I am using ARRAYFORMULA with multiple conditions using SUMIF concatenating the conditions using & and it works. Now I would like to use similarly this idea for a special condition indicating to consider all values using a wildcard ("ALL") for a given column, but it doesn't work.
Here is my example:
On I2if have the following formula:
=ARRAYFORMULA(if(not(ISBLANK(H2:H)),sumif(B2:B & C2:C & D2:D & year(E2:E),
if($G$2="ALL",B2:B,$G$2) & if($G$4="ALL",C2:C,$G$4) & if($G$6="ALL",D2:D,$G$6) &
H2:H,A2:A),))
and it works, when I enter specific values, but when I use my wildcard: ALL indicating that for a given column/criteria all values should be taken into consideration, it doesn't work as expected. The scenario should consider that all criteria can be labeled as ALLin such case it will provide the sum of NUM per year.
Here is my testing sample in Google Spreadsheet:
https://docs.google.com/spreadsheets/d/1c28KRQWgPCEdzVvwvXFOQ3Y13MBDjpEgKdfoLipFAOk/edit?usp=sharing
Notes:
I was able to get a solution for that using SUMPRODUCT but this function doesn't get expanded with ARRAYFORMULA
In my real example I have more conditions, so I am looking for a solution that escalates having more conditions
use:
=QUERY(QUERY(FILTER(A2:E,
IF(G2="All", B2:B<>"×", B2:B=G2),
IF(G4="All", C2:C<>"×", C2:C=G4),
IF(G6="All", D2:D<>"×", D2:D=G6)),
"select year(Col5),sum(Col1)
where Col1 is not null
group by year(Col5)"),
"offset 1", 0)
Related
IDENTIFIER
31-03-2022_13636075
01-04-2022_13650262
04-04-2022_13663174
05-04-2022_13672025
20220099001
11614491_R
10781198
00000000000
11283627_P
11614491_R
-1
how can i remove (only) the "XX-XX-XXXXX_" Part in certain values of a column in SSIS but WITHOUT affecting values that doesn't have this format? For example "21-05-2022_12345678" = "12345678" but the other values i don't want them affected. This are just examples of many rows from this column so i want only the ones that have this format to be affected.
SELECT REVERSE(substring(REVERSE('09-03-2022_13481330'),0,CHARINDEX('_',REVERSE('09-03-2022_13481330'),0)))
result
13481330
but this also affects others values.Also this is in ssms not ssis because i am not sure how to transform this expression in ssis code.
Update : Corrected code in SSIS goes as following:
(FINDSTRING(IDENTIFIER,"__-__-____[_]",1) == 1) ? SUBSTRING(IIDENTIFIER,12,LEN(IDENTIFIER) - 11) : IDENTIFIER
Do you have access to the SQL source? You can do this on the sql by using a LIKE and crafting a match pattern using the single char wildcard _ please see below example
DECLARE #Value VARCHAR(50) = '09-03-2022_13481330'
SELECT CASE WHEN #Value LIKE '__-__-____[_]%' THEN
SUBSTRING(#Value,12,LEN(#Value)-11) ELSE #Value END
Please see the Microsoft Documentation on LIKE and using single char wildcards
If you don't have access to the source SQL it gets a bit more tricky as you might need to use regex in a script task or maybe there is a expression you can apply
Goal: I have a bunch of keywords I'd like to categorise automatically based on topic parameters I set. Categories that match must be in the same column so the keyword data can be filtered.
e.g. If I have "Puppies" as a first topic, it shouldn't appear as a secondary or third topic otherwise the data cannot be filtered as needed.
Example Data: https://docs.google.com/spreadsheets/d/1TWYepApOtWDlwoTP8zkaflD7AoxD_LZ4PxssSpFlrWQ/edit?usp=sharing
Video: https://drive.google.com/file/d/11T5hhyestKRY4GpuwC7RF6tx-xQudNok/view?usp=sharing
Parameters Tab: I will add words in columns D-F that change based on the keyword data set and there will often be hundreds, if not thousands, of options for larger data sets.
Categories Tab: I'd like to have a formula or script that goes down the columns D-F in Parameters and fills in a corresponding value (in Categories! columns D-F respectively) based on partial match with column B or C (makes no difference to me if there's a delimiter like a space or not. Final data sheet should only have one of these columns though).
Things I've Tried:
I've tried a bunch of things. Nested IF formula with regexmatch works but seems clunky.
e.g. this formula in Categories! column D
=IF(REGEXMATCH($B2,LOWER(Parameters!$D$3)),Parameters!$D$3,IF(REGEXMATCH($B2,LOWER(Parameters!$D$4)),Parameters!$D$4,""))
I nested more statements changing out to the next cell in Parameters!D column (as in , manually adding $D$5, $D$6 etc) but this seems inefficient for a list thousands of words long. e.g. third topic will get very long once all dog breed types are added.
Any tips?
Functionality I haven't worked out:
if a string in Categories B or C contains more than one topic in the parameters I set out, is there a way I can have the first 2 to show instead of just the first one?
e.g. Cell A14 in Categories, how can I get a formula/automation to add both "Akita" & "German Shepherd" into the third topic? Concatenation with a CHAR(10) to add to new line is ideal format here. There will be other keywords that won't have both in there in which case these values will just show up individually.
Since this data set has a bunch of mixed breeds and all breeds are added as a third topic, it would be great to differentiate interest in mixes vs pure breeds without confusion.
Any ideas will be greatly appreciated! Also, I'm open to variations in layout and functionality of the spreadsheet in case you have a more creative solution. I just care about efficiently automating a tedious task!!
Try using custom function:
To create custom function:
1.Create or open a spreadsheet in Google Sheets.
2.Select the menu item Tools > Script editor.
3.Delete any code in the script editor and copy and paste the code below into the script editor.
4.At the top, click Save save.
To use custom function:
1.Click the cell where you want to use the function.
2.Type an equals sign (=) followed by the function name and any input value — for example, =DOUBLE(A1) — and press Enter.
3.The cell will momentarily display Loading..., then return the result.
Code:
function matchTopic(p, str) {
var params = p.flat(); //Convert 2d array into 1d
var buildRegex = params.map(i => '(' + i + ')').join('|'); //convert array into series of capturing groups. Example (Dog)|(Puppies)
var regex = new RegExp(buildRegex,"gi");
var results = str.match(regex);
if(results){
// The for loops below will convert the first character of each word to Uppercase
for(var i = 0 ; i < results.length ; i++){
var words = results[i].split(" ");
for (let j = 0; j < words.length; j++) {
words[j] = words[j][0].toUpperCase() + words[j].substr(1);
}
results[i] = words.join(" ");
}
return results.join(","); //return with comma separator
}else{
return ""; //return blank if result is null
}
}
Example Usage:
Parameters:
First Topic:
Second Topic:
Third Topic:
Reference:
Custom Functions
I've added a new sheet ("Erik Help") with separate formulas (highlighted in green currently) for each of your keyword columns. They are each essentially the same except for specific column references, so I'll include only the "First Topic" formula here:
=ArrayFormula({"First Topic";IF(A2:A="",,IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))) & IFERROR(CHAR(10)®EXEXTRACT(REGEXREPLACE(LOWER(B2:B&C2:C),IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))),""),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))))})
This formula first creates the header (which can be changed within the formula itself as you like).
The opening IF condition leaves any row in the results column blank if the corresponding cell in Column A of that row is also blank.
JOIN is used to form a concatenated string of all keywords separated by the pipe symbol, which REGEXEXTRACT interprets as OR.
IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))) will attempt to extract any of the keywords from each concatenated string in Columns B and C. If none is found, IFERROR will return null.
Then a second-round attempt is made:
& IFERROR(CHAR(10)®EXEXTRACT(REGEXREPLACE(LOWER(B2:B&C2:C),IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))),""),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>"")))))
Only this time, REGEXREPLACE is used to replace the results of the first round with null, thus eliminating them from being found in round two. This will cause any second listing from the JOIN clause to be found, if one exists. Otherwise, IFERROR again returns null for round two.
CHAR(10) is the new-line character.
I've written each of the three formulas to return up to two results for each keyword column. If that is not your intention for "First Topic" and "Second Topic" (i.e., if you only wanted a maximum of one result for each of those columns), just select and delete the entire round-two portion of the formula shown above from the formula in each of those columns.
I want to filter my SPARQL query for specific keywords while at the same time excluding other keywords. I thought this may be easily accomplished with FILTER (regex(str(?var),"includedKeyword","i") && !regex(str(?var),"excludedKeyword","i")). It works without the "!" condition, but not with. I also separated the FILTER statements, but no use.
I used this query on http://europeana.ontotext.com/ :
PREFIX dc: <http://purl.org/dc/elements/1.1/>
PREFIX edm: <http://www.europeana.eu/schemas/edm/>
PREFIX ore: <http://www.openarchives.org/ore/terms/>
SELECT DISTINCT ?CHO
WHERE {
?proxy dc:subject ?subject .
FILTER ( regex(str(?subject),"gemälde","i") && !regex(str(?subject),"Fotografie","i") )
?proxy edm:type "IMAGE" .
?proxy ore:proxyFor ?CHO.
?agg edm:aggregatedCHO ?CHO; edm:country "germany".
}
But I always get the result on the first row with the title "Gemäldegalerie", which has a dc:subject of "Fotografie" (the one I want excluded). I think the problem lies in the fact that one object from the Europeana database can have more than one dc:subject property, so maybe it looks only for one of these properties while ignoring the other ones.
Any ideas? Would be very thankful!
The problem is that your combined filter checks for the same binding of ?subject. So it succeeds if at least one value of ?subject matches both conditions (which is almost always true, because the string "Gemäldegalerie", for example, matches your first regex and does not match the second).
So for the negative condition, you need to formulate something that checks for all possible values, rather than just one particular value. You can do this using SPARQL's NOT EXISTS function, for example like this:
PREFIX dc: <http://purl.org/dc/elements/1.1/>
PREFIX edm: <http://www.europeana.eu/schemas/edm/>
PREFIX ore: <http://www.openarchives.org/ore/terms/>
SELECT DISTINCT ?CHO
WHERE {
?proxy edm:type "IMAGE" .
?proxy ore:proxyFor ?CHO.
?agg edm:aggregatedCHO ?CHO; edm:country "germany".
?proxy dc:subject ?subject .
FILTER(regex(str(?subject),"gemälde","i"))
FILTER NOT EXISTS {
?proxy dc:subject ?otherSubject.
FILTER(regex(str(?otherSubject),"Fotografie","i"))
}
}
As an aside: since you are doing regular expression checks, and now combining them with an NOT EXISTS operator, this is likely to become very expensive for the query processor quite quickly. You may want to think about alternative ways to formulate your query (for example, using the exact subject string to include or exclude to eliminate the regex), or even having a look at some non-standard extensions that the SPARQL endpoint might provide (OWLIM, for example, the store on which the Europeana endpoint runs, supports various full-text-search extensions, though I am not sure they are enabled in the Europeana endpoint).
I am trying to compare two string variables to discover if one is contained in the other, specifically if one is composed of the other (so, I would like to avoid retrieving that "information" contains "format". I am interested only in results similar to "information_management" includes "information".
I have tried both FILTER CONTAINS() and FILTER regex() with the same results. How can I modify the query so it includes the fact that there needs to be a space either before or after the term?
SELECT DISTINCT ?l1 ?l2
WHERE
{
?term1 skos:prefLabel ?l1.
?term2 skos:prefLabel ?l2.
FILTER(contains(?l1,?l2))
}
So if I understand you correctly you want to find pairs of terms where one term is contained in the other but is not equal to the other?
If so you can add a !SAMETERM() call into the the FILTER clause like so:
SELECT DISTINCT ?l1 ?l2
WHERE
{
?term1 skos:prefLabel ?l1.
?term2 skos:prefLabel ?l2.
FILTER(!SAMETERM(?l1, ?l2) && contains(?l1,?l2))
}
Edit
Re-reading the question I don't think I addressed the whole question, for the problem where you have the terms "format" and "information" and don't want them to be matched you can do something like the following:
SELECT DISTINCT ?l1 ?l2
WHERE
{
?term1 skos:prefLabel ?l1.
?term2 skos:prefLabel ?l2.
FILTER(!SAMETERM(?l1, ?l2)
&& contains(?l1,?l2)
&& ( STRENDS(STRBEFORE(?l1, ?l2)," ")
|| STRSTARTS(STRAFTER(?l1, ?l2), " ")
))
}
This requires that the string before/after the containing term must end/start with whitespace. You may have to play around with this to get something that more closely models your constraints.
Another solution would be by constructing a regex pattern on the fly, like:
FILTER(regex(concat("\\b", ?l1, "\\b"), ?l2))
I'm not entirely sure that SPARQL/XML Schema requires \b, but I think most implementations will have it.
I have a database filled with some codes like
EE789323
990
78000
These numbers are ALWAYS endings of a larger code. Now I have a function that needs to check if the larger code contains the subcode.
So if I have codes 90 and 990 and my full code is EX888990, it should match both of them.
However I need to do it in the following way:
SELECT * FROM tableWithRecordsWithSubcode
WHERE subcode MATCHES [reg exp with full code];
Is a regular expression like this this even possible?
EDIT:
To clarify the issue I'm having, I'm not using SQL here. I just used that to give an example of the type of query I'm using.
In fact I'm using iOS with CoreData, and I need a predicate to fetch me only the records that match.
In the way that is mentioned below.
Given the observations from a comment:
Do you have two tables, one called tableWithRecordsWithSubcode and another that might be tableWithFullCodeColumn? So the matching condition is in part a join - you need to know which subcodes match any of the full codes in the second table? But you're only interested in the information in the tableWithRecordsWithSubcode table, not in which rows it matches in the other table?
and the laconic "you're correct" response, then we have to rewrite the query somewhat.
SELECT DISTINCT S.*
FROM tableWithRecordsWithSubcode AS S
JOIN tableWithFullCodeColumn AS F
ON F.Fullcode ...ends-with... S.Subcode
or maybe using an EXISTS sub-query:
SELECT S.*
FROM tableWithRecordsWithSubcode AS S
WHERE EXISTS(SELECT * FROM tableWithFullCodeColumn AS F
WHERE F.Fullcode ...ends-with... S.Subcode)
This uses a correlated sub-query but avoids the DISTINCT operation; it may mean the optimizer can work more efficiently.
That just leaves the magical 'X ...ends-with... T' operator to be defined. One possible way to do that is with LENGTH and SUBSTR. However, SUBSTR does not behave the same way in all DBMS, so you may have to tinker with this (possibly adding a third argument, LENGTH(s.subcode)):
LENGTH(f.fullcode) >= LENGTH(s.subcode) AND
SUBSTR(f.fullcode, LENGTH(f.fullcode) - LENGTH(s.subcode)) = s.subcode
This leads to two possible formulations:
SELECT DISTINCT S.*
FROM tableWithRecordsWithSubcode AS S
JOIN tableWithFullCodeColumn AS F
ON LENGTH(F.Fullcode) >= LENGTH(S.Subcode)
AND SUBSTR(F.Fullcode, LENGTH(F.Fullcode) - LENGTH(S.Subcode)) = S.Subcode;
and
SELECT S.*
FROM tableWithRecordsWithSubcode AS S
WHERE EXISTS(
SELECT * FROM tableWithFullCodeColumn AS F
WHERE LENGTH(F.Fullcode) >= LENGTH(S.Subcode)
AND SUBSTR(F.Fullcode, LENGTH(F.Fullcode) - LENGTH(S.Subcode)) = S.Subcode);
This is not going to be a fast operation; joins on computed results such as required by this query seldom are.
I'm not sure why you think that you need a regular expression... Just use the charindex function:
select something
from table
where charindex(code, subcode) <> 0
Edit:
To find strings at the end, you can create a pattern with the % wildcard from the subcode:
select something
from table
where '%' + subcode like code