Matching SAS character variables to a list - sas

Question

So I have a vector of search terms, and my main data set. My goal is to create an indicator for each observation in my main data set where variable1 includes at least one of the search terms. Both the search terms and variable1 are character variables.
Currently, I am trying to use a macro to iterate through the search terms, and for each search term, indicate if it is in the variable1. I do not care which search term triggered the match, I just care that there was a match (hence I only need 1 indicator variable at the end).
I am a novice when it comes to using SAS macros and loops, but have tried searching and piecing together code from some online sites, unfortunately, when I run it, it does nothing, not even give me an error.
I have put the code I am trying to run below.
*for example, I am just testing on one of the SASHELP data sets;
*I take the first five team names to create a search list;
data terms; set sashelp.baseball (obs=5);
search_term = substr(team,1,3);
keep search_term;;
run;
*I will be searching through the baseball data set;
data test; set sashelp.baseball;
run;
%macro search;
%local i name_list next_name;
proc SQL;
select distinct search_term into : name_list separated by ' ' from work.terms;
quit;
%let i=1;
%do %while (%scan(&name_list, &i) ne );
%let next_name = %scan(&name_list, &i);
*I think one of my issues is here. I try to loop through the list, and use the find command to find the next_name and if it is in the variable, then I should get a non-zero value returned;
data test; set test;
indicator = index(team,&next_name);
run;
%let i = %eval(&i + 1);
%end;
%mend;
Thanks

Answer 1

Here's the temporary array solution which is fully data driven.
Store the number of terms in a macro variable to assign the length of arrays
Load terms to search into a temporary array
Loop through for each word and search the terms
Exit loop if you find the term to help speed up the process
/*1*/
proc sql noprint;
select count(*) into :num_search_terms from terms;
quit;
%put &num_search_terms.;
data flagged;
*declare array;
array _search(&num_search_terms.) $ _temporary_;
/*2*/
*load array into memory;
if _n_ = 1 then do j=1 to &num_search_terms.;
set terms;
_search(j) = search_term;
end;
set test;
*set flag to 0 for initial start;
flag = 0;
/*3*/
*loop through and craete flag;
do i=1 to &num_search_terms. while(flag=0); /*4*/
if find(team, _search(i), 'it')>0 then flag=1;
end;
drop i j search_term ;
run;

Answer 2

Not sure I totally understand what you are trying to do but if you want to add a new binary variable that indicates if any of the substrings are found just use code like:
data want;
set have;
indicator = index(term,'string1') or index(term,'string2')
... or index(term,'string27') ;
run;
Not sure what a "vector" would be but if you had the list of terms in a dataset you could easily generate that code from the data. And then use %include to add it to your program.
filename code temp;
data _null_;
set term_list end=eof;
file code ;
if _n_ =1 then put 'indicator=' # ;
else put ' or ' #;
put 'index(term,' string :$quote. ')' #;
if eof then put ';' ;
run;
data want;
set have;
%include code / source2;
run;
If you did want to think about creating a macro to generate code like that then the parameters to the macro might be the two input dataset names, the two input variable names and the output variable name.