Setting age in Parellelised game of life - c++

Question

I am a university student and my teacher is making us to create a prey/predator simulation with OMP for. I had covid during his lectures and he didn’t upload them, so sorry I am being stupid here
Onto the question,
I have implemented Age as the absolute value for the cell as he asked but I simply cannot think of a way to make each cell have their own individual age after breeding. Here is my code:
#pragma omp parallel num_threads(4)
{
#pragma omp for schedule(dynamic, 1)
for (int i = 1; i <= Y; i++) //for loop Y
{
for (int j = 1; j <= X; j++) //for loop X
{
int Left = i - 1;
int Right = i + 1;
int Bottom = j - 1;
int Top = j + 1;
int Fish = 0;
int Shark = 0;
int FishAge = 1;
int SharkAge = -1;
int NewFishAge = 1;
//COUNTING SHARK AND FISH
//SHARK OR FISH - TOP LEFT
if (oldOcean[Left][Top] > 0)
{
Fish++;
}
else if (oldOcean[Left][Top] < 0)
{
Shark--;
}
//SHARK OR FISH - TOP
if (oldOcean[i][Top] > 0)
{
Fish++;
}
else if (oldOcean[i][Top] < 0)
{
Shark--;
}
//SHARK OR FISH - TOP RIGHT
if (oldOcean[Right][Top] > 0)
{
Fish++;
}
else if (oldOcean[Right][Top] < 0)
{
Shark--;
}
//SHARK OR FISH - LEFT
if (oldOcean[Left][j] > 0)
{
Fish++;
}
else if (oldOcean[Left][j] < 0)
{
Shark--;
}
//SHARK OR FISH - LEFT
if (oldOcean[Right][j] > 0)
{
Fish++;
}
else if (oldOcean[Right][j] < 0)
{
Shark--;
}
//SHARK OR FISH - LEFT
if (oldOcean[Left][Bottom] > 0)
{
Fish++;
}
else if (oldOcean[Left][Bottom] < 0)
{
Shark--;
}
//SHARK OR FISH - LEFT
if (oldOcean[i][Bottom] > 0)
{
Fish++;
}
else if (oldOcean[i][Bottom] < 0)
{
Shark--;
}
//SHARK OR FISH - LEFT
if (oldOcean[Right][Bottom] > 0)
{
Fish++;
}
else if (oldOcean[Right][Bottom] < 0)
{
Shark--;
}
//AGE
if (oldOcean[i][j] > 0)
{
oldOcean[i][j]++;
FishAge = oldOcean[i][j] - 2;
}
else if (oldOcean[i][j] < 0)
{
oldOcean[i][j]--;
SharkAge = oldOcean[i][j] * -1;
//std::cout << "AGE" << SharkAge;
}
//EMPTY CELLS & BREEDING
if (oldOcean[i][j] == 0)
{
//newOcean[i][j] = 0;
if (Fish >= 4 && Shark > -4 && FishAge >= 2)
{
newOcean[i][j]=1;
}
else if (Shark <= -4 && Fish < 4 && SharkAge >= 3)
{
newOcean[i][j] = -1;
}
else
{
newOcean[i][j] = 0;
}
newOcean[i][j] = oldOcean[i][j];
}
//FISH CELLS
if (oldOcean[i][j] > 0)
{
if (FishAge < 10)
{
FishAge++;
}
//std::cout <<FishAge;
if (FishAge >= 10 || Shark <= -5)
{
oldOcean[i][j] = 0; //kill fish
FishAge = 0;
}
if (Fish >= 8)
{
newOcean[i][j] = 0; //overpopulation
}
newOcean[i][j] = oldOcean[i][j];
}
//SHARK CELLS
if (oldOcean[i][j] < 0)
{
if (SharkAge <= 20 )
{
SharkAge++;
}
if ((Shark <= -6 && Fish == 0) || SharkAge >= 20)
{
oldOcean[i][j] = 0; // dies of Starvation
SharkAge = 0;
}
if (ChanceofDeath <= rand() / ((int)RAND_MAX + 32))
{
newOcean[i][j] = 0; // Random Death ???
}
newOcean[i][j] = oldOcean[i][j];
}
}
}
}
I am a very amateur coder, so any improvement feel free to tell me too please, I love to learn
my code for the age is under the "//AGE" section
Sorry again, and thanks for the help.

Answer 1

Even without considering age, you must check every cell in every generation. And it should be easy to maintain an age per cell during these checks:
If a dead cell has three neighbors, it gets born (cell.age = 0).
If an alive cell has two or three neighbors, it survives (cell.age++).
If an alive cell has less than two or more than three neighbors, it dies. (No cell.age any more.)