after several hours of searching and experimenting, I'm hoping someone can either help me or rub my nose in a post I've missed which acctually would be helpful as well come to think of it...
Problem:
I've made a quick&dirty fix in several dozens of php scripts (we use to enhance smarty capabilities) with security checks.
Example of input(part1):
///// SMARTY AUTH /////
$auth['model'] = isset($params['model']) ? $params['model'] : null;
$auth['requiredLevel'] = isset($params['requiredlevel']) ? $params['requiredlevel'] : null;
$auth['baseAuthorizationLevel'] = isset($params['_authorizationlevel']) ? $params['_authorizationlevel'] : null;
$auth['defaultRequiredLevel'] = AuthorizationLevel::AULE_WRITE;
$auth['baseModel'] = $smarty->getTemplateVars('model');
///// SMARTY AUTH /////
...which i'd like to replace with a much cleaner solution we've come up with. Now here's the rub; in one section of the file there's a block of lines, luckily with very distinct delimiter lines, but in one of those lines is a piece of code that needs to be merged with a replacement string which replaces a second pattern in a line which follows the before-said block, with optionally a variable number of lines in between.
I'm having trouble figuring out how to piece this nested code together as the shorthand code of sed is quite confusing to me.
So far I've tried to assemble the code needed to capture the first block, but sed keeps giving me the same error each time; extra characters after command
here are some of the attempts I've made:
sed -n 'p/^\/\/\/\/\/ SMARTY AUTH \/\/\/\/\/\\n.*\\n.*\\n.*\\n.*AULE_\([A-Z_]*\);$^.*$^^\/\/\/\/\/ SMARTY AUTH \/\/\/\/\/$/' function.xls_form.php
sed -n 'p/\(^.*SMARTY AUTH.*$^.*$^.*$^.*$^.*AULE_\([A-Z_]*\);$^.*$^.*SMARTY AUTH.*$/' function.xls_form.php
the second part is relatively easy compared to the first;
sed -ei'.orig' 's/RoleContextAuthorizations::smartyAuth(\$auth)/$smarty->hasAccess(\$params,AuthorizationLevel::AULE_\1)/' *.php
where \1 would be the matched snippet from the first part...
Edit:
The first codeblock is an example of input part 1 which needs to be removed; part 2 is RoleContextAuthorizations::smartyAuth($auth) which needs to be replaced with $smarty->hasAccess($params, AuthorizationLevel::AULE_<snippet from part1>)
/edit
Hoping somebody can point me in the right direction, Many thanks in advance!!!
The hold space is going to be key to solving this. You can copy material from the pattern space (where sed normally works) into the hold space, and do various operations with the hold space, etc.
You need to find the AuthorizationLevel::AULE_WRITE type text within the block markers, and copy that to the hold space, and then delete the text within the block markers. And then separately find the other pattern and replace it with information from the hold space.
Given that the markers use slashes, it is also time to use a custom search marker which is introduced by a backslash. The following could be in a file script.sed, to be used as:
sed -f script.sed function.xls_form.php
When you're sure it's working, you can play with -i options to overwrite the original.
\%///// SMARTY AUTH /////%,\%///// SMARTY AUTH /////% {
/.*\(AuthorizationLevel::AULE_[A-Z]\{1,\}\).*/{
s//$smarty->hasAccess($params,\1);/
x
}
d
}
/RoleContextAuthorizations::smartyAuth($auth)/x
The first line searches for the start and end marker, using \% to change the delimiter to %. There's then a group of actions in braces. The second line searches for the authorization level and starts a second group of actions. The substitute command replaces the line with the desired output line. The x swaps the pattern space and the hold space, copying the desired output line to the hold space (and copying the empty hold space to the pattern space — it's x for eXchange pattern and hold spaces). This has saved the AuthorizationLevel information. The inner block ends; the outer block deletes the line and continues the execution. Note that there's no need to escape the $ symbol most of the time — it would matter if it was at the end of a pattern (there's a difference between /a\$/ and /a$/, but no difference between /b$c/ and /b\$c/).
The last line then looks for the RoleContextAuthorizations line and swaps it with the hold space. Everything else is just let through.
Given a data file containing:
Gibberish
Rhubarb
///// SMARTY AUTH /////
$auth['model'] = isset($params['model']) ? $params['model'] : null;
$auth['requiredLevel'] = isset($params['requiredlevel']) ? $params['requiredlevel'] : null;
$auth['baseAuthorizationLevel'] = isset($params['_authorizationlevel']) ? $params['_authorizationlevel'] : null;
$auth['defaultRequiredLevel'] = AuthorizationLevel::AULE_WRITE;
$auth['baseModel'] = $smarty->getTemplateVars('model');
///// SMARTY AUTH /////
More gibberish
More rhubarb - it is good with strawberries, especially in yoghurt
RoleContextAuthorizations::smartyAuth($auth);
Trailing gibbets — ugh; worse are trailing giblets
Finish - EOF
The output from sed -f script.sed data is:
$ sed -f script.sed data
Gibberish
Rhubarb
More gibberish
More rhubarb - it is good with strawberries, especially in yoghurt
$smarty->hasAccess($params,AuthorizationLevel::AULE_WRITE);
Trailing gibbets — ugh; worse are trailing giblets
Finish - EOF
$
I think that's what was wanted.
You can convert the file of sed script into a single line of gibberish, but that's left as an exercise for the reader — it isn't very hard, but GNU sed and BSD (macOS) sed have different rules for when you need semicolons as part of a single line command; you were warned. There are also differences in the rules for the -i option between the GNU and BSD variants of sed.
If you have to preserve some portions of the RoleContextAuthorizations::smartyAuth line, you have to work harder, but it can probably be done. For example, you can add the hold space to the current pattern space with the G command, and then edit the information into the right places. It is simplest if every place the line occurs needs to look the same apart from the AULE_XYZ string — that's what I've assumed here.
Also, note that using x rather than h or g is lazy — but doesn't matter if there's only one RoleContextAuthorizations::smartyAuth line. Using the alternatives would mean that if a file has multiple RoleContextAuthorizations::smartyAuth lines, then you'd be able to make the same substitution in each, unless there's another ///// SMARTY AUTH ///// in the file.
Related
I have a string that represents multiple DNs for Active Directory but has been separated by commas instead of ;
The String:
CN=Admins,ou=App1,ou=groups,dc=pkldap,dc=internal,
CN=Auditors,ou=App1,ou=groups,dc=pkldap,dc=internal,
CN=Operators,ou=App2,ou=groups,dc=pkldap,dc=internal
I am trying to write a regex that will match on both ou=App1 and not the ou=App2 but then also make the , after dc=internal become a ;
Is this possible?
The result would be:
CN=Admins,ou=App1,ou=groups,dc=pkldap,dc=internal;
CN=Auditors,ou=App1,ou=groups,dc=pkldap,dc=internal;
Using #strip and #sub to Clean Up Your LDIF Data
Really, the "correct" answer would be to get valid LDIF in the first place, and then parse it as such with a gem like Net::LDAP. However, the changes you want to your existing file are fairly trivial. For example, we'll start by assigning the String data from your question to a variable named ldif using a here-document literal:
ldif = <<~'LDIF'
CN=Admins,ou=App1,ou=groups,dc=pkldap,dc=internal,
CN=Auditors,ou=App1,ou=groups,dc=pkldap,dc=internal,
CN=Operators,ou=App2,ou=groups,dc=pkldap,dc=internal
LDIF
You can now modify and match the lines from the String that you want with String#each_line to iterate, and String#gsub and a Regexp lookahead assertion to find and collect the lines you want using Array#select on the output from #each_line, and storing the results into a matching_apps Array.
This all sounds much more complicated than it is. Consider the following method chain, which is really just a one-liner wrapped for readability:
matching_apps =
ldif.each_line.select { _1.match? /ou=App1(?=[,;]?$?)/ }
.map { _1.strip.sub /[,;]$/, ";" }
#=>
["CN=Admins,ou=App1,ou=groups,dc=pkldap,dc=internal;",
"CN=Auditors,ou=App1,ou=groups,dc=pkldap,dc=internal;"]
The use of String#strip and String#sub will help to ensure that all lines are normalized the way you want, including the trailing semicolons. However, this is likely to cause problems in subsequent steps, so I'd probably recommend removing those trailing semicolons as well.
Note: You can stop reading here if you just want to solve your immediate question as originally posted. The rest of the answer covers additional considerations related to data normalization, and provides some examples on how and why you might want to strip the semicolons as well.
Why and How to Normalize without Semicolons
You can replace the final substitution from #sub with an empty String (e.g. "") to remove the trailing semicolons (if present). Normalizing without the semicolons now may save you the trouble of having to clean up those lines again later when you iterate over the Array of results stored in matching_apps from Array#select.
For example, if you need to rejoin lines with commas, interpolate the lines within other String objects in subsequent steps, or do anything where those stored semicolons may be an unexpected surprise it's better to deal with it sooner rather than later. If you really need the trailing semicolons, it's very easy to use String#concat or other forms of String interpolation to add them back, but having unexpected characters in a String can be a source of unexpected bugs that are best avoided unless you're sure you'll always need that semicolon at the end.
Example 1: Output Where Semicolons Might be Unexpected
For example, suppose you want to use the results to format output for a command-line client where a trailing semicolon wouldn't be expected. The following works nicely because the semicolons are already stripped:
matching_apps =
ldif.each_line.select { _1.match? /ou=App1(?=[,;]?$?)/ }
.map { _1.strip.sub /[,;]$/, "" }
printf "Make the following calls:\n\n"
matching_apps.each_with_index do |dn, idx|
puts %(#{idx.succ}. ldapsearch -D '#{dn}' [opts])
end
This would print out:
Make the following calls:
1. ldapsearch -D 'CN=Admins,ou=App1,ou=groups,dc=pkldap,dc=internal' [opts]
2. ldapsearch -D 'CN=Auditors,ou=App1,ou=groups,dc=pkldap,dc=internal' [opts]
without having to first strip any trailing semicolons that might not work with the printed command, tool, or other output.
Examples of Rejoining with Commas and Semicolons
On the other hand, you can just as easily rejoin the Array elements with a comma or semicolon if you want. Consider the following two examples:
matching_apps.join ", "
#=> "CN=Admins,ou=App1,ou=groups,dc=pkldap,dc=internal, CN=Auditors,ou=App1,ou=groups,dc=pkldap,dc=internal"
p format("(%s)", matching_apps.join("; "))
#=> "(CN=Admins,ou=App1,ou=groups,dc=pkldap,dc=internal; CN=Auditors,ou=App1,ou=groups,dc=pkldap,dc=internal)"
Keep Flexibility in Mind
If the String objects in your Array still had the trailing semicolons, you'd have to do something about them. So, unless you already know what you plan to do with each String, and whether or not the semicolons will be needed, it's probably best to keep them out of matching_apps in the first place to optimize for flexibility. That's just an opinion, to be sure, but definitely one worth considering.
I am trying to build a connection string that requires pulling 3 IP addresses from another config file. When I get those values, I need to replace the port on each. I plan to replace each port using simple Bash find and replace ${string/pattern/replacement} but my problem is I'm stuck on the best way to parse the pattern out of the IP.
Here is what I have so far:
myFile.config:
ip.1=ip-ip-1-address:1234:5678
ip.2=ip-ip-2-address:1234:5678
ip.3=ip-ip-3-address:1234:5678
Copying some other simple process, I found I can pull the value of each IP like this:
IP1=`grep "ip.1=" /path/to/conf/myFile.config | awk -F "=" '{print $2}'`
which gives me ip.1=ip-ip-1-address:1234:5678. However, I need to replace 1234:5678 with 6543 for example. I've been looking around and I found this awesome answer that detailed using Bash prefix substitution but that relies on knowing the parameter. for example, I would have to do it this way:
test=${ip1##ip-ip-1-address:}
which results in $test being 1234:5678. That's fine but maybe I don't know the IP address as the parameter, so I'm back to considering regex unless there's a way for me to use * as the parameter or something, but I have been unsuccessful so far. For regex, I have tried a bunch such as test=${ip1/(?<=:).*/}.
Note that ${ip1/(?<=:).*/} you tried is an example of string manipulation syntax that does not support regex, only specific patterns.
You seem to want
x='ip.1=ip-ip-1-address:1234:5678'
echo "${x%%:*}:6543" # => ip.1=ip-ip-1-address:6543
The ${x%%:*} takes the value of x and removes all chars from the end till the first : including it. :6543 is added to the result of this manipulation using "${x%%:*}:6543".
To extract that value, you may also use
awk '/^ip\.1=/{sub("^[^:]+:", "");print}' myFile.config
The awk command finds lines starting with ip.1= and then removes all text from the start till the first colon including the colon and only prints these values.
Friends:
I have to process a CSV file, using Perl language and produce an Excel as output, using the Excel::Writer::XSLX module. This is not a homework but a real life problem, where I cannot download whichever Perl version (actually, I need to use Perl 5.6), or whichever Perl module (I have a limited set of them). My OS is UNIX. I can also use (embedding in Perl) ksh and csh (with some limitation, as I have found so far). Please, limit your answers to the tools I have available. Thanks in advance!
Even though I am not a Perl developer, but coming from other languages, I have already done my work. However, the customer is asking for extra processing where I am getting stuck on.
1) The stones in the road I found are coming from two sides: from Perl and from Excel particular styles of processing data. I already found a workaround to handle the Excel, but -as mentioned in the subject- I have difficulties while processing zeroes found in CSV input file. To handle the Excel, I am using the '0 way which is the final way for data representation that Excel seems to have while using the # formatting style.
2) Scenario:
I need to catch standalone zeroes which might be present in whichever line / column / cell of the CSV input file and put them as such (as zeroes) in the Excel output file.
I will go directly to the point of my question to avoid loosing your valuable time. I am providing more details after my question:
Research and question:
I tried to use Perl regex to find standalone "0" and replace them by whichever string, planning to replace them back to "0" at the end of processing.
perl -p -i -e 's/\b0\b/string/g' myfile.csv`
and
perl -i -ple 's/\b0\b/string/g' myfile.csv
Are working; but only from command line. They aren't working when I call them from the Perl script as follows:
system("perl -i -ple 's/\b0\b/string/g' myfile.csv")
Do not know why... I have already tried using exec and eval, instead of system, with the same results.
Note that I have a ton of regex that work perfectly with the same structure, such as the following:
system("perl -i -ple 's/input/output/g' myfile.csv")
I have also tried using backticks and qx//, without success. Note that qx// and backticks have not the same behavior, since qx// is complaining about the boundaries \b because of the forward slash.
I have tried using sed -i, but my System is rejecting -i as invalid flag (do not know if this happens in all UNIX, but at least happens in the one at work. However is accepting perl -i).
I have tried embedding awk (which is working from command line), in this way:
system `awk -F ',' -v OFS=',' '$1 == \"0\" { $1 = "string" }1' myfile.csv > myfile_copy.csv
But this works only for the first column (in command line) and, other than having the disadvantage of having extra copy file, Perl is complaining for > redirection, assuming it as "greater than"...
system(q#awk 'BEGIN{FS=OFS=",";split("1 2 3 4 5",A," ") } { for(i in A)sub(0,"string",$A[i] ) }1' myfile.csv#);
This awk is working from command line, but only 5 columns. But not in Perl using #.
All the combinations of exec and eval have also been tested without success.
I have also tried passing to system each one of the awk components, as arguments, separated by commas, but did not find any valid way to pass the redirector (>), since Perl is rejecting it because of the mentioned reason.
Using another approach, I noticed that the "standalone zeroes" seem to be "swallowed" by the Text::CSV module, thus, I get rid off it, and turned back to a traditional looping in csv line by line and a spliter for commas, preserving the zeroes in that way. However I found the "mystery" of isdual in Perl, and because of the limitation of modules I have, I cannot use the Dumper. Then, I also explored the guts of binaries in Perl and tried the $x ^ $x, which was deprecated since version 5.22 but valid till that version (I said mine is 5.6). This is useful to catch numbers vs strings. However, while if( $x ^ $x ) returns TRUE for strings, if( !( $x ^ $x ) ) does not returns TRUE when $x = 0. [UPDATE: I tried this in a devoted Perl script, just for this purpose, and it is working. I believe that my probable wrong conclusion ("not returning TRUE") was obtained when I did not still realize that Text::CSV was swallowing my zeroes. Doing new tests...].
I will appreciate very much your help!
MORE DETAILS ON MY REQUIREMENTS:
1) This is a dynamic report coming from a database which is handover to me and I pickup programmatically from a folder. Dynamic means that it might have whichever amount of tables, whichever amount of columns in each table, whichever names as column headers, whichever amount of rows in each table.
2) I do not know, and cannot know, the column names, because they vary from report to report. So, I cannot be guided by column names.
A sample input:
Alfa,Alfa1,Beta,Gamma,Delta,Delta1,Epsilon,Dseta,Heta,Zeta,Iota,Kappa
0,J5,alfa,0,111.33,124.45,0,0,456.85,234.56,798.43,330000.00
M1,0,X888,ZZ,222.44,111.33,12.24,45.67,0,234.56,0,975.33
3) Input Explanation
a) This is an example of a random report with 12 columns and 3 rows. Fist row is header.
b) I call "standalone zeroes" those "clean" zeroes which are coming in the CSV file, from second row onwards, between commas, like 0, (if the case is the first position in the row) or like ,0, in subsequent positions.
c) In the second row of the example you can read, from the beginning of the row: 0,J5,alfa,0, which in this particular case, are "words" or "strings". In this case, 4 names (note that two of them are zeroes, which required to be treated as strings). Thus, we have a 4 names-columns example (Alfa,Alfa1,Beta,Gamma are headers for those columns, but only in this scenario). From that point onwards, in the second row, you can see floating point (*.00) numbers and, among them, you can see 2 zeroes, which are numbers. Finally, in the third line, you can read M1,0,X888,Z, which are the names for the first 4 columns. Note, please, that the 4th column in the second row has 0 as name, while the 4th column in the third row has ZZ as name.
Summary: as a general picture, I have a table-report divided in 2 parts, from left to right: 4 columns for names, and 8 columns for numbers.
Always the first M columns are names and the last N columns are numbers.
- It is unknown which number is M: which amount of columns devoted for words / strings I will receive.
- It is unknown which number is N: which amount of columns devoted for numbers I will receive.
- It is KNOWN that, after the M amount of columns ends, always starts N, and this is constant for all the rows.
I have done a quick research on Perl boundaries for regex ( \b ), and I have not found any relevant information regarding if it applies or not in Perl 5.6.
However, since you are using and old Perl version, try the traditional UNIX / Linux style (I mean, what Perl inherits from Shell), like this:
system("perl -i -ple 's/^0/string/g' myfile.csv");
The previous regex should do the work doing the change at the start of the each line in your CSV file, if matches.
Or, maybe better (if you have those "standalone" zeroes, and want avoid any unwanted change in some "leading zeroes" string):
system("perl -i -ple 's/^0,/string,/g' myfile.csv");
[Note that I have added the comma, after the zero; and, of course, after the string].
Note that the first regex should work; the second one is just a "caveat", to be cautious.
I am trying to search a text file that will return a result if more than one word is found in that line. I don't see this explained in the documentation and I have tried various loops with no success.
What I would like to do is something similar to this:
$read(name.txt, s, word1|word2|word3)
or even something like this:
$read(name.txt, w, word1*|*word2*|*word3)
I don't know RegEx that well so I'm assuming this can be done with that but I don't know how to do that.
The documentation in the client self is good but I also recommend this site: http://en.wikichip.org/wiki/mirc. And with your problem there is a nice article : http://en.wikichip.org/wiki/mirc/text_files
All the info is taken from there. So credits to wikichip.
alias testForString {
while ($read(file.txt, nw, *test*, $calc($readn + 1))) {
var %line = $v1
; you can add your own words in the regex, seperate them with a pipe (|)
noop $regex(%line,/(word1|word2|word3|test)/))
echo -a Amount of results: $regml(0)
}
}
$readn is an identifier that returns the line that $read() matched. It is used to start searching for the pattern on the next line. Which is in this case test.
In the code above, $readn starts at 0. We use $calc() to start at line 1. Every match $read() will start searching on the next line. When no more matches are after the line specified $read will return $null - terminating the loop.
The w switch is used to use a wildcard in your search
The n switch prevents evaluating the text it reads as if it was mSL code. In almost EVERY case you must use the n switch. Except if you really need it. Improper use of the $read() identifier without the 'n' switch could leave your script highly vulnerable.
The result is stored in a variable named %line to use it later in case you need it.
After that we use a noop to execute a regex to match your needs. In this case you can use $regml(0) to find the amount of matches which are specified in your regex search. Using an if-statement you can see if there are two or more matches.
Hope you find this helpful, if there's anything unclear, I will try to explain it better.
EDIT
#cp022
I can't comment, so I'll post my comment here, so how does that help in any way to read content from a text file?
I have a csv file with embedded newlines characters.
What I'd like to do is re-write each line with a different EOL character to make parsing by other CSV reader's simpler.
To that end, I know each new line starts with the regular expression /\n"\d+","/ -- which is a newline, quote, some digits, another quote, a comma, then another quote.
I may be wrong, but sed, awk, and most other tools expect a newline at the end. Is there a linux tool that doesn't?
My next idea is to use awk to keep reading lines and push them to a buffer until it finds one starting with the expression above--then it will write it out.
Okay, let's see if I understand what you want correctly. Given a csv file like
"123","foo
bar","baz"
"234","quxqux"
"345","xy
zz
y","asd"
you would like it transformed into something like
"123","fooNEWLINEbar","baz"
"234","quxqux"
"345","xyNEWLINEzzNEWLINEy","asd"
Then the best I can whip up on short notice (without going back to the sed docs properly prepared to maintain sanity) is this sed script:
/^"[0-9]\+","/ !H
/^"[0-9]\+","/ {
x
s/\n/NEWLINE/g
p
x
h
}
$ {
x
s/\n/NEWLINE/g
p
x
h
}
to be used, if the code is in file foo.sed, like this:
sed -n -f foo.sed foo.csv
Explanation:
This goes into some of the lesser-used features of sed, so I'll briefly explain two basic mechanisms:
Pattern ranges
A sed command of the form
/regex1/ command
will apply command to all lines that regex1 can match. For example,
/^1/ s/2/3/g
will replace 2s with 3s in all lines that begin with 1. ! inverts the match, so
/^1/ !s/2/3/g
replaces 2s with 3s in all lines that don't start with 1. Commands can be grouped with {}
The hold buffer
This is one of the lesser-known but very powerful features of sed. Most sed commands work on the pattern space. The pattern space is where new lines of input are written so commands can work on them, so if you're treating lines individually, this mechanic is transparent to you. In addition, sed has a hold buffer where you can hold on to previous input because you'll need it later. There are only a few commands that work on the hold buffer; three of them are of interest to us: h, H and x. h copies the current contents of the pattern space (usually the line of input that was just written there) to the hold buffer. H appends the pattern space to the hold buffer. x swaps the contents of the pattern space and hold buffer.
Taking the script block by block:
/^"[0-9]\+","/ !H
This applies to all lines that don't start with "number"," the H command. This means that those lines are appended to the hold buffer.
/^"[0-9]\+","/ {
x
s/\n/NEWLINE/g
p
x
h
}
This applies to all lines that do start with "number"," the block of commands. That is:
swap the pattern space and hold buffer
Replace newlines in the pattern space (that used to be the hold buffer) with NEWLINE
Print that stuff
swap back (pattern space is now the new input line again)
Write the pattern space to the hold buffer, overwriting what was there before
Lastly,
$ {
x
s/\n/NEWLINE/g
p
x
h
}
does the same thing for the last line of input, so the last logical line of the CSV is not lost.
This means that all parts of a "logical line" of the CSV are assembled in the hold buffer, and when the start of the next one is detected, the assembled line is mangled appropriately and printed.