Is there a way this can be done in list comprehension - python-2.7

Question

I am trying to do this using list comprehension. I am using a subset of python 2.7 that does not allow the use of the command any or all
string_list1 = ['James Dean', 'Mr. James Dean', 'Jon Sparrow', 'Timothy Hook', 'Captain Jon Sparrow']
string_list2 = []
# Get elements that are a substring of other elements
for str1 in string_list1:
for str2 in string_list1:
if str1 in str2 and str1 != str2:
string_list2.append(str1)
print('Substrings: ', string_list2)
# remove element if another element is within it
for str2 in string_list2:
for str1 in string_list1:
if str2 in str1 and str2 != str1:
string_list1.remove(str1)
print('Desired: ', string_list1) # all elements that are unique
The result should be ['James Dean', 'Jon Sparrow', 'Timothy Hook'] basically the substrings and non substring elements

Answer 1

You could apply the same algorithm with list comprehension like this:
lst = ['James Dean', 'Mr. James Dean', 'Jon Sparrow', 'Timothy Hook', 'Captain Jon Sparrow']
res = [primitive for primitive in lst
if primitive not in (superstr for superstr in lst
if [substr for substr in lst if substr in superstr and substr != superstr]
)
]
print(res)
But an interpreter will not see that the inner expression (superstr ...) has to be evaluated only once, not for every iteration of the outer loop. So I would prefer to do this in two steps:
lst = ['James Dean', 'Mr. James Dean', 'Jon Sparrow', 'Timothy Hook', 'Captain Jon Sparrow']
exclude = [superstr for superstr in lst
if [substr for substr in lst if substr in superstr and substr != superstr]
]
res = [primitive for primitive in lst if primitive not in exclude]
print(res)