I am capturing the session id from the string. I want to add word(prefix) before the extracted session id.
Sample input: key=this is sample input; MySessionId=hhjsfd436763jhjhfdjs87787.hghht77f54; key7=jhu8787; type=raw; oldkey=jkjf8787;
I have formed the below regex to capture the MySessionId.
MySessionId=([^.]*)
I want to add a word before the extracted string like below.
Expected output:
ABCD-1234-hhjsfd436763jhjhfdjs87787
Any way to achieve this through Regular expression?
It really depends what language you're using, you'll need to find a function that replaces text in a string (usually it's called replace). It looks like you're dealing with cookies so I'll show you an example in javascript:
//$1 refers to the first group captured by the regex
//i think other languages use $1 too but you should probably check
string = string.replace(/MySessionId([^.]*)/, "ABCD-1234-$1")
Related
I have a string in this shape
State#Received#ID#e23d8926-1327-4fde-9ea7-d364af3325e0
I want to extract the State value via RegEx. So in this above example I only want to extract Received
I have tried the following ([^State#])([A-Za-z]) which matches Received but I am stuck at excluding the rest of the string #ID#e23d8926-1327-4fde-9ea7-d364af3325e0
You should not use a parenthesis for the group you don't want to capture. My solution is that:
State#(?'state'[^#]+)#
Sample: https://regex101.com/r/vAr65j/1
I'm trying to create a custom filter in Google Analytic to remove the query parts of the url which I don't want to see. The url has the following structure
[domain]/?p=899:2000:15018702722302::NO:::
I would like to create a regex which skips the first 12 characters (that is until:/?p=899:2000), and what ever is going to be after that replace it with nothing.
So I made this one: https://regex101.com/r/Xgbfqz/1 (which could be simplified to .{0,12}) , but I actually would like to skip those and only let the regex match whatever is going to be after that, so that I'll be able to tell in Google Analytics to replace it with "".
The part in the url that is always the same is
?p=[3numbers]:[0-4numbers]
Thank you
Your regular expression:
\/\?p=\d{3}\:\d{0,4}(.*)
Tested in Golang RegEx 2 and RegEx101
It search for /p=###:[optional:####] and capture the rest of the right side string.
(extra) JavaScript:
paragraf='[domain]/?p=899:2000:15018702722302::NO:::'
var regex= /\/\?p=\d{3}\:\d{0,4}(.*)/;
var match = regex.exec(paragraf);
alert('The rest of the right side of the string: ' + match[1]);
Easily use "[domain]/?p=899:2000:15018702722302::NO:::".substr(12)
You can try this:
/\?p\=\d{3}:\d{0,4}
Which matches just this: ?p=[3numbers]:[0-4numbers]
Not sure about replacing though.
https://regex101.com/r/Xgbfqz/1
This is probably straightforward but I'm not even sure which phrase I should google to find the answer. Forgive my noobiness.
I've got strings (filenames) that look like this:
site12345678_date20160912_23001_to_23100_of_25871.txt
What this naming convention means is "Records 23001 through 23100 out of 25871 for site 12345678 for September 12th 2016 (20160912)"
What I want to do is extract the date part (those digits between _date and the following _)
The Regex: .*(_date[0-9]{8}).* will return the string _date20160912. But what I'm actually looking for is just 20160912. Obviously, [0-8]{8} doesn't give me what I want in this case because that could be confused with the site, or potentially record counts
How can I responsibly accomplish this sort of 'substringing' with a single regular expression?
You just need to shift you parentheses so as to change the capture group from including '_date' in it. Then you would want to look for your capture group #1:
If done in python, for example, it would look something like:
import re
regex = '.*_date([0-9]{8}).*'
str = 'site12345678_date20160912_23001_to_23100_of_25871.txt'
m = re.match(regex, str)
print m.group(0) # the whole string
print m.group(1) # the string you are looking for '20160912'
See it in action here: https://eval.in/641446
The Regex: .*(_date[0-9]{8}).* will return the string _date20160912.
That means you are using the regex in a method that requires a full string match, and you can access Group 1 value. The only thing you need to change in the regex is the capturing group placement:
.*_date([0-9]{8}).*
^^^^^^^^^^
See the regex demo.
I want to make a regex so I can do a "Search/Replace"
over a json file with many object.
Every object has a key named "resource"
containing a URL.
Take a look at these examples:
"resource":"http://www.img/qwer/123/image.jpg"
"resource":"io.nl.info/221/elephant.gif"
"resource":"simgur.com/icon.png"
I want to make a regex to replace the whole url with
a string like this: img/filename.format.
This way, the result would be:
"resource":"img/image.jpg"
"resource":"img/elephant.gif"
"resource":"img/icon.png"
I'm just starting with regular expressions and I'm
completely lost. I was thinking that one valid idea would
be to write something starting with this pattern "resource":"
and ending with the last five characters. But I don't even know how to try
that.
How could I write the regular expression?
Thanks in advance!
Try this:
Find: "resource":\s*"[^"]+?([^\/"]+)"
Replace: "resource":"img/\1
Using [^"]+? ensures the match won't roll off the end of the current entry and gobble up too much input, and it's reluctant (with the added ?) so it gets the whole image file name (instead ofwhat the last character).
Edit:
I added optional whitespace after the key, which your pastebin has.
See a live demo of this regex with your pastebin.
Regex
.*\/
Debuggex Demo
This will find the text you want to replace. Replace it with img/ if you want to find the whole text you'll need to look for the following Regex:
("resource":").*\/
Debuggex Demo
Then replace with $1img/ this should give you group 1 and the img part.
Let me know if there are any questions
Note: I personally would just use objects since you have the JSON and parse it to a object then iterate over the objects and change each resource on each object independently rather than looking for a magic bullet
If your JSON is an array of objects containing resource field I would do it in 3 steps: convert to object, find resources and replace them, convert back to string (optional)
var tmp = JSON.parse('<your json>');
for (i = 0; i < tmp.length; ++i) {
for (e in tmp[i])
if (e == 'resource')
tmp[i][e] = tmp[i][e].replace(/.*(?=img\/.*\..*)/,'')
}
tmp = JSON.stringify(tmp);
Can someone assist in creating a Regex for the following situation:
I have about 2000 records for which I need to do a search/repleace where I need to make a replacement for a known item in each record that looks like this:
<li>View Product Information</li>
The FILEPATH and FILE are variable, but the surrounding HTML is always the same. Can someone assist with what kind of Regex I would substitute for the "FILEPATH/FILE" part of the search?
you may match the constant part and use grouping to put it back
(<li>View Product Information</li>)
then you should replace the string with $1your_replacement$2, where $1 is the first matching group and $2 the second (if using python for instance you should call Match.group(1) and Match.group(2))
You would have to escape \ chars if you're using Java instead.