Regex: Deal \r\n as normal word - regex

Question

I'm doing a small project which can calculate the count of functions in C++ files(.cpp).
I used the following Regex as "function pattern":
/[a-z|A-Z]+\s*::\s*~?[a-z|A-Z]+\(.*\)/gm
It works for most cases, but fails when there are new line breaks in ().
void CXYZRScanPanel::OnPrepareScanning()
{
//This one is ok.
}
void CXYZRScanPanel::OnPrepareScanning(int k)
{
//This one is ok.
}
void CXYZRScanPanel::OnPrepareScanning(int k,
int j)
{
//This one fails.
}
I'm thinking if there is anything "stronger" than the .* which can skip the \r\n.
Thanks for any help.
If there is no such a thing, I will probably remove all /r/n within () before doing the such.

Answer 1

You could write the pattern using a negated character class starting with [^ matching any char except ( and ) which will also match a newline.
Note that you can omit the | in the character class.
[a-zA-Z]+\s*::\s*~?[a-zA-Z]+(\([^()]*\))
The pattern matches:
[a-zA-Z]+ Match 1+ times chars a-zA-Z
\s*::\s* Match :: between optional whitespace chars
~? Match an optional ~ char
[a-zA-Z]+ Match 1+ times chars a-zA-Z
( Capture group 1
\([^()]*\) Optionally match any char except ( and ) between parenthesis
) Close group 1
See a regex demo