extracting a location from a list with regex - regex

Question

I have a list like so
x=['hello#thepowerhouse.group', 'ThePowerHouse\xa0 is a part of the House of ElektroCouture', 'Our Studio is located at Bikini Berlin Terrace Level, 2nd floor Budapester Str. 46 10787 Berlin', '\xa0', 'Office:\xa0+49 30 20837551', '\xa0', '\xa0']
I want to extract the this element Our Studio is located at Bikini Berlin Terrace Level, 2nd floor Budapester Str. 46 10787 Berlin'
Since I am doing this for several sites I want to extra the element with regular expressions so it can work with others. I thought that I could grab the element by saying if the element has lower case and upper case letters, numbers , commas , and sometimes a period. This is what I attempted but it didn't work.
import re
for element in x:
if re.findall("([A-Za-z0-9,])",element)==True:
print("match")

Answer 1

You can split up your rule into several simple regexes and test them in sequence instead of making some monster-expression.
import re
def is_location(text):
"""Returns True if text contains digits, uppercase and lowercase characters."""
patterns = r'[0-9]', r'[a-z]', r'[A-Z]'
return all(re.search(pattern, text) for pattern in patterns)
x = [
'hello#thepowerhouse.group',
'ThePowerHouse\xa0 is a part of the House of ElektroCouture',
'Our Studio is located at Bikini Berlin Terrace Level, 2nd floor Budapester Str. 46 10787 Berlin',
'\xa0', 'Office:\xa0+49 30 20837551', '\xa0', '\xa0'
]
print(next(filter(is_location, x)))