How to get method/function in a string by using regex - regex

Question

I trying to get arguments from function in the string.
Argument possible to contains:
Example
Placeholder:
{{request.expires_in}}
//can match regex: \{\{[a-zA-z0-9\.\-\_]\}\}
function
#func_compare('string1','string2',1234)
Others:
dERzUxOfnj49g/kCGLR3vhzBOTLwEMgrpa1/MCBpXQR2NIFV1yjraGVZLkujG63J0joj+TvNocjpJSQq2TpPRzLfCSZADcjmbkBkphIpsT8=
//Any string except brackets
Case
Below is the sample case I working with.
Content:
#func_compare('string1',#func_test(2),1234),'Y-m-d H:i:s',#func_strtotime({{request.expires_in}} - 300)
Regex using:
(?<=#func_compare\().*[^\(](?=\))
I expect will get
'string1',#func_test(2),1234
But what matched from the regex now is
'string1',#func_test(2),1234),'Y-m-d H:i:s',#func_strtotime({{request.expires_in}} - 300
Anyone know how to get the arguments in between the #func_strtotime brackets. I will appreciate any response.

Answer 1

Would you please try:
(?<=#func_compare\().*?(?:\(.*?\).*?)?(?=\))
which will work for both cases.
[Explanation of the regex]
.*?(?:\(.*?\).*?)?(?=\))
.*? the shortest match not to overrun the next pattern
(?:\(.*?\).*?)? a group of substring which includes a pair of parens followed by another substring of length 0 or longer
(?=\)) positive lookahead for the right paren

Answer 2

You'll get the result using recursive regex:
(?<=#func_compare\()([^()]*\((?:.*?\)|(?1))*)[^()]*(?=\))
Demo & explanation