How to convert a SINGLE char to system string C++? - c++

I'm working on a program that displays the following chars/integers in a console app.
The code that I wrote works in console app, but doesn't work in form...
I also want to display these values in my form( textBox->text).
My myfunctions.h file:
typedef struct{
char Header [23]; //the char I want to display is 23 characters long
int Version [4]; //4 characters...
char Projectname [21];
char Developer [8];
char email [16];
char Description [132];
char Unknown [1];
}PackedContent;
void BinaryReader(){
system("CLS");
PackedContent t;
fstream myFile;
myFile.open("PackedContent.opf");
if(!myFile){
cout<<"An unknown error occured! Cannot read .opf file... exiting now... \n"<<endl;
}else{
cout <<"Reading packed data content... done!\n"<<endl;
myFile.read((char *)&t, sizeof(PackedContent));
cout<<"\nHeader :" <<t.Header <<endl; // Header info [ok]
//cout<<"\nVersion :" <<t.Version <<endl; // Project Version [err]
cout<<"\nProject name:" <<t.Projectname <<endl; // Project name
cout<<"\nDeveloper name:" <<t.Developer<<endl;
cout<<"\nEmail :" <<t.email <<endl; // Developer email
cout<<"\nDescription :" <<t.Description <<endl; // Project description [ok]
cout<<"Unknown" <<t.Unknown <<endl;
}
Form:
Binary Reader.H (form)
PackedContent t;
BinaryReader();
textBox1->Text = t.Header; // doesnt work...
I've aslo tried:
textBox1->Text = Convert::ToString(t.Header); //doesn't work...

If your char array was null-terminated, like C-strings, you could have passed it as is to an std::string c'tor:
textBox1->Text = std::string(t.Header)
Your char array is not null terminated, so you should also provide the size, like this:
int headerSize = 1; // This variable is just for the example. Instead you can pass the size right in the function below
textBox1->Text = std::string(t.Header, headerSize)
Or:
textBox1->Text = std::string(t.Header, std::size(t.Header))

You have forgot about terminating zero and this is why you have problems.
If you what to store text in c-array which can have length of 23 you need char[24] (23 + 1) to include tailing zero too.
Anyway using this c-array to store text is C-style code not C++ and this should be avoided.
If you do not include terminating zero then for example this call extBox1->Text = t.Header; will try to finds it to perform conversion to String. This will lead to undefined behavior, result string will contain some trash at the end or it will end with a crash.
If your code records terminating zero in this structure, but reaches size limit, then you will have buffer overrun error.

Related

ifstream not reading the same characters as they are written in the file

console
file
Simple explanation: ifstream's get() is reading the wrong chars (console is different from file) and I need to know why.
I am recording registers into a file as a char array. When I write it to the file, it writes successfully. I open the file and find the chars I intended, except notepad apparently shows unicode character 0000 ( NULL) as a space.
For instance, the entries
id = 1000; //an 8-byte long long
name = "stack"; //variable size
surname = "overflow"; //variable size
degree = "internet"; //variable size
sex = 'c'; //1-byte char
birthdate = 256; //4-byte int
become this on the file:
& èstackoverflowinternetc
or, putting the number of unicode characters that disappear when posted here between brackets:
&[3]| [1]è|stack|overflow|internet|c| [1] | //separating each section with a | for easier reading. Some unicode characters disappear when I post them here, but I assure you they are the correct ones
SIZE| ID | name| surname| degree |g| birth
(writing is working fine and puts the expected characters)
Trouble is, when the console in the code below prints what the buffer is reading from the file, it gives me the following record (extra spaces included)
Þstackoverflowinternetc
Which is bad because it returns me the wrong ID and birthdate. Either "-21" and "4747968" or "Ù" and "-1066252288". Other fields are unnaffected. Weird because size bytes show up as empty space in the console, so it shouldn't be able to split name, surname, degree and sex.
ifstream infile("alumni.freire", ios::binary);
if(infile.is_open()){
infile.seekg(pos, ios::beg);
int size;
size = infile.get();
char charreg[size];
charreg[0] = size;
//testing what buffer gives me
for(int i = 1; i < size; i++){
charreg[i] = infile.get();
cout << charreg[i];
}
}
What am I doing wrong?
EDIT: to explain better what I did:
I get the entries on the first "code" from user input and use them as parameters when creating a "reg" class I implemented. The reg class then does (adequatly, I've already tested it) the conversion to strings, and calculates a hidden four-element char array containing instance size, name size, surname size and degree size. When the program writes the class on-file, it is written perfectly, as I showed in the second "code" section. (If you do the calculations you'll see '&' equals the size of the entire thing, for example). When I read it from the file, it appears differently on console for some reason. Different characters. But it reads the right amount of characters because "name", "surname" and "degree" appear correctly.
EDIT n2: I made "charreg[]" into an int array and printed it and the values are correct. I have no idea what's happening anymore.
EDIT n3: Apparently the reason I was getting the wrong chars is that I should have used unsigned chars...
The idea to write, as is, your structure is good. But your approach is wrong.
You must have something to separate your fields.
For example you know that your ID is 8 byte long, great ! You can read 8 bytes :
long long id;
read(fd, &id, 8);
In your example you got -24 because you read the first byte of the full id number.
But for the rest of the file, how can you know the length of the first name and the last name ?
You could read byte by byte until you find an null byte.
But I suggest you to use a more structured file.
For example, you can define a structure like this :
long long id; // 8 bytes
char firstname[256]; // 256 bytes
char lastname[256]; // 256 bytes
char sex; // 1 byte
int birthdate; // 4 bytes
With this structure you can read and write super easily :
struct my_struct s;
read(fd, &s, sizeof(struct my_struct)); // read 8+256+256+1+4 bytes
s.birthdate = 128;
write(fd, &s, sizeof(struct my_struct));// write the structure
Of course you loose the "variable length" of the first name and last name. Do you really need more than 100 chars for a name ?
In a case you really need, you could introduce an header over each variable length value. But you loose the ability to read everything at once.
long long id;
int foo_size;
char *foo;
And then to read it :
struct my_struct s;
read(fd, &s, 12); // read the header, 8 + 4 bytes
char foo[s.foo_size];
read(fd, &s, s.foo_size);
You should define what exactly you need to save. Define a precise data structure that you can easily deduce at read, avoid things like "oh, let's read until null-byte".
I used C function to explain you because it's much more representative. You know what you read and what you write.
Start to play with this, and then try the same with c++ streams/function
I don't know how you are writing back information to the file but here is how I would do that, I'm hoping this is a fairly simple way of doing it. Keep in mind I have no idea what kind of file you are actually working with.
long long id = 1000;
std::string name = "name";
std::string surname = "overflow";
std::string degree = "internet";
unsigned char sex = 'c';
int birthdate = 256;
ofstream outfile("test.txt", ios::binary);
if (outfile.is_open())
{
const char* idBytes = static_cast<char*>(static_cast<void*>(&id));
const char* nameBytes = name.c_str();
const char* surnameBytes = surname.c_str();
const char* degreeBytes = degree.c_str();
const char* birthdateBytes = static_cast<char*>(static_cast<void*>(&birthdate));
outfile.write(idBytes, sizeof(id));
outfile.write(nameBytes, name.length());
outfile.write(surnameBytes, surname.length());
outfile.write(degreeBytes, degree.length());
outfile.put(sex);
outfile.write(birthdateBytes, sizeof(birthdate));
outfile.flush();
outfile.close();
}
and here is how I am going to output it, which to me seems to be coming out as expected.
ifstream infile("test.txt", std::ifstream::ate | ios::binary);
if (infile.is_open())
{
std::size_t fileSize = infile.tellg();
infile.seekg(0);
for (int i = 0; i < fileSize; i++)
{
char c = infile.get();
std::cout << c;
}
std::cout << std::endl;
}

How to read custom string with C++ from binary recursively

I've recently been getting in to IO with C++. I am trying to read a string from a binary file stream.
The custom type is saved like this:
The string is prefixed with the length of the string. So hello, would be stored like this: 6Hello\0.
I am basically reading text from a table (in this case a name table) in a binary file. The file header tells me the offset of this table (112 bytes in this case) and the number of names (318).
Using this information I can read the first byte at this offset. This tells me the length of the string (e.g. 6). So I'll start at the next byte and read 5 more to get the full string "Hello". This seems to work fine with the first name at the offset. trying to recursively read the rest provides a lot of garbage really. I've tried using loops and recursive functions but its not working out so well. Not sure what the problem is, so reverted to the original one name retrieval method. Here's the code:
int printName(fstream& fileObj, __int8 buff, DWORD offset, int& iteration){
fileObj.seekg(offset);
fileObj.read((char*)&buff, sizeof(char));
int nameSize = (int)buff;
char* szName = new char[nameSize];
for(int i=1; i <= nameSize; i++){
fileObj.seekg(offset+i);
fileObj.read((char*)&szName[i-1], sizeof(char));
}
cout << szName << endl;
return 0;
}
Any idea how to iterate through all 318 names without creating dodgy output?
Thanks for taking the time to look through this, your help is greatly appreciated.
You're overcomplicating a bit - there's no need to seek to the next sequential read.
Removing unused and pointless parameters, I would write this function something like this:
void printName(fstream& fileObj, DWORD offset) {
char size = 0;
if (fileObj.seekg(offset) && fileObj.read(&size, sizeof(char)))
{
char* name = new char[size];
if (fileObj.read(name, size))
{
cout << name << endl;
}
delete [] name;
}
}

C++ memory allocation (constructor)

I need to write class which contains char pointer to text line and constructor which retrieves text line from the list of arguments, dynamically allocates memory and copies the text of the line to the component class.
Writed programm doesn't works correctly. Example Error.
What is wrong? Please help!
class A
{
char* text;
public:
A(char *line);
};
A::A(char *line) {
int length = strlen(line);
text = new char[length];
if (strlen(line) <= sizeof(text))
strcpy_s(text, length, line);
else
{
cout << text << endl;
cout << "Too long string" << endl;
}
}
int main()
{
A ob("aaaaaa");
system("PAUSE");
return 0;
}
The sizeof operator returns the size of the object (not the size of a string). So in this case
sizeof(text)
It returns the size of the object text. You declare text as
char* text;
So it returns the size of a char*. The exact size of this will depend on the system, but lets guess its 4. So any string that has a length greater than 4 will result in the output of:
Too long string
If we look at the string: "aaaaaa" is longer than 4 so you get the expected output.
I expect you are trying to check that the previous line succeded.
text = new char[length];
But in C++ the new will either work or throw an exception (causing program termination for this program). So either that line works or the program will exit. So there is no need to check the result of new (unlike C where you should check the result of malloc())
Also note: You should check the result of strcpy_s() as it will return an error on failure. Since you do not provide enough space in the destination it will indicate an error (you don't provide space for the null terminator).

Reading binary text into array?

I have a program that I need to read binary text into. I read the binary text via a redirection:
readData will be an executable made by my Makefile.
Example: readData < binaryText.txt
What I want to do is read the binary text, and store each character in the binary text file as a character inside a char array. The binary text is made up of 32 This is my attempt at doing so...
unsigned char * buffer;
char d;
cin.seekg(0, ios::end);
int length = cin.tellg();
cin.seekg(0, ios::beg);
buffer = new unsigned char [length];
while(cin.get(d))
{
cin.read((char*)&buffer, length);
cout << buffer[(int)d] << endl;
}
However, I keep getting a segmentation fault on this. Might anyone have any ideas on how to read binary text into a char array? Thanks!
I'm more a C programmer rather than a C++, but I think that you should have started your while loop
while(cin.get(&d)){
The easiest would be like this:
std::istringstream iss;
iss << std::cin.rdbuf();
// now use iss.str()
Or, all in one line:
std::string data(static_cast<std::istringstream&>(std::istringstream() << std::cin.rdbuf()).str());
Something like this should do the trick.
You retrieve the filename from the arguments and then read the whole file in one shot.
const char *filename = argv[0];
vector<char> buffer;
// open the stream
std::ifstream is(filename);
// determine the file length
is.seekg(0, ios_base::end);
std::size_t size = is.tellg();
is.seekg(0, std::ios_base::beg);
// make sure we have enough memory space
buffer.reserve(size);
buffer.resize(size, 0);
// load the data
is.read((char *) &buffer[0], size);
// close the file
is.close();
You then just need to iterate over the vector to read characters.
The reason why you are getting segmentation fault is because you are trying to access an array variable using a character value.
Problem:
buffer[(int)d] //d is a ASCII character value, and if the value exceeds the array's range, there comes the segfault.
If what you want is an character array, you already have that from cin.read()
Solution:
cin.read(reinterpret_cast<char*>(buffer), length);
If you want to print out, just use printf
printf("%s", buffer);
I used reinterpret_cast because it thought it is safe to convert to signed character pointer since most characters that are used would range from 0 ~ 127. You should know that character values from 128 to 255 would be converted wrongly.

How to capture length of sscanf'd string?

I'm parsing a string that follows a predictable pattern:
1 character
an integer (one or more digits)
1 colon
a string, whose length came from #2
For example:
s5:stuff
I can see easily how to parse this with PCRE or the like, but I'd rather stick to plain string ops for the sake of speed.
I know I'll need to do it in 2 steps because I can't allocate the destination string until I know its length. My problem is gracefully getting the offset for the start of said string. Some code:
unsigned start = 0;
char type = serialized[start++]; // get the type tag
int len = 0;
char* dest = NULL;
char format[20];
//...
switch (type) {
//...
case 's':
// Figure out the length of the target string...
sscanf(serialized + start, "%d", &len);
// <code type='graceful'>
// increment start by the STRING LENGTH of whatever %d was
// </code>
// Don't forget to skip over the colon...
++start;
// Build a format string which accounts for length...
sprintf(format, "%%%ds", len);
// Finally, grab the target string...
sscanf(serialized + start, format, string);
break;
//...
}
That code is roughly taken from what I have (which isn't complete because of the issue at hand) but it should get the point across. Maybe I'm taking the wrong approach entirely. What's the most graceful way to do this? The solution can either C or C++ (and I'd actually like to see the competing methods if there are enough responses).
You can use the %n conversion specifier, which doesn't consume any input - instead, it expects an int * parameter, and writes the number of characters consumed from the input into it:
int consumed;
sscanf(serialized + start, "%d%n", &len, &consumed);
start += consumed;
(But don't forget to check that sscanf() returned > 0!)
Use the %n format specifier to write the number of characters read so far to an integer argument.
Here's a C++ solution, it could be better, and is hard-coded specifically to deal with your example input, but shouldn't require much modification to get working.
std::stringstream ss;
char type;
unsigned length;
char dummy;
std::string value;
ss << "s5:Helloxxxxxxxxxxx";
ss >> type;
ss >> length;
ss >> dummy;
ss.width(length);
ss >> value;
std::cout << value << std::endl;
Disclaimer:
I'm a noob at C++.
You can probably just use atoi which will ignore the colon.
e.g. len = atoi(serialized + start);
The only thing with atoi is that if it returns zero it could mean either the conversion failed, or that the length was truly zero. So it's not always the most appropriate function.
if you replace you colon with a space scanf will stop on it and you can get the size malloc the size then run another scanf to get the rest of the string`
int main (int argc, const char * argv[]) {
char foo[20];
char *test;
scanf("%s",foo); //"hello world"
printf("foo = %s\n", foo);//prints hello
//get size
test = malloc(sizeof(char)* 10);//replace 10 with your string size
scanf("%s", test);
printf("test = %s\n", test);//prints world
return 0;
}
`
Seems like the format is overspecified... (using a variable length field to specify the length of a variable length field).
If you're using GCC, I'd suggest
if (sscanf(serialized,"%c%d:%as",&type,&len,&dest)<3) return -1;
/* use type, dest; ignore len */
free(dest);
return 0;