I'm building a function for deleting a node in a binary tree; since two of three cases are fairly simple (no children and 1 child) I've built another function to "re-arrange" the nodes beneath the one I'm trying to delete, in case it has two children.
I built the function so that it returns a pointer, which is the re-arranged subtree, but I've also tried making a function that just changes the tree itself, without returning a value, but both seem to create a loop where the tree changes: when I try to print the tree, it's stuck printing between the value I replace and it's left child, back and forth until eventually a segfault 11 pops up. I'm really lost as even the debugger isn't helping me understand where the issue is, can anyone tell me where to look? Thank you in advance for your kind attention and your time
Here is the tree I was thinking of before the deletion:1
And here it is after the deletion:2
'''
if (found the value) // value is head (recursive)
{
Node* to_delete = head;
...
head = subNode (head);
delete to_delete;
}
'''
Node* b_tree :: subNode (Node*&head)
{
Node*curr = head->right;
if (((!curr->right) && (!curr->left)) || (!curr->left)) // if it's a leaf or at least if the left pointer is NULL
{
curr->left = head->left;
head->left = NULL;
Node*to_return = curr;
return to_return;
}else // if there's a lower value...
{
while (curr->left != NULL) // find the lowest in the sub-tree
{
curr = curr->left;
}
if (!curr->right)
{
curr->right = head->right;
curr->left = head->left;
Node* to_return = curr;
curr = NULL;
return to_return;
} else {
Node* temp = curr->right;
curr->right = head->right;
curr->left = head->left;
Node*to_return = curr;
curr = temp;
return to_return;
}
}
};
''' Here's the whole code
'''
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
struct Node
{
Node ();
Node (string, int);
string name;
int value;
Node* left;
Node* right;
};
Node :: Node ()
{
left = right = NULL;
}
Node :: Node (string nome, int valore)
{
this->name = nome;
this->value = valore;
this->left = NULL;
this->right = NULL;
};
class b_tree
{
private:
Node* head;
void insRic (Node*&, Node);
void stampaRic (Node*);
void deleteRic (Node*&, Node);
Node* subNode (Node*&);
public:
b_tree ();
void inserimento (Node);
void delete (Node);
void stampa ();
};
b_tree :: b_tree ()
{
this->head = NULL;
};
void b_tree :: inserimento (Node temp)
{
insRic(this->head, temp);
};
void b_tree :: insRic (Node*& head, Node temp)
{
if (head != NULL)
{
if (temp.value < head->value)
{
insRic(head->left, temp);
} else if (temp.value > head->value)
{
insRic(head->right, temp);
}
} else
{
head = new Node (temp.name, temp.value);
}
};
void b_tree :: stampa ()
{
stampaRic (this->head);
};
void b_tree :: stampaRic (Node* head)
{
if (head != NULL)
{
if (head->left != NULL)
{
stampaRic (head->left);
}
cout << "Nome: " << head->name << " | Valore: " << head->value << endl;
if (head->right != NULL)
{
stampaRic (head->right);
}
}
};
Node* b_tree :: subNode (Node*&head)
{
Node*curr = head->right;
if (((!curr->right) && (!curr->left)) || (!curr->left)) // if it's a leaf or at least if the leftious pointer is NULL
{
curr->left = head->left;
head->left = NULL;
Node*to_return = curr;
return to_return;
}else // if there's a lower value...
{
while (curr->left != NULL) // find the lowest in the sub-tree
{
curr = curr->left;
}
if (!curr->right)
{
curr->right = head->right;
curr->left = head->left;
Node* to_return = curr;
curr = NULL;
return to_return;
} else {
Node* temp = curr->right;
curr->right = head->right;
curr->left = head->left;
Node*to_return = curr;
curr = temp;
return to_return;
}
}
};
void b_tree :: delete (Node temp)
{
deleteRic (this->head, temp);
};
void b_tree :: deleteRic (Node*& head, Node temp)
{
if (head != NULL) // if head points ot something
{
if (head->value != temp.value) // if the node I'm trying to delete has a different name, jusr call it again until it finds it
{
if (temp.value < head->value)
{
eliminaRic (head->left, temp);
} else if (temp.value > head->value)
{
eliminaRic (head->right, temp);
}
} else // once I've found the value I'm trying to delete;
{
Node*to_delete = head;
if ((head->right == NULL) && (head->left == NULL)) // checking that the node is not a leaf
{
head = NULL;
delete to_delete;
} else if (head->left == NULL) // if leftious pointer is null
{
to_delete = head->right;
delete to_delete;
} else if (head->right == NULL) // if right pointer in null
{
head = head->left;
delete to_delete;
}
else if ((head->right != NULL) && (head->left != NULL)) // if neither pointer is null (2 children);
{
head = subNode (head);
delete to_delete;
}
}
}
}
int main ()
{
b_tree*albero = new b_tree ();
Node temp = Node ();
for (int i = 0; i < 7; i++)
{
cout << "Insert name and value; name: "; cin >> temp.name; cout << " value : "; cin >> temp.value; cout << endl;
albero->inserimento(temp);
}
albero->stampa();
cout << "Insert the value of the node you wish to delete: "; cin >> temp.value;
albero->delete(temp);
albero->stampa();
}
'''
Here are some issues:
The main problem is in the second half of subNode. The following line (that occurs twice) creates a cycle:
curr->next = head->next;
As curr is a descendant of head->next, this closes a cycle. This cycle is not broken by anything that follows.
curr = NULL or curr = temp is useless. It only sets a value of a variable and doesn't mutate the tree (which may be what you thought it did).
to_return should not be set to curr, but to head->next.
Not a problem, but the if condition at the top of subNode is equivalent to just !curr->prev.
Not a problem, but head->prev = NULL is not really needed, as head is going to be deleted anyway.
When these points are taken into account, some code repetition can be avoided, and the code can be reduced to the following:
Node* b_tree :: subNode (Node*&head)
{
Node* curr = head->next;
while (curr->prev != NULL)
{
curr = curr->prev;
}
curr->prev = head->prev;
return head-next;
};
Side note: this algorithm will more quickly increase the gravity with which the tree is unbalanced, as a whole subtree is moved at a lower place in the tree. This may even double the height of the tree with just one delete operation. I would therefor prefer the original, popular algorithm for deletion.
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I am trying to make a quicksort algorithm for singly-linked lists. I, however, must be somehow creating a cyclical list in the process. In the concatenate function, the while loop gets stuck printing out 2 and 22 continuously. So, I assume that I must somehow be creating a list where Node 2 points to Node 22 and vice versa. Unfortunately, I have no idea how, since I feel like I have added nullptr to the end of every list where it would matter. I have reviewed my partition function so many times I add more bugs than I fix. Is there something I am missing with how linked lists work?
I have been stuck on this for a while so any help would be greatly appreciated.
Here is my quicksort code.
// quick.cpp
#include "volsort.h"
#include <iostream>
#include <string>
using namespace std;
// Prototypes
Node *qsort(Node *head, bool numeric);
void partition(Node *head, Node *pivot, Node *&left, Node *&right, bool numeric);
Node *concatenate(Node *left, Node *right);
// Implementations
void quick_sort(List &l, bool numeric) {
l.head = qsort(l.head, numeric);
}
Node *qsort(Node *head, bool numeric) {
if (head == nullptr || head->next == nullptr) {
return head;
}
Node *l = nullptr;
Node *r = nullptr;
partition(head, head, l, r, numeric);
l = qsort(l, numeric);
r = qsort(r, numeric);
head = concatenate(l, head);
head = concatenate(head, r);
return head;
}
void partition(Node *head, Node *pivot, Node *&left, Node *&right, bool numeric) {
Node *cur = pivot->next;
bool c;
Node *tl=nullptr, *tr=nullptr;
while (cur != pivot && cur != nullptr) {
if (numeric) {
c = node_number_compare(cur, pivot);//compare numeric elements of the Nodes
}
else {
c = node_string_compare(cur, pivot);//compare string elements of the code
}
if (c) {
if (left == nullptr) {
left = cur;
cur = cur->next;
tl = left;
}
else {
tl->next = cur;
cur = cur->next;
tl = tl->next;
tl->next = nullptr;
}
}
else {
if (right == nullptr) {
right = cur;
cur = cur->next;
tr = right;
}
else {
tr->next = cur;
cur = cur->next;
tr = tr->next;
tr->next = nullptr;
}
}
}
}
Node *concatenate(Node *left, Node *right) {
if (right == nullptr && left == nullptr) {
return nullptr;
}
else if (left == nullptr) {
right->next = nullptr;
return right;
}
else if (right == nullptr) {
left->next = nullptr;
return left;
}
Node *t = left;
while (t->next != nullptr) {
cout << t->number << endl;
t = t->next;
}
t->next = right;
while (t->next != nullptr) {
cout << t->number << endl;
t = t->next;
}
t->next = nullptr;
return left;
}
Input:
45
4
9
22
2
Here's the list class functions if it helps.
#include "volsort.h"
#include <string>
#include <iostream>
List::List() {
head = NULL;
size = 0;
}
List::~List() {
if (head != NULL) { // follow the links, destroying as we go
Node *p = head;
while (p != NULL) {
Node *next = p->next; // retrieve this node's "next" before destroy it
delete p;
p = next;
}
}
}
bool node_number_compare(const Node *a, const Node *b) {
if (a->number <= b-> number) {
return true;
}
else {
return false;
}
}
bool node_string_compare(const Node *a, const Node *b) {
return a->string <= b->string;
}
void List::push_front(const std::string &s) {
Node *node = new Node();
node->next = NULL;
node->string = s;
node->number = std::stoi(s);
if (head == NULL) {
head = node;
size = 1;
}
else {
Node *p = head;
while (p->next != NULL) {p = p->next;} // go to end of list
p->next = node;
size++;
}
}
void List::dump_node(Node *n) {
while (n->next != NULL) {
std::cout << n->number << " " << n->string << std::endl;
}
}
I have previously posted some part of this task here.
I am now implementing a method that removes an element at a given index. My code is
void remove(int index)
{
if (head != NULL)
{
Node *current = get_node(index);
Node *prev = get_node(index - 1);
Node *next = get_node(index + 1);
prev->next = current->next;
delete current;
}
}
however, I am facing this error message
libc++abi.dylib: terminating with uncaught exception of type
std::range_error: IndexError: Index out of range
Abort trap: 6
I am guessing the problem is the pointers, but I am not sure why this is not working. Anyone who can help?
I think you can handle corner cases like this:
#include <iostream>
using namespace std;
struct Node {
Node(int val) {
this->val = val;
}
struct Node * next;
int val;
};
class LinkedList {
public:
Node* head;
LinkedList() {
head = new Node(1);
Node * n1 = new Node(2);
head->next = n1;
Node * n2 = new Node(3);
n1->next = n2;
}
void remove(int index) {
if (head == NULL) {
return;
}
int pos = 0;
Node * cur = head;
Node *prev = NULL;
while (cur != NULL) {
if (pos == index) {
break;
}
pos++;
prev = cur;
cur = cur->next;
}
if (prev == NULL) {
head = head->next;
}
else {
prev->next = cur->next;
}
delete cur;
}
};
void print(Node * head){
cout << "Current linked list:\n";
while(head != NULL) {
cout << head->val << endl;
head = head->next;
}
cout << endl;
}
int main() {
LinkedList * list = new LinkedList();
print(list->head);
list->remove(0);
print(list->head);
list->remove(1);
print(list->head);
list->remove(0);
print(list->head);
}
This code is supposed to reverse a linked list. The following code returns an empty linked list even when provided with a non empty list.
class Solution {
public:
ListNode* reverseList(ListNode* head) {
ListNode* curr, *prev, *next;
if (head == NULL)
{
return head;
}
curr = head;
prev = NULL;
while (curr != NULL)
{
next = curr -> next;
curr -> next = prev;
prev = curr;
curr = next;
}
head = prev;
return head;
}
};
While this code strangely works where I added a cout statement just to check if the else was triggered.
class Solution {
public:
ListNode* reverseList(ListNode* head) {
ListNode* curr, *prev, *next;
if (head == NULL)
{
cout << "Triggered";
return head;
}
curr = head;
prev = NULL;
while (curr != NULL)
{
next = curr -> next;
curr -> next = prev;
prev = curr;
curr = next;
}
head = prev;
return head;
}
};
Can someone please explain why this is happening?
Pretty simple, you have to initialize the pointers, else it leads to unexpected behavior that includes not showing it at all or just showing it if an initialized cout is triggered - but it doesn't have to do anything and that's up to your compiler implementation.
//cpp17
listNode* curr{}, *prev{}, *next{};
//before
listNode* curr = nullptr, *prev = nullptr, *next = nullptr;
It is still not in the reverse order as you intended to do.
class Solution {
public:
ListNode* reverseList(ListNode* head) {
listNode* curr{}, *prev{}, *next{};
//ListNode* curr, *prev, *next;
if (head == NULL)
{
return head;
}
curr = head;
prev = NULL;
while (next != NULL)
{
next = curr -> next;
curr -> next = prev;
prev = curr;
curr = next;
}
head = prev;
return head;
}
};
cheers :)
Like mentioned before I found time to write a solution for an other approach of solving your problem to reverse a linked list via class. For a better understanding for beginners I skipped the rule of three/five and initialized the list in the main function and not via constructor in the class:
#include <iostream>
class listElement
{
std::string data;
listElement* next;
listElement* last;
public:
void setData(std::string);
void append(std::string);
void displayElements();
void reverseDisplayElements(listElement*);
void freeMemory();
listElement* reverseList(listElement*);
};
void listElement::setData(std::string newData)
{
last = this;
data = newData;
next = nullptr;
}
void listElement::append(std::string newData)
{
// Double linked list
// last->next = new listElement();
// last->next->data = newData;
// last->next->next = nullptr;
// last = last->next;
// Singly linked list
//has next the value nullptr?
//If yes, next pointer
if (next == nullptr)
{
next = new listElement();
next->data = newData;
next->next = nullptr;
}
//else the method again
else
next->append(newData);
}
listElement* listElement::reverseList(listElement* head)
{
//return if no element in list
if(head == nullptr)
return nullptr;
//initialize temp
listElement* temp{};
while(head != nullptr){
listElement* next = head->next;
head->next = temp;
temp = head;
head = next;
}
return temp;
}
void listElement::displayElements()
{
//cout the first entry
std::cout << data << std::endl;
//if the end is not reached, call method next again
if (next != nullptr)
next->displayElements();
}
void listElement::reverseDisplayElements(listElement*head)
{
//recursiv from the last to the list beginning - stop
listElement *temp = head;
if(temp != nullptr)
{
if(temp->next != nullptr)
{
reverseDisplayElements(temp->next);
}
std::cout << temp->data << std::endl;
}
}
void listElement::freeMemory()
{
//If the end is not reached, call the method again
if (next != nullptr)
{
next->freeMemory();
delete(next);
}
}
int main ()
{
//Pointer to the Beginning of the list
listElement* linkedList;
//Creating the first element
linkedList = new listElement();
//Write data in the first element
linkedList->setData("Element 1");
//add more elements
linkedList->append("Element 2");
linkedList->append("Element 3");
linkedList->append("Element 4");
//display list
linkedList->displayElements();
//space divider
std::cout << "\nPrint in reverse order:" << std::endl;
//display list in reverse order
//pass list beginning as stop point
linkedList->reverseDisplayElements(linkedList);
std::cout << std::endl;
linkedList->displayElements();
std::cout << "\nReverse elements:" << std::endl;
linkedList = linkedList->reverseList(linkedList);
linkedList->displayElements();
std::cout << std::endl;
//destruct the list and free memory
linkedList->freeMemory();
delete(linkedList);
return 0;
}
Btw. there are many different solutions for that task.
Here using the function returnReverseLinkedList I am returning the reversed linked list of the given linked list. But the problem with this approach is that i lose the original linked list. So I make another fucntion called createReversedLinkedList to make a copy of the original linked list and reverse the copy and maintain possession of both.
unfortunately createReversedLinkedList is giving Runtime error.
obviously my end goal is to check if the given linked list is palindrome or not. This issue is just a stepping stone.
Could someone tell me why?
//Check if a linked list is a palindrome
#include <iostream>
using namespace std;
class node
{
public:
int data;
node *next;
node(int data)
{
this->data = data;
this->next = NULL;
}
};
node *returnReverseLinkedList(node *head)
{
// Will Lose original Linked List
if (head == NULL)
return NULL;
else if (head != NULL && head->next == NULL)
return head;
node *prev = NULL;
node *curr = head;
node *tempNext = head->next;
while (tempNext != NULL)
{
curr->next = prev;
prev = curr;
curr = tempNext;
tempNext = tempNext->next;
}
curr->next = prev;
return curr;
}
node *createReversedLinkedList(node *head)
{
if (head == NULL)
return NULL;
else if (head != NULL && head->next == NULL)
return NULL;
else
{
node *temp = head;
node *newHead = NULL;
node *newTail = NULL;
while (temp != NULL)
{
node *newNode = new node(temp->data);
if (newHead == NULL)
{
newHead = newNode;
newTail = newNode;
}
else
{
newTail->next = newNode;
newTail = newNode;
}
}
return returnReverseLinkedList(newHead);
}
}
bool check_palindrome(node *head)
{
node *original = head;
node *reverse = returnReverseLinkedList(head);
while (original->next != NULL || reverse->next != NULL)
{
if (original->data != reverse->data)
return false;
cout << "debug 2" << endl;
original = original->next;
reverse = reverse->next;
}
return true;
}
// #include "solution.h"
node *takeinput()
{
int data;
cin >> data;
node *head = NULL, *tail = NULL;
while (data != -1)
{
node *newnode = new node(data);
if (head == NULL)
{
head = newnode;
tail = newnode;
}
else
{
tail->next = newnode;
tail = newnode;
}
cin >> data;
}
return head;
}
void print(node *head)
{
node *temp = head;
while (temp != NULL)
{
cout << temp->data << " ";
temp = temp->next;
}
cout << endl;
}
int main()
{
node *head = takeinput();
node *revese2 = createReversedLinkedList(head);
print(revese2);
// bool ans = check_palindrome(head);
// if (ans)
// cout << "true";
// else
// cout << "false";
// return 0;
}
As asked by the OP, building a reversed linked is simply done by building as you would a stack (e.g LIFO) rather than duplicating the same original forward chain. For example:
node *createReversedLinkedList(const node *head)
{
node *newHead = NULL;
for (; head; head = head->next)
{
node *p = new node(head->data)
p->next = newHead;
newHead = p;
}
return newHead;
}
Note we're not hanging our copied nodes on the tail of the new list; they're hanging on the head of the new list, and becoming the new head with each addition. That's it. There is no need to craft an identical list, then reverse it; you can reverse it while building the copy to begin with.
A note on the remainder of your code. You have a dreadful memory leak, even if you fix the reversal generation as I've shown above. In your check_palindrome function, you never free the dynamic reversed copy (and in fact, you can't because you discard the original pointer referring to its head after the first traversal:
bool check_palindrome(node *head)
{
node *original = head;
node *reverse = returnReverseLinkedList(head); // only reference to reversed copy
while (original->next != NULL || reverse->next != NULL)
{
if (original->data != reverse->data)
return false; // completely leaked entire reversed copy
original = original->next;
reverse = reverse->next; // lost original list head
}
return true;
}
The most obvious method for combating that dreadful leak is to remember the original list and use a different pointer to iterate, and don't leave the function until the copy is freed.
bool check_palindrome(const node *head)
{
bool result = true;
node *reverse = returnReverseLinkedList(head);
for (node *p = reverse; p; p = p->next, head = head->next)
{
if (p->data != head->data)
{
result = false;
break;
}
}
while (reverse)
{
node *tmp = reverse;
reverse = reverse->next;
delete tmp;
}
return result;
}
I'm learning C++, I try to implement simple singly linked list but the delete node part fails. I could not comprehend why this basic delete_node part is failing. It seems prev->set_next line in delete_node method does not working correctly. I tried to debug it too but failed to spot the error.
using namespace std; //ignore it for simplicity
class Node {
int data;
Node *next;
public:
Node() {}
void set_data(int a_data)
{
data = a_data;
}
void set_next(Node *a_next)
{
next = a_next;
}
int get_data()
{
return data;
}
Node* get_next()
{
return next;
}
};
class List {
Node *head;
public:
List()
{
head = NULL;
}
void print_list();
void append_node(int data);
void delete_node(int data);
};
void List::print_list()
{
Node *temp = head;
if(temp == NULL)
{
cout << "empty" << endl;
return;
}
if(temp->get_next() == NULL)
{
cout << temp->get_data() << "--->";
cout << "NULL" << endl;
}
else
{
do
{
cout << temp->get_data() << "+++>";
temp = temp->get_next();
} while(temp != NULL);
cout << "NULL" << endl;
}
}
void List::append_node(int data)
{
Node *new_node = new Node();
new_node->set_data(data);
new_node->set_next(NULL);
Node *temp = head;
if(temp != NULL)
{
while(temp->get_next()!=NULL)
{
temp = temp->get_next();
}
temp->set_next(new_node);
}
else
{
head = new_node;
}
}
void List::delete_node(int data)
{
Node *temp = head;
if(temp == NULL)
{
return;
}
else
{
Node *prev = NULL;
do
{
prev = temp;
if(temp->get_data() == data)
{
prev->set_next(temp->get_next());
delete temp;
break;
}
temp = temp->get_next();
} while(temp!=NULL);
}
}
int main()
{
List list;
list.append_node(10);
list.append_node(20);
list.append_node(30);
list.append_node(40);
list.append_node(50);
list.append_node(60);
list.delete_node(30); //
list.print_list();
return 0;
}
valgrind gives me following error.
==22232== Invalid read of size 8
==22232== at 0x400D38: Node::get_next() (20_1.cpp:25)
==22232== by 0x400A5E: List::print_list() (20_1.cpp:62)
==22232== by 0x400C6C: main (20_1.cpp:127)
==22232== Address 0x5abdd28 is 8 bytes inside a block of size 16 free'd
==22232== at 0x4C2F24B: operator delete(void*) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==22232== by 0x400BA8: List::delete_node(int) (20
Lets take a closer look at these lines from the List::delete_node function
prev = temp;
if(temp->get_data() == data)
{
prev->set_next(temp->get_next());
delete temp;
break;
}
The first one make prev point to the very same node that temp is pointing to. After this prev == temp is true.
So when you do
prev->set_next(temp->get_next());
it is the same as
temp->set_next(temp->get_next());
That is, you make temp->next point to temp->next which doesn't change it at all. You never unlink the node from the list, but you do delete it. That makes your printing of the list invalid, as you will dereference a deleted node.
As a simple solution, you could do something like this:
if (head->get_data() == data)
{
// Special case: Head node is the one we want to delete
Node* old_head = head;
// Make the head be the second node in the list, if any
head = head->get_next();
// Delete the old head
delete old_head;
}
else
{
// We know it's not the head node of the list, use the "next" to find it
for (Node* node = head; node->get_next() != 0; node = node->get_next())
{
if (node->get_next()->get_data() == data)
{
// It's the "next" node we want to remove
Node* old_next = node->get_next();
// Unlink the node
node->set_next(node->get_next()->get_next());
delete old_next;
break;
}
}
}
The problem is that at the beginning of your do / while loop pointers temp and prev point to the same Node. Hence, you re-point the node, and then delete it right away.
A better approach is to not use prev at all. Get next, see if its data matches the one being deleted. If it does, "bypass" and delete next. Otherwise, move on to the next node until you hit NULL:
void List::delete_node(int data) {
if(head == NULL) {
return;
}
if (head->get_data() == data) {
Node *toDelete = head;
head = head->get_next();
delete toDelete;
return;
}
Node *temp = head;
for ( ; ; ) {
Node *next = temp->get_next();
if (next == null) {
break;
}
if (next->get_data() == data) {
temp->set_next(next->get_next());
delete next;
break;
}
temp = temp->get_next();
}
}
The exact working solution is
void List::delete_node(int data)
{
Node *temp = head;
Node *prev = NULL;
//first check whether its a parent element or not
if(temp && temp->get_data() == data){
head = head->get_next();
delete temp;
}
else{
while (temp){
if (temp->get_data() == data){
if (prev)
prev->set_next(temp->get_next());
delete temp;
return;
}
prev = temp;
temp = temp->get_next();
}
}
}
This even works for deleting head node
I see a number of problems with your code.
Your Node constructors is not initializing any of the Node members.
Your List class is missing a destructor to free any allocated nodes.
Your print_list() and append_node() implementations are a little more verbose than they need to be.
But, most importantly, regarding your particular question, your list's delete_node() method is not managing its prev variable correctly. prev is always pointing at the current node that is being looked at, not at the previous node that was already looked at. So you are not actually updating your links correctly when removing a node. You are also not updating the list's head member if the node being removed is the head node.
Try something more like this instead:
class Node;
class List {
Node *head;
public:
List();
~List();
void print_list();
void append_node(int data);
void delete_node(int data);
};
class Node {
int data;
Node *next;
public:
Node(int a_data = 0, Node *a_next = NULL);
void set_data(int a_data);
void set_next(Node *a_next);
int get_data();
Node* get_next();
friend class List;
};
Node::Node(int a_data, Node *a_next)
: data(a_data), next(a_next)
{
}
void Node::set_data(int a_data)
{
data = a_data;
}
void Node::set_next(Node *a_next)
{
next = a_next;
}
int Node::get_data()
{
return data;
}
Node* Node::get_next()
{
return next;
}
List::List()
: head(NULL)
{
}
List::~List()
{
Node *temp = head;
while (temp)
{
Node *next = temp->get_next();
delete temp;
temp = next;
}
}
void List::print_list()
{
Node *temp = head;
if (!temp)
{
cout << "empty" << endl;
return;
}
do
{
cout << temp->get_data();
temp = temp->get_next();
if (!temp) break;
cout << "+++>";
}
while (true);
cout << "--->NULL" << endl;
}
void List::append_node(int data)
{
Node **temp = &head;
while (*temp) temp = &((*temp)->next);
*temp = new Node(data);
}
void List::delete_node(int data)
{
Node *temp = head;
Node *prev = NULL;
while (temp)
{
if (temp->get_data() == data)
{
if (prev)
prev->set_next(temp->get_next());
if (temp == head)
head = temp->get_next();
delete temp;
return;
}
prev = temp;
temp = temp->get_next();
}
}
int main()
{
List list;
list.append_node(10);
list.append_node(20);
list.append_node(30);
list.append_node(40);
list.append_node(50);
list.append_node(60);
list.delete_node(30); //
list.print_list();
return 0;
}