How to serialize structure data in C++? - c++

Question

I was asked in an interview to serialize data (so it could be stored in a buffer and sent over some network). This is what I came up with -
struct AMG_ANGLES {
float yaw;
float pitch;
float roll;
};
char b[sizeof(struct AMG_ANGLES)];
char* encode(struct AMG_ANGLES *a)
{
std::memcpy(b, &a, sizeof(struct AMG_ANGLES));
return b;
}
void decode(char* data)
{
// check endianess
AMG_ANGLES *tmp; //Re-make the struct
std::memcpy(&tmp, data, sizeof(tmp));
}
Is this correct? Can anyone give alternate designs? I did not get callback so I'm just trying to learn what I could have improved.

Answer 1

Is this correct?
Most likely, no.
The point of serialization is to convert the data into a form that is completely platform independent - e.g. does not rely on things like endianess or if a float is an IEEE 754 or something very different. This requires:
a) strict agreement on the intended format - e.g. if it's some kind of text (XML, JSON, CSV, ...) or if it's "raw binary" with explicit definitions of the meaning of each individual byte (e.g. like maybe "byte 1 is always the lowest 8 bits of the significand").
b) correct conversion to whatever the intended format is (e.g. maybe like ensuring that byte 1 is always the lowest 8 bits of the significand regardless of any/all platform differences)
However; it is at least technically possible that the code is not supposed to be portable and the specification ("agreement on the intended format") happens to match what you ended up with for the only platform that the code is designed for; and therefore it's at least technically possible that the code is correct.

Answer 2

There could be lots of improvements, but instead of telling all of them I suggest you to examine into cereal . It is widely used serialization/deserialization library, so lots of keypoints are thought.
Some of my thoughts are :
Your code depends on hardware which the program running on because of alignment and endianness. So the serialized data is not portable and compiler dependant.
char* encode(struct AMG_ANGLES *a) function returns char*, it is possibly leaked. To prevent the issue, let std::unique_ptr<T> decide its lifetime or wrap it with a class. But get rid of pointers somehow.
Templatize your serialize/deserialize operations. Otherwise, you could write same functions for other types.
template<typename T>
char* encode( T* a ) // I leave signature as is, just to demonstrate
{
std::memcpy( b , &a , sizeof(T) );
return b;
}
If the format is up to you, it is better to prefer human readable ones rather than binary archiving such as JSON, XML

Answer 3

can someone give alternate design in C?
The "standard" way would be to use printf and scanf to create an ascii representation of the data:
#include <limits.h>
#include <math.h>
#include <stdio.h>
#include <assert.h>
#include <float.h>
struct AMG_ANGLES {
float yaw;
float pitch;
float roll;
};
// declare a buffer at least this long to be sure encode works properly
#define AMG_ANGLES_BUFSIZE ( \
3 * ( /* 3 floats */ \
2 + /* digit and dot */ \
FLT_DECIMAL_DIG - 1 + /* digits after dot */ \
4 /* the 'e±dd' part */ \
) \
+ 2 /* spaces */ \
+ 1 /* zero terminating character */ \
)
int encode(char *dest, size_t destsize, const struct AMG_ANGLES *a) {
return snprintf(dest, destsize, "%.*e %.*e %.*e",
FLT_DECIMAL_DIG - 1, a->yaw,
FLT_DECIMAL_DIG - 1, a->pitch,
FLT_DECIMAL_DIG - 1, a->roll);
// my pedantic self wants to add `assert(snprintf_ret < AMG_ANGLES_BUFSIZE);`
}
int decode(struct AMG_ANGLES *dest, const char *data) {
return sscanf(data, "%e %e %e", &dest->yaw, &dest->pitch, &dest->roll) == 3 ? 0 : -1;
}
int main() {
char buf[AMG_ANGLES_BUFSIZE];
const struct AMG_ANGLES a = { FLT_MIN, FLT_MAX, FLT_MIN };
encode(buf, sizeof(buf), &a);
struct AMG_ANGLES b;
const int decoderet = decode(&b, buf);
assert(decoderet == 0);
assert(b.yaw == FLT_MIN);
assert(b.pitch == FLT_MAX);
assert(b.roll == FLT_MIN);
}
However in bare-metal embedded I try not to use scanf - it's a big function with some dependencies. So it's better to call strtof itself, but it needs some thinking:
int decode2(struct AMG_ANGLES *dest, const char *data) {
errno = 0;
char *endptr = NULL;
dest->yaw = strtof(data, &endptr);
if (errno != 0 || endptr == data) return -1;
if (*endptr != ' ') return -1;
data = endptr + 1;
dest->pitch = strtof(data, &endptr);
if (errno != 0 || endptr == data) return -1;
if (*endptr != ' ') return -1;
data = endptr + 1;
dest->roll = strtof(data, &endptr);
if (errno != 0 || endptr == data) return -1;
if (*endptr != '\0') return -1;
return 0;
}
or with removed code duplication:
int decode2(struct AMG_ANGLES *dest, const char *data) {
// array of pointers to floats to fill
float * const dests[] = { &dest->yaw, &dest->pitch, &dest->roll };
const size_t dests_cnt = sizeof(dests)/sizeof(*dests);
errno = 0;
for (int i = 0; i < dests_cnt; ++i) {
char *endptr = NULL;
*dests[i] = strtof(data, &endptr);
if (errno != 0 || endptr == data) return -1;
// space separates numbers, last number is followed by zero
const char should_be_char = i != dests_cnt - 1 ? ' ' : '\0';
if (*endptr != should_be_char) return -1;
data = endptr + 1;
}
return 0;
}
I needed to use some google and re-read chux answers to properly recall how to use FLT_DECIMAL_DIG in printf to print floats, that's most probably because I rarely worked with floats.

Answer 4

Keep in mind that, when using memcpy different architectures and different compilers will apply padding and endianness differently. To prevent the padding of the struct you could use an attribute provided by GCC
__attribute__ ((packed))
Nevertheless, this does not protect you from alternating endiannes.
The code for serializing and deserializing using memcpy might look like this:
#include <memory>
#include <cstring>
struct __attribute__((packed)) AMG_ANGLES {
float yaw;
float pitch;
float roll;
};
//The buffer is expected to be the same size as the T
template<typename T>
int serialize(const T &data,const std::unique_ptr<char[]> &buffer){
std::memcpy(buffer.get(), &data, sizeof(T));
return sizeof(T);
}
//The buffer is expected to be the same size as the ReturnType
template<typename ReturnType>
ReturnType deserialize(const std::unique_ptr<char[]> &buffer){
ReturnType tmp;
std::memcpy(&tmp, buffer.get(), sizeof(ReturnType));
return tmp;
}
int main()
{
struct AMG_ANGLES angles = {1.2, 1.3, 1.0};
std::unique_ptr<char[]> buffer(new char[sizeof(struct AMG_ANGLES)]);
int size = serialize(angles, buffer);
struct AMG_ANGLES angles_serialized = deserialize<AMG_ANGLES>(buffer);
}

Answer 5

It's better to make some kinds of class like std::stringstream..
std::stringstream is not good to save binary data but it works the same way you want.
so I could make some example that works with std::stringstream..
This code implement only for serialization but it also add code for deserialization.
// C++11
template < typename T, typename decltype(std::declval<T>().to_string())* = nullptr>
std::ostream& operator<< (std::ostream& stream, T&& val)
{
auto str = val.to_string();
std::operator <<(stream, str);
return stream;
}
struct AMG_ANGLES {
float yaw;
float pitch;
float roll;
std::string to_string() const
{
std::stringstream stream;
stream << yaw << pitch << roll;
return stream.str();
}
};
void Test()
{
std::stringstream stream;
stream << 3 << "Hello world" << AMG_ANGLES{1.f, 2.f, 3.f };
}