How to convert char to integer from .txt file in C++ - c++

Question

I have a .txt file that contains:
XXXX:YYYY:ABCCCCE.
I need to write a function that reads this section of the .txt file ABCCCCE and finds the sum of the values of those characters.
Assume:
A = 1, B = 2, C = 3, D = 4, E = 5
Here is what I have so far to distinguish the values of each character:
int getComplexity(char theCode)
{
int complexity;
if(theCode == 'A')
{
complexity = 1;
} else if(theCode == 'B')
{
complexity = 2;
} else if(theCode == 'C')
{
complexity = 3;
} else if(theCode == 'D')
{
complexity = 4;
} else if(theCode == 'E')
{
complexity = 5;
}
return complexity;
}
I'm just not sure how I would read from the .txt file and convert the values. I am new to c++ so any help would be greatly appreciated!

Answer 1

I don't know if this is what your after but:
#include <fstream>
#include <numeric>
#include <vector>
using namespace std;
int Return_Complexity(char character)
{
switch (character)
{
case 'a':
return 1;
break;
case 'b':
return 2;
break;
case 'c':
return 3;
break;
case 'd':
return 4;
break;
case 'e':
return 5;
break;
default:
return 0; //Zero indicates that we didn't find what we're looking for
}
}
int main()
{
ifstream file{ "some-file.txt" };
vector<int> values;
char character;
while (file >> character)
{
int result = Return_Complexity(tolower(character));
if (result > 0) //if its a-e
values.push_back(result);
}
int Result = accumulate(values.begin(), values.end(), 1); //add them together
cout << Result;
}
this pushes back all characters found and then sums them up.
If this is not what your after, i will fix this.