Lets consider simple test case with some test data in Spock
def "numbers to the power of two"(int a, int b, int c) {
expect:
Math.pow(a, b) == c
where:
a | b | c
1 | 2 | 1
2 | 2 | 4
3 | 2 | 9
}
Is it possible with vanilla Intellij or with some plugin to run just single test data entry? For example just 1 | 2 | 1 without needing to comment out all others?
Is it possible with vanilla Intellij or with some plugin to run just single test data entry?
No
Related
I have a string variable and some of the responses have an extra character at the beginning. The character in question is a constant character in all cases. The variable is ICD-code. For example, instead of G23 I have DG23.
Is there a way in Stata to remove the excess D character?
My data looks like this
ID
diag
1
DZ456
2
DG32
3
DY258
4
DD35
5
DS321
6
DD21
7
DA123
For basic information in this territory, consult help string functions.
* Example generated by -dataex-. To install: ssc install dataex
clear
input byte d str5 diag
1 "DZ456"
2 "DG32"
3 "DY258"
4 "DD35"
5 "DS321"
6 "DD21"
7 "DA123"
end
replace diag = substr(diag, 2, .) if substr(diag, 1, 1) == "D"
list
+----------+
| d diag |
|----------|
1. | 1 Z456 |
2. | 2 G32 |
3. | 3 Y258 |
4. | 4 D35 |
5. | 5 S321 |
|----------|
6. | 6 D21 |
7. | 7 A123 |
+----------+
An alternative to string functions is to use regular expressions, see help regex.
replace diag = regexs(1) if regexm(diag, "^D(.*)")
My dataset contains multiple variables called avar_1 to bvar_10 referring to the history of an individual. For some reasons, the history is not always complete and there are some "gaps" (e.g. avar_1 and avar_4 are non-missing, but avar_2 and avar_3 are missing). For each individual, I want to store the first non-missing value in a new variable called var1 the second non-missing in var2 etc, so that I have a history without missing values.
I've tried the following code
local x=1
foreach wave in a b {
forval i=1/10 {
capture drop var`x'
generate var`x'=.
capture replace var`x'=`wave'var`i' if !mi(`wave'`var'`i')
if (!mi(var`x')) {
local x=1+`x'
}
}
}
var1 is generated properly but var2 only contains missings and following variables are not generated. However, I set trace on and saw that the var2 is actually replaced for all variables from avar_1 to bvar_10.
My guess is that the local x is not correctly updated as its value change for the whole dataset but should be different for each observation.
Is that the problem and if so, how can I avoid it?
A concise concrete data example is worth more than a long explanation. Your description seems consistent with an example like this:
* Example generated by -dataex-. To install: ssc install dataex
clear
input str1 id float(avar_1 avar_2 avar_3 bvar_1 bvar_2)
"A" 1 . 6 8 10
"B" 2 4 . 9 .
"C" 3 5 7 . 11
end
* 4 is specific to this example.
rename (bvar_*) (avar_#), renumber(4)
reshape long avar_, i(id) j(which)
(note: j = 1 2 3 4 5)
Data wide -> long
-----------------------------------------------------------------------------
Number of obs. 3 -> 15
Number of variables 6 -> 3
j variable (5 values) -> which
xij variables:
avar_1 avar_2 ... avar_5 -> avar_
-----------------------------------------------------------------------------
drop if missing(avar_)
bysort id (which) : replace which = _n
list, sepby(id)
+--------------------+
| id which avar_ |
|--------------------|
1. | A 1 1 |
2. | A 2 6 |
3. | A 3 8 |
4. | A 4 10 |
|--------------------|
5. | B 1 2 |
6. | B 2 4 |
7. | B 3 9 |
|--------------------|
8. | C 1 3 |
9. | C 2 5 |
10. | C 3 7 |
11. | C 4 11 |
+--------------------+
Positive points:
Your data layout cries out for some structure given by a rename and especially by a reshape long. I don't give here code for a reshape wide as for the great majority of Stata purposes, you'd be better off with this layout.
Negative points:
!mi(var`x')
returns whether the first value of a variable is not missing. If foo were a variable in the dataset, !mi(foo) is evaluated as !mi(foo[1]). That is not what you want here. See https://www.stata.com/support/faqs/programming/if-command-versus-if-qualifier/ for the full story.
I'd recommend more evocative variable names.
I have a numeric variable with values similar to the following system
1
2
12
21
2
I would like to split the values which have length > 1 and put the second half of the value
in another variable.
So the second variable would have the values:
.
.
2
1
.
Theoretically I would just use a simple replace statement, but I am looking for a code/loop, which would
recognize the double digit values and split them automatically and save them in the second variable. Because with time, there will be more observations added and I cannot do this task manually for >10k cases.
Here's one approach:
clear
input foo
1
2
12
21
2
end
generate foo1 = floor(foo/10)
generate foo2 = mod(foo, 10)
list
+-------------------+
| foo foo1 foo2 |
|-------------------|
1. | 1 0 1 |
2. | 2 0 2 |
3. | 12 1 2 |
4. | 21 2 1 |
5. | 2 0 2 |
+-------------------+
More on these functions here, here and here.
If zeros for the first part should be missing, then
replace foo1 = . if foo1 == 0
or (to do it in one)
generate foo1 = floor(foo/10) if foo >= 10
The code is also good for any arguments with three digits or more.
I have a Transactions table with the following structure:
ID | Product | OrderCode | Value
1 | 8 | ABC | 100
2 | 5 | ABC | 150
3 | 4 | ABC | 80
4 | 5 | XPT | 100
5 | 6 | XPT | 100
6 | 8 | XPT | 100
7 | 5 | XYZ | 100
8 | 8 | UYI | 90
How do I create a table (or list) with the order codes of orders with both products 5 and 8?
In the example above it should be the orders ABC and XPT.
There are probably many ways to do this, but here's a fairly general solution what I came up with:
FilteredList =
VAR ProductList = {5, 8}
VAR SummaryTable = SUMMARIZE(Transactions,
Transactions[OrderCode],
"Test",
COUNTROWS(INTERSECT(ProductList, VALUES(Transactions[Product])))
= COUNTROWS(ProductList))
RETURN SELECTCOLUMNS(FILTER(SummaryTable, [Test]), "OrderCode", Transactions[OrderCode])
The key here is if the set of products for a particular order code contains both 5 and 8, then the intersection of VALUES(Transations[Product]) with the set {5,8} is exactly that set and has a count of 2. If it doesn't have both, the count will be 1 or 0 and the test fails.
Please elaborate more on your question, From your above post I understood is you want to filter the list, For that, you can use below code
List<Transactions> listTransactions = listTransactions.FindAll(x=>x.Product == 5 || x.Product == 8)
So I have what I think is a pretty simple problem in open office calc I want fixed, but I can't find the answer anywhere.
If this is my table:
A | B | C
5 | 2 | ?
3 | 1 | ?
I want C to get the value of the B next to it and get the value of A{that number}.
So it should look like this:
A | B | C
5 | 2 | 3
3 | 1 | 5
EDIT:
I'll try to explain better. So what I want cell C1 to do is to get the value of B1. Then, it takes that value, call it X, and gets the value of the cell AX. Where A is the column. So in this case, C1 gets the value of A2 and C2 gets the value of A1.
So this is the answer:
the formula should be =INDIRECT("A"&B1) in the cell C1 and then copied to the C column