Parse number until comma - c++

Question

I have a format where, in a string, 88 is to be parsed as the number 88 while 8,8 is to be parsed as two 8s. I need to go through the string, and for every ., push a 0 to a vector, and otherwise push the number(s) at the current position to the vector according to the above rule. Zeros will never appear in the input string. I don't want to use yacc or another BNF parser generator; it would be overkill for my situation. What's the easiest way to do this? Here's what I've go so far; it's only partial and doesn't even compile:
for(int i=0; i<line.length(); i++){
if (line[i] == '.')
puzzle.push_back(0);
else
//do weird comma stuff
//push stuff
}
Example:
line = ".1.1,1.11"
puzzle = {0,1,0,1,1,0,11}

Answer 1

Here's a sketch what it looks like you're asking for (not compiled, not tested):
int value;
bool in_number = false;
while (cin.getline(line)) {
for (int i = 0; i < line.length(); ++i)
switch(line[i]) {
case '.':
if (in_number) {
puzzle.push_back(value);
in_number = false;
}
puzzle.push_back(0);
break;
case ',':
if (in_number) {
puzzle.push_back(value);
in_number = false;
}
break;
case '0': case '1': case '2': case '3': case '4':
case '5': case '6': case '7': case '8': case '9':
if (in_number) {
value *= 10;
value += line[i] - '0';
} else {
in_number = true;
value = line[i] - '0';
}
break;
}
}

Answer 2

For such tasks common solution is to use regexp:
#include <algorithm>
#include <iostream>
#include <iterator>
#include <regex>
#include <vector>
int main(int argc, char* argv[])
{
std::string s(".1.1,1.11");
std::smatch m;
std::regex e("([0-9]+|\\.)[,]?");
std::vector<int> v;
while (std::regex_search(s, m, e)) {
const std::string& d = m[1];
v.push_back(strtol(d.c_str(), 0, 10));
s = m.suffix().str();
}
std::copy(v.begin(), v.end(), std::ostream_iterator<int>(std::cout, " "));
}

Answer 3

AntolyS's answer is probably cleanest, but I went with a modified version of Pete Becker's answer because I'm a noob and there were to many weird things going on with Antoly's:
int value; bool in_number = false;
for(int i=0; i<line.length(); i++){
if (line[i] == '.'){
if (in_number){
puzzle.push_back(value);
in_number = false;
}
puzzle.push_back(0);
}
else if (line[i] == ','){
if (in_number) {
puzzle.push_back(value);
in_number = false;
}
}
else if (line[i] > '0' && line[i] <= '9'){
if (in_number) {
value *= 10;
value += line[i] - '0';
} else {
in_number = true;
value = line[i] - '0';
}
}
}