I'm trying to find a way to insert line breaks into certain places in a text area column in a NetSuite saved search. In some instances this "comments" value contains data separated by line breaks with each line started by a digit followed by a period. The issue is that when this data is presented to be included as part of the results, the line breaks are removed, causing everything to run together. For the most part, I've been able to at least find where I need to insert the line breaks with the following:
REGEXP_REPLACE({notes}, '\d{1,2}\.', '<br />', 3, 0, 'i')
The problem, though, is that replaces all of the numerical "bullet points" except for what may be at the very first (typically '1.'), which is not desirable. Is there a way to re-insert these line breaks and keep the numerical bullets?
You can re-use the matched text in the replacement pattern through backreferences:
REGEXP_REPLACE({notes}, '(\d{1,2}\.)', '<br />\1', 3, 0, NULL)
This will start searching for a match, case-sensitively (note I replaced 'i' with NULL since digits and a dot char are casefree chars), from the third position in the string, and will replace all matches (due to the 0 occurrence argument) with the same text as matched with <br /> prepended to it.
Related
I have this regex that's worked well so far that splits 'name=value' pairs separated by a given character.
(?s)([^\s=]+)=(.*?)(?=\s+[^\s=]+=|\Z)
I know the separator, but the problem is in the example below (tab separated):
usrName=Wilma sev=4 cat=Detection CommandLine="C:\powershell.exe" -Enc 0ATQBpAG0AAcABDAHIAZQBkAHMAIgA= IOCValue= ProcessEndTime=2023-01-18 15:51:05
https://regex101.com/r/1wgVxs/5
Some values can have no value in the case of 'IOCValue' which works as expected, however some values like the CommandLine are giving me up to -Enc as one match and the remainder to the next pair as another.
What I'm hoping to get out from the above is:
usrName=Wilma
sev=4
cat=Detection
CommandLine="C:\powershell.exe" -Enc 0ATQBpAG0AAcABDAHIAZQBkAHMAIgA=
IOCValue=
ProcessEndTime=2023-01-18 15:51:05
But I'm getting:
usrName=Wilma
sev=4
cat=Detection
CommandLine="C:\powershell.exe" -Enc
0ATQBpAG0AAcABDAHIAZQBkAHMAIgA=
IOCValue=
ProcessEndTime=2023-01-18 15:51:05
Given I know the separator is a tab I think what I need is to only look for name=value pairs when they are at the start of the line or proceeded by the separator (tab). Is this possible?
Note, I can expect a space separator too, but I have a less performant and messy non-regex version I can send these too, so presume tab.
You may use this simplified regex:
(?s)([^\s=]+)=(.*?)(?=\t|\Z)
Updated RegEx Demo
Here, lookahead (?=\t|\Z) will make sure that value part is followed by either a tab character or end position.
For an open source chat analyser in Google Sheets, I need to extract all numeric values after a substring (Example), then total them.
For example, if a cell contains Example1 another text 123 Example500 text, Example1 and Example500 should be extracted out, and their numeric values summed to 501.
This is complicated further by needing to obtain the total for a column of messages.
What I've tried already:
=REGEXEXTRACT(A1, "Example(\d+)"): This only extracts the first matching value, but works!
=SUM(SPLIT(A1, "Example")): This works for messages that only include my target string, but falls apart when other strings are included. The output could possibly be filtered to results that start with a number, but this is very messy and possibly a red herring.
CONCATENATEing all my cells together, then searching for numbers. This is error-prone due to additional numbers within messages.
Another idea is to substitute each Example(\d+) to $1 the captured digit and space |. or replace anything else with empty string (regex101 demo). Knowing that $1 is unset on the right side of the alternation. Then split on space and sum up digits (any other occurring digits have been removed). If Example is a placeholder, replace with e.g. [[:alpha:]]+ for one or more alphabetic characters.
=IF(ISTEXT(A1);SUM(SPLIT(REGEXREPLACE(A1;"Example(\d+)|.";"$1 ");" "));0)
I added IF(ISTEXT(A1);...) for only processing text in the source field (to avoid errors). Else if empty or no text it's set to 0. Just remove if the field always contains text and this is unneeded.
Edit from #TheMaster: As a array formula, we can use BYROW
=BYROW(A:A; LAMBDA(row; IF(ISTEXT(row); SUM(SPLIT(
REGEXREPLACE(row;"Example(\d+)|.";"$1 ");" "));)))
try:
=LAMBDA(x, REGEXEXTRACT(A1, "(\w+)\d+")&
SUMPRODUCT(IF(IFERROR(REGEXMATCH(x, "\w+\d+")),
REGEXEXTRACT(x, "\w+(\d+)"), )))(SPLIT(A1, " "))
update 1:
=LAMBDA(x, REGEXEXTRACT(A1, "(\D+)\d+")&
SUMPRODUCT(IF(IFERROR(REGEXMATCH(x, "\D+\d+")),
REGEXEXTRACT(x, "\D+(\d+)"), )))(SPLIT(A1, " "))
update 2:
=INDEX(LAMBDA(xx, REGEXEXTRACT(xx, "(\D+)\d+")&
BYROW(LAMBDA(x, IF(IFERROR(REGEXMATCH(x, "\D+\d+")),
REGEXEXTRACT(x, "\D+(\d+)"), ))(SPLIT(xx, " ")), LAMBDA(x, SUMPRODUCT(x))))
(A1:INDEX(A:A, MAX((A:A<>"")*ROW(A:A)))))
if you start from A2 just change A1: to A2:
I have a large pipe-delimited text file that should have one 3-column record per line. Many of the records are split up by line breaks within a column.
I need to do a find/replace to get three, and only three, pipes per line/record.
Here's an example (I added the line breaks (\r\n) to demonstrate where they are and what needs to be replaced):
12-1234|The quick brown fox jumped over the lazy dog.|Every line should look similar to this one|\r\n
56-7890A|This record is split\r\n
\r\n
on to multiple lines|More text|\r\n
09-1234AS|\r\n
||\r\n
\r\n
56-1234|Some text|Some more text\r\n
|\r\n
76-5432ABC|A record will always start with two digits, a dash and four digits|There may or may not be up to three letters after the four digits|\r\n
The caveat is that I need to retain those mid-record line breaks for the target system. They need to be replaced with \.br\. So the final result of the above should look like this:
12-1234|The quick brown fox jumped over the lazy dog.|Every line should look similar to this one|\r\n
56-7890A|This record is split\.br\\.br\on multiple lines|More text|\r\n
09-1234AS|\.br\||\.br\\r\n
56-1234|Some text|Some more text\.br\|\r\n
76-5432ABC|A record will always start with two digits, a dash and four digits|There may or may not be up to three letters after the four digits|\r\n
As you can see the mid-record line breaks have all been replaced with \.br\ and the end-of-line line breaks have been retained to keep each three-column/pipe record on its own line. Note the last record's text, explaining how each line/record begins. I included that in case that would help in building a regex to properly identify the beginning of a record.
I'm not sure if this can be done in one find/replace step or if it needs to be (or just should be) split up into a couple of steps.
I had the thought to first search for |\r\n, since all records end with a pipe and a CRLF, and replace those with dummy text !##$. Then search for the remaining line breaks with \r\n, which will be mid-column line breaks and replace those with \.br\, then replace the dummy text with the original line breaks that I want to keep |\r\n.
That worked for all but records that looked like the third record in the first example, which has several line breaks after a pipe within the record. In such a large file as I am working with it wasn't until much later that I found that the above process I was using didn't properly catch those instances.
You can use
(?:\G(?!^(?<!.))|^\d{2}-\d+[A-Z]*\|[^|]*?(?:\|[^|]*?)?)\K\R+
Replace with \\.br\\. See the regex demo. Details:
(?:\G(?!^(?<!.))|^\d{2}-\d+[A-Z]*\|[^|]*?(?:\|[^|]*?)?) - either the end of the previous match (\G(?!^(?<!.))) or (|) start of a line, two digits, 0, one or more digits, zero or more letters, a |, then any zero or more chars other than |, as few as possible, and then an optional sequence of | and any zero or more chars other than |, as few as possible (see ^\d{2}-\d+[A-Z]*\|[^|]*?(?:\|[^|]*?)?)
\K - omit the text matched
\R+ - one or more line breaks.
See the Notepad++ demo:
If you need to remove empty lines after this, use Edit > Line Operations > Remove Empty Lines.
I use linux and I'm trying to use sed for this. I download a CSV from an institutional site providing some data to be analyzed. There are several thousand lines per CSV, and many columns per row (I haven't counted them, but I think the number is useless). The fields are separated by semicolons and quoted, so the format per line is:
"Field 1";"Field 2";"Field 3"; .... ;"Field X";
Each correct line ends with semicolon and '\n'. The problem is that, from time to time, there's some field that incorrectly has a newline, and the solution is to delete the newline character, so the two lines go back to be together into only one. Example of an incorrect line:
"Field 1";"Field 2";"Fi
eld 3";"Field X";
I've found that there can be a \n right after the opening quote or somewhere in the between the quotes.
I've found a way to manage this last case, where the newline is right after the quote:
sed ':a;N;$!ba;s/";"\n/";"/g' file.csv
but not for "any number of alphabet characters after the quote not ending in semicolon". I have a pattern file (to be used with -f) with these lines:
:a;N;$!ba;s/";"\n/";"/g
:a;N;$!ba;s/\([A-z]\)\n/\1/g
:a;N;$!ba;s/\([:alpha:]\)\n/\1/g
The first line of the pattern file works, but I've tried combinations of the second and third and I always get an empty file.
If current line doesn't end with a semicolon, read and append next line to pattern space and remove line break.
sed '/[^;]$/{N;s/\n//}' file
I have a data one on each line in a file as below
BMT.PQ
DMZ.IV
VLD.Q
WPS.T
I am looking for a regex to split out into two categories of output
One where starting letter of the data is between A to M
and other
where starting letter of the data is from N to Z
I tried this
[A-M].* for getting first half of data with first beginning letter from A to M
and i was expecting a result/regex text match of
only :
BMT.PQ
DMZ.PQ
but it also gave a match for
LD.Q which was incorrect for me.
I even unsuccessfully tried [(A-M)(A-M)(A-M)].*
Basically i want to split based on starting letter in the data. One half for data beginning with letters from A to M and second half for data beginning with letter N to Z.
You are close, all you need is to add the ^ for start of string and $ for end of string.
^[A-M].*$
and
^[N-Z].*$
Make sure you enable multiline mode. Multiline mode (usually the m flag) allows ^ and $ to detect start of line and end of line respectively.
The carat symbol represents the start of the string being searched/matched. The two regexs that you probably need are:
^[A-M]
^[N-Z]