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I am currently updating a lot CF 11 code to CF 2018. One of the things I like is that semicolons are options most of the time. Having said that, I am stuggling with the thinking behind this:
Error
<cfscript>
rc = {}
param rc.data2 = ""
</cfscript>
You cannot use a variable reference with "." operators in this context
The CFML compiler was processing:
A script statement beginning with param on line 3, column 1. A
cfscript tag beginning on line 1, column 2.
Not an error
<cfscript>
rc = {}
param rc.data2 = "";
</cfscript>
I don't understand why.
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I'm trying to write a fortran code for 1 phase flow in porous media.
In discretized equations and other long line I have a below problem as you see in the picture.
After that highlighted phrase my code become like comment.
Can anyone help me?
According to this:
In its current state, the syntax highlighting for fixed-form Fortran in the extension only supports a line length of 72 characters. Anything after column 72 appears as comments (green) in the source code, which also affects the appearance of the following lines (when a closing parenthesis is in this green region for example)
You can change it on fortran_fixed-form.tmLanguage.json file or on the VS code settings.
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I am struggling through this date extraction. I have a date like this
("D("yyyy-mm-dd")).
I want to get this "yyyy-mm-dd" and I cannot strip ("D(") this also because I have this format in other places so I tried like this
first searching the string but I am not sure if I am on right track
eg. intabc = istrdate.SearchSubString("D(");
so please suggest how can I get this value.
Input is
"(D(YYYY-MM-DD))"
OUTPUT that I want
(YYYY-MM-DD)
What i have done(not correct way I think )
intabc = istrdate.SearchSubString("D(");
you can use substr() and string::erase() functions in c++98
string str = "\"D(\"yyyy-mm-dd\")";
string result = str.substr(3);
result.erase(result.end() - 1)
result.erase(result.end() - 1)
if you are using c++11 you can also use string::pop_back() method.
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I'm trying to remove all the non-alphabetic characters in a string in a VBScript that will run from the command line.
Here's what I have thus far:
Set wshShell = CreateObject("WScript.Shell")
Dim test
test = "Hello:, world!"
test = strClean(test)
WScript.Echo(test)
Function strClean(strVal)
Set objRegEx = CreateObject(“VBScript.RegExp”)
objRegEx.Global = True
objRegEx.Pattern = “[^A-Za-z\n\r]”
strSearchString = objRegEx.Replace(strVal, “”)
End Function
But I'm getting the following error:
my.vbs (8, 35) Microsoft VBScript compilation error: Invalid character
The quotes you're using are Unicode and are invalid.
You should replace them by ASCII ones.
This is a community answer from Slai's comment that doesn't want to write an answer.See this meta post for more info.
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I am designing a GUI in Matlab,
I have a folder called sth. It contains many files having same structure like,
filename_1_something.mat
filename_2_something.mat
In order to loop over filenames by selecting via index, I need to find a resulting string like this;
filename_%d_something.mat
So I don't need to read all the files in the dir. Two of the filenames are enough to compare strings and find the different char array item and change by %d.
Or anything different than this also appreciated.
using the regex provided by #rock321987 -
names = dir('*.mat');
num = length(names);
expression = '\w*_\d+_\w*\.mat';
for n = 1:num
str = names(n).name;
nameList{n} = regexp(str,expression,'match')
end
works on:
test_1_something.mat
test_10_something.mat
changing the regex to just \w*_\w*\.mat
works for
test_1.mat
1_test.mat
test_1_something.mat
test_10_something.mat
but also works for anything with an string joined by underscore .mat
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I need to extract information form a text using regex for statements like bellow
#1. 02/14/2013 05:21 pm - Safee Safeeul Bashir
- Status changed from New to In Progress
#2. 02/14/2013 10:43 pm - Safee Safeeul Bashir
- Status changed from In Progress to Resolved
- CL set to 1203474
#3. 08/16/2013 02:30 am - Mondal Amit Kumar
Task was automatically close beacuse last update was more than two months and the issue passed
From here I want to extract the date and time where the status is changed to resolve.
For example for this one the date with #2 **02/14/2013 10:43 pm**
How about this:
\d\d/\d\d/\d{4}\s\d\d:\d\d\s[ap]m(?=.*(\n?\r?).*Resolved)
See it on RegExr
The regex can be
\d{2}/\d{2}/\d{4}\s\d{2}:\d{2}\s[pa]m