Django Caching on front-end - django

I was working with 2 applications that are within a DJango project: "customer" and "vendors". Each application has a HTML file named "testindex.html".
Whenever I typed:
http://myhost/customer/basic_info
the correct page would show up
If I typed
http://myhost/vendors/basic_info
the page from http://myhost/customer/basic_info would show up
I found out that it was due to caching (since both applications use "testindex.html"). So again, "testindex.html" is caching.
How can one get around this problem?
TIA
Details are listed below. I have the following views defined:
urls.py for the project
urlpatterns = [
... snip ...
url(r'^customer/', include('libmstr.customer.urls')),
url(r'^vendors/', include('libmstr.vendors.urls')),
]
views.py for customer
from django.shortcuts import render
def basic_info(request):
return render(request, 'testindex.html', {})
views.py for vendors
from django.shortcuts import render
def basic_info(request):
return render(request, 'testindex.html', {})
urls.py for customers
from django.conf.urls import url
from . import views
# list of templates
app_name = 'customer'
urlpatterns = [
url(r'^basic_info/$', views.basic_info, name='basic_info'),
]
urls.py for vendors
from django.conf.urls import url
from . import views
# list of templates
app_name = 'vendors'
urlpatterns = [
url(r'^basic_info/$', views.basic_info, name='basic_info'),
]

It sounds like you have two templates, customers/templates/testindex.html and vendors/templates/testindex.html.
When you call render(request, 'testindex.html', {}), the app directories template loader searches the templates directory for each app in INSTALLED_APPS, and stops the first time it finds a match. If customers is above vendors in INSTALLED_APPS, then it will always use the customers template.
For this reason, Django recommends that you name your templates customers/templates/customers/testindex.html and vendors/templates/vendors/testindex.html, and change your views to use customers/testindex.html and vendors/testindex.html. This way you avoid clashes.

Related

Rendering new custom html templates in existing Django project

I'm not a Django expert but I need to make customizations of this software which is written in Django using the rest framework.
I need to render a custom html template let's say a.html, however when I go to http://localhost:8080/custom/custom/a I get redirected back to different page - not a.html.
This is what I've done so far. I created a new folder in apps called custom:
cvat
apps
custom
templates
custom
_init.py
a.html, b.html, ...
urls.py
apps.py
from django.apps import AppConfig
class CustomConfig(AppConfig):
name = 'cvat.apps.custom'
urls.py
from django.urls import path
from . import views
urlpatterns = [
path('custom/<str:name>', views.CustomView),
]
views.py
from django.shortcuts import render
def CustomView(request, name):
return render(request, 'custom/'+name+'.html')
In addition, I have modified these existing files to add the custom folder that was created in apps:
in urls.py added my url patterns:
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('cvat.apps.engine.urls')),
path('django-rq/', include('django_rq.urls')),
path('custom/', include('cvat.apps.custom.urls')),
]
in base.py added this:
INSTALLED_APPS = [
...
'cvat.apps.custom'
]
Any advice on what I'm doing wrong?
You can try something like this
url can be like this
urlpatterns = [
path('custom/<name>/', views.CustomView),
]
and your view should be like this.
def CustomView(request, name):
return render(request, f'custom/{name}.html')
Hope this will help you.

Python - Django add multiple urlpatterns for multiple views of template

I'm very very new to Python 3 and Django and I get to the following problem: I use a standard Template and now how to set it up when there is 1 view. But I don't get the code right for multiple views. I currently run the page locally
At the moment I have tried to change different orders within urlpatterns, and they do work when only 1 url in in there, but I can't get the second one in
views.py
from django.shortcuts import render, render_to_response
# Create your views here.
def index(request):
return render_to_response('index.html')
def store(request):
return render_to_response('store.html')
urls.py
from django.conf.urls import include, url
from django.contrib import admin
from myapp import views as views
from django.contrib.staticfiles.urls import staticfiles_urlpatterns
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^store/$', views.store, name='store'),
url(r'^admin/', admin.site.urls)
]
urlpatterns += staticfiles_urlpatterns()
I would like the url pattern that lets me go to the index view and the store view
EDIT:
Full code is shared via: https://github.com/lotwij/DjangoTemplate
The error in the comments shows you are going to http:/127.0.0.1:8000/store.html, but your URL pattern url(r'^store/$', ...) does not include the .html, so you should go to http:/127.0.0.1:8000/store/.
The Django URL system uncouples the URL from the name of the template (sometimes the view doesn't even render a template!). You could change the regex to r'^store.html$ if you really want .html in the URL, but I find the URL without the extension is cleaner.

Mezzanine ignores the view, displays the template but does not pass the context

I created a view for my model, with the corresponding urls and template files. Then, in the admin panel, I have created a Rich text page, specifying the same URL (ingredients) defined in urlpatterns. Mezzanine ignores the view, displays the template but does not pass the context.
How can I solve it?
These are the codes:
models.py
from django.db import models
from mezzanine.pages.models import Page
from django.utils.translation import ugettext_lazy as _
class Ingredient(Page):
name = models.CharField(max_length=60)
information = models.TextField(null=True, blank=True, verbose_name=_("Description"))
views.py
from django.template.response import TemplateResponse
from .models import Ingredient
def ingredients(request):
ingredients = Ingredient.objects.all().order_by('name')
templates = ["pages/ingredients.html"]
return TemplateResponse(request, templates, {'ingredients':ingredients})
urls.py
from django.conf.urls import url
from .views import ingredients
urlpatterns = [
url("^$", ingredients, name="ingredients"),
]
TemplateResponse does not expect the request in its arguments. See the docs.
return TemplateResponse(templates, {'ingredients':ingredients})
However I expect you meant to use the standard render function there:
return render(request, "pages/ingredients.html", {'ingredients':ingredients})
Ok, the solution has been define my app urls before any other definition in my project urls.py file.
project_name/project_name/urls.py
# Add the urlpatterns for any custom Django applications here.
# You can also change the ``home`` view to add your own functionality
# to the project's homepage.
urlpatterns = [
url(r'^ingredients/', include("apps.ingredients.urls")),
]
urlpatterns += i18n_patterns(
# Change the admin prefix here to use an alternate URL for the
# admin interface, which would be marginally more secure.
url("^admin/", include(admin.site.urls)),
)

Django views in project directory

I have a project with two apps with their respective views, but I want to create a views.py in django project directory for some generic pages such as about, login... It is correct to place the views.py and templates in the root project folder for this purpose?
I have been reading about this. The practice more recommended for this is create an app that creates cohesion between other apps, call it web_site or site whatever is better for you.
python manage.py startapp my_site
Everything in this site app will be done the regular way.
In the projects url you will want to import the url in this way so the web pages appear in the / url pattern.
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('my_site.urls'))
]
I do this for project level pages like you describe. These are usually simple pages that tie the project's apps together, and not contain any business logic.
You can do that by making views.py file into the project directory.
from django.contrib import admin
from django.urls import path, include
from attendance import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('insert.urls')),
path('login/', views.logins, name='login'),# relevant line
]
And this is the code of login view
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def logins(request):
return HttpResponse("THIS IS LOGIN PAGE !!!")

django urls: "Django tried these URL patterns"

I am trying a tutorial on Django called blog. I have the following structure:
FirstBlog|FirstBlog
settings
urls
__init__
etc
blog
templates | index.html
migrations
views.py
manage.py
The view.py has
from django.shortcuts import render
from django.shortcuts import render_to_response
from blog.models import posts
def home(request):
return render('index.html')
The urls.py has
from django.conf.urls import url
from django.conf.urls import include
from django.contrib import admin
urlpatterns = [
url(r'^blog', 'FirstBlog.blog.views.home',name='home'),
]
and I get this error:
Using the URLconf defined in FirstBlog.urls, Django tried these URL patterns, in this order: ^blog [name='home']
The current URL, , didn't match any of these.
I can't seem to get it right..
Any help would be appreciated.
Thank you,
You are requesting for / url and you have not saved any such mapping. Current mapping is for /blog . So it will work for the same url.
i.e goto the browser and request /blog
If you need it to work for / then change the urls appropriately.
within your blog app, create a urls.py file and add the following code which calls the home view.
blog/urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
#url(r'^',views.home, name='home'),
]
then in your root urls file which can be found at FirstBlog/urls.py
from django.conf.urls import url, include
from django.contrib import admin
urlpatterns = [
url(r'^blog/',include('blog.urls')), #when you visit this url, it will go into the blog application and visit the internal urls in the app
]
PS:
your templates should be in blog/templates/blog/index.html
Read this docs on templates to understand how django locates templates.
This one is to understand how urls work Urls dispatcher
You are doing this in the wrong way! Try doing that using TemplateView from class-based views, which are the current standard from django views.
Check the django documentation: https://docs.djangoproject.com/en/1.9/topics/class-based-views/
Use this at the urls.py:
from django.conf.urls import url
from django.views.generic import TemplateView
urlpatterns = [
url(r'^blog/', TemplateView.as_view(template_name="index.html")),
]
And then, create a folder called templates in the project root ( like this: https://docs.djangoproject.com/en/1.9/intro/tutorial03/#write-views-that-actually-do-something ) named index.html
Simply go to file then select Save all your project instead of save. Or use shortcut Ctrl +k s on windows. Project should be able to sync and display the code on Django interface