Can someone assist in creating a Regex for the following situation:
I have about 2000 records for which I need to do a search/repleace where I need to make a replacement for a known item in each record that looks like this:
<li>View Product Information</li>
The FILEPATH and FILE are variable, but the surrounding HTML is always the same. Can someone assist with what kind of Regex I would substitute for the "FILEPATH/FILE" part of the search?
you may match the constant part and use grouping to put it back
(<li>View Product Information</li>)
then you should replace the string with $1your_replacement$2, where $1 is the first matching group and $2 the second (if using python for instance you should call Match.group(1) and Match.group(2))
You would have to escape \ chars if you're using Java instead.
Related
I have a csv in following format.
id,mobile
1,02146477474
2,08585377474
3,07646474637
4,02158789566
5,04578599525
I want to add a new column and add just leading 3 numbers to that column (for specific cases and all the others NOT_VALID string). So result should be:
id,number,provider
1,02146477474,021
2,08585377474,085
3,07646474637,NOT_VALID
4,02158789566,021
5,04578599525,NOT_VALID
I can use following regex for replacing that. But I would like to use all possible conversations in one step. Using UpdateRecord processor.
${field.value:replaceFirst('085[0-9]+','085')}
When I use something like this:
${field.value:replaceFirst('085[0-9]+','085'):or(${field.value:replaceFirst('086[0-9]+','086')}`)}
This replaces all with false.
Nifi uses Java regex
As soon, as you are using record processing, this should work for you:
${field.value:replaceFirst('^(021|085)?.*','$1')}
The group () optionally ? catches 021 or 085 at the beginning of string ^
The replacement - $1 - is the first group
PS: The sites like https://regex101.com/ helps to understand regex
I have file names in a URL and want to strip out the preceding URL and filepath as well as the version that appears after the ?
Sample URL
Trying to use RegEx to pull, CaptialForecasting_Datasheet.pdf
The REGEXP_EXTRACT in Google Data Studio seems unique. Tried the suggestion but kept getting "could not parse" error. I was able to strip out the first part of the url with the following. Event Label is where I store URL of downloaded PDF.
The URL:
https://www.dudesolutions.com/Portals/0/Documents/HC_Brochure_Digital.pdf?ver=2018-03-18-110927-033
REGEXP_EXTRACT( Event Label , 'Documents/([^&]+)' )
The result:
HC_Brochure_Digital.pdf?ver=2018-03-18-110927-033
Now trying to determine how do I pull out everything after the? where the version data is, so as to extract just the Filename.pdf.
You could try:
[^\/]+(?=\?[^\/]*$)
This will match CaptialForecasting_Datasheet.pdf even if there is a question mark in the path. For example, the regex will succeed in both of these cases:
https://www.dudesolutions.com/somepath/CaptialForecasting_Datasheet.pdf?ver
https://www.dudesolutions.com/somepath?/CaptialForecasting_Datasheet.pdf?ver
Assuming that the name appears right after the last / and ends with the ?, the regular expression below will leave the name in group 1 where you can get it with \1 or whatever the tool that you are using supports.
.*\/(.*)\?
It basically says: get everything in between the last / and the first ? after, and put it in group 1.
Another regular expression that only matches the file name that you want but is more complex is:
(?<=\/)[^\/]*(?=\?)
It matches all non-/ characters, [^\/], immediately preceded by /, (?<=\/) and immediately followed by ?, (?=\?). The first parentheses is a positive lookbehind, and the second expression in parentheses is a positive lookahead.
This REGEXP_EXTRACT formula captures the characters a-zA-Z0-9_. between / and ?
REGEXP_EXTRACT(Event Label, "/([\\w\\.]+)\\?")
Google Data Studio Report to demonstrate.
Please try the following regex
[A-Za-z\_]*.pdf
I have tried it online at https://regexr.com/. Attaching the screenshot for reference
Please note that this only works for .pdf files
Following regex will extract file name with .pdf extension
(?:[^\/][\d\w\.]+)(?<=(?:.pdf))
You can add more extensions like this,
(?:[^\/][\d\w\.]+)(?<=(?:.pdf)|(?:.jpg))
Demo
I'm trying to create a custom filter in Google Analytic to remove the query parts of the url which I don't want to see. The url has the following structure
[domain]/?p=899:2000:15018702722302::NO:::
I would like to create a regex which skips the first 12 characters (that is until:/?p=899:2000), and what ever is going to be after that replace it with nothing.
So I made this one: https://regex101.com/r/Xgbfqz/1 (which could be simplified to .{0,12}) , but I actually would like to skip those and only let the regex match whatever is going to be after that, so that I'll be able to tell in Google Analytics to replace it with "".
The part in the url that is always the same is
?p=[3numbers]:[0-4numbers]
Thank you
Your regular expression:
\/\?p=\d{3}\:\d{0,4}(.*)
Tested in Golang RegEx 2 and RegEx101
It search for /p=###:[optional:####] and capture the rest of the right side string.
(extra) JavaScript:
paragraf='[domain]/?p=899:2000:15018702722302::NO:::'
var regex= /\/\?p=\d{3}\:\d{0,4}(.*)/;
var match = regex.exec(paragraf);
alert('The rest of the right side of the string: ' + match[1]);
Easily use "[domain]/?p=899:2000:15018702722302::NO:::".substr(12)
You can try this:
/\?p\=\d{3}:\d{0,4}
Which matches just this: ?p=[3numbers]:[0-4numbers]
Not sure about replacing though.
https://regex101.com/r/Xgbfqz/1
I'm currently building a simple search page in Node JS Express and Oracle.
I'd like to show the user a snippet of the matching text (first instance would do) to add a bit context of what the SQL found.
Example:
Search term: 'fish'
Results: Henry really likes going fishing, and once he caug ...
I'm not sure the best way to approach this - I could retrieve the whole block of text and do it in Node JS, but I don't really like the idea of dragging the whole text across to the app, just to get a snippet.
I've been thinking that REGEXP_SUBSTR could be way to do it... But I'm not sure whether I could use a regular expression to retrieve x amount of characters before and after the matching word.
Have I got the right idea or am I going about it in the wrong way?
Thanks
SELECT text
, REGEXP_SUBSTR(LOWER(text), LOWER('fish')) AS potential_snippet
FROM table
WHERE LOWER(text) LIKE LOWER('%fish%');
Try this:
select text
, SUBSTR( TEXT, INSTR(LOWER(TEXT),'fish', 1)-50,100 )
FROM test
WHERE INSTR(LOWER(text),'fish', 1)<>0;
Play with the position and length numbers(50 and 100 in my example) to limit the length of the string.
If you need to extract some context with the help of JavaScript, you can use limiting quantifiers in a regex:
/\b.{0,15}fish.{0,15}\b/i
See demo
Here,
\b - matches at the word boundary (so that the context contains only whole words)
.{0,15} - any characters other than a newline (replace with [\s\S] or [^] if you need to include newlines)
fish - the keyword
The /i modifier enables case-insensitive search.
If you need a dynamic regex creation, use a constructor notation:
RegExp("\\b.{0,15}" + keyword + ".{0,15}\\b", "i");
Also, if you need to find multiple matches, use g modifier alongside the i.
I made an article spinner that used regex to find words in this syntax:
{word1|word2}
And then split them up at the "|", but I need a way to make it support tier 2 brackets, such as:
{{word1|word2}|{word3|word4}}
What my code does when presented with such a line, is take "{{word1|word2}" and "{word3|word4}", and this is not as intended.
What I want is when presented with such a line, my code breaks it up as "{word1|word2}|{word3|word4}", so that I can use this with the original function and break it into the actual words.
I am using c#.
Here is the pseudo code of how it might look like:
Check string for regex match to "{{word1|word2}|{word3|word4}}" pattern
If found, store each one as "{word1|word2}|{word3|word4}" in MatchCollection (mc1)
Split the word at the "|" but not the one inside the brackets, and select a random one (aka, "{word1|word2}" or "{word3|word4}")
Store the new results aka "{word1|word2}" and "{word3|word4}" in a new MatchCollection (mc2)
Now search the string again, this time looking for "{word1|word2}" only and ignore the double "{{" "}}"
Store these in mc2.
I can not split these up normally
Here is the regex I use to search for "{word1|word2}":
Regex regexObj = new Regex(#"\{.*?\}", RegexOptions.Singleline);
MatchCollection m = regexObj.Matches(originalText); //How I store them
Hopefully someone can help, thanks!
Edit: I solved this using a recursive method. I was building an article spinner btw.
That is not parsable using a regular expression, instead you have to use a recursive descent parser. Map it to JSON by replacing:
{ with [
| with ,
wordX with "wordX" (regex \w+)
Then your input
{{word1|word2}|{word3|word4}}
becomes valid JSON
[["word1","word2"],["word3","word4"]]
and will map directly to PHP arrays when you call json_decode.
In C#, the same should be possible with JavaScriptSerializer.
I'm really not completely sure WHAT you're asking for, but I'll give it a go:
If you want to get {word1|word2}|{word3|word4} out of any occurrence of {{word1|word2}|{word3|word4}} but not {word1|word2} or {word3|word4}, then use this:
#"\{(\{[^}]*\}\|\{[^}]*\})\}"
...which will match {{word1|word2}|{word3|word4}}, but with {word1|word2}|{word3|word4} in the first matching group.
I'm not sure if this will be helpful or even if it's along the right track, but I'll try to check back every once in a while for more questions or clarifications.
s = "{Spinning|Re-writing|Rotating|Content spinning|Rewriting|SEO Content Machine} is {fun|enjoyable|entertaining|exciting|enjoyment}! try it {for yourself|on your own|yourself|by yourself|for you} and {see how|observe how|observe} it {works|functions|operates|performs|is effective}."
print spin(s)
If you want to use the [square|brackets|syntax] use this line in the process function:
'/[(((?>[^[]]+)|(?R))*)]/x',