Evaluating a string against a pattern with RegExp in Flutter - regex

I'm trying to evaluate a string against a set list of parameters with RegExp in Flutter. For example, the string must contain at least:
One capital letter
One lowercase letter
One number from 0-9
One special character, such as $ or !
This is basically for a password entry field of an application. I have set things up, firstly using validateStructure as follows:
abstract class PasswordValidator {
bool validateStructure(String value);
}
Then, I have used the RegExp function as follows:
class PasswordValidatorSpecial implements PasswordValidator {
bool validateStructure(String value) {
String pattern =
r'^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[!##\$&*~£]).{8,}$';
RegExp regEx = new RegExp(pattern);
return regEx.hasMatch(value);
}
}
This does work well, in a sense that when I pass a string/password through it, it does tell me if at least one of the criteria is not met. However, what I would like to do is for the output to be more specific, telling me which of those criteria isn't met.
For example, if the password were to have everything but a number (from 0-9) I would want to be able to get the output to specifically say that a number is missing, but everything else is present.
How would I adapt my code to be able to do that? I thought perhaps by using conditional 'if' statement, although I don't know how that would work. Thanks!

That's right, you can use RegExr to check your RegExp, separate each part and use them separately to have a custom error. Also instead of return a bool value, you can return a String value, such as the following function:
String validateStructure(String value) {
String patternUpperCaseCharacters = r'^(?=.*?[A-Z])';
String patternLowerCaseCharacters = r'^(?=.*?[a-z])';
String patternNumbers = r'^(?=.*?[0-9])';
String patternSpecialCharacters = r'^(?=.*?[!##\$&*~£])';
RegExp regEx = new RegExp(patternUpperCaseCharacters);
if (regEx.hasMatch(value)) {
regEx = new RegExp(patternLowerCaseCharacters);
if (regEx.hasMatch(value)) {
return "More errors";
} else {
return "You need at least one lowercase letter";
}
} else {
return "You need at least one capital letter";
}
}

Related

regx to check + in entire string using javascript or jquery

i am trying to validate input string to chech whether it contains '+' symbol anywhere in the string. i used for of loop but didnt get what is exprected.
const isMobileValidWithoutPlus = funcLib.isValidMobileWithoutPlus(mobileNumber);
isValidMobileWithoutPlus(mobileNumber) {
if (!mobileNumber) {
return false;
}
const checkRegex = new RegExp('\\+?\\d+');
return checkRegex.test(mobileNumber);
}
but able to get desired out.
The regex for this would be
const rgx = new RegExp(/\+/gm);
Your regular expression checks if you have a string that can either start with + or not, and is followed by one or more numbers. But you're saying you want to just check if there's a "+" anywhere in the number. For that you can use this regex above.
Also, do you need to use a regex?
You can do this using indexOf on a string if using regex is not a must.
let number = "+001234";
function hasPlus(number) {
return number.indexOf('+') !== -1;
}
Regular expressions are generally useful when you don't have one specific string that you're looking for, or when you want to find all the apparitions of a regex in a longer string. In your case, checking if a string contains "+", it isn't necessary to use them.

check if certain char sequences exists in a string builder and remove it

in java, I am trying to find if a given string has one of the many sub strings using multiple ORs in a single If condition and if any of the sub string exists, remove it. I am not sure how to do it. Also, this string search needs to be case insensitive.
Here is the sample code
if (inputString contains any of the subStrings i.e. "_LOCATION" OR "_MANAGEMENT" Or "_ZIPCODE")
{
remove the subString from inPutString
}
Ex: Given the string - "STATE_CAPITAL_LOCATION_MANAGEMENT_PHONE_EMAIL_zipcode"
Resulting string should be - "STATE_CAPITAL_PHONE_EMAIL"
What is the best way to do it.
Thanks
Using separate If statements makes more easier.
Try this code:
String a="STATE_CAPITAL_LOCATION_MANAGEMENT_PHONE_EMAIL_zipcode";
if(a.contains("_LOCATION"))// relace with your string
{
a=a.replace("_LOCATION","");
System.out.println(a);
}
if(a.contains("_MANAGEMENT"))// relace with your string
{
a=a.replace("_MANAGEMENT","");
System.out.println(a);
}
// .....

Regex to filter strings

I need to filter strings based on two requirements
1) they must start with "city_date"
2) they should not have "metro" anywhere in the string.
This need to be done in just one check.
To start I know it should be like this but dont know hoe to eliminate strings with "metro"
string pattern = "city_date_"
Added: I need to use the regex for a SQL LIKE statement. hence i need it in a string.
Use a negative lookahead assertion (I don't know if this is supported in your regex lib)
string pattern = "^city_date(?!.*metro)"
I also added an anchor ^ at the start, that will match the start of the string.
The negative lookahead assertion (?!.*metro) will fail, if there is the string "metro" somewhere ahead.
Regular expressions are usually far more expensive than direct comparisons. If direct comparisons can easily express the requirements, use them. This problem doesn't need the overhead of a regular expression. Just write the code:
std::string str = /* whatever */
const std::string head = "city_date";
const std::string exclude = "metro";
if (str.compare(head, 0, head.size) == 0 && str.find(exclude) == std::string::npos) {
// process valid string
}
by using javascript
input="contains the string your matching"
var pattern=/^city_date/g;
if(pattern.test(input)) // to match city_data at the begining
{
var patt=/metro/g;
if(patt.test(input)) return "false";
else return input; //matched string without metro
}
else
return "false"; //unable to match city_data

Want to Encode text during Regex.Replace call

I have a regex call that I need help with.
I haven't posted my regex, because it is not relevant here.
What I want to be able to do is, during the Replace, I also want to modify the ${test} portion by doing a Html.Encode on the entire text that is effecting the regex.
Basically, wrap the entire text that is within the range of the regex with the bold tag, but also Html.Encode the text inbetween the bold tag.
RegexOptions regexOptions = RegexOptions.Compiled | RegexOptions.IgnoreCase;
text = Regex.Replace(text, regexBold, #"<b>${text}</b>", regexOptions);
There is an incredibly easy way of doing this (in .net). Its called a MatchEvaluator and it lets you do all sorts of cool find and replace. Essentially you just feed the Regex.Replace method the method name of a method that returns a string and takes in a Match object as its only parameter. Do whatever makes sense for your particular match (html encode) and the string you return will replace the entire text of the match in the input string.
Example: Lets say you wanted to find all the places where there are two numbers being added (in text) and you want to replace the expression with the actual number. You can't do that with a strict regex approach, but you can when you throw in a MatchEvaluator it becomes easy.
public void Stuff()
{
string pattern = #"(?<firstNumber>\d+)\s*(?<operator>[*+-/])\s*(?<secondNumber>\d+)";
string input = "something something 123 + 456 blah blah 100 - 55";
string output = Regex.Replace(input, pattern, MatchMath);
//output will be "something something 579 blah blah 45"
}
private static string MatchMath(Match match)
{
try
{
double first = double.Parse(match.Groups["firstNumber"].Value);
double second = double.Parse(match.Groups["secondNumber"].Value);
switch (match.Groups["operator"].Value)
{
case "*":
return (first * second).ToString();
case "+":
return (first + second).ToString();
case "-":
return (first - second).ToString();
case "/":
return (first / second).ToString();
}
}
catch { }
return "NaN";
}
Find out more at http://msdn.microsoft.com/en-us/library/system.text.regularexpressions.matchevaluator.aspx
Don't use Regex.Replace in this case... use..
foreach(Match in Regex.Matches(...))
{
//do your stuff here
}
Heres an implementation of this I've used to pick out special replace strings from content and localize them.
protected string FindAndTranslateIn(string content)
{
return Regex.Replace(content, #"\{\^(.+?);(.+?)?}", new MatchEvaluator(TranslateHandler), RegexOptions.IgnoreCase);
}
public string TranslateHandler(Match m)
{
if (m.Success)
{
string key = m.Groups[1].Value;
key = FindAndTranslateIn(key);
string def = string.Empty;
if (m.Groups.Count > 2)
{
def = m.Groups[2].Value;
if(def.Length > 1)
{
def = FindAndTranslateIn(def);
}
}
if (group == null)
{
return Translate(key, def);
}
else
{
return Translate(key, group, def);
}
}
return string.Empty;
}
From the match evaluator delegate you return everything you want replaced, so where I have returns you would have bold tags and an encode call, mine also supports recursion, so a little over complicated for your needs, but you can just pare down the example for your needs.
This is equivalent to doing an iteration over the collection of matches and doing parts of the replace methods job. It just saves you some code, and you get to use a fancy shmancy delegate.
If you do a Regex.Match, the resulting match objects group at the 0th index, is the subset of the intput that matched the regex.
you can use this to stitch in the bold tags and encode it there.
Can you fill in the code inside {} to add the bold tag, and encode the text?
I'm confused as to how to apply the changes to the entire text block AND replace the section in the text variable at the end.

Regex Rejecting matches because of Instr

What's the easiest way to do an "instring" type function with a regex? For example, how could I reject a whole string because of the presence of a single character such as :? For example:
this - okay
there:is - not okay because of :
More practically, how can I match the following string:
//foo/bar/baz[1]/ns:foo2/#attr/text()
For any node test on the xpath that doesn't include a namespace?
(/)?(/)([^:/]+)
Will match the node tests but includes the namespace prefix which makes it faulty.
I'm still not sure whether you just wanted to detect if the Xpath contains a namespace, or whether you want to remove the references to the namespace. So here's some sample code (in C#) that does both.
class Program
{
static void Main(string[] args)
{
string withNamespace = #"//foo/ns2:bar/baz[1]/ns:foo2/#attr/text()";
string withoutNamespace = #"//foo/bar/baz[1]/foo2/#attr/text()";
ShowStuff(withNamespace);
ShowStuff(withoutNamespace);
}
static void ShowStuff(string input)
{
Console.WriteLine("'{0}' does {1}contain namespaces", input, ContainsNamespace(input) ? "" : "not ");
Console.WriteLine("'{0}' without namespaces is '{1}'", input, StripNamespaces(input));
}
static bool ContainsNamespace(string input)
{
// a namspace must start with a character, but can have characters and numbers
// from that point on.
return Regex.IsMatch(input, #"/?\w[\w\d]+:\w[\w\d]+/?");
}
static string StripNamespaces(string input)
{
return Regex.Replace(input, #"(/?)\w[\w\d]+:(\w[\w\d]+)(/?)", "$1$2$3");
}
}
Hope that helps! Good luck.
Match on :? I think the question isn't clear enough, because the answer is so obvious:
if(Regex.Match(":", input)) // reject
You might want \w which is a "word" character. From javadocs, it is defined as [a-zA-Z_0-9], so if you don't want underscores either, that may not work....
I dont know regex syntax very well but could you not do:
[any alpha numeric]\*:[any alphanumeric]\*
I think something like that should work no?
Yeah, my question was not very clear. Here's a solution but rather than a single pass with a regex, I use a split and perform iteration. It works as well but isn't as elegant:
string xpath = "//foo/bar/baz[1]/ns:foo2/#attr/text()";
string[] nodetests = xpath.Split( new char[] { '/' } );
for (int i = 0; i < nodetests.Length; i++)
{
if (nodetests[i].Length > 0 && Regex.IsMatch( nodetests[i], #"^(\w|\[|\])+$" ))
{
// does not have a ":", we can manipulate it.
}
}
xpath = String.Join( "/", nodetests );