Does pandas have a built-in string matching function for exact matches and not regex? The code below for tropical_two has a slightly higher count. Documentation tells me it does a regex search.
tropical = reviews['description'].map(lambda x: "tropical" in x).sum()
print(tropical)
tropical_two = reviews['description'].str.count("tropical").sum()
print(tropical_two)
The first way is the answer key from Kaggle but something about it seems less readable and intuitive to me compared to a .str function because when I run this it returns True instead of 2 so I am a little confused about if the answer key method is actually counting all occurrences of "tropical" and not just the first.
def in_str(text):
return "tropical" in text
in_str("tropical is tropical")
First 2 lines of dataframe:
0 Italy Aromas include tropical fruit, broom, brimston... Vulkà Bianco 87 NaN Sicily & Sardinia Etna NaN Kerin O’Keefe #kerinokeefe Nicosia 2013 Vulkà Bianco (Etna) White Blend Nicosia
1 Portugal This is ripe and fruity, a wine that is smooth... Avidagos 87 15.0 Douro NaN NaN Roger Voss #vossroger Quinta dos Avidagos 2011 Avidagos Red (Douro) Portuguese Red Quinta dos Avidagos
Notebook here, tropical code in cell #2
https://www.kaggle.com/mikexie0/exercise-summary-functions-and-maps
You may use str.count with word boundary markers to match the exact search term:
tropical_two = reviews['description'].str.count(r'\btropical\b').sum()
print(tropical_two)
There may not be the need for a separate exact API, as str.count can be used for exact matches as well.
Related
Im trying to get the number between '-' and '-' in google sheets but after trying many things I still havent been able to find the solution.
Data record 1
England Premier League
West Ham vs Crystal Palace
2.090 - 3.47 - 3.770
Expected value = 3.47
Data record 2
England League Two
Carlisle vs Scunthorpe
2.830 - 3.15 - 2.820
Expected value = 3.15
Hopefully someone can help me out
Try either of the following
option 1.
=INDEX(IFERROR(REGEXEXTRACT(AE1:AE4," \d+\.\d+ ")*1))
option 2.
=INDEX(IFERROR(REGEXEXTRACT(AE1:AE4,".* - (\d+\.\d+) ")))
(Do adjust the formula according to your ranges and locale)
use:
=INDEX(IFNA(REGEXEXTRACT(A1:A, "- (\d+(?:.\d+)?) -")*1))
I have a database with string column product_name which has data like:
Vans Classic Slip-On Black & White Checkerboard/ White - veľkosť (US) : 6 (EUR: 38)
Vans Old Skool - čierna - veľkosť (US) : 9.5 (EUR: 42.5)
I am trying to extract the US size...
SELECT REGEXP_SUBSTR("product_name", ...) AS "size"
...with desired output like this.
size
6
9.5
I have tried this, but to no avail
SELECT REGEXP_SUBSTR("product_name", '(US)(\d+)') AS "size"
I need to agree with B001, this might not be the best way of saving your information. However, if you are sure your strings are going to have this format, you could use this regex
\(US\) ?: ?(\d+\.?\d*) \(EUR: ?(\d+\.?\d*)\)
This will match the US shoe size first and then the EUR one.
Here is a visual explaination of the regex
Please note that this regex will match BOTH sizes, I'm not sure which one you prefer
You can test more cases in this regex101
When working in the web UI I had to double slash my slashes. Thus the following worked as you want.
select REGEXP_SUBSTR(str, '\\(US\\)\\s\\:\\s(\\d+\\.?\\d*)',1,1,'i',1)
from values ('Vans Classic Slip-On Black & White Checkerboard/ White - veľkosť (US) : 6 (EUR: 38)'),
('Vans Old Skool - čierna - veľkosť (US) : 9.5 (EUR: 42.5)') v(str);
gives:
REGEXP_SUBSTR(STR, '\\(US\\)\\S\\:\\S(\\D+\\.?\\D*)',1,1,'I',1)
6
9.5
I have a list like so
x=['hello#thepowerhouse.group', 'ThePowerHouse\xa0 is a part of the House of ElektroCouture', 'Our Studio is located at Bikini Berlin Terrace Level, 2nd floor Budapester Str. 46 10787 Berlin', '\xa0', 'Office:\xa0+49 30 20837551', '\xa0', '\xa0']
I want to extract the this element Our Studio is located at Bikini Berlin Terrace Level, 2nd floor Budapester Str. 46 10787 Berlin'
Since I am doing this for several sites I want to extra the element with regular expressions so it can work with others. I thought that I could grab the element by saying if the element has lower case and upper case letters, numbers , commas , and sometimes a period. This is what I attempted but it didn't work.
import re
for element in x:
if re.findall("([A-Za-z0-9,])",element)==True:
print("match")
You can split up your rule into several simple regexes and test them in sequence instead of making some monster-expression.
import re
def is_location(text):
"""Returns True if text contains digits, uppercase and lowercase characters."""
patterns = r'[0-9]', r'[a-z]', r'[A-Z]'
return all(re.search(pattern, text) for pattern in patterns)
x = [
'hello#thepowerhouse.group',
'ThePowerHouse\xa0 is a part of the House of ElektroCouture',
'Our Studio is located at Bikini Berlin Terrace Level, 2nd floor Budapester Str. 46 10787 Berlin',
'\xa0', 'Office:\xa0+49 30 20837551', '\xa0', '\xa0'
]
print(next(filter(is_location, x)))
Looking for help on building a regex that captures a 1-line string after a specific word.
The challenge I'm running into is that the program where I need to build this regex uses a single line format, in other words dot matches new line. So the formula I created isn't working. See more details below. Any advice or tips?
More specific regex task:
I'm trying to grab the line that comes after the word Details from entries like below. The goal is pull out 100% Silk, or 100% Velvet. This is the material of the product that always comes after Details.
Raw data:
<p>Loose fitted blouse green/yellow lily print.
V-neck opening with a closure string.
Small tie string on left side of top.</p>
<h3>Details</h3> <p>100% Silk.</p>
<p>Made in Portugal.</p> <h3>Fit</h3>
<p>Model is 5‰Ûª10,‰Û size 2 wearing size 34.</p> <p>Size 34 measurements</p>
OR
<p>The velvet version of this dress. High waist fit with hook and zipper closure.
Seams run along edges of pants to create a box-like.</p>
<h3>Details</h3> <p>100% Velvet.</p>
<p>Made in the United States.</p>
<h3>Fit</h3> <p>Model is 5‰Ûª10‰Û, size 2 and wearing size M pants.</p> <p>Size M measurements Length: 37.5"åÊ</p>
<p>These pants run small. We recommend sizing up.</p>
Here is the current formula I created that's not working:
Replace (.)(\bDetails\s+(.)) with $3
The output gives the below:
<p>100% Silk.</p>
<p>Made in Portugal.</p>
<h3>Fit</h3>
<p>Model is 5‰Ûª10,‰Û size 2 wearing size 34.</p>
<p>Size 34 measurements</p>
OR
<p>100% Velvet.</p>
<p>Made in the United States.</p>
<h3>Fit</h3> <p>Model is 5‰Ûª10‰Û, size 2 and wearing size M pants.</p> <p>Size M measurements Length: 37.5"åÊ</p>
<p>These pants run small. We recommend sizing up.</p>
`
How do I capture just the desired string? Let me know if you have any tips! Thank you!
Difficult to provide a working solution in your situation as you mention your program has "limited regex features" but don't explain what limitations.
Here is a Regex you can try to work with to capture the target string
^(?:<h3>Details<\/h3>)(.*)$
I would personally use BeautifulSoup for something like this, but here are two solutions you could use:
Match the line after "Details", then pull out the data.
matches = re.findall('(?<=Details<).*$', text)
matches = [i.strip('<>') for i in matches]
matches = [i.split('<')[0] for i in [j.split('>')[-1] for j in matches]]
Replace "Details<...>data" with "Detailsdata", then find the data.
text = re.sub('Details<.*?<.*>', '', text)
matches = re.findall('(?<=Details).*?(?=<)', text)
I've got a regex that is responsible for matching the pattern A:B in lines where you might have multiple matches (i.e. "A:B A: B A : B A:B", etc.) The problem lies in the complexity of what A represents.
I'm using the regex:
\b[\w|\(|\)+]+\s*:(?:(?![\w+]+\s*:).)*
to match items in:
Data_1: Tutor Elementary: 10 a F Test: 7.87 sips
Turning 1 Data (A Run), Data: 0.0 10.0 10.0 17.3 0.0
Turning 2 Data (A Run), Data2: 0.0 6.8 0.0 6.8 6.8
Data_1: Tutor Pool: Data2: A B C
Turning 2 (A Run), ABSOLUTE: 368 337 428 0 2 147
Data_4 : 4AZE Localization : 33.14 lat -86 long
Time: 0.75 Data Scenario: 3121.2
The question is this, if you examine this setup (I use https://regex101.com/), lines 2,3,5 don't return exactly what I'm looking for. Where the match is the first in the line, I want it to grab everything from the beginning of the line to the first ':'. Is this type of conditional regex possible? I've tried every possible way I could imagine, but I haven't been successful yet.
Thanks in advance!
A little complex, but try this here
^(.*?:.*?)(\b\w+\b\s*:.*?)\b\w+\b:.*$|^(.*?:.*?)\b\w+\b\s*:(.*?)$|^(.*)$