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I have the STRING - TX1234XT batch 44, 1111ABCDEF
TX1234XT (Can be different length)
batch 44 (number can be different length)
ABCDEF (can be a different length, but always have 1111 at the start)
What I need is to generate two columns:
BatchNumber Name
44 1111ABCDEF
1 1111SAMPLE
999 1111Example
Starting point:
First is done:
REGEXP_EXTRACT(reference, r'1111[a-zA-Z0-9_.+-]+') AS Name
Second
- REGEXP_REPLACE(REGEXP_EXTRACT(reference, r'batch [0-9_.+-]+'),r'batch ','') AS BatchNumber
SORTED ^_^
I don't really know Google Big Query, but if you want to extract the batch number and the value at the end, you could go with this regular expression:
/^.*?batch\s*(\d+),\s*(1111.+)$/
(\d+) will capture your batch id.
(1111.+) will capture the value starting with 1111.
Example here: https://regex101.com/r/SJXmIV/2
Related
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In a text with many lines in notepad++, some lines are unintentionally broken into the next line without an end point. I want to merge lines that are more than 10 characters long that do not end with a dot(.) with of regex. Also put a space between merged lines.
For example, the following text:
tttttttttt
aaaaaaaaaaaaaaaa
bbbbbbbbbbbbbbbbbb.
ccccccccccccccccc
dddddddddddddddddd.
Convert to:
tttttttttt
aaaaaaaaaaaaaaaa bbbbbbbbbbbbbbbbbb.
ccccccccccccccccc dddddddddddddddddd.
I also tried the following regex code but it didn't work:
[^\.]\n
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I am struggling through this date extraction. I have a date like this
("D("yyyy-mm-dd")).
I want to get this "yyyy-mm-dd" and I cannot strip ("D(") this also because I have this format in other places so I tried like this
first searching the string but I am not sure if I am on right track
eg. intabc = istrdate.SearchSubString("D(");
so please suggest how can I get this value.
Input is
"(D(YYYY-MM-DD))"
OUTPUT that I want
(YYYY-MM-DD)
What i have done(not correct way I think )
intabc = istrdate.SearchSubString("D(");
you can use substr() and string::erase() functions in c++98
string str = "\"D(\"yyyy-mm-dd\")";
string result = str.substr(3);
result.erase(result.end() - 1)
result.erase(result.end() - 1)
if you are using c++11 you can also use string::pop_back() method.
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I am designing a GUI in Matlab,
I have a folder called sth. It contains many files having same structure like,
filename_1_something.mat
filename_2_something.mat
In order to loop over filenames by selecting via index, I need to find a resulting string like this;
filename_%d_something.mat
So I don't need to read all the files in the dir. Two of the filenames are enough to compare strings and find the different char array item and change by %d.
Or anything different than this also appreciated.
using the regex provided by #rock321987 -
names = dir('*.mat');
num = length(names);
expression = '\w*_\d+_\w*\.mat';
for n = 1:num
str = names(n).name;
nameList{n} = regexp(str,expression,'match')
end
works on:
test_1_something.mat
test_10_something.mat
changing the regex to just \w*_\w*\.mat
works for
test_1.mat
1_test.mat
test_1_something.mat
test_10_something.mat
but also works for anything with an string joined by underscore .mat
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I have a text file with lots of sentences. These sentences can occur in patterns. How do I recognize these patterns?
For example:
i woke up in the morning
i went to school
i played football
i came back home
i woke up in the morning
i went to school
i played basketball
At this point I want the program to say that "I played football" should have appeared.
This task seems to little bit complicate,but you can try this simple code for understanding or if finds it useful you can further implement it::
//the sentences/input input String
String sampleString1="xyz";
String[] sampleString2=sampleString1.split(".");
for(int i=1;i<=sampleString2.length;i++){
//The pattern which you can specify to match with the sentence
if(sampleString2[i].substring(0, 14).equals(sampleString2[0].substring(0,16))){
//code to execute the matched sentence.
System.out.println("Sentence matching with pattern ::" + sampleString2[i]);
}
}
If the pattern to be matched is the first line of the sequence ,then try this code.
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If there is a string like this "abcdefghijklm.com 80 /abcdefgh.php" where the domainname followed by http port and the sub string is first 8 digits of the domain name always and followed by ".php" (the sub-string character will change to 6 OR 8 OR 5 at times but however all those length would contain same characters of domain name and endswith .php
more examples like this,
xyzklmopqr.com 80 xyzklm.php
lkjhgfdsaq.com 80 lkjhg.php
mjuyhnbgtr.com 80 mjuyhnbg.php
This works and you can easily change the numbers
(\w{5,6}|\w{8})\w*\.com 80 \1\.php
It's a little simpler than the other guy's solution
The following should work:
(((\w{5})\w?)\w{2}?)\w*\.com 80 (\1|\2|\3)\.php
Note that this works for the specific lengths you mentioned in your question (5, 6, and 8), not for any generic length substring.
Example: http://www.rubular.com/r/NwCcihN6o6
I would try ([a-z]{6})\S* 80 \1\.php
That would work for your 6 case, you can change the number as needed for your other cases.