C++ template for Runnable function - c++

Question

I am writing a library for thread management using C++ for my app and as part of the same I am trying to write a template class that takes a FunctionPointer to be executed inside the run function. I am a Java developer and trying to visualize as follows:
class MyRunnable : public Runnable {
public:
MyRunnable(fp)
{
mFp = fp;
}
private:
FunctionPointer mFp;
// Will be called by the thread pool using a thread
void run()
{
mFp();
}
}
class ThreadManager {
public:
void execute(MyRunnable runnable) {
executeOnAThreadPool(runnable);
}
}
Since I am not fluent with C++ syntax, I am finding hard to get the constructor defined to take a FunctionPointer as argument with variable number of arguments for the FunctionPointer. Something like:
MyRunnable(Fp fp, Args... args)
Can someone please help me defining the constructor for MyRunnable class above.
Thanks.

Answer 1

Not sure... but seems to me that you're looking something as
class MyRunnable
{
private:
std::function<void()> mF;
public:
template <typename F, typename ... Args>
MyRunnable (F && f, Args && ... args)
: mF{ [&f, &args...](){ std::forward<F>(f)(std::forward<Args>(args)...); } }
{ }
void run ()
{ mF(); }
};
The following is a full compiling example
#include <iostream>
#include <functional>
class MyRunnable
{
private:
std::function<void()> mF;
public:
template <typename F, typename ... Args>
MyRunnable (F && f, Args && ... args)
: mF{ [&f, &args...](){ std::forward<F>(f)(std::forward<Args>(args)...); } }
{ }
void run ()
{ mF(); }
};
void foo (int a, long b, std::string const & c)
{ std::cout << "executing foo() with " << a << ", " << b << ", " << c << '\n'; }
int main ()
{
MyRunnable mr{foo, 1, 2l, "three"};
std::cout << "before run" << '\n';
mr.run();
}
that prints
before run
executing foo() with 1, 2, three