How to print variables using FMZM high precision fortran - fortran

I would like to use FM package capabilities for the study of a problem in number theory.
I installed the package, compiled libraries, and ran the two test suites supplied, all without any problems.
I wrote test.f:
use fmzm
TYPE (IM), SAVE :: n
n = 0
WRITE(*,*) n
end
and compiled using
gfortran -c -O3 -Wall test.f
gfortran fmsave.o fm.o fmzm90.o test.o -o test
which returned no error or warning. But got disappointed by discovering the output:
./test
200000
The number 200000 appears to be a memory location for the variable n. I experimented a little, and if I change n to complex type (ZM) it outputs 200000, 199999. Similarly if I declare and initialize two variable instead of one.
If I change TYPE (IM), SAVE :: n to INTEGER n, and compile exactly as above, I get the expected 0 as output.
If I replace the code by
n = 0
do
n=n+1
if (n < 10) WRITE(*,*) n
end do
then the output 200000 repeats 9 times and then stops. So it is the WRITE function which only finds the location and not the value. PRINT does the same.

As Vladimir points out, unless you write out a value of a standard type, it seems you have to first convert to a string using a maneuver such as
str = im_format('i100', n)
str = adjustl(str)
str = trim(str)
print*, str
where the middle two lines can be left out.

Related

The sum function returns answers different from an explicit loop

I am converting f77 code to f90 code, and part of the code needs to sum over elements of a 3d matrix. In f77 this was accomplished by using 3 loops (over outer,middle,inner indices). I decided to use the f90 intrinsic sum (3 times) to accomplish this, and much to my surprise the answers differ. I am using the ifort compiler, have debugging, check-bounds, no optimization all turned on
Here is the f77-style code
r1 = 0.0
do k=1,nz
do j=1,ny
do i=1,nx
r1 = r1 + foo(i,j,k)
end do
end do
end do
and here is the f90 code
r = SUM(SUM(SUM(foo, DIM=3), DIM=2), DIM=1)
I have tried all sorts of variations, such as swapping the order of the loops for the f77 code, or creating temporary 2D matrices and 1D arrays to "reduce" the dimensions while using SUM, but the explicit f77 style loops always give different answers from the f90+ SUM function.
I'd appreciate any suggestions that help understand the discrepancy.
By the way this is using one serial processor.
Edited 12:13 pm to show complete example
! ifort -check bounds -extend-source 132 -g -traceback -debug inline-debug-info -mkl -o verify verify.f90
! ./verify
program verify
implicit none
integer :: nx,ny,nz
parameter(nx=131,ny=131,nz=131)
integer :: i,j,k
real :: foo(nx,ny,nz)
real :: r0,r1,r2
real :: s0,s1,s2
real :: r2Dfooxy(nx,ny),r1Dfoox(nx)
call random_seed
call random_number(foo)
r0 = 0.0
do k=1,nz
do j=1,ny
do i=1,nx
r0 = r0 + foo(i,j,k)
end do
end do
end do
r1 = 0.0
do i=1,nx
do j=1,ny
do k=1,nz
r1 = r1 + foo(i,j,k)
end do
end do
end do
r2 = 0.0
do j=1,ny
do i=1,nx
do k=1,nz
r2 = r2 + foo(i,j,k)
end do
end do
end do
!*************************
s0 = 0.0
s0 = SUM(SUM(SUM(foo, DIM=3), DIM=2), DIM=1)
s1 = 0.0
r2Dfooxy = SUM(foo, DIM = 3)
r1Dfoox = SUM(r2Dfooxy, DIM = 2)
s1 = SUM(r1Dfoox)
s2 = SUM(foo)
!*************************
print *,'nx,ny,nz = ',nx,ny,nz
print *,'size(foo) = ',size(foo)
write(*,'(A,4(ES15.8))') 'r0,r1,r2 = ',r0,r1,r2
write(*,'(A,3(ES15.8))') 'r0-r1,r0-r2,r1-r2 = ',r0-r1,r0-r2,r1-r2
write(*,'(A,4(ES15.8))') 's0,s1,s2 = ',s0,s1,s2
write(*,'(A,3(ES15.8))') 's0-s1,s0-s2,s1-s2 = ',s0-s1,s0-s2,s1-s2
write(*,'(A,3(ES15.8))') 'r0-s1,r1-s1,r2-s1 = ',r0-s1,r1-s1,r2-s1
stop
end
!**********************************************
sample output
nx,ny,nz = 131 131 131
size(foo) = 2248091
r0,r1,r2 = 1.12398225E+06 1.12399525E+06 1.12397238E+06
r0-r1,r0-r2,r1-r2 = -1.30000000E+01 9.87500000E+00 2.28750000E+01
s0,s1,s2 = 1.12397975E+06 1.12397975E+06 1.12398225E+06
s0-s1,s0-s2,s1-s2 = 0.00000000E+00-2.50000000E+00-2.50000000E+00
r0-s1,r1-s1,r2-s1 = 2.50000000E+00 1.55000000E+01-7.37500000E+00
First, welcome to StackOverflow. Please take the tour! There is a reason we expect a Minimal, Complete, and Verifiable example because we look at your code and can only guess at what might be the case and that is not too helpful for the community.
I hope the following suggestions helps you figure out what is going on.
Use the size() function and print what Fortran thinks are the sizes of the dimensions as well as printing nx, ny, and nz. As far as we know, the array is declared bigger than nx, ny, and nz and these variables are set according to the data set. Fortran does not necessarily initialize arrays to zero depending on whether it is a static or allocatable array.
You can also try specifying array extents in the sum function:
r = Sum(foo(1:nx,1:ny,1:nz))
If done like this, at least we know that the sum function is working on the exact same slice of foo that the loops loop over.
If this is the case, you will get the wrong answer even though there is nothing 'wrong' with the code. This is why it is particularly important to give that Minimal, Complete, and Verifiable example.
I can see the differences now. These are typical rounding errors from adding small numbers to a large sum. The processor is allowed to use any order of the summation it wants. There is no "right" order. You cannot really say that the original loops make the "correct" answer and the others do not.
What you can do is to use double precision. In extreme circumstances there are tricks like the Kahan summation but one rarely needs that.
Addition of a small number to a large sum is imprecise and especially so in single precision. You still have four significant digits in your result.
One typically does not use the DIM= argument, that is used in certain special circumstances.
If you want to sum all elements of foo, use just
s0 = SUM(foo)
That is enough.
What
s0 = SUM(SUM(SUM(foo, DIM=3), DIM=2), DIM=1)
does is that it will make a temporary 2D arrays with each element be the sum of the respective row in the z dimension, then a 1D array with each element the sum over the last dimension of the 2D array and then finally the sum of that 1D array. If it is done well, the final result will be the same, but it well eat a lot of CPU cycles.
The sum intrinsic function returns a processor-dependant approximation to the sum of the elements of the array argument. This is not the same thing as adding sequentially all elements.
It is simple to find an array x where
summation = x(1) + x(2) + x(3)
(performed strictly left to right) is not the best approximation for the sum treating the values as "mathematical reals" rather than floating point numbers.
As a concrete example to look at the nature of the approximation with ifort, we can look at the following program. We need to enable optimizations here to see effects; the importance of order of summation is apparent even with optimizations disabled (with -O0 or -debug).
implicit none
integer i
real x(50)
real total
x = [1.,(EPSILON(0.)/2, i=1, SIZE(x)-1)]
total = 0
do i=1, SIZE(x)
total = total+x(i)
print '(4F17.14)', total, SUM(x(:i)), SUM(DBLE(x(:i))), REAL(SUM(DBLE(x(:i))))
end do
end program
If adding up in strict order we get 1., seeing that anything smaller in magnitude than epsilon(0.) doesn't affect the sum.
You can experiment with the size of the array and order of its elements, the scaling of the small numbers and the ifort floating point compilation options (such as -fp-model strict, -mieee-fp, -pc32). You can also try to find an example like the above using double precision instead of default real.

gfortran and ifort gives different results

I am making a small code that will read numbers from 2.txt which is bunch of random real numbers, save it in a 2d array and pass it on the information to a subroutine. In the subroutine, I am assigning a particular dimension of this array to another matrix to save this for future calculation.
implicit none
double precision, allocatable :: x1(:,:)
integer :: nstep, nheatoms, k, i, j
open(unit=999,file="2.txt",status="old")
nstep = 5
nheatoms = 2
allocate(x1(3,nheatoms))
do k = 1, nstep
do i = 1, 3
do j = 1, nheatoms
read(999,*) x1(i,j)
end do
read(999,*)
end do
call diffusion(nstep,nheatoms,x1)
end do
stop
end
subroutine diffusion(nstep,nheatoms,qhecent)
implicit none
integer, intent (in) :: nheatoms, nstep
double precision :: qhecent(3,nheatoms)
integer :: j
double precision, allocatable :: qhestep(:,:)
integer :: nstepdiff, ncross
integer, save :: l = 0
double precision :: diff
l = l + 1
allocate(qhestep(nstep,nheatoms))
do j = 1, nheatoms
qhestep(l,j) = qhecent(3,j)
end do
if (l .gt. 1) then
do j = 1, nheatoms
write(*,*)qhestep(l,j), qhestep(l-1,j)
end do
end if
end subroutine
The 2.txt file is as follows:
1.0
2.1
3.2
-1.1
-2.2
-3.3
5.0
3.5
4.4
1.9
2.1
1.5
6.0
3.5
4.4
1.9
2.8
2.5
6.0
3.5
4.4
1.9
2.1
3.2
6.0
3.5
4.4
1.9
-4.3
7.9
Now if I compile with gfortran, most of the time I obtain the output as:
2.1000000000000001 -2.2000000000000002
1.5000000000000000 -3.2999999999999998
2.7999999999999998 2.1000000000000001
2.5000000000000000 1.5000000000000000
2.1000000000000001 2.7999999999999998
3.2000000000000002 2.5000000000000000
-4.2999999999999998 2.1000000000000001
7.9000000000000004 3.2000000000000002
which is expected. But if I run the code several times, an unknown number appear in the output, such as the example:
2.1000000000000001 -2.2000000000000002
1.5000000000000000 -3.2999999999999998
2.7999999999999998 1.2882297539194267E-231
2.5000000000000000 0.0000000000000000
2.1000000000000001 2.7999999999999998
3.2000000000000002 2.5000000000000000
-4.2999999999999998 2.1000000000000001
7.9000000000000004 3.2000000000000002
If I compile with ifort, then I obtain the output that have two zeros, which is wrong.
2.10000000000000 -2.20000000000000
1.50000000000000 -3.30000000000000
2.80000000000000 0.000000000000000E+000
2.50000000000000 0.000000000000000E+000
2.10000000000000 2.80000000000000
3.20000000000000 2.50000000000000
-4.30000000000000 2.10000000000000
7.90000000000000 3.20000000000000
I must stress that compiling on ifort most of the time gives correct results as in the case for gfortran. I am on a Mac OS High Sierra.
Thanks in advance.
Both compilers should give garbage results, as you are allocating qhestep in diffusion for each DO k loop. On exiting diffusion, qhestep is deallocated, so the accumulated information should be lost. That ifort returns the same heap address for qhestep on each call is misleading.
To overcome the problem, you should use allocate (qhestep(nstep,nheatoms)) before entering the DO k loop, then transfer the accumulation array in call diffusion.
That ifort gives your expected result is unfortunate, as it disguises a significant logic error. Each ALLOCATE basically provides a new memory location for the array.
You also provide no error tests when reading the file. I would recommend using iostat= for the reads and also report the data as it is read.
In summary, your approach gives the wrong result, which both compilers provide. The ifort results you provided are also wrong in some cases, but correct in others, which is misleading.

End of record error in file opening

I am currently writing a code to simulate particle collisions. I am trying to open as much files as there are particles (N) and then put the data for positions and velocities in each of these files for each step of the time integration (using Euler's method, but that is not relevant). For that, I tried using a do loop so it will open all the files I need - then I put all the data in them with a different do loop later - and then close them all.
I first tried just doing a do loop to open the files - but it gave errors of the type "file already open in another unit", so I did the following:
module parameters
implicit none
character :: posvel
integer :: i, j, N
real :: tmax
real, parameter :: tmin=0.0, pi=3.14159265, k=500.0*10E3, dt=10.0E-5, dx=10.0E-3, g=9.806, ro=1.5*10E3
real, dimension(:), allocatable :: xold, xnew, vold, vnew, m, F, r
end module parameters
PROGRAM Collision
use parameters
implicit none
write(*,*) 'Enter total number of particles (integer number):'
read(*,*) N
allocate(xold(N))
allocate(vold(N))
allocate(xnew(N))
allocate(vnew(N))
allocate(m(N))
allocate(F(N))
allocate(r(N))
xold(1) = 0.0
vold(1) = 0.0
m(1) = 6.283*10E-9
r(1) = 10E-4
xold(2) = 5.0
vold(2) = 0.0
m(2) = 6.283*10E-9
r(2) = 10E-4
write(*,*) 'Type total time elapsed for the simulation(real number):'
read(*,*) tmax
do i = 1, N
write(posvel,"(a,i3.3,a)") "posveldata",i,".txt"
open(unit=i,file=posvel, status="unknown")
end do
do i = 1, N
close(unit=i)
end do
END PROGRAM Collision
The last ten lines are the ones that regard to my problem.
That worked in codeblocks - it opened just the number of files I needed, but I'm actually using gfortran and it gives me and "end of record" error in the write statement.
How can I make it to execute properly and give me the N different files that I need?
P.S.: It is not a problem of compilation, but after I execute the program.
Your character string in the parameter module has only 1 character length, so it cannot contain the full file name. So please use a longer string, for example
character(100) :: posvel
Then you can open each file as
do i = 1, N
write(posvel,"(a,i0,a)") "posveldata",i,".txt"
open(unit=i,file=trim(posvel), status="unknown")
end do
Here, I have used the format i0 to automatically determine a proper width for integer, and trim() for removing unnecessary blanks in the file name (though they may not be necessary). The write statement can also be written more compactly as
write(posvel,"('posveldata',i0,'.txt')") i
by embedding character literals into the format specification.
The error message "End of record" comes from the above issue. This can be confirmed by the following code
character c
write(c,"(a)") "1"
print *, "c = ", c
write(c,"(a)") "23" !! line 8 in test.f90
print *, "c = ", c
for which gfortran gives
c = 1
At line 8 of file test.f90
Fortran runtime error: End of record
This means that while c is used as an internal file, this "file" does not have enough space to accommodate two characters (here "23"). For comparison, ifort14 gives
c = 1
forrtl: severe (66): output statement overflows record, unit -5, file Internal Formatted Write
while Oracle Fortran12 gives
c = 1
****** FORTRAN RUN-TIME SYSTEM ******
Error 1010: record too long
Location: the WRITE statement at line 8 of "test.f90"
Aborted
(It is interesting that Oracle Fortran reports the record to be "too long", which may refer to the input string.)

Segmentation fault - invalid memory reference

Hey I am trying to get my LAPACK libraries to work and I have searched and searched but I can't seem to figure out what I am doing wrong.
I try running my code, and I get the following error
Program received signal SIGSEGV: Segmentation fault - invalid memory reference.
Backtrace for this error:
#0 0x7FFB23D405F7
#1 0x7FFB23D40C3E
#2 0x7FFB23692EAF
#3 0x401ED1 in sgesv_
#4 0x401D0B in MAIN__ at CFDtest.f03:? Segmentation fault (core dumped)
I will paste my main code here, hopefully someone can help me with this problem.
****************************************************
PROGRAM CFD_TEST
USE MY_LIB
IMPLICIT DOUBLE PRECISION (A-H,O-Z)
DIMENSION ET(0:10), VN(0:10), WT(0:10)
DIMENSION SO(0:10), FU(0:10), DMA(0:10,0:10)
DIMENSION DMA2(0:10,0:10), QN(0:10), WKSPCE(0:10)
INTEGER*8 :: pivot(10), inf
INTEGER*8 :: N
EXTERNAL SGESV
!SET THE PARAMETERS
SIGMA1 = 0.D0
SIGMA2 = 0.D0
TAU = 1.D0
EF = 1.D0
EXP = 2.71828182845904509D0
COST = EXP/(1.D0+EXP*EXP)
DO 1 N=2, 10
!COMPUATION OF THE NODES, WEIGHTS AND DERIVATIVE MATRIX
CALL ZELEGL(N,ET,VN)
CALL WELEGL(N,ET,VN,WT)
CALL DMLEGL(N,10,ET,VN,DMA)
!CONSTRUCTION OF THE MATRIX CORRESPONDING TO THE
!DIFFERENTIAL OPERATOR
DO 2 I=0, N
DO 2 J=0, N
SUM = 0.D0
DO 3 K=0, N
SUM = SUM + DMA(I,K)*DMA(K,J)
3 CONTINUE
OPER = -SUM
IF(I .EQ. J) OPER = -SUM + TAU
DMA2(I,J) = OPER
2 CONTINUE
!CHANGE OF THE ENTRIES OF THE MATRIX ACCORDING TO THE
!BOUNDARY CONDITIONS
DO 4 J=0, N
DMA2(0,J) = 0.D0
DMA2(N,J) = 0.D0
4 CONTINUE
DMA2(0,0) = 1.D0
DMA2(N,N) = 1.D0
!CONSTRUCTION OF THE RIGHT-HAND SIDE VECTOR
DO 5 I=1, N-1
FU(I) = EF
5 CONTINUE
FU(0) = SIGMA1
FU(N) = SIGMA2
!SOLUTION OF THE LINEAR SYSTEM
N1 = N + 1
CALL SGESV(N,N,DMA2,pivot,FU,N,inf)
DO 6 I = 0, N
FU(I) = SO(I)
6 CONTINUE
PRINT *, pivot
1 CONTINUE
RETURN
END PROGRAM CFD_TEST
*****************************************************
The commands I run to compile are
gfortran -c MY_LIB.f03
gfortran -c CFDtest.f03
gfortran MY_LIB.o CFDtest.o -o CFDtest -L/usr/local/lib -llapack -lblas
I ran the command
-fbacktrace -g -Wall -Wextra CFDtest
CFDtest: In function _fini':
(.fini+0x0): multiple definition of_fini'
/usr/lib/gcc/x86_64-linux-gnu/4.9/../../../x86_64-linux-gnu/crti.o:/build/buildd/glibc-2.19/csu/../sysdeps/x86_64/crti.S:80: first defined here
CFDtest: In function data_start':
(.data+0x0): multiple definition ofdata_start'
/usr/lib/gcc/x86_64-linux-gnu/4.9/../../../x86_64-linux-gnu/crt1.o:(.data+0x0): first defined here
CFDtest: In function data_start':
(.data+0x8): multiple definition of__dso_handle'
/usr/lib/gcc/x86_64-linux-gnu/4.9/crtbegin.o:(.data+0x0): first defined here
CFDtest:(.rodata+0x0): multiple definition of _IO_stdin_used'
/usr/lib/gcc/x86_64-linux-gnu/4.9/../../../x86_64-linux-gnu/crt1.o:(.rodata.cst4+0x0): first defined here
CFDtest: In function_start':
(.text+0x0): multiple definition of _start'
/usr/lib/gcc/x86_64-linux-gnu/4.9/../../../x86_64-linux-gnu/crt1.o:(.text+0x0): first defined here
CFDtest: In function_init':
(.init+0x0): multiple definition of _init'
/usr/lib/gcc/x86_64-linux-gnu/4.9/../../../x86_64-linux-gnu/crti.o:/build/buildd/glibc-2.19/csu/../sysdeps/x86_64/crti.S:64: first defined here
/usr/lib/gcc/x86_64-linux-gnu/4.9/crtend.o:(.tm_clone_table+0x0): multiple definition of__TMC_END'
CFDtest:(.data+0x10): first defined here
/usr/bin/ld: error in CFDtest(.eh_frame); no .eh_frame_hdr table will be created.
collect2: error: ld returned 1 exit status
You haven't posted your code for MY_LIB.f03 so we cannot compile CFDtest.f03 exactly as you have supplied it.
(As an aside, the usual naming convention is that f90 in a .f90 file is not supposed to imply the language version being targeted. Rather, .f90 denotes free format while .f is used for fixed format. By extension, your .f03 files would be better (i.e., more portable if) named as .f90.)
I commented out the USE MY_LIB line and ran your code through nagfor -u -c cfd_test.f90. The output, broken down, is
Extension: cfd_test.f90, line 13: Byte count on numeric data type
detected at *#8
Extension: cfd_test.f90, line 15: Byte count on numeric data type
detected at *#8
Byte counts are not portable. The kind value for an 8-byte integer is selected_int_kind(18). (Similarly you might like to use a kind(0.0d0) kind value for your double precision data.)
Error: cfd_test.f90, line 48: Implicit type for I
detected at 2#I
Error: cfd_test.f90, line 50: Implicit type for J
detected at 2#J
Error: cfd_test.f90, line 54: Implicit type for K
detected at 3#K
Error: cfd_test.f90, line 100: Implicit type for N1
detected at N1#=
You have these implicitly typed, which implies they are 4-byte (default) integers. You should probably declare these explicitly as 8-byte integers (using the 8-byte integer kind value above) if that's what you intend.
Questionable: cfd_test.f90, line 116: Variable COST set but never referenced
Questionable: cfd_test.f90, line 116: Variable N1 set but never referenced
Warning: cfd_test.f90, line 116: Unused local variable QN
Warning: cfd_test.f90, line 116: Unused local variable WKSPCE
You need to decide what you intend to do with these, or whether they are just deletable cruft.
With the implicit integers declared explicitly, there is further output
Warning: cfd_test.f90, line 116: Variable SO referenced but never set
This looks bad.
Obsolescent: cfd_test.f90, line 66: 2 is a shared DO termination label
Your DO loops would probably be better using the modern END DO terminators (not shared!)
Error: cfd_test.f90, line 114: RETURN is only allowed in SUBROUTINEs and FUNCTIONs
This is obviously easy to fix.
For the LAPACK call, one source of explicit interfaces for these routines is the NAG Fortran Library (through the nag_library module). Since your real data is not single precision, you should be using dgesv instead of sgesv. Adding USE nag_library, ONLY: dgesv and switching to call dgesv instead of sgesv, then recompiling as above, reveals
Incorrect data type INTEGER(KIND=4) (expected INTEGER) for argument N (no. 1) of DGESV
so you should indeed be using default (4-byte integers) - at least for the LAPACK build on your system, which will almost certainly be using 4-byte integers. Thus you might want to forget all about kinding your integers and just use the default integer type for all. Correcting this gives
Array supplied for scalar argument LDA (no. 4) of DGESV
so you do need to add this argument. Maybe pass size(DMA2,1)?
With this argument added to the call the code compiles successfully, but without the definitions for your *LEGL functions I couldn't go through any run-time testing.
Here is my modified (and pretty-printed) version of your program
Program cfd_test
! Use my_lib
! Use nag_library, Only: dgesv
Implicit None
Integer, Parameter :: wp = kind(0.0D0)
Real (Kind=wp) :: ef, oper, sigma1, sigma2, tau
Integer :: i, inf, j, k, n, sum
Real (Kind=wp) :: dma(0:10, 0:10), dma2(0:10, 0:10), et(0:10), fu(0:10), &
so(0:10), vn(0:10), wt(0:10)
Integer :: pivot(10)
External :: dgesv, dmlegl, welegl, zelegl
Intrinsic :: kind, size
! SET THE PARAMETERS
sigma1 = 0._wp
sigma2 = 0._wp
tau = 1._wp
ef = 1._wp
Do n = 2, 10
! COMPUATION OF THE NODES, WEIGHTS AND DERIVATIVE MATRIX
Call zelegl(n, et, vn)
Call welegl(n, et, vn, wt)
Call dmlegl(n, 10, et, vn, dma)
! CONSTRUCTION OF THE MATRIX CORRESPONDING TO THE
! DIFFERENTIAL OPERATOR
Do i = 0, n
Do j = 0, n
sum = 0._wp
Do k = 0, n
sum = sum + dma(i, k)*dma(k, j)
End Do
oper = -sum
If (i==j) oper = -sum + tau
dma2(i, j) = oper
End Do
End Do
! CHANGE OF THE ENTRIES OF THE MATRIX ACCORDING TO THE
! BOUNDARY CONDITIONS
Do j = 0, n
dma2(0, j) = 0._wp
dma2(n, j) = 0._wp
End Do
dma2(0, 0) = 1._wp
dma2(n, n) = 1._wp
! CONSTRUCTION OF THE RIGHT-HAND SIDE VECTOR
Do i = 1, n - 1
fu(i) = ef
End Do
fu(0) = sigma1
fu(n) = sigma2
! SOLUTION OF THE LINEAR SYSTEM
Call dgesv(n, n, dma2, size(dma2,1), pivot, fu, n, inf)
Do i = 0, n
fu(i) = so(i)
End Do
Print *, pivot
End Do
End Program
In general your development experience will be the most pleasant if you use as good a checking compiler as you can get your hands on and if you make sure you ask it to diagnose as much as it can for you.
As far as I can tell, there could be a number of problems:
Your integers with INTEGER*8 might be too long, maybe INTEGER*4 or simply INTEGER would be better
You call SGESV on double arguments instead of DGESV
Your LDA argument is missing, so your code should perhaps look like CALL DGESV(N,N,DMA2,N,pivot,FU,N,inf) but you need to check whether this is what you want.

Trouble with EQUIVALENCE statements in Fortran 77 Code

I am working on getting a raytracing code working and I think I may have isolated the problem. I am new to working with Fortran 77, but would like to gain more experience using this language (even if it is dated). I have some EQUIVALENCE statements in one of the subroutines that may be used to pipe variables into the subroutine (this could be half the problem right here).
The subroutine:
c s/r qparxdp
SUBROUTINE QPARAB PARA001
implicit real*8 (a-h, o-z)
character*8 modx, id
C PLAIN PARABOLIC OR QUASI-PARABOLIC PROFILE PARA002
C W(104) = 0. FOR A PLAIN PARABOLIC PROFILE PARA003
C = 1. FOR A QUASI-PARABOLIC PROFILE PARA004
COMMON /XX/ MODX(2),X,PXPR,PXPTH,PXPPH,PXPT,HMAX PARA005
COMMON R(6) /WW/ ID(10),W0,W(400) PARA006
EQUIVALENCE (EARTHR,W(2)),(F,W(6)),(FC,W(101)),(HM,W(102)), PARA007
1 (YM,W(103)),(QUASI,W(104)),(PERT,W(150)) PARA008
data ipass / 0 /
ENTRY ELECTX PARA010
print*, W(2), W(6), W(101), W(102), W(103), W(104), W(150)
print*, ' Electx W(6), f ', F, EARTHR, FC, HM, YM, QUASI, PERT, ipass
ipass = ipass + 1
if(ipass.gt.10000) ipass = 2
if(ipass.eq.1) return
modx(1) = 'qparab'
HMAX=HM PARA011
x = 0.d0
pxpr = 0.d0
pxpth = 0.d0
pxpph = 0.d0
H=R(1)-EARTHR PARA013
if(f.le.0.d0) print*, ' YM', YM
FCF2=(FC/F)**2 PARA014
CONST=1.d0 PARA015
IF (QUASI.EQ.1.d0) CONST=(EARTHR+HM-YM)/R(1) PARA016
Z=(H-HM)/YM*CONST PARA017
X=dMAX1(0.d0,FCF2*(1.d0-Z*Z)) PARA018
print*, 'X in qparx', X, Z
IF (X.EQ.0.d0) GO TO 50 PARA019
IF (QUASI.EQ.1.d0) CONST=(EARTHR+HM)*(EARTHR+HM-YM)/R(1)**2 PARA020
PXPR=-2.d0*Z*FCF2/YM*CONST PARA021
50 IF (PERT.NE.0.d0) CALL ELECT1 PARA022
RETURN PARA023
END PARA024-
Immediately before the subroutine or entry ELECTX is called I placed some print statements in the RINDEX Subroutine/Entry.
I check a few of the inputs immediately before the call of RINDEX
ENTRY RINDEX
write(*,*), 'Starting Rindex in ahnwfnc', F
if(ray.eq.0.d0.and.ipass.eq.0) print*, ' no magnetic field'
ipass = 1
OM=PIT2*1.d6*F
C2=C*C
K2=KR*KR+KTH*KTH+KPH*KPH
OM2=OM*OM
VR =C/OM*KR
VTH=C/OM*KTH
VPH=C/OM*KPH
write(*,*), OM, C2, K2, OM2, VR, VTH, VPH, F
CALL ELECTX
What I get out of this little section of code is:
fstep,fbeg,fend 1. 7. 8.
fbeg,fstep,f 7. 1. 0.
f 7. 7.
f before Rindex 7.
Starting Rindex in ahnwfnc 7.
43982297.2 8.98755431E+10 1. 1.93444246E+15 0.00640514066 0.00231408417
0.000282636641 7.
0. 0. 0. 0. 0. 0. 0.
Electx W(6),f 0. 0. 0. 0. 0. 0. 0. 1
So this is a longwinded way of asking - what is going on? I expected the variables like f, for example, to be passed into the subroutine QPARAB, so when I print in the subroutine, I'd expect to see F = 7. I am probably fundamentally misunderstanding something simple. As I have mentioned, the fact that I can't seem to get variables like F into the subroutine QPARAB is actually a big issue because the following calculations come out to 0s or NaNs. I would expect it to have some value. So maybe the data isn't getting in somehow? Everything else (at this point) seems to be working, to some degree.
Where this code comes from:
And I am using a small shell script (this could be a total mess):
g77 -c -O3 raytr_dp.for readw_dp.for trace_dp.for reach_dp.for backup_d.for dummy.for \
polcar_d.for printr_d.for rkam_dp.for hamltn_d.for ahwfnc_d.for \
qparxdp.for dipoly_d.for spoints.for ggm_dp.for secnds.for
g77 -o main -O3 raytr_dp.o readw_dp.o trace_dp.o reach_dp.o backup_d.o dummy.o \
polcar_d.o printr_d.o rkam_dp.o hamltn_d.o ahwfnc_d.o \
qparxdp.o dipoly_d.o spoints.o ggm_dp.o secnds.o
The g77 routines I am using were downloaded at: http://hpc.sourceforge.net/ and finally I get the same error using gfortran,
Using built-in specs.
COLLECT_GCC=gfortran
COLLECT_LTO_WRAPPER=/usr/local/gfortran/libexec/gcc/x86_64-apple-darwin13/4.9.0/lto-wrapper
Target: x86_64-apple-darwin13
Thread model: posix
gcc version 4.9.0 (GCC)
Subroutine QPARAB takes no arguments, e.g. nothing is passed to it. It loads the following variables from common blocks (variables shared between scope) MODX, X, PXPR, PXPTH, PXPPH, PXPT, HMAX, ID, W0, and W. Additionally it declares local scope variables modx and id and then assigns implicit typing to all undeclared variables (which are local in scope).
Your variable of interest, F is equivalent to writing W(6). This says that implicit variable F (type real*8) must have the same memory location as W(6). F isn't passed into this subroutine, it is a name local to the subroutine that is really a specific array member of W. If you want to pass a value into the subroutine into F, you need to set the variable W(6) prior to calling the subroutine. Note that in order to do this you will need W in scope and thus you will need the /WW/ common block referenced in the subroutine you are calling from.