already have alongside wsgi.py, asgi.py, etc. and it will only store app specific urls.
from django.urls import path
from .views import index
urlpatterns = [
path('test/', index, name='generalized-test-url'),
]
Now, you should render the template inside your view.
def index(request):
return render(request, 'pages/newhomepage.html', context)
Lastly, in your root urls.py file, you need to include the app urls. Lets say your app name is blog.
from django.urls import path, include
urlpatterns = [
path('blog/', include('blog.urls')),
]
I'm learning Django and I have a problem that there is no answer for it on internet
here is the problem,
I created a folder as 'app', and I create another folder in app as 'challenges' (in VS Code in a Django application),
so we have 2 nested folders
now I want to create an HTML page, and I create a file as 'index.html',
but VS Code cannot know this file as an HTML file
You need to make a folder structure like this
>app_name
>>...
>>templates
>>>app_name
>>>>index.html
views.py
from django.shortcuts import render
def index(request):
return render(request, 'app_name/index.html)
urls.py
from . import views
urlpatterns = [
path('', views.index),
]
I've tried multiple methods of writing views but I don't think it is a problem here. App is installed in settings.py
It displays error every time.
project structure:
structure
views.py (app folder)
from django.http import HttpResponse
from django.shortcuts import render
def home_view(request):
return HttpResponse('Hello World')
url.py in apps folder
from django.urls import path
from . import views
urlpatterns = [
path('home_view/', views.home_view)
]
apps.py in app folder
from django.apps import AppConfig
class AppConfig(AppConfig):
default_auto_field = 'django.db.models.BigAutoField'
name = 'app'
urls.py in store folder
from django.contrib import admin
from django.urls import path, include
from app import views
urlpatterns = [
path('app/home_view/', include('app.url')),
path('admin/', admin.site.urls),
]
error message:
error
As a django web development expert I saw some small corrections to be done:
In store urls.py file its app/ and app.urls
from django.contrib import admin
from django.urls import path, include
from app import views
urlpatterns = [
path('app/', include('app.urls')),
path('admin/', admin.site.urls),
]
Then change the app url.py file name to standard name urls.py.
also don't forget to add your app to installed_apps variable in settings.py file:
INSTALLED_APPS=[
'app',
'django.contin.auth',
#and other already specified apps
]
Rest all files have no bugs!!
According to this the correct path for HttpResponse is:
http://localhost:8000/app/home_view/
OR
http://127.0.0.1:8000/app/home_view/
In your urls.py file
Change
path('app/home_view/', include('app.url')),
To
path('', include('app.url')),
Then
On your browser go to:
127.0.0.1:8000/home_view/
The main thing it must be app.urls not app.url. change your file to url.py to urls.py, its recommended.
If you have defined path('app/home_view/', include('app.urls')) in urls.py of your store folder, then it goes to your urls.py which is in app.
In your app's urls.py you have written path('home_view/',views.home_view).
It means if you type 127.0.0.1:8000/app/home_view/home_view/ then it will render your HttpResponse that is Hello world.
I was working with 2 applications that are within a DJango project: "customer" and "vendors". Each application has a HTML file named "testindex.html".
Whenever I typed:
http://myhost/customer/basic_info
the correct page would show up
If I typed
http://myhost/vendors/basic_info
the page from http://myhost/customer/basic_info would show up
I found out that it was due to caching (since both applications use "testindex.html"). So again, "testindex.html" is caching.
How can one get around this problem?
TIA
Details are listed below. I have the following views defined:
urls.py for the project
urlpatterns = [
... snip ...
url(r'^customer/', include('libmstr.customer.urls')),
url(r'^vendors/', include('libmstr.vendors.urls')),
]
views.py for customer
from django.shortcuts import render
def basic_info(request):
return render(request, 'testindex.html', {})
views.py for vendors
from django.shortcuts import render
def basic_info(request):
return render(request, 'testindex.html', {})
urls.py for customers
from django.conf.urls import url
from . import views
# list of templates
app_name = 'customer'
urlpatterns = [
url(r'^basic_info/$', views.basic_info, name='basic_info'),
]
urls.py for vendors
from django.conf.urls import url
from . import views
# list of templates
app_name = 'vendors'
urlpatterns = [
url(r'^basic_info/$', views.basic_info, name='basic_info'),
]
It sounds like you have two templates, customers/templates/testindex.html and vendors/templates/testindex.html.
When you call render(request, 'testindex.html', {}), the app directories template loader searches the templates directory for each app in INSTALLED_APPS, and stops the first time it finds a match. If customers is above vendors in INSTALLED_APPS, then it will always use the customers template.
For this reason, Django recommends that you name your templates customers/templates/customers/testindex.html and vendors/templates/vendors/testindex.html, and change your views to use customers/testindex.html and vendors/testindex.html. This way you avoid clashes.
I have a project with two apps with their respective views, but I want to create a views.py in django project directory for some generic pages such as about, login... It is correct to place the views.py and templates in the root project folder for this purpose?
I have been reading about this. The practice more recommended for this is create an app that creates cohesion between other apps, call it web_site or site whatever is better for you.
python manage.py startapp my_site
Everything in this site app will be done the regular way.
In the projects url you will want to import the url in this way so the web pages appear in the / url pattern.
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('my_site.urls'))
]
I do this for project level pages like you describe. These are usually simple pages that tie the project's apps together, and not contain any business logic.
You can do that by making views.py file into the project directory.
from django.contrib import admin
from django.urls import path, include
from attendance import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('insert.urls')),
path('login/', views.logins, name='login'),# relevant line
]
And this is the code of login view
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def logins(request):
return HttpResponse("THIS IS LOGIN PAGE !!!")