Recognizing patterns given a set of sentences [closed] - regex

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I have a text file with lots of sentences. These sentences can occur in patterns. How do I recognize these patterns?
For example:
i woke up in the morning
i went to school
i played football
i came back home
i woke up in the morning
i went to school
i played basketball
At this point I want the program to say that "I played football" should have appeared.

This task seems to little bit complicate,but you can try this simple code for understanding or if finds it useful you can further implement it::
//the sentences/input input String
String sampleString1="xyz";
String[] sampleString2=sampleString1.split(".");
for(int i=1;i<=sampleString2.length;i++){
//The pattern which you can specify to match with the sentence
if(sampleString2[i].substring(0, 14).equals(sampleString2[0].substring(0,16))){
//code to execute the matched sentence.
System.out.println("Sentence matching with pattern ::" + sampleString2[i]);
}
}
If the pattern to be matched is the first line of the sequence ,then try this code.

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Merging broken lines [closed]

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In a text with many lines in notepad++, some lines are unintentionally broken into the next line without an end point. I want to merge lines that are more than 10 characters long that do not end with a dot(.) with of regex. Also put a space between merged lines.
For example, the following text:
tttttttttt
aaaaaaaaaaaaaaaa
bbbbbbbbbbbbbbbbbb.
ccccccccccccccccc
dddddddddddddddddd.
Convert to:
tttttttttt
aaaaaaaaaaaaaaaa bbbbbbbbbbbbbbbbbb.
ccccccccccccccccc dddddddddddddddddd.
I also tried the following regex code but it didn't work:
[^\.]\n

Why lone line in fortran code in one part is highlighted and become like comment? [closed]

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I'm trying to write a fortran code for 1 phase flow in porous media.
In discretized equations and other long line I have a below problem as you see in the picture.
After that highlighted phrase my code become like comment.
Can anyone help me?
According to this:
In its current state, the syntax highlighting for fixed-form Fortran in the extension only supports a line length of 72 characters. Anything after column 72 appears as comments (green) in the source code, which also affects the appearance of the following lines (when a closing parenthesis is in this green region for example)
You can change it on fortran_fixed-form.tmLanguage.json file or on the VS code settings.

Replace the words "can't, don't" by "can not, do not" using python [closed]

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I need to replace words like "{can't, don't, won't }" by "{can not, do not, would not}" using python
The problem is:
"can't" can be detected by checking suffix "n't", so we can replace "n't" by "not"
But how can we transform "ca" to "can" as when we split "can't" it should be transformed to "can not"?
Since the rules of English are large and sometimes inconsistent, your best bet is probably just to set up full word maps rather than trying to figure out on the fly which letters are represented by the apostrophe.
In other words, a dictionary with values like:
can't -> can not
don't -> do not
won't -> will not
:
oughtn't -> ought not

how to write a cpp program for replace string [closed]

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how to write a cpp program for replace string using only 1 text file
for example if in text file abc.txt
Hello
how are you
good
bye
i want output like
Hello
how are you
bad
bye
all above thing will be done in text file
Pretty easy. Open the file, get the text. Then iterate throw each word and ask the user if he/she wants to change that word. If yes, write new word on new file. If not, write old word on new file.
Now you just need to translate that to c++

How to get filename structure in a folder in Matlab [closed]

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I am designing a GUI in Matlab,
I have a folder called sth. It contains many files having same structure like,
filename_1_something.mat
filename_2_something.mat
In order to loop over filenames by selecting via index, I need to find a resulting string like this;
filename_%d_something.mat
So I don't need to read all the files in the dir. Two of the filenames are enough to compare strings and find the different char array item and change by %d.
Or anything different than this also appreciated.
using the regex provided by #rock321987 -
names = dir('*.mat');
num = length(names);
expression = '\w*_\d+_\w*\.mat';
for n = 1:num
str = names(n).name;
nameList{n} = regexp(str,expression,'match')
end
works on:
test_1_something.mat
test_10_something.mat
changing the regex to just \w*_\w*\.mat
works for
test_1.mat
1_test.mat
test_1_something.mat
test_10_something.mat
but also works for anything with an string joined by underscore .mat