I have some urls saved in DB like hello world
with break tags, so i need to delete them, the problem that <br/> are in other places to so i can't delete all of them,
i write RegExp <*"*<br\/?>"> but it select not only <br> and quotes too.
You really shouldn't be using regular expressions for parsing HTML or XML.
Having said that. As I understand it, you have br tags inside the href attribute of a tags.
try :
href\s*?=\s*?\"(.*?)(<br\/?\>)\"
If you try to search about the right lines in the database, then this is your regex extended to match the whole line:
<.*\".*<br\/>\">.*>
After this you can mach the '<br/>' directly in those lines. Is there a language to edit your DB?
Some of the other answers here are okay. I'll offer an alternative:
https://regex101.com/r/uG5PBA/2
This'll put the break tags in a capture group -- group 1, so that you can simply nix them.
Regex:
<a[\s\S]*?(\<br\/>)[\s\S]*?<\/a>
Test String:
hello worldhello world
Related
I have response body which contains
"<h3 class="panel-title">Welcome
First Last </h3>"
I want to fetch 'First Last' as a output
The regular expression I have tried are
"Welcome(\s*([A-Za-z]+))(\s*([A-Za-z]+))"
"Welcome \s*([A-Za-z]+)\s*([A-Za-z]+)"
But not able to get the result. If I remove the newline and take it as
"<h3 class="panel-title">Welcome First Last </h3>" it is detecting in online regex maker.
I suspect your problem is the carriage return between "Welcome" and the user name. If you use the "single-line mode" flag (?s) in your regex, it will ignore newlines. Try these:
(?s)Welcome(\s*([A-Za-z]+))(\s*([A-Za-z]+))
(?s)Welcome \s*([A-Za-z]+)\s*([A-Za-z]+)
(this works in jMeter and any other java or php based regex, but not in javascript. In the comments on the question you say you're using javascript and also jMeter - if it is a jMeter question, then this will help. if javaScript, try one of the other answers)
Well, usually I don't recommend regex for this kind of work. DOM manipulation plays at its best.
but you can use following regex to yank text:
/(?:<h3.*?>)([^<]+)(?:<\/h3>)/i
See demo at https://regex101.com/r/wA2sZ9/1
This will extract First and Last names including extra spacing. I'm sure you can easily deal with spaces.
In jmeter reg exp extractor you can use:
<h3 class="panel-title">Welcome(.*?)</h3>
Then take value using $1$.
In the data you shown welcome is followed by enter.If actually its part of response then you have to use \n.
<h3 class="panel-title">Welcome\n(.*?)</h3>
Otherwise above one is enough.
First verify this in jmeter using regular expression tester of response body.
Welcome([\s\S]+?)<
Try this, it will definitely work.
Regular expressions are greedy by default, try this
Welcome\s*([A-Za-z]+)\s*([A-Za-z]+)
Groups 1 and 2 contain your data
Check it here
I'm having a battle with a regex. (MOBI creation)
I have two files: one with XML, the other an HTML table of contents.
The important parts of the XML:
<navPoint id="_NeedsHTMLid" playOrder="40">
<navLabel><text>Needs anchor text from link.)</text></navLabel>
...
The HTML TOC, of course, looks like:
schema.org Article Mark-up
======
Hours and hours... worked with Textpad forever. Saw remarks here, now I'm using NotePad++... some of the regex results are different (NOT that I had it working anyway.) #_[\b(\w\b] was returning the ID: now? Not so much!
Does anyone know how to yank both the ID and the anchor text out of these? I'd be so grateful.
You can use this to get the id and the anchor text at the same time:
_(\w+)\b|([a-Z\s.]+[)]+)
#_[\b(\w\b] is not a valid regex. Try _([^"]+)\b.
Edited: try [^"] in place of \w.
If you want to match the ids and the text, go to Search > Find menu (shortcut CTRL+F) and do the following:
Find what:
id="([a-zA-Z0-9\-\:\_\.]+)"|<text>(.+?)<\/text>
Select radio button "Regular Expression"
Then press Find All in Current Document
You can test it with your example at regex101.
Here's a StackOverflow post about valid id names.
I didn't provided you with a Search and Replace solution, since you didn't mentioned anything about a replacement.
I've searched around quite a bit now, but I can't get any suggestions to work in my situation. I've seen success with negative lookahead or lookaround, but I really don't understand it.
I wish to use RegExp to find URLs in blocks of text but ignore them when quoted. While not perfect yet I have the following to find URLs:
(https?\://)?(\w+\.)+\w{2,}(:[0-9])?\/?((/?\w+)+)?(\.\w+)?
I want it to match the following:
www.test.com:50/stuff
http://player.vimeo.com/video/63317960
odd.name.amazone.com/pizza
But not match:
"www.test.com:50/stuff
http://plAyerz.vimeo.com/video/63317960"
"odd.name.amazone.com/pizza"
Edit:
To clarify, I could be passing a full paragraph of text through the expression. Sample paragraph of what I'd like below:
I would like the following link to be found www.example.com. However this link should be ignored "www.example.com". It would be nice, but not required, to have "www.example.com and www.example.com" ignored as well.
A sample of a different one I have working below. language is php:
$articleEntry = "Hey guys! Check out this cool video on Vimeo: player.vimeo.com/video/63317960";
$pattern = array('/\n+/', '/(https?\:\/\/)?(player\.vimeo\.com\/video\/[0-9]+)/');
$replace = array('<br/><br/>',
'<iframe src="http://$2?color=40cc20" width="500" height="281" frameborder="0" webkitAllowFullScreen mozallowfullscreen allowFullScreen></iframe>');
$articleEntry = preg_replace($pattern,$replace,$articleEntry);
The result of the above will replace any new lines "\n" with a double break "" and will embed the Vimeo video by replacing the Vimeo address with an iframe and link.
I've found a solution!
(?=(([^"]+"){2})*[^"]*$)((https?:\/\/)?(\w+\.)+\w{2,}(:[0-9]+)?((\/\w+)+(\.\w+)?)?\/?)
The first part from (? to *$) what makes it work for me. I found this as an answer in java Regex - split but ignore text inside quotes? by https://stackoverflow.com/users/548225/anubhava
While I had read that question before, I had overlooked his answer because it wasn't the one that "solved" the question. I just changed the single quote to double quote and it works out for me.
add ^ and $ to your regex
^(https?\://)?(\w+\.)+\w{2,}(:[0-9])?\/?((/?\w+)+)?(\.\w+)?$
please notice you might need to escape the slashes after http (meaning https?\:\/\/)
update
if you want it to be case sensitive, you shouldn't use \w but [a-z]. the \w contains all letters and numbers, so you should be careful while using it.
I am trying to extract javascript code from HTML content that I receive via CFHTTP request.
I have this simple regex that catches everyting as long as there is no linebreak in the code between the tags.
var result=REMatch("<script[^>]*>(.*?)</script>",html);
This will catch:
<script>testtesttest</script<
but not
<script>
testtest
</script>
I have tried to use (?m) for multiline, but it doesn't work like that.
I am using the reference to figure it out but I am just not getting it with regex.
Heads up, normally there would be javascript between the script tags, not simple text so also characters like {}();:-_ etc.
Can anyone help me out?
Cheers
[[UPDATE]]
Thanks guys, I will try the solutions. I favor regex because but I will look into the HTML Parser too.
(?m) multiline mode is for making ^ and $ match on line breaks (not just start/end of string as is default), but what you're trying to do here is make . include newlines - for that you want (?s) (dot-all mode).
However, I probably wouldn't do this with regex - a HTML parser is a more robust solution. Here's how to do it with jSoup:
var result = jsoup.parse(html).select('script').text();
More details on using jSoup in CF are available here, or alternatively you can use the TagSoup parser, which ships with CF10 (so you don't need to worry about jars/etc).
If you really want regex, then you can use this:
var result = rematch('<script[^>]*>(?:[^<]+|<(?!/script>))+',html);
Unlike using (?s).*? this avoids matching empty blocks (but it will still fail in certain edge cases - if accuracy is required use a HTML parser).
To extract just the text from the first script block, you can strip the script tag with this:
result = ListRest( result[1] , '>' );
You can use dot matches all mode or replace . with [\s\S] to get the same effect.
<script[^>]*>[\s\S]*?</script> would match everything including newlines.
I need some help with a VB RegEx.
I've got two RegEx that I need to do two specific things.
RegEx one - I am not exactly sure how to do this, but I need to get everything within a Href tag. i.e.
String = "<a href=""test.html"">"
I need the RegEx to return .... test.html
RegEx Two - I have partly got this working.
I've got tags like
RegEx = "<div class=""top""(.*?)</div>"
String = "<div class=""top""><a><b><div class=""bottom""></div></b></a></div>"
The problem I have is this isnt returning anything, it should return everything withing "top", but it returns nothing.
Neither use-case can be solved well with regular expressions.
Use an HTML parser instead, e.g. the HTML Agility Pack.
Well, if your html doesn't contain nested tags you can do the first part with regex (as long as you can control your search source code, you can be much more certain of your results).
\<a href=""([^""]+)\>
the test.html will be found in the non-passive group referred to as $1.
The second part I'm concerned that you have nested tags in there and it's failing on that. The thing with regex and html is that regex can't delve well into the nested-allowable-but-not-best-practice code that can execute as expected but isn't well formed.
Can you post some search source for the second case so we can look?