Through openstack client command line tool to get the server list with the accurate ip address not the "--ip <ip-address-regex>", and I used the "--sort-column" and "--limit" optional arguments can't get my expectancy.
Such as the picture, I want to get the only list with the IP "10.17.192.14".
Related
I install OpenVPN from its original source on google cloud instance and installed correctly. it is working and connect from OpenVPN client and also change IP of PC but when I type example google.com no open
but when I type any IP address of any working server it shows and opens websites from IP but not domain.
As you are able to browse with IP but not with DNS name it seems like a DNS resolver issue. For this reason,I would start troubleshooting by checking the internal name resolver
cat /etc/resolv.conf
What we are looking in here is the information about the name server your are using.
At this point you might want to check "~/client-configs/base.conf" file as per the OpneVPN configuration documention:
Finally, add a few commented out lines. We want to include these with
every config, but should only enable them for Linux clients that ship
with a /etc/openvpn/update-resolv-conf file. This script uses the
resolvconf utility to update DNS information for Linux clients.
"~/client-configs/base.conf
"# script-security 2"
"# up /etc/openvpn/update-resolv-conf"
"# down /etc/openvpn/update-resolv-conf"
If your client is running Linux and has an
/etc/openvpn/update-resolv-conf file, you should uncomment these lines
from the generated OpenVPN client configuration file.
I would also check the OpenVPN "/etc/openvpn/server.conf" and make sure DNS configuration in plance. It would be also worthwhile to check network configuration specially IP forwading and make sure default route going out through intended interface
As per "How To Set Up an OpenVPN Server on Ubuntu 16.04" document the recommendation is:
Your public interface should follow the word "dev". For example, this
result shows the interface named wlp11s0, which is highlighted below:
default via x.x.x.x dev wlp11s0 proto static metric 600
I have a system with multiple NIC and so multiple ip addresses and I've to use an SDK whose initialization that needs my local address and the remote address.
I want to autoselect the local endpoint. At the moment I'm enumerating all local addresses (via GetAdaptersAddresses) checking for the best match ( to be correct I should use the subnet mask).
But given that this job is done by the routing table is there any Windows API that given a remote address gives me back the right local endpoint ?
is there any Windows API that given a remote address gives me back the right local endpoint ?
Have a look at GetBestInterface() and GetBestInterfaceEx().
Both functions return an index to an interface. You can then retrieve the interface's IP by enumerating network interfaces with GetIpAddrTable(), or enumerating network adapters with GetAdaptersInfo()/GetAdaptersAddresses(), until you find an entry with a matching interface index.
I am running this example http://kaaproject.github.io/kaa/docs/v0.10.0/Programming-guide/Your-first-Kaa-application/ .
But data is not storing on the server side.
What should I do now?
When I running db.logs_my_application_token.
find() from mongo console,
it is showing nothing.
Do I have to provide some IP or host in my code, I am using KAA SANDBOX from AWS.
Console Output of Raspberry Pi attachedenter image description here here...
Finally I am able to do that using ..
Perform these two steps may be this can solve your problem.
Just run this command on host machine
sudo /usr/lib/kaa-sandbox/bin/change_kaa_host.sh $new host name/ip$
Then change the IP address of using Admin UI, for that you need to
sign in using username : kaa and passwword : kaa123
then go to setting > general setting then change the IP address preceded by :8080, enter your machine's public IP address, that can be easily accessible from anywhere.
Tips :: if you are using AWS instance then use public IP address of your instance.
Further error persist then drop your previous instance and launch a new instance.
For more details go the official documentation page
Hope it will be helpful for you.
You do not need to provide IP address.
You should download the generated SDK file and compile it with the source code. and then run it.
Now that apple has changed their review environment to an IPv6 only network ive been running into troubles with my application while testing.
The application requires the user to input their server/systems IP address, port (4401) and credentials to gain access to the application. Following the guidelines provided by apple i set up a NAT64 environment to test my application's compatibility. Running iOS 9.3.2 on an iphone 5s.
My work environment has several internal networks. I connected my iMac to the internal server (10.10.50.XX) via Ethernet which also has an external IP which is what i provide to apple. The 50 network does not run behind a proxy, but there are some sites which get filtered, but can access by confirming. I then shared my Ethernet connection through WiFI.
I connected the device and had internet access with the same pages being filtered. The device gets assigned a local-link address of 169.254.XX.XX. From what ive read my device is connecting to the ipv6 only network correctly, as the iphone does not show the ipv6 address only local link.
If I am correctly connected to the shared IPv6 network, the problem I am having is connecting to my server on the 50 network from my application. The application fails when ever i try to connected to the 10.10.50.XX network or the external(understandable because my imac is on the 50 internal network) .
Testing the application using IPv4 with a wireless router that is connected to the 50 network runs perfectly.I think it is an issue with the local link address not being able to see the 50 network or something.
Heres some brief background info on how i connect to the server. The user inputs all the credentials and the IP address and port of the server they want to connect to. The application saves this as a text (utf-8) and uses boost shared_ptr to send it to the cpp connection class which validates the credentials and provides access to the user. This cpp connection class handles the connection, synchronization, logging, requests and response from the server.
Is it possible to somehow get access to the 50 network, using the NAT64 internet sharing option?
If you're passing an IP address straight down to your network lib, then no. When your device is on the IPv6-only side of the NAT64, the server's IPv4 address is useless.
You almost certainly need a DNS name for the server you're trying to reach. The NAT64 relies first on DNS64 to create IPv6 addresses for your application when the server is IPv4-only. These synthesised addresses contain the IPv4 address(es) for the server, giving the NAT64 the information it needs to translate from IPv6 to IPv4.
Updating this to add: as suggested by user102008 in the comment thread attached to this answer, you may also be able to pass the IPv4 string literal though getaddrinfo() (see code listing 10-1 on this page). When you're behind a NAT64, a synthesised IPv6 address should be among the results returned by that call. The NAT64 will translate from this address back to IPv4 to reach the host you specified. In this case, if the system knows the correct prefix to use for the NAT64, a hostname is not necessary.
We are developing a Server software on Linux using C/C++, this software will limit the download rate for those requests which are from the Internet, but for those from local machines (intranet) it won't set any limit.
The problem is how to judge an IP address is local or not, is it possible to do it through c/c++ by reading some network number settings (maybe from router?)?
UPDATE
When I say local ip, I mean it is from within the company. For example, suppose the company has three subnets (this company only has a DSL link to the internet), they are 10.123.1.xxx, 172.16.1.xxx and 192.168.1.xxx, then all ip addresses from these three subnets should be considered as local address.
The private address ranges are:
10.0.0.0 - 10.255.255.255 (10/8 prefix)
172.16.0.0 - 172.31.255.255 (172.16/12 prefix)
192.168.0.0 - 192.168.255.255 (192.168/16 prefix)
You might also want to filter out link-local addresses (169.254/16)
You could then parse the ip address in your code(to get the addresses you could use avahi or something similiar and save all the addresses to a file and then parse each address individually)and check it matches these addresses. If it does not then limit its connection
Edit
You could also look into using the getifaddrs function that will list local addresses
If you run a traceroute on the IP address of the machine requesting a connection, you should be able to see whether the route takes you through the "gateway outside the company" (typically your ISP). A simple example in my house would be the Time Warner gateway that my internal router connects to. If the route to the client does not go through the ISP (as you mentioned, you have a DSL link; so the IP address of the DSL endpoint should be known), then it's an internal request. This doesn't require you to know the full map of IP addresses inside the company - you can assume your routers have it figured out.
To get this information you can run a system command from inside your program and parse the response.
To start with, run it from the command line (with a known "internal" and "external" IP address), and look at the difference. If you need further help after that, please update your question with the information you gathered.