I am dealing with a bunch of xml files that contain one-line-comments like this: // Some comment.
I am pretty sure that xml comments look like this: <!-- Some comment -->
I would like to use a regular expression in the Atom editor to find and replace all wrong comment syntax.
according to this question, the comment can be found with (?<=\s)//([^\n\r]*) and replaced with something like <!--$1-->. There must be an error somewhere since clicking replace button leaves the comment as is, instaed of replacing it. Actually I can't even replace it with a simple character.
The find and replace works with a different regex in the "Find" field:
Find: name.*
Replace: baloon
Is there anything I can write in the "Find" and "Replace" field to achieve this transformation?
Atom editor search and replace currently does not support lookbehind constructs, like (?<=\s). To "imitate" it, you may use a capturing group with an alternation between start of string, ^, and a whitespace, \s.
So, you may use
Find What: (^|\s)//([^\n\r]+)
Replace With: $1<!--$2-->
See the regex demo. NOTE \s may match newlines, so you may probably want to use (^|[^\S\r\n])//([^\n\r]+) to avoid matching across line breaks.
If you do not need to check for a whitespace, just remove that first capturing group and use a mere:
Find What: //([^\n\r]+)
Replace With: <!--$1-->
See another regex demo.
Related
I have an XML code:
<Line1>Matched_text Other_text</Line1>
<Line2>Text_to_replace</Line2>
How to tell Notepad++ to find Matched_text and replace Text_to_replace to Replaced_text? There are several similar blocks of code, with one exactly Matched _text and different Other_text and Text_to_replace. I want to replace all in once.
My idea is to put
Matched_text*<Line2>*</Line2>
in the Find field, and
Matched_text*<Line2>Replaced_text</Line2>
in the Replace field. I know that \1 in regex might be useful, but I don't know where to start.
The actual code is:
<Name>Matched_text, Other_text</Name>
<IsBillable>false</IsBillable>
<Color>-Text_to_replace</Color>
The regex you're looking for is something like the following.
Find: (Matched_text[\w,\s<>\/]*<Color>-).*(</Color>)
Replace: \1Replaced_text\2
Broken down:
`()` is how you tell regex that you want to keep things (for use in /1, /2, etc.), these are called capture groups in regex land.
`Matched_text[\w,\s<>\/]*` means you want your anchor `Matched_text` and everything after it up till the next part of the expression.
`<Color>-).*(</Color>)` Select everything between <Color>- and </Color> for replacement.
If you have any questions about the expression, I highly recommend looking at a regex cheatsheet.
I use Notepad++,
i need to search and replace entire word that contain a specific keyword.
Ex: someting HELP.blablabla.blabla someting
i would like to search entire text for words that contain the keyword "HELP" untill the first space OR the first comma.
In this case: HELP.blablabla.blabla
thanks a lot
Go to the search panel, check the regex checkbox on the bottom and try: (HELP)([^ ,]*)
Note: There are a space character after the ^
This regex means: Search for the entire word HELP (HELP) followed by anything that it isn't an space or an comma [^ ,] the ^ inside the brackets is a denial
Edit:
You can use just HELP[^ ,]* the parenthesis is just to create capturing groups if you need to use the specific groups to replace later. As pointed by #alphabravo
You say search and replace an entire word but if it were that simple then I wonder why a regular search and replace isn't sufficient. So I'm reading between the lines and assuming you want to match on full lines of text.
I think I've used npp enough to get the syntax right. I don't remember any eccentricities that would apply. Is the comma/space optional?
^[^, ]*HELP[^, ]*[, ]
I'm kinda thinking this one might be good enough:
^[^, ]*HELP
I have a bunch of artists that are named in this fashion:
Killers, The
Treatment, The
Virginmarys, The
I need them to look like
The Killers
The Treatment
The Virginmarys
I'm able to match the lines with , The ((^|\n)(.*, The) is what I've used) but the more advanced syntax is eluding me. I can use regex on the replacement syntax as well (it's for a TextPipe filter so it might as well be for Notepad++ or any other Regex text editor).
You should be able to use the following:
Find: (\S+),\s\S*
Replace: The $1
Or include the The..
Find: (\S+),\s+(\S+)
Replace: $2 $1
Depending on your editor, you may be better off using \1, \2, and so on for capture groups.
Since you need to specifically capture the title before the comma, do so:
(^|\n)(.*), The
And replace it putting the "the" in the right place:
\1The \2
Regular expressions define matches but not substitutions.
How and in which way you can perform substitutions is highly dependant on the application.
Most editors that provide regular expression support work on a line per line basis.
Some of them will allow substitutions such as
s/^(.*Banana)/INSERTED LINE\n\1/
which would then insert the specific pattern before each match. Note that others may not allow newlines in the substitution pattern at all. In VIM, you can input newlines into the command prompt using Ctrl+K Return Return. YMMV.
In Java, you would just first print the insertion text, then print the matching line.
I have a text file with several lines like these ones:
cd_cod_bus
nm_number_ex
cd_goal
And I want to get rid of the - and uppercase the following character using Notepad++ (I can also use other tool but if it doesn't get the problem more troublesome).
So I tried to get the characters with the following regex (?<=_)\w and replace it using \U\1\E\2 for the uppercasing trick but here is where my problems came. I think the regex is OK but once I click replace all I get this result:
cd_od_us
nm_umber_x
cd_oal
as you can see it is only deleting the match.
Do you know where the problem is?
Thanks.
The search regex has no capture groups, i.e. the \1 and \2 references in the replacement do not refer to anything.
Try this instead:
Search: _(\w)
Replace \U\1\E
There you have a capture group in the search part (the parenthesis around the \w) and the \1 in the replacement refers back to what was captured.
replace
_(.)
with
\U$1
will give you:
cdCodBus
nmNumberEx
cdGoal
and for your
I can also use other tool but if it doesn't get the problem more troublesome
I suggest you try vim.
Try this,
_(\w)
and replace with
\U\1
here's a screenshot
I got a string like this:
PREFIX-('STRING WITH SPACES TO REPLACE')
and i need this:
PREFIX-('STRING_WITH_SPACES_TO_REPLACE')
I'm using Notepad++ for the Regex Search and Replace, but i'm shure every other Editor capable of regex replacements can do it to.
I'm using:
PREFIX-\('(.*)(\s)(.*)'\)
for search and
PREFIX-('\1_\3')
for replace
but that replaces only one space from the string.
The regex search feature in Notepad++ is very, very weak. The only way I can see to do this in NPP is to manually select the part of the text you want to work on, then do a standard find/replace with the In selection box checked.
Alternatively, you can run the document through an external script, or you can get a better editor. EditPad Pro has the best regex support I've ever seen in an editor. It's not free, but it's worth paying for. In EPP all I had to do was this:
search: ((?:PREFIX-\('|\G)[^\s']+)\s+
replace: $1_
EDIT: \G matches the position where the previous match ended, or the beginning of the input if there was no previous match. In other words, the first time you apply the regex, \G acts like \A. You can prevent that by adding a negative lookahead, like so:
((?:PREFIX-\('|(?!\A)\G)[^\s']+)\s+
If you want to prevent a match at the very beginning of the text no matter what it starts with, you can move the lookahead outside the group:
(?!\A)((?:PREFIX-\('|\G)[^\s']+)\s+
And, just in case you were wondering, a lookbehind will work just as well as a lookahead:
((?:PREFIX-\('|(?<!\A)\G)[^\s']+)\s+
You have to keep matching from the beggining of the string untill you can match no more.
find /(PREFIX-\('[^\s']*)\s([^']*'\))/
replace $1_$2
like: while (/(PREFIX-\('[^\s']*)\s([^']*'\))/$1_$2/) {}
How about using Replace all for about 20 times? Or until you're sure no string contains more spaces
Due to nature of regex, it's not possible to do this in one step by normal regular expression.
But if I be in your place, I do such replaces in several steps:
find such patterns and mark them with special character
(Like replacing STRING WITH SPACES TO REPLACE with #STRING WITH SPACES TO REPLACE#
Replace #([^#\s]*)\s to #\1_ server times.
Remove markers!
I studied a little the regex tool in Notepad++ because I didn't know their possibilities.
I conclude that they aren't powerful enough to do what you want.
Your are obliged to learn and use a programming language having a real regex capability. There are a number of them. Personnaly, I use Python. It would take 1 mn to do what you want with it
You'd have to run the replace several times for each space but this regex will work
/(?<=PREFIX-\(')([^\s]+)\s+/g
Replace with
\1_ or $1_
See it working at http://refiddle.com/10z