I want to get a bloc of lines which contains < or > operator until an empty newline
i try with this regex .*[<>][^,\r\n]+?\(.*\S.*,.*\S.*\).*(?:(\n).*)
You find here my example : https://regex101.com/r/UQYLB5/1/
Expected Result :
MATCH 1 :
BAR18>17M(3,5.2)V
MATCH 2 :
BAR19>1.243037M(3,5.2)V
INFORMATION PROCESS
TAKE B/F: 19V[1]
LIGHT PC CARD:
MATCH 3 :
TEFAL17>1.262259M(4.5,5.5)V
SISS17 : 1789-ID
LIGHT 19/17
MAPPING NICE :
MATCH 4 :
MASCARPONE19>493.818969M(3,5.2)V
BATA17 : CDER78945 -- 1875
LEFT ERREUR - CAME BACK
MATCH 5 :
REPAR_178>748.515487M(4.5,5.5)V
CHAN1 / STEREO MIX
If you don't want to match lines which could consist of spaces only, you could use match either < or > and match at least a non whitespace char \S in the following lines:
^[^<>\r\n]*[<>].*(?:\r?\n[^\r\n\S]*\S.*)*
The pattern will match:
^ Start of string
[^<>\r\n]* Match any char except < `
[<>].* Match either < or > and the rest of the line
(?: Non capture group
\r?\n Match a newline
[^\r\n\S]* Match any char except a newline
\S.* Match a non whitespace char and the rest of the line
)* Close the group and repeat 0+ times
Regex demo
If the first line should also contain a , after matching < or >:
^[^<>\r\n]*[<>][^\r\n,]*,.*(?:\r?\n[^\r\n\S]*\S.*)*
Regex demo
Related
I would like to extract two different test strings /i/int/2021/11/18/019e1691-614c-4402-a8c1-d0239ad1ac45/,640-1_999899,480-1_999899,960-1_999899,1280-1_999899,1920-1_999899,.mp4.csmil/master.m3u8?set-segment-duration=responsive
and
/i/int/2021/11/25/,live_20211125_215206_sendeton_640x360-50p-1200kbit,live_20211125_215206_sendeton_480x270-50p-700kbit,live_20211125_215206_sendeton_960x540-50p-1600kbit,live_20211125_215206_sendeton_1280x720-50p-3200kbit,live_20211125_215206_sendeton_1920x1080-50p-5000kbit,.mp4.csmil/master.m3u8
with a single RegEx and in Group-1.
By using this RegEx ^.[i,na,fm,d]+\/(.+([,\/])?(\/|.+=.+,\/).+\/[,](live.([^,]).).+_)?.+(640).*$ I can get the second string to match the desired result int/2021/11/25/,live_20211125_215206_
but the first string does not match in Group-1 and the missing expected test string 1 extraction is int/2021/11/18/019e1691-614c-4402-a8c1-d0239ad1ac45
Any pointers on this is appreciated.
Thanks!
If you want both values in group 1, you can use:
^/(?:[id]|na|fm)/([^/\s]*/\d{4}/\d{2}/\d{2}/\S*?)(?:/,|[^_]+_)640(?:\D|$)
The pattern matches:
^ Start of string
/ Match literally
(?:[id]|na|fm) Match one of i d na fm
/ Match literally
( Capture group 1
[^/\s]*/ Match any char except a / or a whitespace char, then match /
\d{4}/\d{2}/\d{2}/ Match a date like pattern
\S*? Match optional non whitespace chars, as few as possible
) Close group 1
(?:/,|[^_]+_) Match either /, or 1+ chars other than _ and then match _
640 Match literally
(?:\D|$) Match either a non digits or assert end of string
See a regex demo and a go demo.
We can't know all the rules of how the strings your are matching are constructed, but for just these two example strings provided:
package main
import (
"fmt"
"regexp"
)
func main() {
var re = regexp.MustCompile(`(?m)(\/i/int/\d{4}/\d{2}/\d{2}/.*)(?:\/,|_[\w_]+)640`)
var str = `
/i/int/2021/11/18/019e1691-614c-4402-a8c1-d0239ad1ac45/,640-1_999899,480-1_999899,960-1_999899,1280-1_999899,1920-1_999899,.mp4.csmil/master.m3u8?set-segment-duration=responsive
/i/int/2021/11/25/,live_20211125_215206_sendeton_640x360-50p-1200kbit,live_20211125_215206_sendeton_480x270-50p-700kbit,live_20211125_215206_sendeton_960x540-50p-1600kbit,live_20211125_215206_sendeton_1280x720-50p-3200kbit,live_20211125_215206_sendeton_1920x1080-50p-5000kbit,.mp4.csmil/master.m3u8`
match := re.FindAllStringSubmatch(str, -1)
for _, val := range match {
fmt.Println(val[1])
}
}
I want to match the string b5 with optional $ in front of the b or tha 5 :
=b5
b$5
= $b$5
($b5)
But the 5 can't be followed by any number . And the b can't be preceded by any alphabet. So this should return false :
b55
ab5
I tried this :
\W\$*b\$*5\W
it works fine. i will match X=($b$5) but the problem is : it won't match anymore if the '5' is the last character in the line.
because 5 is last character
You can use
(?:\W|^)\$*b\$*5(?:\W|$)
(?:\W|^)\$*b\$*5\b
See the RE2 regex demo.
Details
(?:\W|^) - a non-capturing group matching either a non-word char or start of string
\$* - zero or more $ chars
b - a b char
\$* - zero or more $ chars
5 - a 5 char
(?:\W|$) - a non-capturing group matching either a non-word char or end of string or
\b - a word boundary.
I'm doing a small project which can calculate the count of functions in C++ files(.cpp).
I used the following Regex as "function pattern":
/[a-z|A-Z]+\s*::\s*~?[a-z|A-Z]+\(.*\)/gm
It works for most cases, but fails when there are new line breaks in ().
void CXYZRScanPanel::OnPrepareScanning()
{
//This one is ok.
}
void CXYZRScanPanel::OnPrepareScanning(int k)
{
//This one is ok.
}
void CXYZRScanPanel::OnPrepareScanning(int k,
int j)
{
//This one fails.
}
I'm thinking if there is anything "stronger" than the .* which can skip the \r\n.
Thanks for any help.
If there is no such a thing, I will probably remove all /r/n within () before doing the such.
You could write the pattern using a negated character class starting with [^ matching any char except ( and ) which will also match a newline.
Note that you can omit the | in the character class.
[a-zA-Z]+\s*::\s*~?[a-zA-Z]+(\([^()]*\))
The pattern matches:
[a-zA-Z]+ Match 1+ times chars a-zA-Z
\s*::\s* Match :: between optional whitespace chars
~? Match an optional ~ char
[a-zA-Z]+ Match 1+ times chars a-zA-Z
( Capture group 1
\([^()]*\) Optionally match any char except ( and ) between parenthesis
) Close group 1
See a regex demo
for i,v in array
for i , v in array
for i , v in array
for i, v in array
for i,v in array
for i, v in array
for[\s+,.](.+)
https://regex101.com/r/Vd3w7C/2
How i could match anything after the v
but
i,v, and in array will have different values
i mean something like:
for ppp,gflgkf heekd gfvb
You could use
\bfor\s+[^\s,]+(?:\s*,\s*[^\s,]+)*\s+(.+)
The pattern matches:
\bfor\s+ Match for and 1+ whitespace chars
[^\s,]+ Match 1+ times any char except a whitspace char or ,
(?: Non capture group
\s*,\s*[^\s,]+ Match a comma between optional whitespace chars, and match at least a single char other than a comma or whitespace chars
)*\s+ Close the group and optionally repeat it followed by 1+ whitespace chars
(.+) Capture 1+ times any char except a newline in group 1
See a regex demo.
how can we remove the text before the line that start's with second comma(line 5 in the example),how can i do that using regex?
example :
,
abc,xyz,ggg,nrmr
cde,jjj,kkkk,iiii,tem,posting
234,mm/dd/yy
,
454654,output2,sample
45646,output1,non-sample
16546,225.02
ABC,2.98
expected :
454654,output2,sample
45646,output1,non-sample
16546,225.02
ABC,2.98
It seems you may use
val s = """,
abc,xyz,ggg,nrmr
cde,jjj,kkkk,iiii,tem,posting
234,mm/dd/yy
,
454654,output2,sample
45646,output1,non-sample
16546,225.02
ABC,2.98"""
val res = s.replaceFirst("(?sm)\\A(.*?^,$){2}", "").trim()
println(res)
// =>
// 454654,output2,sample
// 45646,output1,non-sample
// 16546,225.02
// ABC,2.98
See the Scala demo.
Pattern details:
(?sm) - s enables . to match any char in the string including newlines, and m makes ^ and $ match start/end of line respectively
\\A - the start of string
(.*?^,$){2} - 2 occurrences of:
.*? - any 0+ chars as few as possible up to the leftmost
^,$ - line that only contains ,.