Probably simple but my head is fried right now with figures. I'm using COGNOS 11 and trying to make a data item display character length of '4' i.e 0014 rather than just 14. I can do this in the edit within the report properties but I'm trying to do a concatenate string and it keeps reverting to 14.
I've been trying CAST([Demand No], varchar(4)) as the expression definition (comes up as 'No error') but it still keeps dropping the leading 00 on the report.
My full concatenated string so far [Unit ID]||to_char(cast([Demand Date],date), 'ddmmyyyy')||cast([Demand No], varchar(4)). This produces XXXXXXDDMMYYYY0000 but only when the last four characters are 0000 but it looks like this XXXXXXDDMMYYYY00 if the leading 0's are dropped.
You could try lpad(cast([Demand No], varchar(4)),2,'0')
Not elegant, but this uses generic Cognos functions:
substring('0000', 1, 4 - char_length(cast([Demand No], varchar(4)))) || cast([Demand No], varchar(4))
Related
I have a series of values in Tableau that are long strings intermixed with letters and numbers. I am unable to control the data output, but would like to parse the names from these strings. They follow the following format:
Potato 1TByte 4.5 NFA
Board 256GByte 553 NCA
Launch 4 512GByte 4.5 NFA
Launch 4S 512GByte 4.5 NCA
From each of these, I am attempting to capture the following:
"Potato"
"Board"
"Launch 4"
"Launch 4S"
Each string follows the same format: the name, followed by size, followed by some extra information we don't really care about.
I've tried to put together some text parsing strings, but am coming up short, and am still trying to learn regular expressions.
The Tableau calculated field I was trying to work with was something like the following:
LEFT([String], FIND([String], "Byte") - 2)
The issue is that the text and numbers preceding Byte can be anywhere from 4 to 2 characters and I need a way to identify the length of that.
Any help would be greatly appreciated!
One option which uses a regex replacement:
REGEXP_REPLACE('Launch 4 512GByte 4.5 NFA', ' \d+[A-Z]Byte .*$', '')
This strips off everything from the Byte term to the right, leaving us with only the product name.
You could try the following - this seems to work - Screenshot of Tableau output. Find below the formulas for the various derived columns you see in the screenshot (Your source column is called [Name])
Step1 = LEFT([Name],FIND([Name],"Byte")-1)
Step2 = LEN([Step1])-LEN(REPLACE([Step1]," ",""))
Step3 = FINDNTH([Step1]," ",[Step2])
Step4 = LEFT([Step1],[Step3]-1)
And of course you can nest all these in a single calculated field - kept them as separate columns for easier understanding
Can someone please tell me what I am doing wrong in this formula?
=ARRAYFORMULA(REGEXEXTRACT((A2:A&"")+(B2:B&"")+(C2:C&"")), "02(\d{14})37")
I'm trying to extract a 14 digit number that sits between 02 and 37 that may be in columnA, columnB or columnC.
I've tried this also, with the expected result showing on the first row only:
=ARRAYFORMULA(REGEXEXTRACT(textjoin(" ",true,A2:C),"02(\d{6,14})37"))
I'm really confuzzled.
it needs to be like this:
=ARRAYFORMULA(IFERROR(IFERROR(IFERROR(IFERROR(
REGEXEXTRACT(A2:A&"", "02(\d{14})37"),
REGEXEXTRACT(B2:B&"", "02(\d{14})37")),
REGEXEXTRACT(C2:C&"", "02(\d{14})37")))))
I am using the below date/time format in gSheets:
01 Apr at 11:00
I wonder whether it is possible to use Data Validation (or any other function) to report error (add the small red triangle to the corner of the cell) when the format differs in any way.
Possible values in the given format:
01 -> any number between 01-31 (but not "1", there must be the leading zero)
space
Apr -> 3 letters for month (Jan, Feb, Mar... Dec)
space
at
space
11 -> hours in 24h format (00, 01...23)
:
00 -> minutes (00, 01,...59)
Is there any way to validate that the cell contains "text/data" exactly in the above mentioned format?
The right way to do this is using Regular Expression and "regexmatch()" function in Google Sheets. For the given example, I made the below regular expression:
[0-3][0-9] (Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) at [0-2][0-9]\:[0-5][0-9]
Process:
Select range of cells to be validated
Go to Data > Data Validation
Under Criteria select "Own pattern is" (not sure the exact translation used in EN)
Paste: =regexmatch(to_text(K4); "[0-3][0-9] (Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) at [0-2][0-9]\:[0-5][0-9]")
Make sure that instead of K4 in "to_text(K4)" there is a upper-left cell from the selected range
Save
Hope it helps someone :)
You may try the formula for data validation:
=not(iserror(SUBSTITUTE(A1," at","")*1))*(len(A1)=15)*(right(A1,2)*1<61)
not(iserror(SUBSTITUTE(A1," at","")*1)) checks all statemant is legal date
(len(A1)=15) checks dates are entered with 2 digits
(right(A1,2)*1<61) cheks too much minutes, for some reason 01 Apr at 11:99 is a legal date..
Select the range of fields, where you need the data validation to occur to.
Press on -> Data -> Data validation
For "Criteria" select "Custom formula is"
Enter the following in the textfield next to "Custom formula is":
=regexmatch(Tablename!B2; "^[a-z_]*$")
Where as "Tablename" should be replaced by the table name and "B2" should be replaced by the first cell of the range.
Inside the "" you enter then your regex-expression. Here this would allow only small letters and underscores.
Using the to_text() function additionally didn't work for me. So you should maybe avoid it in order to make sure, that it works.
Press save
For data scrubbing I have lot of hard coded values in my program. I am trying to put those values into a table. One of the conditions for this scrubbing is to find the length of the character and code (character_length(name) = 1).
But when I try to emulate the this by using ^.$, it is not catching values like ¿, ¥, Ã
please let me know if I am doing something wrong .
When I run below code and I see this 3 values ¿, ¥, Ã
select name from email_table
where character_length(name) = 1
and name not in
(select name from email_table
where regexp_similar(translate(name USING LATIN_TO_UNICODE WITH ERROR),'^.$', 'i') = 1)
It seems like the issue is due to version.
We have TD14 and TD 15 on different servers and I did following query
select case when regexp_similar('¥','^.$', 'i')=1
then 'Y'
else 'N'
end as output;
In case of TD 14, I get output as 'N' and in case of TD 15 answer is 'Y'.
I have a column of data, diagnosis codes to be exact. the problem is that when the data is imported it turns 111.0 into 111 (or any whole number). I am wondering if there is an update query I can run that will add the ".0" to the end of any value that is 3 characters long. I had a problem of it stripping a value from 008.45 to 8.45 but I figured that part out using:
UPDATE Master SET DIAGNOSIS01 = LEFT("00", 3-LEN(DIAGNOSIS01)) + DIAGNOSIS01
WHERE LEN(DIAGNOSIS01)<3 AND Len(DIAGNOSIS01)>0;
I got that from here on stackoverflow. Is there a variation of this update query I can use to add to the right if it's only 3 digits?
Additional info... formats of the values in this column include xxx.x or xxx.xx with x being a number
When it comes to sql I am very new so please treat me like I'm 3... ;)
UPDATE Master
SET Master.DIAGNOSIS01 = IIf(Len([Master].[DIAGNOSIS01])=3,[Master].[DIAGNOSIS01] & ".0",[Master].[DIAGNOSIS01]);